Counting the number of lines between same repeating pattern
Clash Royale CLAN TAG#URR8PPP
0
I have refer this Grep the lines between the occurrence of the same pattern , I don't want to split into file; instead, I want to store it into an array. File count.txt contain:
0
1
2
3
0
1
2
0
1
My script code is:
total=$(sed -n $= count.txt)
c=0
k=0
lineno=0
var="0"
for i in $(cat count.txt);
do
if ["$i" -eq "$var"]
then
arr[$((k++))]=c
c=0
c=$((c+1))
else
c=$((c+1))
if ["$lineno" -eq "$total"]
then
arr[$((k++))]=c
fi
fi
lineno=$((lineno+1))
done
The above logic is tested on C++ launguage which on printing the array shows : 0 4 3 2
Firstly, my script is showing error like line 9: [0: command not found.
Secondly, is there any efficient method to store the repeated count in array, like above output?
bash awk sed
edited 2 days ago
Rui F Ribeiro
39.3k1479131
asked Dec 27 '18 at 13:01
AryaArya
1
add a comment |
0
I have refer this Grep the lines between the occurrence of the same pattern , I don't want to split into file; instead, I want to store it into an array. File count.txt contain:
0
1
2
3
0
1
2
0
1
My script code is:
total=$(sed -n $= count.txt)
c=0
k=0
lineno=0
var="0"
for i in $(cat count.txt);
do
if ["$i" -eq "$var"]
then
arr[$((k++))]=c
c=0
c=$((c+1))
else
c=$((c+1))
if ["$lineno" -eq "$total"]
then
arr[$((k++))]=c
fi
fi
lineno=$((lineno+1))
done
The above logic is tested on C++ launguage which on printing the array shows : 0 4 3 2
Firstly, my script is showing error like line 9: [0: command not found.
Secondly, is there any efficient method to store the repeated count in array, like above output?
bash awk sed
edited 2 days ago
Rui F Ribeiro
39.3k1479131
asked Dec 27 '18 at 13:01
AryaArya
1
1
Thecommand not founderror is because your[test lacks the required whitespace:[ "$i" -eq "$var" ]
– steeldriver
Dec 27 '18 at 13:06
@msp9011 I want the output: 4 3 2 in array
– Arya
Dec 27 '18 at 13:17
There is not output instruction; in addition=cis putting the letter c in the variable, may be you want=$cand the first test is right the first time as0=0this explains the potential output 0 in sequence instead of4 3 2.
– matzeri
Dec 27 '18 at 14:22
add a comment |
0
0
0
I have refer this Grep the lines between the occurrence of the same pattern , I don't want to split into file; instead, I want to store it into an array. File count.txt contain:
0
1
2
3
0
1
2
0
1
My script code is:
total=$(sed -n $= count.txt)
c=0
k=0
lineno=0
var="0"
for i in $(cat count.txt);
do
if ["$i" -eq "$var"]
then
arr[$((k++))]=c
c=0
c=$((c+1))
else
c=$((c+1))
if ["$lineno" -eq "$total"]
then
arr[$((k++))]=c
fi
fi
lineno=$((lineno+1))
done
The above logic is tested on C++ launguage which on printing the array shows : 0 4 3 2
Firstly, my script is showing error like line 9: [0: command not found.
Secondly, is there any efficient method to store the repeated count in array, like above output?
bash awk sed
edited 2 days ago
Rui F Ribeiro
39.3k1479131
asked Dec 27 '18 at 13:01
AryaArya
1
I have refer this Grep the lines between the occurrence of the same pattern , I don't want to split into file; instead, I want to store it into an array. File count.txt contain:
0
1
2
3
0
1
2
0
1
My script code is:
total=$(sed -n $= count.txt)
c=0
k=0
lineno=0
var="0"
for i in $(cat count.txt);
do
if ["$i" -eq "$var"]
then
arr[$((k++))]=c
c=0
c=$((c+1))
else
c=$((c+1))
if ["$lineno" -eq "$total"]
then
arr[$((k++))]=c
fi
fi
lineno=$((lineno+1))
done
The above logic is tested on C++ launguage which on printing the array shows : 0 4 3 2
Firstly, my script is showing error like line 9: [0: command not found.
