Is this number secretly Fibonacci?

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Background



Most of you know what a Fibonacci number is. Some of you may know that all positive integers can be represented as a sum of one or more Fibonacci numbers, according to Zeckendorf's Theorem. If the number of terms in the optimal Zeckendorf Representation of an integer n is itself a Fibonacci number, we will call n "secretly" Fibonacci.



For example:



139 = 89 + 34 + 13 + 3
This is a total of 4 integers. Since 4 is not a Fibonacci number, 139 is not secretly Fibonacci

140 = 89 + 34 + 13 + 3 + 1
This is a total of 5 integers. Since 5 is a Fibonacci number, 140 is secretly Fibonacci


Notes



  • The optimal Zeckendorf Representation can be found using a greedy algorithm. Simply take the largest Fibonacci number <= n and subtract it from n until you reach 0

  • All Fibonacci numbers can be represented as a sum of 1 Fibonacci number (itself). Since 1 is a Fibonacci number, all Fibonacci numbers are also secretly Fibonacci.

Challenge



Your challenge is to write a program or function that takes an integer and returns whether that integer is secretly Fibonacci.



Input



You may take input in any reasonable format. You may assume the input will be a single positive integer.



Output



Output one of two distinct results for whether the input is secretly Fibonacci. Examples include True/False, 1/0, etc.



Scoring



This is code-golf, so shortest answer in bytes wins! Standard loopholes are forbidden.



Test Cases



Truthy (secretly Fibonacci)
1
2
4
50
140
300099

Falsey (NOT secretly Fibonacci)
33
53
54
139
118808









share|improve this question

























    up vote
    4
    down vote

    favorite












    Background



    Most of you know what a Fibonacci number is. Some of you may know that all positive integers can be represented as a sum of one or more Fibonacci numbers, according to Zeckendorf's Theorem. If the number of terms in the optimal Zeckendorf Representation of an integer n is itself a Fibonacci number, we will call n "secretly" Fibonacci.



    For example:



    139 = 89 + 34 + 13 + 3
    This is a total of 4 integers. Since 4 is not a Fibonacci number, 139 is not secretly Fibonacci

    140 = 89 + 34 + 13 + 3 + 1
    This is a total of 5 integers. Since 5 is a Fibonacci number, 140 is secretly Fibonacci


    Notes



    • The optimal Zeckendorf Representation can be found using a greedy algorithm. Simply take the largest Fibonacci number <= n and subtract it from n until you reach 0

    • All Fibonacci numbers can be represented as a sum of 1 Fibonacci number (itself). Since 1 is a Fibonacci number, all Fibonacci numbers are also secretly Fibonacci.

    Challenge



    Your challenge is to write a program or function that takes an integer and returns whether that integer is secretly Fibonacci.



    Input



    You may take input in any reasonable format. You may assume the input will be a single positive integer.



    Output



    Output one of two distinct results for whether the input is secretly Fibonacci. Examples include True/False, 1/0, etc.



    Scoring



    This is code-golf, so shortest answer in bytes wins! Standard loopholes are forbidden.



    Test Cases



    Truthy (secretly Fibonacci)
    1
    2
    4
    50
    140
    300099

    Falsey (NOT secretly Fibonacci)
    33
    53
    54
    139
    118808









    share|improve this question























      up vote
      4
      down vote

      favorite









      up vote
      4
      down vote

      favorite











      Background



      Most of you know what a Fibonacci number is. Some of you may know that all positive integers can be represented as a sum of one or more Fibonacci numbers, according to Zeckendorf's Theorem. If the number of terms in the optimal Zeckendorf Representation of an integer n is itself a Fibonacci number, we will call n "secretly" Fibonacci.



      For example:



      139 = 89 + 34 + 13 + 3
      This is a total of 4 integers. Since 4 is not a Fibonacci number, 139 is not secretly Fibonacci

      140 = 89 + 34 + 13 + 3 + 1
      This is a total of 5 integers. Since 5 is a Fibonacci number, 140 is secretly Fibonacci


      Notes



      • The optimal Zeckendorf Representation can be found using a greedy algorithm. Simply take the largest Fibonacci number <= n and subtract it from n until you reach 0

      • All Fibonacci numbers can be represented as a sum of 1 Fibonacci number (itself). Since 1 is a Fibonacci number, all Fibonacci numbers are also secretly Fibonacci.

      Challenge



      Your challenge is to write a program or function that takes an integer and returns whether that integer is secretly Fibonacci.



      Input



      You may take input in any reasonable format. You may assume the input will be a single positive integer.



