Capacitor in parallel with a resistor between live and full bridge rectifier
Clash Royale CLAN TAG#URR8PPP
$begingroup$
I have an LED light bulb and dismantled it to look at the circuit inside.
I made some google search for pcb but couldn't find any relevant info about FST-855 or FST-854:
After drawing the schematic, I could not figure out what is the purpose of some of the elements. Here is the schematic (sorry for hand drawing):
I was expecting to see the electrolytic cap however did not understand the reason for film cap. Can you tell me why there is this "capacitor in parallel with a resistor" in between Live and full wave rectifier?
led capacitor
asked Jan 24 at 0:30
user458835user458835
112
$endgroup$
add a comment |
$begingroup$
I have an LED light bulb and dismantled it to look at the circuit inside.
I made some google search for pcb but couldn't find any relevant info about FST-855 or FST-854:
After drawing the schematic, I could not figure out what is the purpose of some of the elements. Here is the schematic (sorry for hand drawing):
I was expecting to see the electrolytic cap however did not understand the reason for film cap. Can you tell me why there is this "capacitor in parallel with a resistor" in between Live and full wave rectifier?
led capacitor
asked Jan 24 at 0:30
user458835user458835
112
$endgroup$
5
$begingroup$
A helpful search term: "capacitive dropper"
$endgroup$
– Hearth
Jan 24 at 0:50
add a comment |
$begingroup$
I have an LED light bulb and dismantled it to look at the circuit inside.
I made some google search for pcb but couldn't find any relevant info about FST-855 or FST-854:
After drawing the schematic, I could not figure out what is the purpose of some of the elements. Here is the schematic (sorry for hand drawing):
I was expecting to see the electrolytic cap however did not understand the reason for film cap. Can you tell me why there is this "capacitor in parallel with a resistor" in between Live and full wave rectifier?
led capacitor
asked Jan 24 at 0:30
user458835user458835
112
$endgroup$
I have an LED light bulb and dismantled it to look at the circuit inside.
I made some google search for pcb but couldn't find any relevant info about FST-855 or FST-854:
After drawing the schematic, I could not figure out what is the purpose of some of the elements. Here is the schematic (sorry for hand drawing):
I was expecting to see the electrolytic cap however did not understand the reason for film cap. Can you tell me why there is this "capacitor in parallel with a resistor" in between Live and full wave rectifier?
led capacitor
led capacitor
asked Jan 24 at 0:30
user458835user458835
112
asked Jan 24 at 0:30
user458835user458835
112
edited Jan 24 at 0:41
user458835
asked Jan 24 at 0:30
user458835user458835
112
asked Jan 24 at 0:30
user458835user458835
112
asked Jan 24 at 0:30
user458835user458835
112
112
5
$begingroup$
A helpful search term: "capacitive dropper"
$endgroup$
– Hearth
Jan 24 at 0:50
add a comment |
5
$begingroup$
A helpful search term: "capacitive dropper"
$endgroup$
– Hearth
Jan 24 at 0:50
5
5
$begingroup$
A helpful search term: "capacitive dropper"
$endgroup$
– Hearth
Jan 24 at 0:50
$begingroup$
A helpful search term: "capacitive dropper"
$endgroup$
– Hearth
Jan 24 at 0:50
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Welcome to Electrical Engineering!
The point of the capacitor is to limit the current through the full bridge rectifier. According to the “824J400V” indication, it is a 820nF capacitor. Its impedance at 50Hz is 3882Ω. It will limit the current to less than 62mA at 240V.
The point of the resistor in parallel is to discharge the capacitor when the bulb is disconnected.
answered Jan 24 at 0:40
user2233709user2233709
978210
$endgroup$
$begingroup$
Does that "J" has something to do with the square root of -1 due to some AC property of capacitors? Is that for Joules? How can we infer 820nF from 824J?
$endgroup$
– user458835
Jan 24 at 14:53
$begingroup$
@user458835 824J consists of value and tolerance. Value is 824 (write 4 zeroes following 82. The right-most number always indicates the number of zeroes. The result in picoFarads. So, 820000 picoFarads equal to 820 nanoFarads). Finally J indicates the tolerance: F: 1%, J: 5%, K: 10%, M: 20%.
