mjhjmtu

I tried to change an string to index to use for an array but I have been unable to get it to work.

This is my file

$ cat file1.txt
101,Harish,BAN
102,Srinu,HYD

And this code:

#!/bin/bash
IFS=','
while read line
do
 DELIM_REMOVE=`echo $line|sed 's/,/ /g'`
 V=($DEL_REMOVE)
 echo $DELIM_REMOVE
 for i in "$!V[@]"; do
 printf 'V[%s] = %sn' "$i" "$V[i]"
 echo "$V[i]"
 done
done < /home/ec2-user/file1.txt
echo "$V[i]"

I also need to use the dynamically generated variables in loop to another loop.

Don't use shell loops to process text, use a text processing utility.

awk -F, 'for (i = 0; i < NF; i++) printf "v[%d] = %sn", i, $(i+1)' < file1.txt

If you have to use a bash loop, then it would make more sense to write it as:

while IFS=, read -ra v; do
 for i in "$!v[@]"; do
 printf 'v[%d] = %sn' "$i" "$v[i]"
 done
done < file1.txt

With the caveat that if the last field is empty, it will be skipped.

There are several issues with your script.

• The name of the variable in V=($DEL_REMOVE) should be V=($DELIM_REMOVE)
  


• You are setting IFS to a comma (,) but you are removing the comma with sed.

By doing those two changes your script starts to do something reasonable.

Making some other changes, your script becomes:

#!/bin/bash

IFS=' ' # Use the space to split
set -f # Avoid globing of values with *,? or 
while read -r line # read the variable without removing backslash
do
 v=( $line//,/ ) # Convert to an array by splitting with the shell.
 for i in "$!v[@]"; do
 printf 'v[%s] = %sn' "$i" "$v[i]"
 done
done < file1.txt

Which will print:

v[0] = 101
v[1] = Harish
v[2] = BAN
v[0] = 102
v[1] = Srinu
v[2] = HYD

Is that what you expected it to do?