      Output



      Output one of two distinct results for whether the input is secretly Fibonacci. Examples include True/False, 1/0, etc.



      Scoring



      This is code-golf, so shortest answer in bytes wins! Standard loopholes are forbidden.



      Test Cases



      Truthy (secretly Fibonacci)
      1
      2
      4
      50
      140
      300099

      Falsey (NOT secretly Fibonacci)
      33
      53
      54
      139
      118808









      share|improve this question













      Background



      Most of you know what a Fibonacci number is. Some of you may know that all positive integers can be represented as a sum of one or more Fibonacci numbers, according to Zeckendorf's Theorem. If the number of terms in the optimal Zeckendorf Representation of an integer n is itself a Fibonacci number, we will call n "secretly" Fibonacci.



      For example:



      139 = 89 + 34 + 13 + 3
      This is a total of 4 integers. Since 4 is not a Fibonacci number, 139 is not secretly Fibonacci

      140 = 89 + 34 + 13 + 3 + 1
      This is a total of 5 integers. Since 5 is a Fibonacci number, 140 is secretly Fibonacci


      Notes



      • The optimal Zeckendorf Representation can be found using a greedy algorithm. Simply take the largest Fibonacci number <= n and subtract it from n until you reach 0

      • All Fibonacci numbers can be represented as a sum of 1 Fibonacci number (itself). Since 1 is a Fibonacci number, all Fibonacci numbers are also secretly Fibonacci.

      Challenge



      Your challenge is to write a program or function that takes an integer and returns whether that integer is secretly Fibonacci.



      Input



      You may take input in any reasonable format. You may assume the input will be a single positive integer.



      Output



      Output one of two distinct results for whether the input is secretly Fibonacci. Examples include True/False, 1/0, etc.



      Scoring



      This is code-golf, so shortest answer in bytes wins! Standard loopholes are forbidden.



      Test Cases



      Truthy (secretly Fibonacci)
      1
      2
      4
      50
      140
      300099

      Falsey (NOT secretly Fibonacci)
      33
      53
      54
      139
      118808






      code-golf decision-problem fibonacci






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      asked 2 hours ago









      Cowabunghole

      708316




      708316




















          3 Answers
          3






          active

          oldest

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          up vote
          1
          down vote














          JavaScript (Node.js), 54 bytes





          x=>g(g(x))<2;g=(x,i=1,j=1)=>j>x?x&&g(x-i)+1:g(x,j,i+j)


          Try it online!






          share|improve this answer



























            up vote
            1
            down vote














            R, 83 bytes





            function(n)T=1:0
            while(n>T)T=c(T[1]+T[2],T)
            while(n)n=n-T[T<=n][1]
            F=F+1
            F%in%T


            Try it online!






            share|improve this answer



























              up vote
              0
              down vote














              Jelly, 15 bytes



              ‘ÆḞ€fRṪạµƬL’Ɗ⁺Ị


              A monadic link accepting a non-negative integer which yields 1 if "Secretly Fibonacci" and 0 otherwise.



              Try it online! (too inefficient for the larger test cases)



              How?



              ‘ÆḞ€fRṪạµƬL’Ɗ⁺Ị - Link: integer, I
              µƬ - perform the monadic link to the left as a function of the current I,
              - collecting up all the inputs until the results are no longer unique:
              ‘ - increment I -> I+1
              ÆḞ€ - nth Fibonacci number for €ach n in [1,I+1]
              R - range from 1 to I
              f - filter discard (discard Fibonacci numbers not in the range, i.e. > I)
              Ṫ - tail (get the largest)
              ạ - absolute difference with I
              - This gives us a list from I decreasing by Fibonacci numbers to 0
              - e.g. for 88 we get [88,33,12,4,1,0]
              - because (88-33)+(33-12)+(12-4)+(4-1)+(1-0)=55+21+8+3+1=88
              L - length (the number of Fibonacci numbers required plus one)
              ’ - decrement (the number of Fibonacci numbers required)
              Ɗ - treat the last three links (which is everything to the left) as a monad:
              ⁺ - ...and repeat it
              - i.e. get the number of Fibonacci numbers required for the number of
              - Fibonacci numbers required to represent I.
              - This is 1 if I is Secretly Fibonacci, and greater if not)
              Ị - insignificant? (is the absolute value of that <= 1?)





              share|improve this answer




















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                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes








                up vote
                1
                down vote














                JavaScript (Node.js), 54 bytes





                x=>g(g(x))<2;g=(x,i=1,j=1)=>j>x?x&&g(x-i)+1:g(x,j,i+j)


                Try it online!






