Return the index of an element which matches a value

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0
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I have an array -

val=(4196976 4601313 4242010 0 3581283 2392831 3176852 3205880 3794451 0 3627872)

I am trying to find the index of all the elements whose values are equal to 0

How can i achienve this?

This is what i have tried -

for ((i = 1; i <= 10; i++)); do
 if [ "$i" -eq "0" ]; then
 echo "Index: $i, value: $val[i]"
 fi
done

The output should be

Index: 3, value: 0
Index: 9, value: 0

asked 22 hours ago

PepeHands

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up vote
0
down vote

favorite

I have an array -

val=(4196976 4601313 4242010 0 3581283 2392831 3176852 3205880 3794451 0 3627872)

I am trying to find the index of all the elements whose values are equal to 0

How can i achienve this?

This is what i have tried -

for ((i = 1; i <= 10; i++)); do
 if [ "$i" -eq "0" ]; then
 echo "Index: $i, value: $val[i]"
 fi
done

The output should be

Index: 3, value: 0
Index: 9, value: 0

asked 22 hours ago

PepeHands

add a comment |

up vote
0
down vote

favorite

I have an array -

val=(4196976 4601313 4242010 0 3581283 2392831 3176852 3205880 3794451 0 3627872)

I am trying to find the index of all the elements whose values are equal to 0

How can i achienve this?

This is what i have tried -

for ((i = 1; i <= 10; i++)); do
 if [ "$i" -eq "0" ]; then
 echo "Index: $i, value: $val[i]"
 fi
done

The output should be

Index: 3, value: 0
Index: 9, value: 0

asked 22 hours ago

PepeHands

I have an array -

val=(4196976 4601313 4242010 0 3581283 2392831 3176852 3205880 3794451 0 3627872)

I am trying to find the index of all the elements whose values are equal to 0

How can i achienve this?

This is what i have tried -

for ((i = 1; i <= 10; i++)); do
 if [ "$i" -eq "0" ]; then
 echo "Index: $i, value: $val[i]"
 fi
done

The output should be

Index: 3, value: 0
Index: 9, value: 0

linux bash

asked 22 hours ago

PepeHands

asked 22 hours ago

PepeHands

asked 22 hours ago

PepeHands

asked 22 hours ago

PepeHands

asked 22 hours ago

PepeHands

add a comment |

2 Answers
2

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up vote
0
down vote

accepted

#!/bin/bash
val=(4196976 4601313 4242010 0 3581283 2392831 3176852 3205880 3794451 0 3627872)
n=0
for i in $val[@]; do
 [ $i -eq 0 ] && echo Index: $n, value: $i
 ((n++))
done

answered 21 hours ago

Ipor Sircer

9,97211023

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up vote
2
down vote

If the array has gaps in it, it might be better to loop over the indices of the array instead:

for i in "$!val[@]"
do
 if [[ $val[i] -eq 0 ]]
 then
 echo "Index: $i, value: $val[i]"
 fi
done

So, if your array was like:

val=([100]=327823 [54]=0 [787998]=377463287)

You'd still get 54 as the index.

This should also work for associative arrays (strings as indices instead of integers).

answered 21 hours ago

Olorin

1,479112

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
0
down vote

accepted

#!/bin/bash
val=(4196976 4601313 4242010 0 3581283 2392831 3176852 3205880 3794451 0 3627872)
n=0
for i in $val[@]; do
 [ $i -eq 0 ] && echo Index: $n, value: $i
 ((n++))
done

answered 21 hours ago

Ipor Sircer

9,97211023

add a comment |

up vote
0
down vote

accepted

#!/bin/bash
val=(4196976 4601313 4242010 0 3581283 2392831 3176852 3205880 3794451 0 3627872)
n=0
for i in $val[@]; do
 [ $i -eq 0 ] && echo Index: $n, value: $i
 ((n++))
done

answered 21 hours ago

Ipor Sircer

9,97211023

add a comment |

up vote
0
down vote

accepted

#!/bin/bash
val=(4196976 4601313 4242010 0 3581283 2392831 3176852 3205880 3794451 0 3627872)
n=0
for i in $val[@]; do
 [ $i -eq 0 ] && echo Index: $n, value: $i
 ((n++))
done

answered 21 hours ago

Ipor Sircer

9,97211023

#!/bin/bash
val=(4196976 4601313 4242010 0 3581283 2392831 3176852 3205880 3794451 0 3627872)
n=0
for i in $val[@]; do
 [ $i -eq 0 ] && echo Index: $n, value: $i
 ((n++))
done

answered 21 hours ago

Ipor Sircer

9,97211023

answered 21 hours ago

Ipor Sircer

9,97211023

answered 21 hours ago

Ipor Sircer

9,97211023

answered 21 hours ago

Ipor Sircer

9,97211023

add a comment |

up vote
2
down vote

If the array has gaps in it, it might be better to loop over the indices of the array instead:

for i in "$!val[@]"
do
 if [[ $val[i] -eq 0 ]]
 then
 echo "Index: $i, value: $val[i]"
 fi
done

So, if your array was like:

val=([100]=327823 [54]=0 [787998]=377463287)

You'd still get 54 as the index.

This should also work for associative arrays (strings as indices instead of integers).

answered 21 hours ago

Olorin

1,479112

add a comment |

up vote
2
down vote

If the array has gaps in it, it might be better to loop over the indices of the array instead:

for i in "$!val[@]"
do
 if [[ $val[i] -eq 0 ]]
 then
 echo "Index: $i, value: $val[i]"
 fi
done

So, if your array was like:

val=([100]=327823 [54]=0 [787998]=377463287)

You'd still get 54 as the index.

This should also work for associative arrays (strings as indices instead of integers).

answered 21 hours ago

Olorin

1,479112

add a comment |

up vote
2
down vote

If the array has gaps in it, it might be better to loop over the indices of the array instead:

for i in "$!val[@]"
do
 if [[ $val[i] -eq 0 ]]
 then
 echo "Index: $i, value: $val[i]"
 fi
done

So, if your array was like:

val=([100]=327823 [54]=0 [787998]=377463287)

You'd still get 54 as the index.

This should also work for associative arrays (strings as indices instead of integers).

answered 21 hours ago

Olorin

1,479112

If the array has gaps in it, it might be better to loop over the indices of the array instead:

for i in "$!val[@]"
do
 if [[ $val[i] -eq 0 ]]
 then
 echo "Index: $i, value: $val[i]"
 fi
done

So, if your array was like:

val=([100]=327823 [54]=0 [787998]=377463287)

You'd still get 54 as the index.

This should also work for associative arrays (strings as indices instead of integers).

answered 21 hours ago

Olorin

1,479112

answered 21 hours ago

Olorin

1,479112

answered 21 hours ago

Olorin

1,479112

answered 21 hours ago

Olorin

1,479112

add a comment |

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