$endgroup$
– Rohat Kılıç
Jan 24 at 15:30
$begingroup$
@RohatKılıç Thanks for the explanation, I did not know the meaning of the J letter…
$endgroup$
– user2233709
Jan 24 at 17:43
$begingroup$
Series capacitor on live AC is also used on transformerless power supplies. You may find a voltage divider comprised of both resistor and capacitor in order to reduce the voltage without consuming power on the capacitor.
$endgroup$
– Filipe Nicoli
Jan 26 at 2:27
add a comment |
Your Answer
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$begingroup$
Welcome to Electrical Engineering!
The point of the capacitor is to limit the current through the full bridge rectifier. According to the “824J400V” indication, it is a 820nF capacitor. Its impedance at 50Hz is 3882Ω. It will limit the current to less than 62mA at 240V.
The point of the resistor in parallel is to discharge the capacitor when the bulb is disconnected.
answered Jan 24 at 0:40
user2233709user2233709
978210
$endgroup$
$begingroup$
Does that "J" has something to do with the square root of -1 due to some AC property of capacitors? Is that for Joules? How can we infer 820nF from 824J?
$endgroup$
– user458835
Jan 24 at 14:53
$begingroup$
@user458835 824J consists of value and tolerance. Value is 824 (write 4 zeroes following 82. The right-most number always indicates the number of zeroes. The result in picoFarads. So, 820000 picoFarads equal to 820 nanoFarads). Finally J indicates the tolerance: F: 1%, J: 5%, K: 10%, M: 20%.
$endgroup$
– Rohat Kılıç
Jan 24 at 15:30
$begingroup$
@RohatKılıç Thanks for the explanation, I did not know the meaning of the J letter…
$endgroup$
– user2233709
Jan 24 at 17:43
$begingroup$
Series capacitor on live AC is also used on transformerless power supplies. You may find a voltage divider comprised of both resistor and capacitor in order to reduce the voltage without consuming power on the capacitor.
$endgroup$
– Filipe Nicoli
Jan 26 at 2:27
add a comment |
$begingroup$
Welcome to Electrical Engineering!
The point of the capacitor is to limit the current through the full bridge rectifier. According to the “824J400V” indication, it is a 820nF capacitor. Its impedance at 50Hz is 3882Ω. It will limit the current to less than 62mA at 240V.
The point of the resistor in parallel is to discharge the capacitor when the bulb is disconnected.
answered Jan 24 at 0:40
user2233709user2233709
978210
$endgroup$
$begingroup$
Does that "J" has something to do with the square root of -1 due to some AC property of capacitors? Is that for Joules? How can we infer 820nF from 824J?
$endgroup$
– user458835
Jan 24 at 14:53
$begingroup$
@user458835 824J consists of value and tolerance. Value is 824 (write 4 zeroes following 82. The right-most number always indicates the number of zeroes. The result in picoFarads. So, 820000 picoFarads equal to 820 nanoFarads). Finally J indicates the tolerance: F: 1%, J: 5%, K: 10%, M: 20%.
$endgroup$
– Rohat Kılıç
Jan 24 at 15:30
$begingroup$
@RohatKılıç Thanks for the explanation, I did not know the meaning of the J letter…
$endgroup$
– user2233709
Jan 24 at 17:43
$begingroup$
Series capacitor on live AC is also used on transformerless power supplies. You may find a voltage divider comprised of both resistor and capacitor in order to reduce the voltage without consuming power on the capacitor.
$endgroup$
– Filipe Nicoli
Jan 26 at 2:27
add a comment |
$begingroup$
Welcome to Electrical Engineering!
The point of the capacitor is to limit the current through the full bridge rectifier. According to the “824J400V” indication, it is a 820nF capacitor. Its impedance at 50Hz is 3882Ω. It will limit the current to less than 62mA at 240V.
The point of the resistor in parallel is to discharge the capacitor when the bulb is disconnected.
answered Jan 24 at 0:40
user2233709user2233709
978210
$endgroup$
Welcome to Electrical Engineering!
The point of the capacitor is to limit the current through the full bridge rectifier. According to the “824J400V” indication, it is a 820nF capacitor. Its impedance at 50Hz is 3882Ω. It will limit the current to less than 62mA at 240V.
The point of the resistor in parallel is to discharge the capacitor when the bulb is disconnected.
answered Jan 24 at 0:40
user2233709user2233709
978210
answered Jan 24 at 0:40
user2233709user2233709
978210
answered Jan 24 at 0:40
user2233709user2233709
978210
answered Jan 24 at 0:40
user2233709user2233709
978210
978210
$begingroup$
Does that "J" has something to do with the square root of -1 due to some AC property of capacitors? Is that for Joules? How can we infer 820nF from 824J?
