How to create a list of six unit vectors in 3D?
Clash Royale CLAN TAG#URR8PPP
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I want to have a list 1,0,0,0,1,0,0,0,1,-1,0,0,0,-1,0,0,0,-1. How to generate it smartly?
list-manipulation
asked Nov 30 at 15:10
Artificial Stupidity
21219
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up vote
2
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I want to have a list 1,0,0,0,1,0,0,0,1,-1,0,0,0,-1,0,0,0,-1. How to generate it smartly?
list-manipulation
asked Nov 30 at 15:10
Artificial Stupidity
21219
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I want to have a list 1,0,0,0,1,0,0,0,1,-1,0,0,0,-1,0,0,0,-1. How to generate it smartly?
list-manipulation
asked Nov 30 at 15:10
Artificial Stupidity
21219
I want to have a list 1,0,0,0,1,0,0,0,1,-1,0,0,0,-1,0,0,0,-1. How to generate it smartly?
list-manipulation
list-manipulation
asked Nov 30 at 15:10
Artificial Stupidity
21219
asked Nov 30 at 15:10
Artificial Stupidity
21219
asked Nov 30 at 15:10
Artificial Stupidity
21219
asked Nov 30 at 15:10
Artificial Stupidity
21219
asked Nov 30 at 15:10
Artificial Stupidity
21219
21219
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
up vote
5
down vote
accepted
Perhaps this
Join[IdentityMatrix[3], -IdentityMatrix[3]]
(* 1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1 *)
answered Nov 30 at 15:22
Michael E2
144k11193463
+1: Good one! Thanks!
– Artificial Stupidity
Nov 30 at 15:23
1
I like the variantJoin[#, -#] &@IdentityMatrix[3]
– mikado
Nov 30 at 16:53
1
@mikado Yeah, I thought of that, but too much top-row-shift typing for my podgy fingers compared to I-d--<kbd>return</kbd>... :)
– Michael E2
Nov 30 at 17:04
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up vote
2
down vote
Join@@(Permutations[#]&/@#,-#&@1,0,0)
1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1
answered Nov 30 at 15:23
J42161217
3,682220
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up vote
1
down vote
UnitVector:
Join[#, -#] &@(UnitVector[3, #] & /@ Range[3])
1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1
answered Dec 1 at 11:31
Αλέξανδρος Ζεγγ
3,7301927
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
5
down vote
accepted
Perhaps this
Join[IdentityMatrix[3], -IdentityMatrix[3]]
(* 1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1 *)
answered Nov 30 at 15:22
Michael E2
144k11193463
+1: Good one! Thanks!
– Artificial Stupidity
Nov 30 at 15:23
1
I like the variantJoin[#, -#] &@IdentityMatrix[3]
– mikado
Nov 30 at 16:53
1
@mikado Yeah, I thought of that, but too much top-row-shift typing for my podgy fingers compared to I-d--<kbd>return</kbd>... :)
– Michael E2
Nov 30 at 17:04
add a comment |
up vote
5
down vote
accepted
Perhaps this
Join[IdentityMatrix[3], -IdentityMatrix[3]]
(* 1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1 *)
answered Nov 30 at 15:22
Michael E2
144k11193463
+1: Good one! Thanks!
– Artificial Stupidity
Nov 30 at 15:23
1
I like the variantJoin[#, -#] &@IdentityMatrix[3]
– mikado
Nov 30 at 16:53
1
@mikado Yeah, I thought of that, but too much top-row-shift typing for my podgy fingers compared to I-d--<kbd>return</kbd>... :)
– Michael E2
Nov 30 at 17:04
add a comment |
up vote
5
down vote
accepted
up vote
5
down vote
accepted
Perhaps this
Join[IdentityMatrix[3], -IdentityMatrix[3]]
(* 1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1 *)
answered Nov 30 at 15:22
Michael E2
144k11193463
Perhaps this
Join[IdentityMatrix[3], -IdentityMatrix[3]]
(* 1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1 *)
answered Nov 30 at 15:22
Michael E2
144k11193463
answered Nov 30 at 15:22
Michael E2
144k11193463
answered Nov 30 at 15:22
Michael E2
144k11193463
answered Nov 30 at 15:22
Michael E2
144k11193463
144k11193463
+1: Good one! Thanks!
