Get key/value pair from Firebase response nested JSON object

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10















I am getting the following response from a GET API call to Firebase database. It is a nested JSON objects.



I want to get all the values for key name from each nested object into an array using JavaScript



GET REST API Response:




"barID1":
"address": "4 East Terrace, Sydney NSW 2000",
"appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
"description": “description text”,
"imgURLs": [ "Https:url1”, "https:url2”, "https:url3” ],
"lat": -34.810585,
"lon": 138.616739,
"name": "Africola",
"phone": "(08) 8223 3885",
"status": "active",
"venueImgURL": "https:url”
,
"barID2":
"address": "138/140 Gouger St, Sydney NSW 2000",
"appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
"description": “description text”,
"imgURLs": [ "Https:url1”, "https:url2”, "https:url3” ],
"lat": -34.848082,
"lon": 138.599813,
"name": "Disco Mexico Taqueria",
"phone": "0416 855 108",
"status": "active",
"venueImgURL": "https:url”











share|improve this question




























    10















    I am getting the following response from a GET API call to Firebase database. It is a nested JSON objects.



    I want to get all the values for key name from each nested object into an array using JavaScript



    GET REST API Response:




    "barID1":
    "address": "4 East Terrace, Sydney NSW 2000",
    "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
    "description": “description text”,
    "imgURLs": [ "Https:url1”, "https:url2”, "https:url3” ],
    "lat": -34.810585,
    "lon": 138.616739,
    "name": "Africola",
    "phone": "(08) 8223 3885",
    "status": "active",
    "venueImgURL": "https:url”
    ,
    "barID2":
    "address": "138/140 Gouger St, Sydney NSW 2000",
    "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
    "description": “description text”,
    "imgURLs": [ "Https:url1”, "https:url2”, "https:url3” ],
    "lat": -34.848082,
    "lon": 138.599813,
    "name": "Disco Mexico Taqueria",
    "phone": "0416 855 108",
    "status": "active",
    "venueImgURL": "https:url”











    share|improve this question


























      10












      10








      10








      I am getting the following response from a GET API call to Firebase database. It is a nested JSON objects.



      I want to get all the values for key name from each nested object into an array using JavaScript



      GET REST API Response:




      "barID1":
      "address": "4 East Terrace, Sydney NSW 2000",
      "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
      "description": “description text”,
      "imgURLs": [ "Https:url1”, "https:url2”, "https:url3” ],
      "lat": -34.810585,
      "lon": 138.616739,
      "name": "Africola",
      "phone": "(08) 8223 3885",
      "status": "active",
      "venueImgURL": "https:url”
      ,
      "barID2":
      "address": "138/140 Gouger St, Sydney NSW 2000",
      "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
      "description": “description text”,
      "imgURLs": [ "Https:url1”, "https:url2”, "https:url3” ],
      "lat": -34.848082,
      "lon": 138.599813,
      "name": "Disco Mexico Taqueria",
      "phone": "0416 855 108",
      "status": "active",
      "venueImgURL": "https:url”











      share|improve this question
















      I am getting the following response from a GET API call to Firebase database. It is a nested JSON objects.



      I want to get all the values for key name from each nested object into an array using JavaScript



      GET REST API Response:




      "barID1":
      "address": "4 East Terrace, Sydney NSW 2000",
      "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
      "description": “description text”,
      "imgURLs": [ "Https:url1”, "https:url2”, "https:url3” ],
      "lat": -34.810585,
      "lon": 138.616739,
      "name": "Africola",
      "phone": "(08) 8223 3885",
      "status": "active",
      "venueImgURL": "https:url”
      ,
      "barID2":
      "address": "138/140 Gouger St, Sydney NSW 2000",
      "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
      "description": “description text”,
      "imgURLs": [ "Https:url1”, "https:url2”, "https:url3” ],
      "lat": -34.848082,
      "lon": 138.599813,
      "name": "Disco Mexico Taqueria",
      "phone": "0416 855 108",
      "status": "active",
      "venueImgURL": "https:url”








      javascript arrays json object






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      share|improve this question













      share|improve this question




      share|improve this question








      edited Feb 14 at 4:18









      Jack Bashford

      10.9k31645




      10.9k31645










      asked Feb 14 at 3:57









      RoggieRoggie

      215213




      215213






















          5 Answers
          5






          active

          oldest

          votes


















          6














          It can be done using:



          1. Using Array.reduce to accumulate the name values into a single array.


          2. Using Object.keys and Array.map to iterate through the keys and map it to the name array.


          3. Using Object.values and Array.map


          4. Using Array.from and utilizing the second mapping function parameter to map individual objects to an array of names.





          const obj = "barID1":"address":"4 East Terrace, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.810585,"lon":138.616739,"name":"Africola","phone":"(08) 8223 3885","status":"active","venueImgURL":"https:url","barID2":"address":"138/140 Gouger St, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.848082,"lon":138.599813,"name":"Disco Mexico Taqueria","phone":"0416 855 108","status":"active","venueImgURL":"https:url";

          //using Object.values & reduce
          let name = Object.values(obj).reduce((acc, ele) =>
          return acc.concat(ele.name)
          , );
          console.log(name);

          //using Object.keys & map
          name = Object.keys(obj).map((ele) => obj[ele]['name']);
          console.log(name);

          //using Object.values & map
          name = Object.values(obj).map((ele) => ele.name);
          console.log(name);

          //using Array.from
          name = Array.from(Object.values(obj), ele => ele.name);
          console.log(name);








          share|improve this answer

























          • Please not that solutions 3 and 4 are ECMA 2015/2017. This may not be what you want.

