A cipher for people who don't normally enjoy ciphers

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
10
down vote

favorite












I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.



So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:




I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]



However, instead of just encrypting it once, I have done so six times, using six different methods.



The output for each encryption is as follows:
Encryption Output




The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.



The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?



Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in



Method 1




Why is one of the 6-letter words "worth" so much more than the other?




Method 3




How often do you see a 3-letter word have a higher value than a 4-letter word?




Method 6




The key to this one is figuring out how I ordered the letters of the alphabet











share|improve this question























  • Shouldn't the phrase have 4 words?
    – Display name
    yesterday










  • Oops! - thanks for catching that!
    – Dmihawk
    yesterday










  • I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
    – Omega Krypton
    15 hours ago










  • I'll need to double check in the morning
    – Dmihawk
    15 hours ago










  • Sorry I was wrong
    – Omega Krypton
    2 hours ago














up vote
10
down vote

favorite












I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.



So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:




I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]



However, instead of just encrypting it once, I have done so six times, using six different methods.



The output for each encryption is as follows:
Encryption Output




The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.



The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?



Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in



Method 1




Why is one of the 6-letter words "worth" so much more than the other?




Method 3




How often do you see a 3-letter word have a higher value than a 4-letter word?




Method 6




The key to this one is figuring out how I ordered the letters of the alphabet











share|improve this question























  • Shouldn't the phrase have 4 words?
    – Display name
    yesterday










  • Oops! - thanks for catching that!
    – Dmihawk
    yesterday










  • I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
    – Omega Krypton
    15 hours ago










  • I'll need to double check in the morning
    – Dmihawk
    15 hours ago










  • Sorry I was wrong
    – Omega Krypton
    2 hours ago












up vote
10
down vote

favorite









up vote
10
down vote

favorite











I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.



So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:




I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]



However, instead of just encrypting it once, I have done so six times, using six different methods.



The output for each encryption is as follows:
Encryption Output




The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.



The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?



Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in



Method 1




Why is one of the 6-letter words "worth" so much more than the other?




Method 3




How often do you see a 3-letter word have a higher value than a 4-letter word?




Method 6




The key to this one is figuring out how I ordered the letters of the alphabet











share|improve this question















I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.



So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:




I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]



However, instead of just encrypting it once, I have done so six times, using six different methods.



The output for each encryption is as follows:
Encryption Output




The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.



The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?



Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in



Method 1




Why is one of the 6-letter words "worth" so much more than the other?




Method 3




How often do you see a 3-letter word have a higher value than a 4-letter word?




Method 6




The key to this one is figuring out how I ordered the letters of the alphabet








cipher






share|improve this question















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share|improve this question




share|improve this question








edited 6 hours ago

























asked yesterday









Dmihawk

1,596422




1,596422











  • Shouldn't the phrase have 4 words?
    – Display name
    yesterday










  • Oops! - thanks for catching that!
    – Dmihawk
    yesterday










  • I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
    – Omega Krypton
    15 hours ago










  • I'll need to double check in the morning
    – Dmihawk
    15 hours ago










  • Sorry I was wrong
    – Omega Krypton
    2 hours ago
















  • Shouldn't the phrase have 4 words?
    – Display name
    yesterday










  • Oops! - thanks for catching that!
    – Dmihawk
    yesterday










  • I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
    – Omega Krypton
    15 hours ago










  • I'll need to double check in the morning
    – Dmihawk
    15 hours ago










  • Sorry I was wrong
    – Omega Krypton
    2 hours ago















Shouldn't the phrase have 4 words?
– Display name
yesterday




Shouldn't the phrase have 4 words?
– Display name
yesterday












Oops! - thanks for catching that!
– Dmihawk
yesterday




Oops! - thanks for catching that!
– Dmihawk
yesterday












I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
15 hours ago




I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
15 hours ago












I'll need to double check in the morning
– Dmihawk
15 hours ago




I'll need to double check in the morning
– Dmihawk
15 hours ago












Sorry I was wrong
– Omega Krypton
2 hours ago




Sorry I was wrong
– Omega Krypton
2 hours ago










4 Answers
4






active

oldest

votes

















up vote
6
down vote













This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!



