Convert dataframe into dictionary
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I have a dataframe and i want it to select a few columns and convert it into Dictionary in the a certain manner
Dataframe:
and here's the output I want
20: [4.6, 4.3, 4.3, 20],
21: [4.6, 4.3, 4.3, 21],
22: [6.0, 5.6, 9.0, 22],
23: [8.75, 5.6, 6.6, 23]
I have tried this
items_dic = data[["Length","Width","Height","Pid" ]].set_index('Pid').T.to_dict('list')
items_dic = 20: [4.6, 4.3, 4.3],
21: [4.6, 4.3, 4.3],
22: [6.0, 5.6, 9.0],
23: [8.75, 5.6, 6.6]
but this does not include Pid in the list of values
Can someone explain why ?
python python-3.x pandas dataframe dictionary
add a comment |
I have a dataframe and i want it to select a few columns and convert it into Dictionary in the a certain manner
Dataframe:
and here's the output I want
20: [4.6, 4.3, 4.3, 20],
21: [4.6, 4.3, 4.3, 21],
22: [6.0, 5.6, 9.0, 22],
23: [8.75, 5.6, 6.6, 23]
I have tried this
items_dic = data[["Length","Width","Height","Pid" ]].set_index('Pid').T.to_dict('list')
items_dic = 20: [4.6, 4.3, 4.3],
21: [4.6, 4.3, 4.3],
22: [6.0, 5.6, 9.0],
23: [8.75, 5.6, 6.6]
but this does not include Pid in the list of values
Can someone explain why ?
python python-3.x pandas dataframe dictionary
2
Please, write the dataframe in proper format, not in picture.
– pistol2myhead
Mar 12 at 6:19
1
I am sorry but I am fairly new to SO and I don't know how to do that
– Rahul Sharma
Mar 12 at 6:22
2
drop=False
inset_index
is what you need
– Sreeram TP
Mar 12 at 6:25
add a comment |
I have a dataframe and i want it to select a few columns and convert it into Dictionary in the a certain manner
Dataframe:
and here's the output I want
20: [4.6, 4.3, 4.3, 20],
21: [4.6, 4.3, 4.3, 21],
22: [6.0, 5.6, 9.0, 22],
23: [8.75, 5.6, 6.6, 23]
I have tried this
items_dic = data[["Length","Width","Height","Pid" ]].set_index('Pid').T.to_dict('list')
items_dic = 20: [4.6, 4.3, 4.3],
21: [4.6, 4.3, 4.3],
22: [6.0, 5.6, 9.0],
23: [8.75, 5.6, 6.6]
but this does not include Pid in the list of values
Can someone explain why ?
python python-3.x pandas dataframe dictionary
I have a dataframe and i want it to select a few columns and convert it into Dictionary in the a certain manner
Dataframe:
and here's the output I want
20: [4.6, 4.3, 4.3, 20],
21: [4.6, 4.3, 4.3, 21],
22: [6.0, 5.6, 9.0, 22],
23: [8.75, 5.6, 6.6, 23]
I have tried this
items_dic = data[["Length","Width","Height","Pid" ]].set_index('Pid').T.to_dict('list')
items_dic = 20: [4.6, 4.3, 4.3],
21: [4.6, 4.3, 4.3],
22: [6.0, 5.6, 9.0],
23: [8.75, 5.6, 6.6]
but this does not include Pid in the list of values
Can someone explain why ?
python python-3.x pandas dataframe dictionary
python python-3.x pandas dataframe dictionary
edited Mar 29 at 13:43
Davy de Vries
577416
577416
asked Mar 12 at 6:16
Rahul SharmaRahul Sharma
167113
167113
2
Please, write the dataframe in proper format, not in picture.
– pistol2myhead
Mar 12 at 6:19
1
I am sorry but I am fairly new to SO and I don't know how to do that
– Rahul Sharma
Mar 12 at 6:22
2
drop=False
inset_index
is what you need
– Sreeram TP
Mar 12 at 6:25
add a comment |
2
Please, write the dataframe in proper format, not in picture.
– pistol2myhead
Mar 12 at 6:19
1
I am sorry but I am fairly new to SO and I don't know how to do that
– Rahul Sharma
Mar 12 at 6:22
2
drop=False
inset_index
is what you need
– Sreeram TP
Mar 12 at 6:25
2
2
Please, write the dataframe in proper format, not in picture.
– pistol2myhead
Mar 12 at 6:19
Please, write the dataframe in proper format, not in picture.
– pistol2myhead
Mar 12 at 6:19
1
1
I am sorry but I am fairly new to SO and I don't know how to do that
– Rahul Sharma
Mar 12 at 6:22
I am sorry but I am fairly new to SO and I don't know how to do that
– Rahul Sharma
Mar 12 at 6:22
2
2
drop=False
in set_index
is what you need– Sreeram TP
Mar 12 at 6:25
drop=False
in set_index
is what you need– Sreeram TP
Mar 12 at 6:25
add a comment |
2 Answers
2
active
oldest
votes
Set parameter drop=False
in DataFrame.set_index
, because default parameter drop=False
move column to index:
cols = ["Length","Width","Height","Pid"]
items_dic = data[cols].set_index('Pid', drop=False).T.to_dict('list')
print (items_dic)
20: [4.6, 4.3, 4.3, 20.0],
21: [4.6, 4.3, 4.3, 21.0],
22: [6.0, 5.6, 9.0, 22.0],
23: [8.75, 5.6, 6.6, 23.0]
add a comment |
Or use dict(zip(...))