Secondly, is there any efficient method to store the repeated count in array, like above output?
bash awk sed
bash awk sed
edited 2 days ago
Rui F Ribeiro
39.3k1479131
asked Dec 27 '18 at 13:01
AryaArya
1
edited 2 days ago
Rui F Ribeiro
39.3k1479131
asked Dec 27 '18 at 13:01
AryaArya
1
edited 2 days ago
Rui F Ribeiro
39.3k1479131
edited 2 days ago
Rui F Ribeiro
39.3k1479131
edited 2 days ago
Rui F Ribeiro
39.3k1479131
39.3k1479131
asked Dec 27 '18 at 13:01
AryaArya
1
asked Dec 27 '18 at 13:01
AryaArya
1
asked Dec 27 '18 at 13:01
AryaArya
1
1
1
Thecommand not founderror is because your[test lacks the required whitespace:[ "$i" -eq "$var" ]
– steeldriver
Dec 27 '18 at 13:06
@msp9011 I want the output: 4 3 2 in array
– Arya
Dec 27 '18 at 13:17
There is not output instruction; in addition=cis putting the letter c in the variable, may be you want=$cand the first test is right the first time as0=0this explains the potential output 0 in sequence instead of4 3 2.
– matzeri
Dec 27 '18 at 14:22
add a comment |
1
Thecommand not founderror is because your[test lacks the required whitespace:[ "$i" -eq "$var" ]
– steeldriver
Dec 27 '18 at 13:06
@msp9011 I want the output: 4 3 2 in array
– Arya
Dec 27 '18 at 13:17
There is not output instruction; in addition=cis putting the letter c in the variable, may be you want=$cand the first test is right the first time as0=0this explains the potential output 0 in sequence instead of4 3 2.
– matzeri
Dec 27 '18 at 14:22
1
1
The
command not found error is because your [ test lacks the required whitespace: [ "$i" -eq "$var" ]– steeldriver
Dec 27 '18 at 13:06
The
command not found error is because your [ test lacks the required whitespace: [ "$i" -eq "$var" ]– steeldriver
Dec 27 '18 at 13:06
@msp9011 I want the output: 4 3 2 in array
– Arya
Dec 27 '18 at 13:17
@msp9011 I want the output: 4 3 2 in array
– Arya
Dec 27 '18 at 13:17
There is not output instruction; in addition
=c is putting the letter c in the variable, may be you want =$c and the first test is right the first time as 0=0 this explains the potential output 0 in sequence instead of 4 3 2.– matzeri
Dec 27 '18 at 14:22
There is not output instruction; in addition
=c is putting the letter c in the variable, may be you want =$c and the first test is right the first time as 0=0 this explains the potential output 0 in sequence instead of 4 3 2.– matzeri
Dec 27 '18 at 14:22
add a comment |
2 Answers
2
active
oldest
votes
1
An awk one-liner:
awk -v patt="0" -v prev=1 '
$0 ~ patt print NR - prev; prev = NR
END print NR + 1 - prev
' file
answered Dec 27 '18 at 15:07
glenn jackmanglenn jackman
50.4k570107
add a comment |
0
Try this,
LINES=(`cat count.txt `)
arr=()
arrIndex=0
a=`echo $LINES`
for i in "$!LINES[@]"; do
if [[ "$LINES[$i]" = "$a" ]]; then
arr[arrIndex]=`echo "$i"`
arrIndex=$((arrIndex+1))
fi
done
arr[arrIndex]=`echo $#LINES[@]`
arrOut=()
for ((i=1; i<"$#arr[@]"; ++i))
do
j=`expr $i - 1 `
arrOut[$i]=`echo "$arr[$i] $arr[$j]" | awk 'a=$1-$2;print a'`
done
echo $arrOut[@]
answered Dec 27 '18 at 14:13
msp9011msp9011
3,82843863
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
An awk one-liner:
awk -v patt="0" -v prev=1 '
$0 ~ patt print NR - prev; prev = NR
END print NR + 1 - prev
' file
answered Dec 27 '18 at 15:07
glenn jackmanglenn jackman
