ps command shows user id and not user name
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With Centos 6.6, when I run ps command, the first column is User ID and not user name.
root@cluster:mahmood# ps aux | grep Xvnc
506 11881 0.6 0.1 168580 63164 ? S Jun03 24:56 /usr/bin/Xvnc :6 -desktop cluster.hpc.org:6 (haghsheno) -auth /home/mahmood/.Xauthority -geometry 1000x900 -rfbwait 30000 -rfbauth /home/mahmood/.vnc/passwd -rfbport 5906 -fp catalogue:/etc/X11/fontpath.d -pn
Why such thing happens? and how can I change that to user name?
centos users ps
edited Jun 6 '17 at 15:05
Jeff Schaller
41.4k1056131
asked Jun 6 '17 at 13:59
mahmoodmahmood
3651721
add a comment |
With Centos 6.6, when I run ps command, the first column is User ID and not user name.
root@cluster:mahmood# ps aux | grep Xvnc
506 11881 0.6 0.1 168580 63164 ? S Jun03 24:56 /usr/bin/Xvnc :6 -desktop cluster.hpc.org:6 (haghsheno) -auth /home/mahmood/.Xauthority -geometry 1000x900 -rfbwait 30000 -rfbauth /home/mahmood/.vnc/passwd -rfbport 5906 -fp catalogue:/etc/X11/fontpath.d -pn
Why such thing happens? and how can I change that to user name?
centos users ps
edited Jun 6 '17 at 15:05
Jeff Schaller
41.4k1056131
asked Jun 6 '17 at 13:59
mahmoodmahmood
3651721
2
Is answerd hier why unix.stackexchange.com/questions/363910/…
– user192526
Jun 6 '17 at 14:01
1
Does it show the numeric UID for processes of all users, or just some? Dogetent passwd 506andgetent passwd $usernamework? (I thinkgetentshould lookup by number on CentOS)
– ilkkachu
Jun 6 '17 at 14:19
It shows for some users. As pointed by Bahamut, it seems that the user name length is important!
– mahmood
Jun 6 '17 at 14:21
or maybe you have a numeric username: unix.stackexchange.com/questions/287077/…
– Jeff Schaller
Jun 6 '17 at 15:09
add a comment |
With Centos 6.6, when I run ps command, the first column is User ID and not user name.
root@cluster:mahmood# ps aux | grep Xvnc
506 11881 0.6 0.1 168580 63164 ? S Jun03 24:56 /usr/bin/Xvnc :6 -desktop cluster.hpc.org:6 (haghsheno) -auth /home/mahmood/.Xauthority -geometry 1000x900 -rfbwait 30000 -rfbauth /home/mahmood/.vnc/passwd -rfbport 5906 -fp catalogue:/etc/X11/fontpath.d -pn
Why such thing happens? and how can I change that to user name?
centos users ps
edited Jun 6 '17 at 15:05
Jeff Schaller
41.4k1056131
asked Jun 6 '17 at 13:59
mahmoodmahmood
3651721
With Centos 6.6, when I run ps command, the first column is User ID and not user name.
root@cluster:mahmood# ps aux | grep Xvnc
506 11881 0.6 0.1 168580 63164 ? S Jun03 24:56 /usr/bin/Xvnc :6 -desktop cluster.hpc.org:6 (haghsheno) -auth /home/mahmood/.Xauthority -geometry 1000x900 -rfbwait 30000 -rfbauth /home/mahmood/.vnc/passwd -rfbport 5906 -fp catalogue:/etc/X11/fontpath.d -pn
Why such thing happens? and how can I change that to user name?
centos users ps
centos users ps
edited Jun 6 '17 at 15:05
Jeff Schaller
41.4k1056131
asked Jun 6 '17 at 13:59
mahmoodmahmood
3651721
edited Jun 6 '17 at 15:05
Jeff Schaller
41.4k1056131
asked Jun 6 '17 at 13:59
mahmoodmahmood
3651721
edited Jun 6 '17 at 15:05
Jeff Schaller
41.4k1056131
edited Jun 6 '17 at 15:05
Jeff Schaller
41.4k1056131
edited Jun 6 '17 at 15:05
Jeff Schaller
41.4k1056131
41.4k1056131
asked Jun 6 '17 at 13:59
mahmoodmahmood
3651721
asked Jun 6 '17 at 13:59
mahmoodmahmood
3651721
asked Jun 6 '17 at 13:59
mahmoodmahmood
3651721
3651721
2
Is answerd hier why unix.stackexchange.com/questions/363910/…
– user192526
Jun 6 '17 at 14:01
1
Does it show the numeric UID for processes of all users, or just some? Dogetent passwd 506andgetent passwd $usernamework? (I thinkgetentshould lookup by number on CentOS)
– ilkkachu
Jun 6 '17 at 14:19
It shows for some users. As pointed by Bahamut, it seems that the user name length is important!
– mahmood
Jun 6 '17 at 14:21
or maybe you have a numeric username: unix.stackexchange.com/questions/287077/…
– Jeff Schaller
Jun 6 '17 at 15:09
add a comment |
2
Is answerd hier why unix.stackexchange.com/questions/363910/…
– user192526
Jun 6 '17 at 14:01
1
Does it show the numeric UID for processes of all users, or just some? Dogetent passwd 506andgetent passwd $usernamework? (I thinkgetentshould lookup by number on CentOS)
– ilkkachu
Jun 6 '17 at 14:19
It shows for some users. As pointed by Bahamut, it seems that the user name length is important!