:
>>> cols = ["Length","Width","Height","Pid"]
>>> items_dic = dict(zip(df['Pid'],df[cols].values.tolist()))
>>> items_dic
20: [4.8, 4.3, 4.3, 20.0], 21: [4.8, 4.3, 4.3, 21.0], 22: [6.0, 5.6, 9.0, 22.0], 23: [8.75, 5.6, 6.6, 23.0], 24: [6.0, 5.16, 6.6, 24.0]
>>>
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Set parameter drop=False
in DataFrame.set_index
, because default parameter drop=False
move column to index:
cols = ["Length","Width","Height","Pid"]
items_dic = data[cols].set_index('Pid', drop=False).T.to_dict('list')
print (items_dic)
20: [4.6, 4.3, 4.3, 20.0],
21: [4.6, 4.3, 4.3, 21.0],
22: [6.0, 5.6, 9.0, 22.0],
23: [8.75, 5.6, 6.6, 23.0]
add a comment |
Set parameter drop=False
in DataFrame.set_index
, because default parameter drop=False
move column to index:
cols = ["Length","Width","Height","Pid"]
items_dic = data[cols].set_index('Pid', drop=False).T.to_dict('list')
print (items_dic)
20: [4.6, 4.3, 4.3, 20.0],
21: [4.6, 4.3, 4.3, 21.0],
22: [6.0, 5.6, 9.0, 22.0],
23: [8.75, 5.6, 6.6, 23.0]
add a comment |
Set parameter drop=False
in DataFrame.set_index
, because default parameter drop=False
move column to index:
cols = ["Length","Width","Height","Pid"]
items_dic = data[cols].set_index('Pid', drop=False).T.to_dict('list')
print (items_dic)
20: [4.6, 4.3, 4.3, 20.0],
21: [4.6, 4.3, 4.3, 21.0],
22: [6.0, 5.6, 9.0, 22.0],
23: [8.75, 5.6, 6.6, 23.0]
Set parameter drop=False
in DataFrame.set_index
, because default parameter drop=False
move column to index:
cols = ["Length","Width","Height","Pid"]
items_dic = data[cols].set_index('Pid', drop=False).T.to_dict('list')
print (items_dic)
20: [4.6, 4.3, 4.3, 20.0],
21: [4.6, 4.3, 4.3, 21.0],
22: [6.0, 5.6, 9.0, 22.0],
23: [8.75, 5.6, 6.6, 23.0]
edited Mar 12 at 6:26
answered Mar 12 at 6:19
jezraeljezrael
357k26322399
357k26322399
add a comment |
add a comment |
Or use dict(zip(...))
:
>>> cols = ["Length","Width","Height","Pid"]
>>> items_dic = dict(zip(df['Pid'],df[cols].values.tolist()))
>>> items_dic
20: [4.8, 4.3, 4.3, 20.0], 21: [4.8, 4.3, 4.3, 21.0], 22: [6.0, 5.6, 9.0, 22.0], 23: [8.75, 5.6, 6.6, 23.0], 24: [6.0, 5.16, 6.6, 24.0]
>>>
add a comment |
Or use dict(zip(...))
:
>>> cols = ["Length","Width","Height","Pid"]
>>> items_dic = dict(zip(df['Pid'],df[cols].values.tolist()))
>>> items_dic
20: [4.8, 4.3, 4.3, 20.0], 21: [4.8, 4.3, 4.3, 21.0], 22: [6.0, 5.6, 9.0, 22.0], 23: [8.75, 5.6, 6.6, 23.0], 24: [6.0, 5.16, 6.6, 24.0]
>>>
add a comment |
Or use dict(zip(...))
:
>>> cols = ["Length","Width","Height","Pid"]
>>> items_dic = dict(zip(df['Pid'],df[cols].values.tolist()))
>>> items_dic
20: [4.8, 4.3, 4.3, 20.0], 21: [4.8, 4.3, 4.3, 21.0], 22: [6.0, 5.6, 9.0, 22.0], 23: [8.75, 5.6, 6.6, 23.0], 24: [6.0, 5.16, 6.6, 24.0]
>>>
Or use dict(zip(...))
:
>>> cols = ["Length","Width","Height","Pid"]
>>> items_dic = dict(zip(df['Pid'],df[cols].values.tolist()))
>>> items_dic
20: [4.8, 4.3, 4.3, 20.0], 21: [4.8, 4.3, 4.3, 21.0], 22: [6.0, 5.6, 9.0, 22.0], 23: [8.75, 5.6, 6.6, 23.0], 24: [6.0, 5.16, 6.6, 24.0]
>>>
edited Mar 12 at 7:45
Mudits
70811028
70811028
answered Mar 12 at 6:23
U9-ForwardU9-Forward
18.1k51744
18.1k51744
add a comment |
add a comment |
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2
Please, write the dataframe in proper format, not in picture.
– pistol2myhead
Mar 12 at 6:19
1
I am sorry but I am fairly new to SO and I don't know how to do that
– Rahul Sharma
Mar 12 at 6:22
2
drop=False
inset_index
is what you need– Sreeram TP
Mar 12 at 6:25