Checking for invalid date in bash script

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;

I am checking for a valid date scrpt.bash test 2019-05-03

date -d $2 2>: 1>:; c=$?

If $c is 1 then the date is invalid. If I enter 2019-05-03 I will get a 0 which is correct. If i enter 2019-05-03u I get a 0 which is incorrect. I can enter 2019-05-03uu then it throws an error. How can I just check if the date is valid.

asked Mar 12 at 14:06

user3525290

1224

1

Is the date always provided in this format? 2019-05-03

– Luciano Andress Martini
Mar 12 at 14:24

Have you try date -d $2 && c=$?

– Romeo Ninov
Mar 12 at 14:24

Romeo as he says date is returning sucess (0), even if the date contain a additional character at end. So && will make no difference as it will check the command return too to make a decision.

– Luciano Andress Martini
Mar 12 at 14:25

1

date is valid against what criteria? Against what your date -d supports?

– Stéphane Chazelas
Mar 12 at 14:32

add a comment |

I am checking for a valid date scrpt.bash test 2019-05-03

date -d $2 2>: 1>:; c=$?

asked Mar 12 at 14:06

user3525290

1224

1

Is the date always provided in this format? 2019-05-03

– Luciano Andress Martini
Mar 12 at 14:24

Have you try date -d $2 && c=$?

– Romeo Ninov
Mar 12 at 14:24

Romeo as he says date is returning sucess (0), even if the date contain a additional character at end. So && will make no difference as it will check the command return too to make a decision.

– Luciano Andress Martini
Mar 12 at 14:25

1

date is valid against what criteria? Against what your date -d supports?

– Stéphane Chazelas
Mar 12 at 14:32

add a comment |

I am checking for a valid date scrpt.bash test 2019-05-03

date -d $2 2>: 1>:; c=$?

asked Mar 12 at 14:06

user3525290

1224

I am checking for a valid date scrpt.bash test 2019-05-03

date -d $2 2>: 1>:; c=$?

bash date error-handling

asked Mar 12 at 14:06

user3525290

1224

asked Mar 12 at 14:06

user3525290

1224

asked Mar 12 at 14:06

user3525290

1224

asked Mar 12 at 14:06

user3525290

1224

asked Mar 12 at 14:06

user3525290

1224

1

Is the date always provided in this format? 2019-05-03

– Luciano Andress Martini
Mar 12 at 14:24

Have you try date -d $2 && c=$?

– Romeo Ninov
Mar 12 at 14:24

Romeo as he says date is returning sucess (0), even if the date contain a additional character at end. So && will make no difference as it will check the command return too to make a decision.

– Luciano Andress Martini
Mar 12 at 14:25

1

date is valid against what criteria? Against what your date -d supports?

– Stéphane Chazelas
Mar 12 at 14:32

add a comment |

1

Is the date always provided in this format? 2019-05-03

– Luciano Andress Martini
Mar 12 at 14:24

Have you try date -d $2 && c=$?

– Romeo Ninov
Mar 12 at 14:24

Romeo as he says date is returning sucess (0), even if the date contain a additional character at end. So && will make no difference as it will check the command return too to make a decision.

– Luciano Andress Martini
Mar 12 at 14:25

1

date is valid against what criteria? Against what your date -d supports?

– Stéphane Chazelas
Mar 12 at 14:32

Is the date always provided in this format? 2019-05-03

– Luciano Andress Martini
Mar 12 at 14:24

Have you try date -d $2 && c=$?

– Romeo Ninov
Mar 12 at 14:24

Romeo as he says date is returning sucess (0), even if the date contain a additional character at end. So && will make no difference as it will check the command return too to make a decision.

– Luciano Andress Martini
Mar 12 at 14:25

date is valid against what criteria? Against what your date -d supports?

– Stéphane Chazelas
Mar 12 at 14:32

add a comment |

1 Answer
1

active

oldest

votes

If date is always provided in this format: '2019-05-03', this will probably work always:

#!/bin/sh -

if [ -n "$2" ] && [ "$(date -d "$2" +%Y-%m-%d 2> /dev/null)" = "$2" ]; then
 echo 'This date is valid'
fi

edited Mar 12 at 14:36

Stéphane Chazelas

314k57594952

answered Mar 12 at 14:31

Luciano Andress Martini

4,1901237

add a comment |

Your Answer

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "106"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);

);

draft saved

draft discarded

StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f505886%2fchecking-for-invalid-date-in-bash-script%23new-answer', 'question_page');

);

Post as a guest

Name

Required, but never shown

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

If date is always provided in this format: '2019-05-03', this will probably work always:

#!/bin/sh -

if [ -n "$2" ] && [ "$(date -d "$2" +%Y-%m-%d 2> /dev/null)" = "$2" ]; then
 echo 'This date is valid'
fi

edited Mar 12 at 14:36

Stéphane Chazelas

314k57594952

answered Mar 12 at 14:31

Luciano Andress Martini

4,1901237

add a comment |

If date is always provided in this format: '2019-05-03', this will probably work always:

#!/bin/sh -

if [ -n "$2" ] && [ "$(date -d "$2" +%Y-%m-%d 2> /dev/null)" = "$2" ]; then
 echo 'This date is valid'
fi

edited Mar 12 at 14:36

Stéphane Chazelas

314k57594952

answered Mar 12 at 14:31

Luciano Andress Martini

4,1901237

add a comment |

If date is always provided in this format: '2019-05-03', this will probably work always:

#!/bin/sh -

if [ -n "$2" ] && [ "$(date -d "$2" +%Y-%m-%d 2> /dev/null)" = "$2" ]; then
 echo 'This date is valid'
fi

edited Mar 12 at 14:36

Stéphane Chazelas

314k57594952

answered Mar 12 at 14:31

Luciano Andress Martini

4,1901237

If date is always provided in this format: '2019-05-03', this will probably work always:

#!/bin/sh -

if [ -n "$2" ] && [ "$(date -d "$2" +%Y-%m-%d 2> /dev/null)" = "$2" ]; then
 echo 'This date is valid'
fi

edited Mar 12 at 14:36

Stéphane Chazelas

314k57594952

answered Mar 12 at 14:31

Luciano Andress Martini

4,1901237

edited Mar 12 at 14:36

Stéphane Chazelas

314k57594952

edited Mar 12 at 14:36

Stéphane Chazelas

314k57594952

edited Mar 12 at 14:36

Stéphane Chazelas

314k57594952

answered Mar 12 at 14:31

Luciano Andress Martini

4,1901237

answered Mar 12 at 14:31

Luciano Andress Martini

4,1901237

answered Mar 12 at 14:31

Luciano Andress Martini

4,1901237

add a comment |

draft saved

draft discarded

Thanks for contributing an answer to Unix & Linux Stack Exchange!

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

搜尋此網誌

mjhjmtu