How to pass a list of file names to xargs after checking if the file exists?
Clash Royale CLAN TAG#URR8PPP
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I have a command (command1) that returns a list of file names like below
/consumer/a.txt
/consumer/b.txt
/consumer/doesnotexist.txt
When I pipe the output like command1 | xargs command2 command2 throws exception if one of the files does not exist.
How do I remove non-existant files before piping it to command2. I am expecting something in the lines of
command1 | xargs remove_nonexistant_files | xargs command2
command2 should receive
/consumer/a.txt
/consumer/b.txt
as input.
bash files osx
asked 7 mins ago
Sathish
11
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up vote
0
down vote
favorite
I have a command (command1) that returns a list of file names like below
/consumer/a.txt
/consumer/b.txt
/consumer/doesnotexist.txt
When I pipe the output like command1 | xargs command2 command2 throws exception if one of the files does not exist.
How do I remove non-existant files before piping it to command2. I am expecting something in the lines of
command1 | xargs remove_nonexistant_files | xargs command2
command2 should receive
/consumer/a.txt
/consumer/b.txt
as input.
bash files osx
asked 7 mins ago
Sathish
11
New contributor
Sathish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have a command (command1) that returns a list of file names like below
/consumer/a.txt
/consumer/b.txt
/consumer/doesnotexist.txt
When I pipe the output like command1 | xargs command2 command2 throws exception if one of the files does not exist.
How do I remove non-existant files before piping it to command2. I am expecting something in the lines of
command1 | xargs remove_nonexistant_files | xargs command2
command2 should receive
/consumer/a.txt
/consumer/b.txt
as input.
bash files osx
asked 7 mins ago
Sathish
11
New contributor
Sathish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I have a command (command1) that returns a list of file names like below
/consumer/a.txt
/consumer/b.txt
/consumer/doesnotexist.txt
When I pipe the output like command1 | xargs command2 command2 throws exception if one of the files does not exist.
How do I remove non-existant files before piping it to command2. I am expecting something in the lines of
command1 | xargs remove_nonexistant_files | xargs command2
command2 should receive
/consumer/a.txt
/consumer/b.txt
as input.
bash files osx
bash files osx
asked 7 mins ago
Sathish
11
New contributor
Sathish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 7 mins ago
Sathish
11
New contributor
Sathish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 6 mins ago
asked 7 mins ago
Sathish
11
New contributor
Sathish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 7 mins ago
Sathish
11
asked 7 mins ago
Sathish
11
11
New contributor
Sathish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Sathish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Sathish is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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2 Answers
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$ for file in $(command1); do if [[ -f "$file" ]]; then echo "$file"; done | xargs command2
answered 6 mins ago
DopeGhoti
41.9k55180
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command1 |
xargs sh -c 'for p do [ -f "$p" ] && printf "%sn" "$p"; done' sh |
xargs command 2
The extra bit in the middle is a another xargs invocation of a short script that basically just loops over its given command line arguments and prints the pathnames that correspond to existing regular files (or symbolic links to regular files). These existing pathnames are then passed on to the last part of the pipeline.
answered 34 secs ago
Kusalananda
112k15216344
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
$ for file in $(command1); do if [[ -f "$file" ]]; then echo "$file"; done | xargs command2
answered 6 mins ago
DopeGhoti
41.9k55180
add a comment |Â
up vote
0
down vote
$ for file in $(command1); do if [[ -f "$file" ]]; then echo "$file"; done | xargs command2
answered 6 mins ago
DopeGhoti
41.9k55180
add a comment |Â
up vote
0
down vote
up vote
0
down vote
$ for file in $(command1); do if [[ -f "$file" ]]; then echo "$file"; done | xargs command2
answered 6 mins ago
DopeGhoti
41.9k55180
$ for file in $(command1); do if [[ -f "$file" ]]; then echo "$file"; done | xargs command2
answered 6 mins ago
DopeGhoti
41.9k55180
answered 6 mins ago
DopeGhoti
41.9k55180
answered 6 mins ago
DopeGhoti
41.9k55180
answered 6 mins ago
DopeGhoti
41.9k55180
41.9k55180
add a comment |Â
add a comment |Â
up vote
0
down vote
command1 |
xargs sh -c 'for p do [ -f "$p" ] && printf "%sn" "$p"; done' sh |
xargs command 2
The extra bit in the middle is a another xargs invocation of a short script that basically just loops over its given command line arguments and prints the pathnames that correspond to existing regular files (or symbolic links to regular files). These existing pathnames are then passed on to the last part of the pipeline.
answered 34 secs ago
Kusalananda
112k15216344
add a comment |Â
up vote
0
down vote
command1 |
xargs sh -c 'for p do [ -f "$p" ] && printf "%sn" "$p"; done' sh |
xargs command 2
The extra bit in the middle is a another xargs invocation of a short script that basically just loops over its given command line arguments and prints the pathnames that correspond to existing regular files (or symbolic links to regular files). These existing pathnames are then passed on to the last part of the pipeline.
answered 34 secs ago
Kusalananda
112k15216344
add a comment |Â
up vote
0
down vote
up vote
0
down vote
command1 |
xargs sh -c 'for p do [ -f "$p" ] && printf "%sn" "$p"; done' sh |
xargs command 2
The extra bit in the middle is a another xargs invocation of a short script that basically just loops over its given command line arguments and prints the pathnames that correspond to existing regular files (or symbolic links to regular files). These existing pathnames are then passed on to the last part of the pipeline.
answered 34 secs ago
Kusalananda
112k15216344
command1 |
xargs sh -c 'for p do [ -f "$p" ] && printf "%sn" "$p"; done' sh |
xargs command 2
The extra bit in the middle is a another xargs invocation of a short script that basically just loops over its given command line arguments and prints the pathnames that correspond to existing regular files (or symbolic links to regular files). These existing pathnames are then passed on to the last part of the pipeline.
answered 34 secs ago
Kusalananda
112k15216344
answered 34 secs ago
Kusalananda
112k15216344
answered 34 secs ago
Kusalananda
112k15216344
answered 34 secs ago
Kusalananda
112k15216344
112k15216344
add a comment |Â
add a comment |Â
Sathish is a new contributor. Be nice, and check out our Code of Conduct.
Sathish is a new contributor. Be nice, and check out our Code of Conduct.
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