– Artificial Stupidity
Nov 30 at 15:23
1
I like the variantJoin[#, -#] &@IdentityMatrix[3]
– mikado
Nov 30 at 16:53
1
@mikado Yeah, I thought of that, but too much top-row-shift typing for my podgy fingers compared to I-d--<kbd>return</kbd>... :)
– Michael E2
Nov 30 at 17:04
add a comment |
+1: Good one! Thanks!
– Artificial Stupidity
Nov 30 at 15:23
1
I like the variantJoin[#, -#] &@IdentityMatrix[3]
– mikado
Nov 30 at 16:53
1
@mikado Yeah, I thought of that, but too much top-row-shift typing for my podgy fingers compared to I-d--<kbd>return</kbd>... :)
– Michael E2
Nov 30 at 17:04
+1: Good one! Thanks!
– Artificial Stupidity
Nov 30 at 15:23
+1: Good one! Thanks!
– Artificial Stupidity
Nov 30 at 15:23
1
1
I like the variant
Join[#, -#] &@IdentityMatrix[3]– mikado
Nov 30 at 16:53
I like the variant
Join[#, -#] &@IdentityMatrix[3]– mikado
Nov 30 at 16:53
1
1
@mikado Yeah, I thought of that, but too much top-row-shift typing for my podgy fingers compared to I-d--<kbd>return</kbd>... :)
– Michael E2
Nov 30 at 17:04
@mikado Yeah, I thought of that, but too much top-row-shift typing for my podgy fingers compared to I-d--<kbd>return</kbd>... :)
– Michael E2
Nov 30 at 17:04
add a comment |
up vote
2
down vote
Join@@(Permutations[#]&/@#,-#&@1,0,0)
1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1
answered Nov 30 at 15:23
J42161217
3,682220
add a comment |
up vote
2
down vote
Join@@(Permutations[#]&/@#,-#&@1,0,0)
1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1
answered Nov 30 at 15:23
J42161217
3,682220
add a comment |
up vote
2
down vote
up vote
2
down vote
Join@@(Permutations[#]&/@#,-#&@1,0,0)
1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1
answered Nov 30 at 15:23
J42161217
3,682220
Join@@(Permutations[#]&/@#,-#&@1,0,0)
1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1
answered Nov 30 at 15:23
J42161217
3,682220
answered Nov 30 at 15:23
J42161217
3,682220
answered Nov 30 at 15:23
J42161217
3,682220
answered Nov 30 at 15:23
J42161217
3,682220
3,682220
add a comment |
add a comment |
up vote
1
down vote
UnitVector:
Join[#, -#] &@(UnitVector[3, #] & /@ Range[3])
1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1
answered Dec 1 at 11:31
Αλέξανδρος Ζεγγ
3,7301927
add a comment |
up vote
1
down vote
UnitVector:
Join[#, -#] &@(UnitVector[3, #] & /@ Range[3])
1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1
answered Dec 1 at 11:31
Αλέξανδρος Ζεγγ
3,7301927
add a comment |
up vote
1
down vote
up vote
1
down vote
UnitVector:
Join[#, -#] &@(UnitVector[3, #] & /@ Range[3])
1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1
answered Dec 1 at 11:31
Αλέξανδρος Ζεγγ
3,7301927
UnitVector:
Join[#, -#] &@(UnitVector[3, #] & /@ Range[3])
1, 0, 0, 0, 1, 0, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, -1
answered Dec 1 at 11:31
Αλέξανδρος Ζεγγ
3,7301927
answered Dec 1 at 11:31
Αλέξανδρος Ζεγγ
3,7301927
answered Dec 1 at 11:31
Αλέξανδρος Ζεγγ
3,7301927
answered Dec 1 at 11:31
Αλέξανδρος Ζεγγ
3,7301927
3,7301927
add a comment |
add a comment |
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