A cipher for people who don't normally enjoy ciphers
Clash Royale CLAN TAG#URR8PPP
up vote
10
down vote
favorite
I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.
So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:
I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]
However, instead of just encrypting it once, I have done so six times, using six different methods.
The output for each encryption is as follows:
The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.
The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?
Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in
Method 1
Why is one of the 6-letter words "worth" so much more than the other?
Method 3
How often do you see a 3-letter word have a higher value than a 4-letter word?
Method 6
The key to this one is figuring out how I ordered the letters of the alphabet
cipher
add a comment |
up vote
10
down vote
favorite
I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.
So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:
I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]
However, instead of just encrypting it once, I have done so six times, using six different methods.
The output for each encryption is as follows:
The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.
The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?
Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in
Method 1
Why is one of the 6-letter words "worth" so much more than the other?
Method 3
How often do you see a 3-letter word have a higher value than a 4-letter word?
Method 6
The key to this one is figuring out how I ordered the letters of the alphabet
cipher
Shouldn't the phrase have 4 words?
– Display name
yesterday
Oops! - thanks for catching that!
– Dmihawk
yesterday
I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
15 hours ago
I'll need to double check in the morning
– Dmihawk
15 hours ago
Sorry I was wrong
– Omega Krypton
2 hours ago
add a comment |
up vote
10
down vote
favorite
up vote
10
down vote
favorite
I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.
So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:
I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]
However, instead of just encrypting it once, I have done so six times, using six different methods.
The output for each encryption is as follows:
The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.
The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?
Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in
Method 1
Why is one of the 6-letter words "worth" so much more than the other?
Method 3
How often do you see a 3-letter word have a higher value than a 4-letter word?
Method 6
The key to this one is figuring out how I ordered the letters of the alphabet
cipher
I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.
So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:
I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]
However, instead of just encrypting it once, I have done so six times, using six different methods.
The output for each encryption is as follows:
The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.
The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?
Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in
Method 1
Why is one of the 6-letter words "worth" so much more than the other?
Method 3
How often do you see a 3-letter word have a higher value than a 4-letter word?
Method 6
The key to this one is figuring out how I ordered the letters of the alphabet
cipher
cipher
edited 6 hours ago
asked yesterday
Dmihawk
1,596422
1,596422
Shouldn't the phrase have 4 words?
– Display name
yesterday
Oops! - thanks for catching that!
– Dmihawk
yesterday
I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
15 hours ago
I'll need to double check in the morning
– Dmihawk
15 hours ago
Sorry I was wrong
– Omega Krypton
2 hours ago
add a comment |
Shouldn't the phrase have 4 words?
– Display name
yesterday
Oops! - thanks for catching that!
– Dmihawk
yesterday
I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
15 hours ago
I'll need to double check in the morning
– Dmihawk
15 hours ago
Sorry I was wrong
– Omega Krypton
2 hours ago
Shouldn't the phrase have 4 words?
– Display name
yesterday
Shouldn't the phrase have 4 words?
– Display name
yesterday
Oops! - thanks for catching that!
– Dmihawk
yesterday
Oops! - thanks for catching that!
– Dmihawk
yesterday
I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
15 hours ago
I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
15 hours ago
I'll need to double check in the morning
– Dmihawk
15 hours ago
I'll need to double check in the morning
– Dmihawk
15 hours ago
Sorry I was wrong
– Omega Krypton
2 hours ago
Sorry I was wrong
– Omega Krypton
2 hours ago
add a comment |
4 Answers
4
active
oldest
votes
up vote
6
down vote
This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!
Partial Answer:
The phrase is:
WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)
Method 1 is
Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)
Method 2 is:
Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)
Method 4 is:
the sum of values of each letter on a telephone keypad, like this:
e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39
Method 5 is
the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)
Good spotting! :)
– Dmihawk
yesterday
Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
– Dmihawk
15 hours ago
Method 6? @Dmihawk Thanks!
– Omega Krypton
15 hours ago
Sorry, meant 5!
