mjhjmtu

There are 10 files and they are zipped into Ten.zip. How to read first n lines (say 2 lines) from all 10 files in a zipped file? Is there any easy command for this?

There is not an "easy" command because unzip does not offer this functionality natively. You must ask it to extract some or all of the files and process them yourself. Here's another way:

zipinfo -1 Ten.zip | while IFS= read -r filename
do 
 unzip -p Ten.zip "$filename" | sed 2q
done

The difference here is to use zipinfo to list the archive's contents, one per line; we then read those filenames line by line and ask unzip to extract that file to the screen (with -p so that the filename is not printed) and then pipe that through sed to have it print (by default), quitting at line 2.

This has a chance to fail if you had archived files with newlines in their name; you wouldn't do that, though, because unzip mangles the filename upon extraction:

$ touch file$'n'name
$ zip foo.zip file*name
$ rm file*name
$ zipinfo -1 foo.zip
file^Jname
$ unzip foo.zip
Archive: foo.zip
 extracting: filename
$ ls -lrt
...
filename

Using unzip and grep:

(Note: This answer takes reference of @RomanPerekhrest's answer and a post here)

bash-3.2$ unzip -l ten.zip
Archive: ten.zip
 Length Date Time Name
--------- ---------- ----- ----
 6 02-07-2018 09:16 0.txt
 6 02-07-2018 09:16 1.txt
 6 02-07-2018 09:16 2.txt
 6 02-07-2018 09:16 3.txt
 6 02-07-2018 09:16 4.txt
 6 02-07-2018 09:16 5.txt
 6 02-07-2018 09:16 6.txt
 6 02-07-2018 09:16 7.txt
 6 02-07-2018 09:16 8.txt
 6 02-07-2018 09:16 9.txt
--------- -------
 60 10 files
bash-3.2$

Extract the contents of zipped files to stdout/screen:

bash-3.2$ unzip -c ten.zip | grep -A2 extracting
 extracting: 0.txt
0
0
--
 extracting: 1.txt
1
1
--
 extracting: 2.txt
2
2
--
 extracting: 3.txt
3
3
And so on..

Command: unzip -c ten.zip | grep -A[n] extracting.
Here 'n' can be the number of lines user wants to view.

unzip + awk solution:

Sample 10xml.zip archive structure:

$ unzip -l 10xml.zip 
Archive: 10xml.zip
 Length Date Time Name
--------- ---------- ----- ----
 20 2018-02-07 11:20 home/osboxes/temp_files/1.xml
 20 2018-02-07 11:20 home/osboxes/temp_files/2.xml
 20 2018-02-07 11:20 home/osboxes/temp_files/3.xml
 20 2018-02-07 11:20 home/osboxes/temp_files/4.xml
 20 2018-02-07 11:20 home/osboxes/temp_files/5.xml
 20 2018-02-07 11:20 home/osboxes/temp_files/6.xml
 20 2018-02-07 11:20 home/osboxes/temp_files/7.xml
 20 2018-02-07 11:20 home/osboxes/temp_files/8.xml
 20 2018-02-07 11:20 home/osboxes/temp_files/9.xml
 21 2018-02-07 11:20 home/osboxes/temp_files/10.xml
--------- -------
 201 10 files

• 
  unzip -l <archive> - list archive files (short format)

Extracting the first 2 lines from each file in the archive:

unzip -c 10xml.zip | awk -v n=2 'NR==1 next /^ +inflating:/ n=NR+2; next n && NR<=n'

• 
  unzip -c <archive> - extract files to stdout/screen. The name of each file is printed as it is extracted.