            – Pierre Arlaud
            Feb 14 at 10:41


















          2














          You could extract the values of the input object via Object.values() and then map() the name from each object value as shown below to achieve this:






          const data = 
          barID1:
          address: "4 East Terrace, Sydney NSW 2000",
          appStoreURL: "http://itunes.apple.com/app/idXXXXXXXXX",
          description: "description text",
          imgURLs: [ "Https:url1", "https:url2", "https:url3" ],
          lat: -34.810585,
          lon: 138.616739,
          name: "Africola",
          phone: "(08) 8223 3885",
          status: "active",
          venueImgURL: "https:url"
          ,
          barID2:
          address: "138/140 Gouger St, Sydney NSW 2000",
          appStoreURL: "http://itunes.apple.com/app/idXXXXXXXXX",
          description: "description text",
          imgURLs: [ "Https:url1", "https:url2", "https:url3" ],
          lat: -34.848082,
          lon: 138.599813,
          name: "Disco Mexico Taqueria",
          phone: "0416 855 108",
          status: "active",
          venueImgURL: "https:url"



          console.log( Object.values(data).map(object => object.name) )








          share|improve this answer






























            2














            You can map() the Object.values() of the json structure.






            const json = 
            "barID1":
            "address": "4 East Terrace, Sydney NSW 2000",
            "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
            "description": "description text",
            "imgURLs": [ "Https:url1", "https:url2", "https:url3" ],
            "lat": -34.810585,
            "lon": 138.616739,
            "name": "Africola",
            "phone": "(08) 8223 3885",
            "status": "active",
            "venueImgURL": "https:url"
            ,
            "barID2":
            "address": "138/140 Gouger St, Sydney NSW 2000",
            "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
            "description": "description text",
            "imgURLs": [ "Https:url1", "https:url2", "https:url3" ],
            "lat": -34.848082,
            "lon": 138.599813,
            "name": "Disco Mexico Taqueria",
            "phone": "0416 855 108",
            "status": "active",
            "venueImgURL": "https:url"

            ;

            let res = Object.values(json).map((name) => name);
            console.log(res);








            share|improve this answer






























              2














              The simplest solution is Object.values:






              const data = "barID1":"address":"4 East Terrace, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.810585,"lon":138.616739,"name":"Africola","phone":"(08) 8223 3885","status":"active","venueImgURL":"https:url","barID2":"address":"138/140 Gouger St, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.848082,"lon":138.599813,"name":"Disco Mexico Taqueria","phone":"0416 855 108","status":"active","venueImgURL":"https:url";
              const namesArr = Object.values(data).map(( name ) => name);
              console.log(namesArr);








              share|improve this answer






























                1














                Here I use for in to loop each object in your JSON then push the name into the result array.






                const data = 
                "barID1":
                "address": "4 East Terrace, Sydney NSW 2000",
                "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                "description": "description text",
                "imgURLs": ["Https:url1", "https: url2", "https:url3"],
                "lat": -34.810585,
                "lon": 138.616739,
                "name": "Africola",
                "phone": "(08) 8223 3885",
                "status": "active",
                "venueImgURL": "https:url"
                ,
                "barID2":
                "address": "138/140 Gouger St, Sydney NSW 2000",
                "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                "description": "description text",
                "imgURLs": ["Https:url1", "https: url2", "https:url3"],
                "lat": -34.848082,
                "lon": 138.599813,
                "name": "Disco Mexico Taqueria",
                "phone": "0416 855 108",
                "status": "active",
                "venueImgURL": "https:url"



                let result =
                for (let i in data)
                result.push(data[i].name)

                console.log(result)








                share|improve this answer






















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                  5 Answers
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                  oldest

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                  5 Answers
                  5






                  active

                  oldest

                  votes









                  active

                  oldest

                  votes






                  active

                  oldest

                  votes









                  6














                  It can be done using:



                  1. Using Array.reduce to accumulate the name values into a single array.


                  2. Using Object.keys and Array.map to iterate through the keys and map it to the name array.


                  3. Using Object.values and Array.map


                  4. Using Array.from and utilizing the second mapping function parameter to map individual objects to an array of names.





                  const obj = "barID1":"address":"4 East Terrace, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.810585,"lon":138.616739,"name":"Africola","phone":"(08) 8223 3885","status":"active","venueImgURL":"https:url","barID2":"address":"138/140 Gouger St, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.848082,"lon":138.599813,"name":"Disco Mexico Taqueria","phone":"0416 855 108","status":"active","venueImgURL":"https:url";

                  //using Object.values & reduce
                  let name = Object.values(obj).reduce((acc, ele) =>
                  return acc.concat(ele.name)
                  , );
                  console.log(name);

                  //using Object.keys & map
                  name = Object.keys(obj).map((ele) => obj[ele]['name']);
                  console.log(name);

                  //using Object.values & map
                  name = Object.values(obj).map((ele) => ele.name);
                  console.log(name);

                  //using Array.from
                  name = Array.from(Object.values(obj), ele => ele.name);
                  console.log(name);








                  share|improve this answer

























                  • Please not that solutions 3 and 4 are ECMA 2015/2017. This may not be what you want.