– Dmihawk
15 hours ago
You are absolutely correct on method 4, but I'm not sure how you got to 35 for the first word. I get 9 + 6 + 15 + 15 = 45
– Dmihawk
6 hours ago
|
show 1 more comment
up vote
4
down vote
Based on @Omega Krypton's method 5, the phrase is:
WELL DONE, NOW UPVOTE PUZZLE
I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...
Nicely done :) now you just need to deduce the other 5 encryption methods!
– Dmihawk
yesterday
1
I upvoted the puzzle lah :)
– Omega Krypton
22 hours ago
add a comment |
up vote
3
down vote
Method 2 is
Sum of A1Z26 values
add a comment |
up vote
2
down vote
I believe Method 1 is
the (English) Scrabble value for each word.
Well done! Good find :)
– Dmihawk
1 hour ago
add a comment |
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
6
down vote
This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!
Partial Answer:
The phrase is:
WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)
Method 1 is
Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)
Method 2 is:
Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)
Method 4 is:
the sum of values of each letter on a telephone keypad, like this:
e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39
Method 5 is
the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)
Good spotting! :)
– Dmihawk
yesterday
Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
– Dmihawk
15 hours ago
Method 6? @Dmihawk Thanks!
– Omega Krypton
15 hours ago
Sorry, meant 5!
– Dmihawk
15 hours ago
You are absolutely correct on method 4, but I'm not sure how you got to 35 for the first word. I get 9 + 6 + 15 + 15 = 45
– Dmihawk
6 hours ago
|
show 1 more comment
up vote
6
down vote
This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!
Partial Answer:
The phrase is:
WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)
Method 1 is
Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)
Method 2 is:
Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)
Method 4 is:
the sum of values of each letter on a telephone keypad, like this:
e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39
Method 5 is
the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)
Good spotting! :)
– Dmihawk
yesterday
Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
– Dmihawk
15 hours ago
Method 6? @Dmihawk Thanks!
– Omega Krypton
15 hours ago
Sorry, meant 5!
– Dmihawk
15 hours ago
You are absolutely correct on method 4, but I'm not sure how you got to 35 for the first word. I get 9 + 6 + 15 + 15 = 45
– Dmihawk
6 hours ago
|
show 1 more comment
up vote
6
down vote
up vote
6
down vote
This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!
Partial Answer:
The phrase is:
WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)
Method 1 is
Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)
Method 2 is:
Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)
Method 4 is:
the sum of values of each letter on a telephone keypad, like this:
e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39
Method 5 is
the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)
This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!
Partial Answer:
The phrase is:
WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)
Method 1 is
Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)
Method 2 is:
Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)
Method 4 is:
the sum of values of each letter on a telephone keypad, like this:
e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39
Method 5 is
the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)
edited 2 hours ago
answered yesterday
Omega Krypton
951114
951114
Good spotting! :)
– Dmihawk
yesterday
Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
– Dmihawk
15 hours ago
Method 6? @Dmihawk Thanks!
– Omega Krypton
15 hours ago
Sorry, meant 5!
– Dmihawk
15 hours ago
You are absolutely correct on method 4, but I'm not sure how you got to 35 for the first word. I get 9 + 6 + 15 + 15 = 45
– Dmihawk
6 hours ago
|
show 1 more comment
Good spotting! :)
– Dmihawk
yesterday
Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
– Dmihawk
15 hours ago
Method 6? @Dmihawk Thanks!
– Omega Krypton
15 hours ago
Sorry, meant 5!
– Dmihawk
15 hours ago
You are absolutely correct on method 4, but I'm not sure how you got to 35 for the first word. I get 9 + 6 + 15 + 15 = 45
– Dmihawk
6 hours ago
Good spotting! :)
– Dmihawk
yesterday
Good spotting! :)
– Dmihawk
yesterday
Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
– Dmihawk
15 hours ago
Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
– Dmihawk
15 hours ago
Method 6? @Dmihawk Thanks!
– Omega Krypton
15 hours ago
Method 6? @Dmihawk Thanks!
