mjhjmtu

I have a file:

property(Address1, 4.5)
property(Address2, 2.2)
property(Address3, 9.0)
property(Address4, 3.4)
---

I want to replace the floating points based on some conditions (For example: if the number is between 2 and 4, I will replace it by Low, otherwise High) to produce this:

property(Address1, High)
property(Address2, Low)
property(Address3, High)
property(Address4, Low)
---

My try: (1) First extract the number using $. (2) Check whether the condition satisfies (3) then print it. But in this process I am failing to output the Address* to the output file.

This does (strictly) what you ask for:

awk ' print $1, (($2>2)&&($2<4))?"Low)":"High)" '

But it is taking advantage of the fact that an string like 9.0) (with the trailing parenthesis) is converted to the number 9 by awk. That may fail if an space gets added for example.

A more strict solution is to also use the closing parenthesis as a field delimiter to remove it from the contents of field number 2.

awk -F'[ )]' 'print $1,(($2>2)&&($2<4))?"Low)":"High)"'

I have tried with if and else condition

sed "s/)$//g" filename| awk 'if($2 > 2 && $2 < 4) $2="low)";print $0else$2="high)";print $0'
 property(Address1, high)
 property(Address2, low)
 property(Address3, high)
 property(Address4, low)

With perl, assuming numbers are in the format [-]<digits>[.<digits>], and matching on them wherever they are in the input provided they're neither preceded nor followed by word characters (so Address1 is not changed to AddressHigh for instance):

<input perl -pe 's(?<!w)-?d[d.]*(?!w)$& >=2 && $& <=4 ? "Low" : "High"ge'