                    – Pierre Arlaud
                    Feb 14 at 10:41















                  6














                  It can be done using:



                  1. Using Array.reduce to accumulate the name values into a single array.


                  2. Using Object.keys and Array.map to iterate through the keys and map it to the name array.


                  3. Using Object.values and Array.map


                  4. Using Array.from and utilizing the second mapping function parameter to map individual objects to an array of names.





                  const obj = "barID1":"address":"4 East Terrace, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.810585,"lon":138.616739,"name":"Africola","phone":"(08) 8223 3885","status":"active","venueImgURL":"https:url","barID2":"address":"138/140 Gouger St, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.848082,"lon":138.599813,"name":"Disco Mexico Taqueria","phone":"0416 855 108","status":"active","venueImgURL":"https:url";

                  //using Object.values & reduce
                  let name = Object.values(obj).reduce((acc, ele) =>
                  return acc.concat(ele.name)
                  , );
                  console.log(name);

                  //using Object.keys & map
                  name = Object.keys(obj).map((ele) => obj[ele]['name']);
                  console.log(name);

                  //using Object.values & map
                  name = Object.values(obj).map((ele) => ele.name);
                  console.log(name);

                  //using Array.from
                  name = Array.from(Object.values(obj), ele => ele.name);
                  console.log(name);








                  share|improve this answer

























                  • Please not that solutions 3 and 4 are ECMA 2015/2017. This may not be what you want.

                    – Pierre Arlaud
                    Feb 14 at 10:41













                  6












                  6








                  6







                  It can be done using:



                  1. Using Array.reduce to accumulate the name values into a single array.


                  2. Using Object.keys and Array.map to iterate through the keys and map it to the name array.


                  3. Using Object.values and Array.map


                  4. Using Array.from and utilizing the second mapping function parameter to map individual objects to an array of names.





                  const obj = "barID1":"address":"4 East Terrace, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.810585,"lon":138.616739,"name":"Africola","phone":"(08) 8223 3885","status":"active","venueImgURL":"https:url","barID2":"address":"138/140 Gouger St, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.848082,"lon":138.599813,"name":"Disco Mexico Taqueria","phone":"0416 855 108","status":"active","venueImgURL":"https:url";

                  //using Object.values & reduce
                  let name = Object.values(obj).reduce((acc, ele) =>
                  return acc.concat(ele.name)
                  , );
                  console.log(name);

                  //using Object.keys & map
                  name = Object.keys(obj).map((ele) => obj[ele]['name']);
                  console.log(name);

                  //using Object.values & map
                  name = Object.values(obj).map((ele) => ele.name);
                  console.log(name);

                  //using Array.from
                  name = Array.from(Object.values(obj), ele => ele.name);
                  console.log(name);








                  share|improve this answer















                  It can be done using:



                  1. Using Array.reduce to accumulate the name values into a single array.


                  2. Using Object.keys and Array.map to iterate through the keys and map it to the name array.


                  3. Using Object.values and Array.map


                  4. Using Array.from and utilizing the second mapping function parameter to map individual objects to an array of names.





                  const obj = "barID1":"address":"4 East Terrace, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.810585,"lon":138.616739,"name":"Africola","phone":"(08) 8223 3885","status":"active","venueImgURL":"https:url","barID2":"address":"138/140 Gouger St, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.848082,"lon":138.599813,"name":"Disco Mexico Taqueria","phone":"0416 855 108","status":"active","venueImgURL":"https:url";

                  //using Object.values & reduce
                  let name = Object.values(obj).reduce((acc, ele) =>
                  return acc.concat(ele.name)
                  , );
                  console.log(name);

                  //using Object.keys & map
                  name = Object.keys(obj).map((ele) => obj[ele]['name']);
                  console.log(name);

                  //using Object.values & map
                  name = Object.values(obj).map((ele) => ele.name);
                  console.log(name);

                  //using Array.from
                  name = Array.from(Object.values(obj), ele => ele.name);
                  console.log(name);








                  const obj = "barID1":"address":"4 East Terrace, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.810585,"lon":138.616739,"name":"Africola","phone":"(08) 8223 3885","status":"active","venueImgURL":"https:url","barID2":"address":"138/140 Gouger St, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.848082,"lon":138.599813,"name":"Disco Mexico Taqueria","phone":"0416 855 108","status":"active","venueImgURL":"https:url";

                  //using Object.values & reduce
                  let name = Object.values(obj).reduce((acc, ele) =>
                  return acc.concat(ele.name)
                  , );
                  console.log(name);

