mjhjmtu

I have many pairs of integers like (a,b),(c,d),(e,f) .. so on. I need to check if the value of 1st element lies between a range of 90% to 150% of the 2nd element and print the value as Pass.

The values (a,b) are from different columns of a file for two different times respectively.

File1:1 12 123 1234-text-1 12345

File2:2 23 234 1239-text-1 12347

a="$(find . -name *abc.gz* -mtime 1 | xargs zcat | awk -F"," 'print $4' | grep "text-1" | awk '$1=$1;print' | awk 'print $1')"

b="$(find . -name *abc.gz* -mtime 10 | xargs zcat | awk -F"," 'print $4' | | grep "text-1"| awk '$1=$1;print' | awk 'print $1')"

#a=1234
#b=1239

b1="$(bc <<<"$b*9/10")"
b2="$(bc <<<"$b*15/10")"

if [ $a -ge $b1 -a $a -le $b2 ];
 then
 echo "PASS"
 else
 echo "FAIL"
fi

I need to do it for different text values like 'text-2', 'text-3' etc for different columns of a file $5, $6 etc.

Please guide me a single iterative solution in Bash.

This doesn't answer your whole question, but note that bash cannot do any sort of floating point arithmetic:

$ if [ 1234 -ge 1115.1 -a 1234 -le 1858.5 ]; then echo ok; else echo nope; fi
bash: [: 1115.1: integer expression expected
nope

You can have bc do the comparisons:

check() 
check 1234 1239 # => OK
check 1234 12390 # => NO