mjhjmtu

I use Ubuntu 16.04 and I execute a list of remote scripts that are in the same directory (a GitHub repository):

curl -s https://raw.githubusercontent.com/$user/$repo/master/1.sh | tr -d 'r' | bash
curl -s https://raw.githubusercontent.com/$user/$repo/master/2.sh | tr -d 'r' | bash
curl -s https://raw.githubusercontent.com/$user/$repo/master/3.sh | tr -d 'r' | bash
curl -s https://raw.githubusercontent.com/$user/$repo/master/4.sh | tr -d 'r' | bash
curl -s https://raw.githubusercontent.com/$user/$repo/master/5.sh | tr -d 'r' | bash
curl -s https://raw.githubusercontent.com/$user/$repo/master/6.sh | tr -d 'r' | bash

How would you cope with the awful redundancy?

I think of a for loop but I have no idea how to construct it. All for loops I've seen so far doesn't give me a clue on how to do that particular task of reusing a curl pattern (and piped output) for different files in the same remote directory.

You are more than welcome to share an example.

Update

• There might be more or less than six such curl operations.


• I would use any plausible way but if it requires a utility please recommend a utility available in the Debian repositories.

For two or more files you could use Unix seq:

for var in $(seq 6)
 do 
 curl -s https://raw.githubusercontent.com/$user/$repo/master/$var.sh | tr -d 'r' | bash
 done

Explanation:

1. Use the output of seq to attain a count up to 6 (as the question lists 6 curl operations).


2. Read the output into the variable var and use this in your curl command.

The fastest one with GNU parallel:

parallel -j0 -k "curl -s https://raw.githubusercontent.com/$user/$repo/master/1.sh 
 | tr -d 'r' | bash" ::: 1..6

You may also specify the crucial number via dynamic variable:

n=7
parallel -j0 -k "curl -s https://raw.githubusercontent.com/$user/$repo/master/1.sh 
 | tr -d 'r' | bash" ::: $(seq $n)

https://www.gnu.org/software/parallel/man.html