                  //using Object.keys & map
                  name = Object.keys(obj).map((ele) => obj[ele]['name']);
                  console.log(name);

                  //using Object.values & map
                  name = Object.values(obj).map((ele) => ele.name);
                  console.log(name);

                  //using Array.from
                  name = Array.from(Object.values(obj), ele => ele.name);
                  console.log(name);





                  const obj = "barID1":"address":"4 East Terrace, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.810585,"lon":138.616739,"name":"Africola","phone":"(08) 8223 3885","status":"active","venueImgURL":"https:url","barID2":"address":"138/140 Gouger St, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.848082,"lon":138.599813,"name":"Disco Mexico Taqueria","phone":"0416 855 108","status":"active","venueImgURL":"https:url";

                  //using Object.values & reduce
                  let name = Object.values(obj).reduce((acc, ele) =>
                  return acc.concat(ele.name)
                  , );
                  console.log(name);

                  //using Object.keys & map
                  name = Object.keys(obj).map((ele) => obj[ele]['name']);
                  console.log(name);

                  //using Object.values & map
                  name = Object.values(obj).map((ele) => ele.name);
                  console.log(name);

                  //using Array.from
                  name = Array.from(Object.values(obj), ele => ele.name);
                  console.log(name);






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Feb 14 at 7:32









                  Wai Ha Lee

                  6,016123965




                  6,016123965










                  answered Feb 14 at 4:05









                  Amardeep BhowmickAmardeep Bhowmick

                  3,78211126




                  3,78211126












                  • Please not that solutions 3 and 4 are ECMA 2015/2017. This may not be what you want.

                    – Pierre Arlaud
                    Feb 14 at 10:41

















                  • Please not that solutions 3 and 4 are ECMA 2015/2017. This may not be what you want.

                    – Pierre Arlaud
                    Feb 14 at 10:41
















                  Please not that solutions 3 and 4 are ECMA 2015/2017. This may not be what you want.

                  – Pierre Arlaud
                  Feb 14 at 10:41





                  Please not that solutions 3 and 4 are ECMA 2015/2017. This may not be what you want.

                  – Pierre Arlaud
                  Feb 14 at 10:41













                  2














                  You could extract the values of the input object via Object.values() and then map() the name from each object value as shown below to achieve this:






                  const data = 
                  barID1:
                  address: "4 East Terrace, Sydney NSW 2000",
                  appStoreURL: "http://itunes.apple.com/app/idXXXXXXXXX",
                  description: "description text",
                  imgURLs: [ "Https:url1", "https:url2", "https:url3" ],
                  lat: -34.810585,
                  lon: 138.616739,
                  name: "Africola",
                  phone: "(08) 8223 3885",
                  status: "active",
                  venueImgURL: "https:url"
                  ,
                  barID2:
                  address: "138/140 Gouger St, Sydney NSW 2000",
                  appStoreURL: "http://itunes.apple.com/app/idXXXXXXXXX",
                  description: "description text",
                  imgURLs: [ "Https:url1", "https:url2", "https:url3" ],
                  lat: -34.848082,
                  lon: 138.599813,
                  name: "Disco Mexico Taqueria",
                  phone: "0416 855 108",
                  status: "active",
                  venueImgURL: "https:url"



                  console.log( Object.values(data).map(object => object.name) )








                  share|improve this answer



























                    2














                    You could extract the values of the input object via Object.values() and then map() the name from each object value as shown below to achieve this:






                    const data = 
                    barID1:
                    address: "4 East Terrace, Sydney NSW 2000",
                    appStoreURL: "http://itunes.apple.com/app/idXXXXXXXXX",
                    description: "description text",
                    imgURLs: [ "Https:url1", "https:url2", "https:url3" ],
                    lat: -34.810585,
                    lon: 138.616739,
                    name: "Africola",
                    phone: "(08) 8223 3885",
                    status: "active",
                    venueImgURL: "https:url"
                    ,
                    barID2:
                    address: "138/140 Gouger St, Sydney NSW 2000",
                    appStoreURL: "http://itunes.apple.com/app/idXXXXXXXXX",
                    description: "description text",
                    imgURLs: [ "Https:url1", "https:url2", "https:url3" ],
                    lat: -34.848082,
                    lon: 138.599813,
                    name: "Disco Mexico Taqueria",
                    phone: "0416 855 108",
                    status: "active",
                    venueImgURL: "https:url"



                    console.log( Object.values(data).map(object => object.name) )








                    share|improve this answer

























                      2












                      2








                      2







                      You could extract the values of the input object via Object.values() and then map() the name from each object value as shown below to achieve this:






                      const data = 
                      barID1:
                      address: "4 East Terrace, Sydney NSW 2000",
                      appStoreURL: "http://itunes.apple.com/app/idXXXXXXXXX",
                      description: "description text",
                      imgURLs: [ "Https:url1", "https:url2", "https:url3" ],
                      lat: -34.810585,
                      lon: 138.616739,
                      name: "Africola",
                      phone: "(08) 8223 3885",
                      status: "active",
                      venueImgURL: "https:url"
                      ,
                      barID2:
                      address: "138/140 Gouger St, Sydney NSW 2000",
                      appStoreURL: "http://itunes.apple.com/app/idXXXXXXXXX",
                      description: "description text",
                      imgURLs: [ "Https:url1", "https:url2", "https:url3" ],
                      lat: -34.848082,
                      lon: 138.599813,
                      name: "Disco Mexico Taqueria",
                      phone: "0416 855 108",
                      status: "active",
                      venueImgURL: "https:url"