                share|improve this answer
























                  up vote
                  1
                  down vote














                  JavaScript (Node.js), 54 bytes





                  x=>g(g(x))<2;g=(x,i=1,j=1)=>j>x?x&&g(x-i)+1:g(x,j,i+j)


                  Try it online!






                  share|improve this answer






















                    up vote
                    1
                    down vote










                    up vote
                    1
                    down vote










                    JavaScript (Node.js), 54 bytes





                    x=>g(g(x))<2;g=(x,i=1,j=1)=>j>x?x&&g(x-i)+1:g(x,j,i+j)


                    Try it online!






                    share|improve this answer













                    JavaScript (Node.js), 54 bytes





                    x=>g(g(x))<2;g=(x,i=1,j=1)=>j>x?x&&g(x-i)+1:g(x,j,i+j)


                    Try it online!







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered 2 hours ago









                    l4m2

                    4,0081431




                    4,0081431




















                        up vote
                        1
                        down vote














                        R, 83 bytes





                        function(n)T=1:0
                        while(n>T)T=c(T[1]+T[2],T)
                        while(n)n=n-T[T<=n][1]
                        F=F+1
                        F%in%T


                        Try it online!






                        share|improve this answer
























                          up vote
                          1
                          down vote














                          R, 83 bytes





                          function(n)T=1:0
                          while(n>T)T=c(T[1]+T[2],T)
                          while(n)n=n-T[T<=n][1]
                          F=F+1
                          F%in%T


                          Try it online!






                          share|improve this answer






















                            up vote
                            1
                            down vote










                            up vote
                            1
                            down vote










                            R, 83 bytes





                            function(n)T=1:0
                            while(n>T)T=c(T[1]+T[2],T)
                            while(n)n=n-T[T<=n][1]
                            F=F+1
                            F%in%T


                            Try it online!






                            share|improve this answer













                            R, 83 bytes





                            function(n)T=1:0
                            while(n>T)T=c(T[1]+T[2],T)
                            while(n)n=n-T[T<=n][1]
                            F=F+1
                            F%in%T


                            Try it online!







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 1 hour ago









                            Giuseppe

                            15.5k31051




                            15.5k31051




















                                up vote
                                0
                                down vote














                                Jelly, 15 bytes



                                ‘ÆḞ€fRṪạµƬL’Ɗ⁺Ị


                                A monadic link accepting a non-negative integer which yields 1 if "Secretly Fibonacci" and 0 otherwise.



                                Try it online! (too inefficient for the larger test cases)



                                How?



                                ‘ÆḞ€fRṪạµƬL’Ɗ⁺Ị - Link: integer, I
                                µƬ - perform the monadic link to the left as a function of the current I,
                                - collecting up all the inputs until the results are no longer unique:
                                ‘ - increment I -> I+1
                                ÆḞ€ - nth Fibonacci number for €ach n in [1,I+1]
                                R - range from 1 to I
                                f - filter discard (discard Fibonacci numbers not in the range, i.e. > I)
                                Ṫ - tail (get the largest)
                                ạ - absolute difference with I
                                - This gives us a list from I decreasing by Fibonacci numbers to 0
                                - e.g. for 88 we get [88,33,12,4,1,0]
                                - because (88-33)+(33-12)+(12-4)+(4-1)+(1-0)=55+21+8+3+1=88
                                L - length (the number of Fibonacci numbers required plus one)
                                ’ - decrement (the number of Fibonacci numbers required)
                                Ɗ - treat the last three links (which is everything to the left) as a monad:
                                ⁺ - ...and repeat it
                                - i.e. get the number of Fibonacci numbers required for the number of
                                - Fibonacci numbers required to represent I.
                                - This is 1 if I is Secretly Fibonacci, and greater if not)
                                Ị - insignificant? (is the absolute value of that <= 1?)





                                share|improve this answer
























                                  up vote
                                  0
                                  down vote














                                  Jelly, 15 bytes



                                  ‘ÆḞ€fRṪạµƬL’Ɗ⁺Ị


                                  A monadic link accepting a non-negative integer which yields 1 if "Secretly Fibonacci" and 0 otherwise.



                                  Try it online! (too inefficient for the larger test cases)



                                  How?