Partial Answer:



The phrase is:




WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)




Method 1 is




Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)




Method 2 is:




Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)




Method 4 is:




the sum of values of each letter on a telephone keypad, like this:
keypad
e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39




Method 5 is




the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)







share|improve this answer






















  • Good spotting! :)
    – Dmihawk
    yesterday










  • Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
    – Dmihawk
    15 hours ago










  • Method 6? @Dmihawk Thanks!
    – Omega Krypton
    15 hours ago











  • Sorry, meant 5!
    – Dmihawk
    15 hours ago










  • You are absolutely correct on method 4, but I'm not sure how you got to 35 for the first word. I get 9 + 6 + 15 + 15 = 45
    – Dmihawk
    6 hours ago

















up vote
4
down vote













Based on @Omega Krypton's method 5, the phrase is:




WELL DONE, NOW UPVOTE PUZZLE




I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...






share|improve this answer




















  • Nicely done :) now you just need to deduce the other 5 encryption methods!
    – Dmihawk
    yesterday






  • 1




    I upvoted the puzzle lah :)
    – Omega Krypton
    22 hours ago

















up vote
3
down vote













Method 2 is




Sum of A1Z26 values







share|improve this answer



























    up vote
    2
    down vote













    I believe Method 1 is




    the (English) Scrabble value for each word.







    share|improve this answer




















    • Well done! Good find :)
      – Dmihawk
      1 hour ago










    Your Answer





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    4 Answers
    4






    active

    oldest

    votes








    4 Answers
    4






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    6
    down vote













    This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!



    Partial Answer:



    The phrase is:




    WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)




    Method 1 is




    Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)




    Method 2 is:




    Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)




    Method 4 is:




    the sum of values of each letter on a telephone keypad, like this:
    keypad
    e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39




    Method 5 is




    the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)







    share|improve this answer






















    • Good spotting! :)
      – Dmihawk
      yesterday










    • Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
      – Dmihawk
      15 hours ago










    • Method 6? @Dmihawk Thanks!
      – Omega Krypton
      15 hours ago











    • Sorry, meant 5!
      – Dmihawk
      15 hours ago










    • You are absolutely correct on method 4, but I'm not sure how you got to 35 for the first word. I get 9 + 6 + 15 + 15 = 45
      – Dmihawk
      6 hours ago














    up vote
    6
    down vote













    This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!



    Partial Answer:



    The phrase is:




    WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)




    Method 1 is




    Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)




    Method 2 is:




    Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)




    Method 4 is:




    the sum of values of each letter on a telephone keypad, like this:
    keypad
    e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39




    Method 5 is




    the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)







    share|improve this answer






















    • Good spotting! :)
      – Dmihawk
      yesterday










    • Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
      – Dmihawk
      15 hours ago










    • Method 6? @Dmihawk Thanks!
      – Omega Krypton
      15 hours ago











    • Sorry, meant 5!
      – Dmihawk
      15 hours ago










    • You are absolutely correct on method 4, but I'm not sure how you got to 35 for the first word. I get 9 + 6 + 15 + 15 = 45
      – Dmihawk
      6 hours ago












    up vote
    6
    down vote










    up vote
    6
    down vote









    This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!



    Partial Answer:



    The phrase is:




    WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)




    Method 1 is




    Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)




    Method 2 is:




    Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)




    Method 4 is:




    the sum of values of each letter on a telephone keypad, like this:
    keypad
    e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39




    Method 5 is




    the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)







    share|improve this answer














    This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!



    Partial Answer:



    The phrase is:




    WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)




    Method 1 is




    Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)




    Method 2 is:




    Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)




    Method 4 is:




    the sum of values of each letter on a telephone keypad, like this:
    keypad
    e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39




    Method 5 is




    the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)








    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 2 hours ago

























    answered yesterday









    Omega Krypton

    951114




    951114











    • Good spotting! :)
      – Dmihawk
      yesterday










    • Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
      – Dmihawk
      15 hours ago










    • Method 6? @Dmihawk Thanks!
      – Omega Krypton
      15 hours ago











    • Sorry, meant 5!
      – Dmihawk
      15 hours ago










    • You are absolutely correct on method 4, but I'm not sure how you got to 35 for the first word. I get 9 + 6 + 15 + 15 = 45
      – Dmihawk
      6 hours ago
















    • Good spotting! :)
      – Dmihawk
      yesterday










    • Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
      – Dmihawk
      15 hours ago










    • Method 6? @Dmihawk Thanks!
      – Omega Krypton
      15 hours ago











    • Sorry, meant 5!
      – Dmihawk
      15 hours ago










    • You are absolutely correct on method 4, but I'm not sure how you got to 35 for the first word. I get 9 + 6 + 15 + 15 = 45
      – Dmihawk
      6 hours ago