                      console.log( Object.values(data).map(object => object.name) )








                      share|improve this answer













                      You could extract the values of the input object via Object.values() and then map() the name from each object value as shown below to achieve this:






                      const data = 
                      barID1:
                      address: "4 East Terrace, Sydney NSW 2000",
                      appStoreURL: "http://itunes.apple.com/app/idXXXXXXXXX",
                      description: "description text",
                      imgURLs: [ "Https:url1", "https:url2", "https:url3" ],
                      lat: -34.810585,
                      lon: 138.616739,
                      name: "Africola",
                      phone: "(08) 8223 3885",
                      status: "active",
                      venueImgURL: "https:url"
                      ,
                      barID2:
                      address: "138/140 Gouger St, Sydney NSW 2000",
                      appStoreURL: "http://itunes.apple.com/app/idXXXXXXXXX",
                      description: "description text",
                      imgURLs: [ "Https:url1", "https:url2", "https:url3" ],
                      lat: -34.848082,
                      lon: 138.599813,
                      name: "Disco Mexico Taqueria",
                      phone: "0416 855 108",
                      status: "active",
                      venueImgURL: "https:url"



                      console.log( Object.values(data).map(object => object.name) )








                      const data = 
                      barID1:
                      address: "4 East Terrace, Sydney NSW 2000",
                      appStoreURL: "http://itunes.apple.com/app/idXXXXXXXXX",
                      description: "description text",
                      imgURLs: [ "Https:url1", "https:url2", "https:url3" ],
                      lat: -34.810585,
                      lon: 138.616739,
                      name: "Africola",
                      phone: "(08) 8223 3885",
                      status: "active",
                      venueImgURL: "https:url"
                      ,
                      barID2:
                      address: "138/140 Gouger St, Sydney NSW 2000",
                      appStoreURL: "http://itunes.apple.com/app/idXXXXXXXXX",
                      description: "description text",
                      imgURLs: [ "Https:url1", "https:url2", "https:url3" ],
                      lat: -34.848082,
                      lon: 138.599813,
                      name: "Disco Mexico Taqueria",
                      phone: "0416 855 108",
                      status: "active",
                      venueImgURL: "https:url"



                      console.log( Object.values(data).map(object => object.name) )





                      const data = 
                      barID1:
                      address: "4 East Terrace, Sydney NSW 2000",
                      appStoreURL: "http://itunes.apple.com/app/idXXXXXXXXX",
                      description: "description text",
                      imgURLs: [ "Https:url1", "https:url2", "https:url3" ],
                      lat: -34.810585,
                      lon: 138.616739,
                      name: "Africola",
                      phone: "(08) 8223 3885",
                      status: "active",
                      venueImgURL: "https:url"
                      ,
                      barID2:
                      address: "138/140 Gouger St, Sydney NSW 2000",
                      appStoreURL: "http://itunes.apple.com/app/idXXXXXXXXX",
                      description: "description text",
                      imgURLs: [ "Https:url1", "https:url2", "https:url3" ],
                      lat: -34.848082,
                      lon: 138.599813,
                      name: "Disco Mexico Taqueria",
                      phone: "0416 855 108",
                      status: "active",
                      venueImgURL: "https:url"



                      console.log( Object.values(data).map(object => object.name) )






                      share|improve this answer












                      share|improve this answer



                      share|improve this answer










                      answered Feb 14 at 4:04









                      Dacre DennyDacre Denny

                      13.1k41032




                      13.1k41032





















                          2














                          You can map() the Object.values() of the json structure.






                          const json = 
                          "barID1":
                          "address": "4 East Terrace, Sydney NSW 2000",
                          "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                          "description": "description text",
                          "imgURLs": [ "Https:url1", "https:url2", "https:url3" ],
                          "lat": -34.810585,
                          "lon": 138.616739,
                          "name": "Africola",
                          "phone": "(08) 8223 3885",
                          "status": "active",
                          "venueImgURL": "https:url"
                          ,
                          "barID2":
                          "address": "138/140 Gouger St, Sydney NSW 2000",
                          "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                          "description": "description text",
                          "imgURLs": [ "Https:url1", "https:url2", "https:url3" ],
                          "lat": -34.848082,
                          "lon": 138.599813,
                          "name": "Disco Mexico Taqueria",
                          "phone": "0416 855 108",
                          "status": "active",
                          "venueImgURL": "https:url"

                          ;

                          let res = Object.values(json).map((name) => name);
                          console.log(res);








                          share|improve this answer



























                            2














                            You can map() the Object.values() of the json structure.