                                  ‘ÆḞ€fRṪạµƬL’Ɗ⁺Ị - Link: integer, I
                                  µƬ - perform the monadic link to the left as a function of the current I,
                                  - collecting up all the inputs until the results are no longer unique:
                                  ‘ - increment I -> I+1
                                  ÆḞ€ - nth Fibonacci number for €ach n in [1,I+1]
                                  R - range from 1 to I
                                  f - filter discard (discard Fibonacci numbers not in the range, i.e. > I)
                                  Ṫ - tail (get the largest)
                                  ạ - absolute difference with I
                                  - This gives us a list from I decreasing by Fibonacci numbers to 0
                                  - e.g. for 88 we get [88,33,12,4,1,0]
                                  - because (88-33)+(33-12)+(12-4)+(4-1)+(1-0)=55+21+8+3+1=88
                                  L - length (the number of Fibonacci numbers required plus one)
                                  ’ - decrement (the number of Fibonacci numbers required)
                                  Ɗ - treat the last three links (which is everything to the left) as a monad:
                                  ⁺ - ...and repeat it
                                  - i.e. get the number of Fibonacci numbers required for the number of
                                  - Fibonacci numbers required to represent I.
                                  - This is 1 if I is Secretly Fibonacci, and greater if not)
                                  Ị - insignificant? (is the absolute value of that <= 1?)





                                  share|improve this answer






















                                    up vote
                                    0
                                    down vote










                                    up vote
                                    0
                                    down vote










                                    Jelly, 15 bytes



                                    ‘ÆḞ€fRṪạµƬL’Ɗ⁺Ị


                                    A monadic link accepting a non-negative integer which yields 1 if "Secretly Fibonacci" and 0 otherwise.



                                    Try it online! (too inefficient for the larger test cases)



                                    How?



                                    ‘ÆḞ€fRṪạµƬL’Ɗ⁺Ị - Link: integer, I
                                    µƬ - perform the monadic link to the left as a function of the current I,
                                    - collecting up all the inputs until the results are no longer unique:
                                    ‘ - increment I -> I+1
                                    ÆḞ€ - nth Fibonacci number for €ach n in [1,I+1]
                                    R - range from 1 to I
                                    f - filter discard (discard Fibonacci numbers not in the range, i.e. > I)
                                    Ṫ - tail (get the largest)
                                    ạ - absolute difference with I
                                    - This gives us a list from I decreasing by Fibonacci numbers to 0
                                    - e.g. for 88 we get [88,33,12,4,1,0]
                                    - because (88-33)+(33-12)+(12-4)+(4-1)+(1-0)=55+21+8+3+1=88
                                    L - length (the number of Fibonacci numbers required plus one)
                                    ’ - decrement (the number of Fibonacci numbers required)
                                    Ɗ - treat the last three links (which is everything to the left) as a monad:
                                    ⁺ - ...and repeat it
                                    - i.e. get the number of Fibonacci numbers required for the number of
                                    - Fibonacci numbers required to represent I.
                                    - This is 1 if I is Secretly Fibonacci, and greater if not)
                                    Ị - insignificant? (is the absolute value of that <= 1?)





                                    share|improve this answer













                                    Jelly, 15 bytes



                                    ‘ÆḞ€fRṪạµƬL’Ɗ⁺Ị


                                    A monadic link accepting a non-negative integer which yields 1 if "Secretly Fibonacci" and 0 otherwise.



                                    Try it online! (too inefficient for the larger test cases)



                                    How?



                                    ‘ÆḞ€fRṪạµƬL’Ɗ⁺Ị - Link: integer, I
                                    µƬ - perform the monadic link to the left as a function of the current I,
                                    - collecting up all the inputs until the results are no longer unique:
                                    ‘ - increment I -> I+1
                                    ÆḞ€ - nth Fibonacci number for €ach n in [1,I+1]
                                    R - range from 1 to I
                                    f - filter discard (discard Fibonacci numbers not in the range, i.e. > I)
                                    Ṫ - tail (get the largest)
                                    ạ - absolute difference with I
                                    - This gives us a list from I decreasing by Fibonacci numbers to 0
                                    - e.g. for 88 we get [88,33,12,4,1,0]
                                    - because (88-33)+(33-12)+(12-4)+(4-1)+(1-0)=55+21+8+3+1=88
                                    L - length (the number of Fibonacci numbers required plus one)
                                    ’ - decrement (the number of Fibonacci numbers required)
                                    Ɗ - treat the last three links (which is everything to the left) as a monad:
                                    ⁺ - ...and repeat it
                                    - i.e. get the number of Fibonacci numbers required for the number of
                                    - Fibonacci numbers required to represent I.
                                    - This is 1 if I is Secretly Fibonacci, and greater if not)
                                    Ị - insignificant? (is the absolute value of that <= 1?)






                                    share|improve this answer












                                    share|improve this answer



                                    share|improve this answer










                                    answered 10 mins ago









                                    Jonathan Allan

                                    49.5k534163




                                    49.5k534163



























                                         

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