– Omega Krypton
15 hours ago
Sorry, meant 5!
– Dmihawk
15 hours ago
Sorry, meant 5!
– Dmihawk
15 hours ago
You are absolutely correct on method 4, but I'm not sure how you got to 35 for the first word. I get 9 + 6 + 15 + 15 = 45
– Dmihawk
6 hours ago
You are absolutely correct on method 4, but I'm not sure how you got to 35 for the first word. I get 9 + 6 + 15 + 15 = 45
– Dmihawk
6 hours ago
|
show 1 more comment
up vote
4
down vote
Based on @Omega Krypton's method 5, the phrase is:
WELL DONE, NOW UPVOTE PUZZLE
I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...
Nicely done :) now you just need to deduce the other 5 encryption methods!
– Dmihawk
yesterday
1
I upvoted the puzzle lah :)
– Omega Krypton
22 hours ago
add a comment |
up vote
4
down vote
Based on @Omega Krypton's method 5, the phrase is:
WELL DONE, NOW UPVOTE PUZZLE
I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...
Nicely done :) now you just need to deduce the other 5 encryption methods!
– Dmihawk
yesterday
1
I upvoted the puzzle lah :)
– Omega Krypton
22 hours ago
add a comment |
up vote
4
down vote
up vote
4
down vote
Based on @Omega Krypton's method 5, the phrase is:
WELL DONE, NOW UPVOTE PUZZLE
I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...
Based on @Omega Krypton's method 5, the phrase is:
WELL DONE, NOW UPVOTE PUZZLE
I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...
answered yesterday
Dr Xorile
10.7k12258
10.7k12258
Nicely done :) now you just need to deduce the other 5 encryption methods!
– Dmihawk
yesterday
1
I upvoted the puzzle lah :)
– Omega Krypton
22 hours ago
add a comment |
Nicely done :) now you just need to deduce the other 5 encryption methods!
– Dmihawk
yesterday
1
I upvoted the puzzle lah :)
– Omega Krypton
22 hours ago
Nicely done :) now you just need to deduce the other 5 encryption methods!
– Dmihawk
yesterday
Nicely done :) now you just need to deduce the other 5 encryption methods!
– Dmihawk
yesterday
1
1
I upvoted the puzzle lah :)
– Omega Krypton
22 hours ago
I upvoted the puzzle lah :)
– Omega Krypton
22 hours ago
add a comment |
up vote
3
down vote
Method 2 is
Sum of A1Z26 values
add a comment |
up vote
3
down vote
Method 2 is
Sum of A1Z26 values
add a comment |
up vote
3
down vote
up vote
3
down vote
Method 2 is
Sum of A1Z26 values
Method 2 is
Sum of A1Z26 values
answered 18 hours ago
ImongMama
48117
48117
add a comment |
add a comment |
up vote
2
down vote
I believe Method 1 is
the (English) Scrabble value for each word.
Well done! Good find :)
– Dmihawk
1 hour ago
add a comment |
up vote
2
down vote
I believe Method 1 is
the (English) Scrabble value for each word.
Well done! Good find :)
– Dmihawk
1 hour ago
add a comment |
up vote
2
down vote
up vote
2
down vote
I believe Method 1 is
the (English) Scrabble value for each word.
I believe Method 1 is
the (English) Scrabble value for each word.
answered 1 hour ago
Braegh
1263
1263
Well done! Good find :)
– Dmihawk
1 hour ago
add a comment |
Well done! Good find :)
– Dmihawk
1 hour ago
Well done! Good find :)
– Dmihawk
1 hour ago
Well done! Good find :)
– Dmihawk
1 hour ago
add a comment |
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Shouldn't the phrase have 4 words?
– Display name
yesterday
Oops! - thanks for catching that!
– Dmihawk
yesterday
I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
15 hours ago
I'll need to double check in the morning
– Dmihawk
15 hours ago
Sorry I was wrong
– Omega Krypton
2 hours ago