mjhjmtu

This is similar to How can I generate a full listing of the files installed by a package? However, I haven't installed the package, yet.

I wanted to list all files which will be installed by APT package xorg. In other words: all files which will be installed when I type apt install xorg. However, apt-file listed only the immediate files of xorg - not of its dependencies:

$ apt-file list xorg
xorg: /usr/share/bug/xorg/script
xorg: /usr/share/doc/xorg/changelog.gz
xorg: /usr/share/doc/xorg/copyright
xorg: /usr/share/lintian/overrides/xorg

How can I list all associated files?

(I will add an awful bash pipe combination as an answer. This is what I'm using right now, but its just a loop with many calls to apt-file and therefore very, very slow. I'm looking for a better answer.)

This is what I'm using right now, but it might be buggy and is definitely not very performant:

apt-cache depends xorg | grep '..(Depends|Recommends): [^<]' | sed 's/[^:]*: //' | while read LINE; do [[ -z "$LINE" ]] || apt-file list "$LINE"; done | sed 's/[^:]*: //' | sort

Step-by-step:

Get list of packages which will be installed:

apt-cache depends xorg

Select the "depends" and "recommends" entries:

grep '..(Depends|Recommends): [^<]'

Strip everything except the package name:

sed 's/[^:]*: //'

If the line isn't empty, run apt-file with each package name:

while read LINE; do [[ -z "$LINE" ]] || apt-file list "$LINE"; done

apt-file list returns lines where each line begins with the corresponding package name for the file. Remove package name from line, which leaves only the filename:

sed 's/[^:]*: //'

Sort lines:

sort