    Good spotting! :)
    – Dmihawk
    yesterday




    Good spotting! :)
    – Dmihawk
    yesterday












    Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
    – Dmihawk
    15 hours ago




    Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
    – Dmihawk
    15 hours ago












    Method 6? @Dmihawk Thanks!
    – Omega Krypton
    15 hours ago





    Method 6? @Dmihawk Thanks!
    – Omega Krypton
    15 hours ago













    Sorry, meant 5!
    – Dmihawk
    15 hours ago




    Sorry, meant 5!
    – Dmihawk
    15 hours ago












    You are absolutely correct on method 4, but I'm not sure how you got to 35 for the first word. I get 9 + 6 + 15 + 15 = 45
    – Dmihawk
    6 hours ago




    You are absolutely correct on method 4, but I'm not sure how you got to 35 for the first word. I get 9 + 6 + 15 + 15 = 45
    – Dmihawk
    6 hours ago










    up vote
    4
    down vote













    Based on @Omega Krypton's method 5, the phrase is:




    WELL DONE, NOW UPVOTE PUZZLE




    I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...






    share|improve this answer




















    • Nicely done :) now you just need to deduce the other 5 encryption methods!
      – Dmihawk
      yesterday






    • 1




      I upvoted the puzzle lah :)
      – Omega Krypton
      22 hours ago














    up vote
    4
    down vote













    Based on @Omega Krypton's method 5, the phrase is:




    WELL DONE, NOW UPVOTE PUZZLE




    I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...






    share|improve this answer




















    • Nicely done :) now you just need to deduce the other 5 encryption methods!
      – Dmihawk
      yesterday






    • 1




      I upvoted the puzzle lah :)
      – Omega Krypton
      22 hours ago












    up vote
    4
    down vote










    up vote
    4
    down vote









    Based on @Omega Krypton's method 5, the phrase is:




    WELL DONE, NOW UPVOTE PUZZLE




    I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...






    share|improve this answer












    Based on @Omega Krypton's method 5, the phrase is:




    WELL DONE, NOW UPVOTE PUZZLE




    I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered yesterday









    Dr Xorile

    10.7k12258




    10.7k12258











    • Nicely done :) now you just need to deduce the other 5 encryption methods!
      – Dmihawk
      yesterday






    • 1




      I upvoted the puzzle lah :)
      – Omega Krypton
      22 hours ago
















    • Nicely done :) now you just need to deduce the other 5 encryption methods!
      – Dmihawk
      yesterday






    • 1




      I upvoted the puzzle lah :)
      – Omega Krypton
      22 hours ago















    Nicely done :) now you just need to deduce the other 5 encryption methods!
    – Dmihawk
    yesterday




    Nicely done :) now you just need to deduce the other 5 encryption methods!
    – Dmihawk
    yesterday




    1




    1




    I upvoted the puzzle lah :)
    – Omega Krypton
    22 hours ago




    I upvoted the puzzle lah :)
    – Omega Krypton
    22 hours ago










    up vote
    3
    down vote













    Method 2 is




    Sum of A1Z26 values







    share|improve this answer
























      up vote
      3
      down vote













      Method 2 is




      Sum of A1Z26 values







      share|improve this answer






















        up vote
        3
        down vote










        up vote
        3
        down vote









        Method 2 is




        Sum of A1Z26 values







        share|improve this answer












        Method 2 is




        Sum of A1Z26 values








        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 18 hours ago









        ImongMama

        48117




        48117




















            up vote
            2
            down vote













            I believe Method 1 is




            the (English) Scrabble value for each word.







            share|improve this answer




















            • Well done! Good find :)
              – Dmihawk
              1 hour ago














            up vote
            2
            down vote













            I believe Method 1 is




            the (English) Scrabble value for each word.







            share|improve this answer




















            • Well done! Good find :)
              – Dmihawk
              1 hour ago












            up vote
            2
            down vote










            up vote
            2
            down vote









            I believe Method 1 is




            the (English) Scrabble value for each word.







            share|improve this answer












            I believe Method 1 is




            the (English) Scrabble value for each word.








            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 1 hour ago









            Braegh

            1263




            1263











            • Well done! Good find :)
              – Dmihawk
              1 hour ago
















            • Well done! Good find :)
              – Dmihawk
              1 hour ago















            Well done! Good find :)
            – Dmihawk
            1 hour ago




            Well done! Good find :)
            – Dmihawk
            1 hour ago

















             

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