                            const json = 
                            "barID1":
                            "address": "4 East Terrace, Sydney NSW 2000",
                            "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                            "description": "description text",
                            "imgURLs": [ "Https:url1", "https:url2", "https:url3" ],
                            "lat": -34.810585,
                            "lon": 138.616739,
                            "name": "Africola",
                            "phone": "(08) 8223 3885",
                            "status": "active",
                            "venueImgURL": "https:url"
                            ,
                            "barID2":
                            "address": "138/140 Gouger St, Sydney NSW 2000",
                            "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                            "description": "description text",
                            "imgURLs": [ "Https:url1", "https:url2", "https:url3" ],
                            "lat": -34.848082,
                            "lon": 138.599813,
                            "name": "Disco Mexico Taqueria",
                            "phone": "0416 855 108",
                            "status": "active",
                            "venueImgURL": "https:url"

                            ;

                            let res = Object.values(json).map((name) => name);
                            console.log(res);








                            share|improve this answer

























                              2












                              2








                              2







                              You can map() the Object.values() of the json structure.






                              const json = 
                              "barID1":
                              "address": "4 East Terrace, Sydney NSW 2000",
                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                              "description": "description text",
                              "imgURLs": [ "Https:url1", "https:url2", "https:url3" ],
                              "lat": -34.810585,
                              "lon": 138.616739,
                              "name": "Africola",
                              "phone": "(08) 8223 3885",
                              "status": "active",
                              "venueImgURL": "https:url"
                              ,
                              "barID2":
                              "address": "138/140 Gouger St, Sydney NSW 2000",
                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                              "description": "description text",
                              "imgURLs": [ "Https:url1", "https:url2", "https:url3" ],
                              "lat": -34.848082,
                              "lon": 138.599813,
                              "name": "Disco Mexico Taqueria",
                              "phone": "0416 855 108",
                              "status": "active",
                              "venueImgURL": "https:url"

                              ;

                              let res = Object.values(json).map((name) => name);
                              console.log(res);








                              share|improve this answer













                              You can map() the Object.values() of the json structure.






                              const json = 
                              "barID1":
                              "address": "4 East Terrace, Sydney NSW 2000",
                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                              "description": "description text",
                              "imgURLs": [ "Https:url1", "https:url2", "https:url3" ],
                              "lat": -34.810585,
                              "lon": 138.616739,
                              "name": "Africola",
                              "phone": "(08) 8223 3885",
                              "status": "active",
                              "venueImgURL": "https:url"
                              ,
                              "barID2":
                              "address": "138/140 Gouger St, Sydney NSW 2000",
                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                              "description": "description text",
                              "imgURLs": [ "Https:url1", "https:url2", "https:url3" ],
                              "lat": -34.848082,
                              "lon": 138.599813,
                              "name": "Disco Mexico Taqueria",
                              "phone": "0416 855 108",
                              "status": "active",
                              "venueImgURL": "https:url"

                              ;

                              let res = Object.values(json).map((name) => name);
                              console.log(res);








                              const json = 
                              "barID1":
                              "address": "4 East Terrace, Sydney NSW 2000",
                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                              "description": "description text",
                              "imgURLs": [ "Https:url1", "https:url2", "https:url3" ],
                              "lat": -34.810585,
                              "lon": 138.616739,
                              "name": "Africola",
                              "phone": "(08) 8223 3885",
                              "status": "active",
                              "venueImgURL": "https:url"
                              ,
                              "barID2":
                              "address": "138/140 Gouger St, Sydney NSW 2000",
                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                              "description": "description text",
                              "imgURLs": [ "Https:url1", "https:url2", "https:url3" ],
                              "lat": -34.848082,
                              "lon": 138.599813,
                              "name": "Disco Mexico Taqueria",
                              "phone": "0416 855 108",
                              "status": "active",
                              "venueImgURL": "https:url"

                              ;

                              let res = Object.values(json).map((name) => name);
                              console.log(res);





                              const json = 
                              "barID1":
                              "address": "4 East Terrace, Sydney NSW 2000",
                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                              "description": "description text",
                              "imgURLs": [ "Https:url1", "https:url2", "https:url3" ],
                              "lat": -34.810585,
                              "lon": 138.616739,
                              "name": "Africola",
                              "phone": "(08) 8223 3885",
                              "status": "active",
                              "venueImgURL": "https:url"
                              ,
                              "barID2":
                              "address": "138/140 Gouger St, Sydney NSW 2000",
                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                              "description": "description text",
                              "imgURLs": [ "Https:url1", "https:url2", "https:url3" ],
                              "lat": -34.848082,
                              "lon": 138.599813,
                              "name": "Disco Mexico Taqueria",
                              "phone": "0416 855 108",
                              "status": "active",
                              "venueImgURL": "https:url"

                              ;

                              let res = Object.values(json).map((name) => name);
                              console.log(res);






                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered Feb 14 at 4:06









                              ShiderszShidersz

                              9,0612833




                              9,0612833





















                                  2














                                  The simplest solution is Object.values:






                                  const data = "barID1":"address":"4 East Terrace, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.810585,"lon":138.616739,"name":"Africola","phone":"(08) 8223 3885","status":"active","venueImgURL":"https:url","barID2":"address":"138/140 Gouger St, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.848082,"lon":138.599813,"name":"Disco Mexico Taqueria","phone":"0416 855 108","status":"active","venueImgURL":"https:url";
                                  const namesArr = Object.values(data).map(( name ) => name);
                                  console.log(namesArr);








                                  share|improve this answer



























                                    2














                                    The simplest solution is Object.values:






                                    const data = "barID1":"address":"4 East Terrace, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.810585,"lon":138.616739,"name":"Africola","phone":"(08) 8223 3885","status":"active","venueImgURL":"https:url","barID2":"address":"138/140 Gouger St, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.848082,"lon":138.599813,"name":"Disco Mexico Taqueria","phone":"0416 855 108","status":"active","venueImgURL":"https:url";
                                    const namesArr = Object.values(data).map(( name ) => name);
                                    console.log(namesArr);








                                    share|improve this answer

























                                      2












                                      2








                                      2







                                      The simplest solution is Object.values:






                                      const data = "barID1":"address":"4 East Terrace, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.810585,"lon":138.616739,"name":"Africola","phone":"(08) 8223 3885","status":"active","venueImgURL":"https:url","barID2":"address":"138/140 Gouger St, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.848082,"lon":138.599813,"name":"Disco Mexico Taqueria","phone":"0416 855 108","status":"active","venueImgURL":"https:url";
                                      const namesArr = Object.values(data).map(( name ) => name);
                                      console.log(namesArr);








                                      share|improve this answer













                                      The simplest solution is Object.values:






                                      const data = "barID1":"address":"4 East Terrace, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.810585,"lon":138.616739,"name":"Africola","phone":"(08) 8223 3885","status":"active","venueImgURL":"https:url","barID2":"address":"138/140 Gouger St, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.848082,"lon":138.599813,"name":"Disco Mexico Taqueria","phone":"0416 855 108","status":"active","venueImgURL":"https:url";
                                      const namesArr = Object.values(data).map(( name ) => name);
                                      console.log(namesArr);








                                      const data = "barID1":"address":"4 East Terrace, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.810585,"lon":138.616739,"name":"Africola","phone":"(08) 8223 3885","status":"active","venueImgURL":"https:url","barID2":"address":"138/140 Gouger St, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.848082,"lon":138.599813,"name":"Disco Mexico Taqueria","phone":"0416 855 108","status":"active","venueImgURL":"https:url";
                                      const namesArr = Object.values(data).map(( name ) => name);
                                      console.log(namesArr);





                                      const data = "barID1":"address":"4 East Terrace, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.810585,"lon":138.616739,"name":"Africola","phone":"(08) 8223 3885","status":"active","venueImgURL":"https:url","barID2":"address":"138/140 Gouger St, Sydney NSW 2000","appStoreURL":"http://itunes.apple.com/app/idXXXXXXXXX","description":"description text","imgURLs":["Https:url1","https:url2","https:url3"],"lat":-34.848082,"lon":138.599813,"name":"Disco Mexico Taqueria","phone":"0416 855 108","status":"active","venueImgURL":"https:url";
                                      const namesArr = Object.values(data).map(( name ) => name);
                                      console.log(namesArr);






                                      share|improve this answer












                                      share|improve this answer



                                      share|improve this answer










                                      answered Feb 14 at 4:18









                                      Jack BashfordJack Bashford

                                      10.9k31645




                                      10.9k31645





















                                          1














                                          Here I use for in to loop each object in your JSON then push the name into the result array.






                                          const data = 
                                          "barID1":
                                          "address": "4 East Terrace, Sydney NSW 2000",
                                          "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                                          "description": "description text",
                                          "imgURLs": ["Https:url1", "https: url2", "https:url3"],
                                          "lat": -34.810585,
                                          "lon": 138.616739,
                                          "name": "Africola",
                                          "phone": "(08) 8223 3885",
                                          "status": "active",
                                          "venueImgURL": "https:url"
                                          ,
                                          "barID2":
                                          "address": "138/140 Gouger St, Sydney NSW 2000",
                                          "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                                          "description": "description text",
                                          "imgURLs": ["Https:url1", "https: url2", "https:url3"],
                                          "lat": -34.848082,
                                          "lon": 138.599813,
                                          "name": "Disco Mexico Taqueria",
                                          "phone": "0416 855 108",
                                          "status": "active",
                                          "venueImgURL": "https:url"



                                          let result =
                                          for (let i in data)
                                          result.push(data[i].name)

                                          console.log(result)








                                          share|improve this answer



























                                            1














                                            Here I use for in to loop each object in your JSON then push the name into the result array.