50.4k570107
add a comment |
1
An awk one-liner:
awk -v patt="0" -v prev=1 '
$0 ~ patt print NR - prev; prev = NR
END print NR + 1 - prev
' file
answered Dec 27 '18 at 15:07
glenn jackmanglenn jackman
50.4k570107
add a comment |
1
1
1
An awk one-liner:
awk -v patt="0" -v prev=1 '
$0 ~ patt print NR - prev; prev = NR
END print NR + 1 - prev
' file
answered Dec 27 '18 at 15:07
glenn jackmanglenn jackman
50.4k570107
An awk one-liner:
awk -v patt="0" -v prev=1 '
$0 ~ patt print NR - prev; prev = NR
END print NR + 1 - prev
' file
answered Dec 27 '18 at 15:07
glenn jackmanglenn jackman
50.4k570107
answered Dec 27 '18 at 15:07
glenn jackmanglenn jackman
50.4k570107
answered Dec 27 '18 at 15:07
glenn jackmanglenn jackman
50.4k570107
answered Dec 27 '18 at 15:07
glenn jackmanglenn jackman
50.4k570107
50.4k570107
add a comment |
add a comment |
0
Try this,
LINES=(`cat count.txt `)
arr=()
arrIndex=0
a=`echo $LINES`
for i in "$!LINES[@]"; do
if [[ "$LINES[$i]" = "$a" ]]; then
arr[arrIndex]=`echo "$i"`
arrIndex=$((arrIndex+1))
fi
done
arr[arrIndex]=`echo $#LINES[@]`
arrOut=()
for ((i=1; i<"$#arr[@]"; ++i))
do
j=`expr $i - 1 `
arrOut[$i]=`echo "$arr[$i] $arr[$j]" | awk 'a=$1-$2;print a'`
done
echo $arrOut[@]
answered Dec 27 '18 at 14:13
msp9011msp9011
3,82843863
add a comment |
0
Try this,
LINES=(`cat count.txt `)
arr=()
arrIndex=0
a=`echo $LINES`
for i in "$!LINES[@]"; do
if [[ "$LINES[$i]" = "$a" ]]; then
arr[arrIndex]=`echo "$i"`
arrIndex=$((arrIndex+1))
fi
done
arr[arrIndex]=`echo $#LINES[@]`
arrOut=()
for ((i=1; i<"$#arr[@]"; ++i))
do
j=`expr $i - 1 `
arrOut[$i]=`echo "$arr[$i] $arr[$j]" | awk 'a=$1-$2;print a'`
done
echo $arrOut[@]
answered Dec 27 '18 at 14:13
msp9011msp9011
3,82843863
add a comment |
0
0
0
Try this,
LINES=(`cat count.txt `)
arr=()
arrIndex=0
a=`echo $LINES`
for i in "$!LINES[@]"; do
if [[ "$LINES[$i]" = "$a" ]]; then
arr[arrIndex]=`echo "$i"`
arrIndex=$((arrIndex+1))
fi
done
arr[arrIndex]=`echo $#LINES[@]`
arrOut=()
for ((i=1; i<"$#arr[@]"; ++i))
do
j=`expr $i - 1 `
arrOut[$i]=`echo "$arr[$i] $arr[$j]" | awk 'a=$1-$2;print a'`
done
echo $arrOut[@]
answered Dec 27 '18 at 14:13
msp9011msp9011
3,82843863
Try this,
LINES=(`cat count.txt `)
arr=()
arrIndex=0
a=`echo $LINES`
for i in "$!LINES[@]"; do
if [[ "$LINES[$i]" = "$a" ]]; then
arr[arrIndex]=`echo "$i"`
arrIndex=$((arrIndex+1))
fi
done
arr[arrIndex]=`echo $#LINES[@]`
arrOut=()
for ((i=1; i<"$#arr[@]"; ++i))
do
j=`expr $i - 1 `
arrOut[$i]=`echo "$arr[$i] $arr[$j]" | awk 'a=$1-$2;print a'`
done
echo $arrOut[@]
answered Dec 27 '18 at 14:13
msp9011msp9011
3,82843863
answered Dec 27 '18 at 14:13
msp9011msp9011
3,82843863
answered Dec 27 '18 at 14:13
msp9011msp9011
3,82843863
answered Dec 27 '18 at 14:13
msp9011msp9011
3,82843863
3,82843863
add a comment |
add a comment |
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1
The
command not founderror is because your[test lacks the required whitespace:[ "$i" -eq "$var" ]– steeldriver
Dec 27 '18 at 13:06
@msp9011 I want the output: 4 3 2 in array
– Arya
Dec 27 '18 at 13:17
There is not output instruction; in addition
=cis putting the letter c in the variable, may be you want=$cand the first test is right the first time as0=0this explains the potential output 0 in sequence instead of4 3 2.– matzeri
Dec 27 '18 at 14:22