$endgroup$
– user458835
Jan 24 at 14:53
$begingroup$
@user458835 824J consists of value and tolerance. Value is 824 (write 4 zeroes following 82. The right-most number always indicates the number of zeroes. The result in picoFarads. So, 820000 picoFarads equal to 820 nanoFarads). Finally J indicates the tolerance: F: 1%, J: 5%, K: 10%, M: 20%.
$endgroup$
– Rohat Kılıç
Jan 24 at 15:30
$begingroup$
@RohatKılıç Thanks for the explanation, I did not know the meaning of the J letter…
$endgroup$
– user2233709
Jan 24 at 17:43
$begingroup$
Series capacitor on live AC is also used on transformerless power supplies. You may find a voltage divider comprised of both resistor and capacitor in order to reduce the voltage without consuming power on the capacitor.
$endgroup$
– Filipe Nicoli
Jan 26 at 2:27
add a comment |
$begingroup$
Does that "J" has something to do with the square root of -1 due to some AC property of capacitors? Is that for Joules? How can we infer 820nF from 824J?
$endgroup$
– user458835
Jan 24 at 14:53
$begingroup$
@user458835 824J consists of value and tolerance. Value is 824 (write 4 zeroes following 82. The right-most number always indicates the number of zeroes. The result in picoFarads. So, 820000 picoFarads equal to 820 nanoFarads). Finally J indicates the tolerance: F: 1%, J: 5%, K: 10%, M: 20%.
$endgroup$
– Rohat Kılıç
Jan 24 at 15:30
$begingroup$
@RohatKılıç Thanks for the explanation, I did not know the meaning of the J letter…
$endgroup$
– user2233709
Jan 24 at 17:43
$begingroup$
Series capacitor on live AC is also used on transformerless power supplies. You may find a voltage divider comprised of both resistor and capacitor in order to reduce the voltage without consuming power on the capacitor.
$endgroup$
– Filipe Nicoli
Jan 26 at 2:27
$begingroup$
Does that "J" has something to do with the square root of -1 due to some AC property of capacitors? Is that for Joules? How can we infer 820nF from 824J?
$endgroup$
– user458835
Jan 24 at 14:53
$begingroup$
Does that "J" has something to do with the square root of -1 due to some AC property of capacitors? Is that for Joules? How can we infer 820nF from 824J?
$endgroup$
– user458835
Jan 24 at 14:53
$begingroup$
@user458835 824J consists of value and tolerance. Value is 824 (write 4 zeroes following 82. The right-most number always indicates the number of zeroes. The result in picoFarads. So, 820000 picoFarads equal to 820 nanoFarads). Finally J indicates the tolerance: F: 1%, J: 5%, K: 10%, M: 20%.
$endgroup$
– Rohat Kılıç
Jan 24 at 15:30
$begingroup$
@user458835 824J consists of value and tolerance. Value is 824 (write 4 zeroes following 82. The right-most number always indicates the number of zeroes. The result in picoFarads. So, 820000 picoFarads equal to 820 nanoFarads). Finally J indicates the tolerance: F: 1%, J: 5%, K: 10%, M: 20%.
$endgroup$
– Rohat Kılıç
Jan 24 at 15:30
$begingroup$
@RohatKılıç Thanks for the explanation, I did not know the meaning of the J letter…
$endgroup$
– user2233709
Jan 24 at 17:43
$begingroup$
@RohatKılıç Thanks for the explanation, I did not know the meaning of the J letter…
$endgroup$
– user2233709
Jan 24 at 17:43
$begingroup$
Series capacitor on live AC is also used on transformerless power supplies. You may find a voltage divider comprised of both resistor and capacitor in order to reduce the voltage without consuming power on the capacitor.
$endgroup$
– Filipe Nicoli
Jan 26 at 2:27
$begingroup$
Series capacitor on live AC is also used on transformerless power supplies. You may find a voltage divider comprised of both resistor and capacitor in order to reduce the voltage without consuming power on the capacitor.
$endgroup$
– Filipe Nicoli
Jan 26 at 2:27
add a comment |
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5
$begingroup$
A helpful search term: "capacitive dropper"
$endgroup$
– Hearth
Jan 24 at 0:50