                                            const data = 
                                            "barID1":
                                            "address": "4 East Terrace, Sydney NSW 2000",
                                            "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                                            "description": "description text",
                                            "imgURLs": ["Https:url1", "https: url2", "https:url3"],
                                            "lat": -34.810585,
                                            "lon": 138.616739,
                                            "name": "Africola",
                                            "phone": "(08) 8223 3885",
                                            "status": "active",
                                            "venueImgURL": "https:url"
                                            ,
                                            "barID2":
                                            "address": "138/140 Gouger St, Sydney NSW 2000",
                                            "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                                            "description": "description text",
                                            "imgURLs": ["Https:url1", "https: url2", "https:url3"],
                                            "lat": -34.848082,
                                            "lon": 138.599813,
                                            "name": "Disco Mexico Taqueria",
                                            "phone": "0416 855 108",
                                            "status": "active",
                                            "venueImgURL": "https:url"



                                            let result =
                                            for (let i in data)
                                            result.push(data[i].name)

                                            console.log(result)








                                            share|improve this answer

























                                              1












                                              1








                                              1







                                              Here I use for in to loop each object in your JSON then push the name into the result array.






                                              const data = 
                                              "barID1":
                                              "address": "4 East Terrace, Sydney NSW 2000",
                                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                                              "description": "description text",
                                              "imgURLs": ["Https:url1", "https: url2", "https:url3"],
                                              "lat": -34.810585,
                                              "lon": 138.616739,
                                              "name": "Africola",
                                              "phone": "(08) 8223 3885",
                                              "status": "active",
                                              "venueImgURL": "https:url"
                                              ,
                                              "barID2":
                                              "address": "138/140 Gouger St, Sydney NSW 2000",
                                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                                              "description": "description text",
                                              "imgURLs": ["Https:url1", "https: url2", "https:url3"],
                                              "lat": -34.848082,
                                              "lon": 138.599813,
                                              "name": "Disco Mexico Taqueria",
                                              "phone": "0416 855 108",
                                              "status": "active",
                                              "venueImgURL": "https:url"



                                              let result =
                                              for (let i in data)
                                              result.push(data[i].name)

                                              console.log(result)








                                              share|improve this answer













                                              Here I use for in to loop each object in your JSON then push the name into the result array.






                                              const data = 
                                              "barID1":
                                              "address": "4 East Terrace, Sydney NSW 2000",
                                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                                              "description": "description text",
                                              "imgURLs": ["Https:url1", "https: url2", "https:url3"],
                                              "lat": -34.810585,
                                              "lon": 138.616739,
                                              "name": "Africola",
                                              "phone": "(08) 8223 3885",
                                              "status": "active",
                                              "venueImgURL": "https:url"
                                              ,
                                              "barID2":
                                              "address": "138/140 Gouger St, Sydney NSW 2000",
                                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                                              "description": "description text",
                                              "imgURLs": ["Https:url1", "https: url2", "https:url3"],
                                              "lat": -34.848082,
                                              "lon": 138.599813,
                                              "name": "Disco Mexico Taqueria",
                                              "phone": "0416 855 108",
                                              "status": "active",
                                              "venueImgURL": "https:url"



                                              let result =
                                              for (let i in data)
                                              result.push(data[i].name)

                                              console.log(result)








                                              const data = 
                                              "barID1":
                                              "address": "4 East Terrace, Sydney NSW 2000",
                                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                                              "description": "description text",
                                              "imgURLs": ["Https:url1", "https: url2", "https:url3"],
                                              "lat": -34.810585,
                                              "lon": 138.616739,
                                              "name": "Africola",
                                              "phone": "(08) 8223 3885",
                                              "status": "active",
                                              "venueImgURL": "https:url"
                                              ,
                                              "barID2":
                                              "address": "138/140 Gouger St, Sydney NSW 2000",
                                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                                              "description": "description text",
                                              "imgURLs": ["Https:url1", "https: url2", "https:url3"],
                                              "lat": -34.848082,
                                              "lon": 138.599813,
                                              "name": "Disco Mexico Taqueria",
                                              "phone": "0416 855 108",
                                              "status": "active",
                                              "venueImgURL": "https:url"



                                              let result =
                                              for (let i in data)
                                              result.push(data[i].name)

                                              console.log(result)





                                              const data = 
                                              "barID1":
                                              "address": "4 East Terrace, Sydney NSW 2000",
                                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                                              "description": "description text",
                                              "imgURLs": ["Https:url1", "https: url2", "https:url3"],
                                              "lat": -34.810585,
                                              "lon": 138.616739,
                                              "name": "Africola",
                                              "phone": "(08) 8223 3885",
                                              "status": "active",
                                              "venueImgURL": "https:url"
                                              ,
                                              "barID2":
                                              "address": "138/140 Gouger St, Sydney NSW 2000",
                                              "appStoreURL": "http://itunes.apple.com/app/idXXXXXXXXX",
                                              "description": "description text",
                                              "imgURLs": ["Https:url1", "https: url2", "https:url3"],
                                              "lat": -34.848082,
                                              "lon": 138.599813,
                                              "name": "Disco Mexico Taqueria",
                                              "phone": "0416 855 108",
                                              "status": "active",
                                              "venueImgURL": "https:url"



                                              let result =
                                              for (let i in data)
                                              result.push(data[i].name)

                                              console.log(result)






                                              share|improve this answer












                                              share|improve this answer



                                              share|improve this answer










                                              answered Feb 14 at 4:04









                                              holydragonholydragon

                                              2,49421028




                                              2,49421028



























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