– mahmood
Jun 6 '17 at 14:21
or maybe you have a numeric username: unix.stackexchange.com/questions/287077/…
– Jeff Schaller
Jun 6 '17 at 15:09
2
2
Is answerd hier why unix.stackexchange.com/questions/363910/…
– user192526
Jun 6 '17 at 14:01
Is answerd hier why unix.stackexchange.com/questions/363910/…
– user192526
Jun 6 '17 at 14:01
1
1
Does it show the numeric UID for processes of all users, or just some? Do
getent passwd 506 and getent passwd $username work? (I think getent should lookup by number on CentOS)– ilkkachu
Jun 6 '17 at 14:19
Does it show the numeric UID for processes of all users, or just some? Do
getent passwd 506 and getent passwd $username work? (I think getent should lookup by number on CentOS)– ilkkachu
Jun 6 '17 at 14:19
It shows for some users. As pointed by Bahamut, it seems that the user name length is important!
– mahmood
Jun 6 '17 at 14:21
It shows for some users. As pointed by Bahamut, it seems that the user name length is important!
– mahmood
Jun 6 '17 at 14:21
or maybe you have a numeric username: unix.stackexchange.com/questions/287077/…
– Jeff Schaller
Jun 6 '17 at 15:09
or maybe you have a numeric username: unix.stackexchange.com/questions/287077/…
– Jeff Schaller
Jun 6 '17 at 15:09
add a comment |
2 Answers
2
active
oldest
votes
If the id is not inside passwd (grep 506 /etc/passwd) there is no username to display.
In this case add an corresponding entry inside /etc/passwd.
EDIT
As mentioned by Jeff Schaller and KevinO:
This answer isn't quite complete! It's better to locate these lines from /etc/passwd, whose third field ($3, separated by colon -F:) contains exactly the value of 506. See first comment from Jeff. My simple example above would show lines containing username yx506, id 123506, and so on.
But anyway: if the userid is missing inside /etc/passwd, this answer could be a solution.
I'll try to be more concrete in future ...
edited Jun 6 '17 at 15:35
Jeff Schaller
41.4k1056131
answered Jun 6 '17 at 14:10
ChristophSChristophS
40329
orawk -F: '$3 == 506' /etc/passwdorgetent passwd | awk -F: '$3 == 506'
– Jeff Schaller
Jun 6 '17 at 15:08
Yes, my example could result in more than just one line. Wanted to keep it simple ... ;) Thanks anyway!
– ChristophS
Jun 6 '17 at 15:12
This answer isn't quite complete, as an entry may be in/etc/passwdbut still not display the textual user name. As an example, I have fromps -efa line of :68 1964 1 0 May17 ? 00:00:30 hald(so it is showing the numeric id; most other lines have "root" or "apache" showing), butgrep 68 /etc/passwdgiveshaldaemon:x:68:68:HAL daemon:/:/sbin/nologin.
– KevinO
Jun 6 '17 at 15:16
userid 1506, username tax506, gid 5061, etc etc etc
– Jeff Schaller
Jun 6 '17 at 15:19
@Jeff/Kevin: I hope the edit is acceptable for you ...
– ChristophS
Jun 6 '17 at 15:33
|
show 2 more comments
Unfortunately the default ps does not display a username if the username is longer than 8 chars. If your system is running sssd with LDAP you can use "getent passwd userid" to find the user if they are in the LDAP database or the password file. My username "tvb" almost always shows up. However the username "flonglastname" would not in most cases. Other commands like "w" will show the first 8 chars "flonglas" and truncate the remaining. In the example by @KevinO above, "haldaemon" is 9 chars so that's why it doesn't appear in ps as a username, but a userid instead.
% getent passwd haldaemon
haldaemon:x:68:68:HAL daemon:/:/sbin/nologin
Also, the answer at blog.dbi-services.com helps with a way to specify the field length of the username field even in BSD format ps output. Simplifying their suggestion a little gives:
env PS_FORMAT='user:12,pid,%cpu,%mem,vsz,rss,tty,stat,start,time,command' ps ax | grep haldaemon
haldaemon 2032 0.0 0.0 53100 2020 ? Ssl Aug 12 00:01:10 hald
Which provides the desired output.
answered Jan 25 at 21:57
The Veritable BugeaterThe Veritable Bugeater
11
You know that you don’t need to useenvto run a command with a customized environment, right?
– G-Man
Jan 25 at 22:51
add a comment |
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2 Answers
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active
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votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
If the id is not inside passwd (grep 506 /etc/passwd) there is no username to display.
In this case add an corresponding entry inside /etc/passwd.
EDIT
As mentioned by Jeff Schaller and KevinO:
This answer isn't quite complete! It's better to locate these lines from /etc/passwd, whose third field ($3, separated by colon -F:) contains exactly the value of 506. See first comment from Jeff. My simple example above would show lines containing username yx506, id 123506, and so on.
But anyway: if the userid is missing inside /etc/passwd, this answer could be a solution.
I'll try to be more concrete in future ...
edited Jun 6 '17 at 15:35
Jeff Schaller
41.4k1056131
answered Jun 6 '17 at 14:10
ChristophSChristophS
40329
orawk -F: '$3 == 506' /etc/passwdorgetent passwd | awk -F: '$3 == 506'
– Jeff Schaller
Jun 6 '17 at 15:08
Yes, my example could result in more than just one line. Wanted to keep it simple ... ;) Thanks anyway!
– ChristophS
Jun 6 '17 at 15:12
This answer isn't quite complete, as an entry may be in/etc/passwdbut still not display the textual user name. As an example, I have fromps -efa line of :68 1964 1 0 May17 ? 00:00:30 hald(so it is showing the numeric id; most other lines have "root" or "apache" showing), butgrep 68 /etc/passwdgiveshaldaemon:x:68:68:HAL daemon:/:/sbin/nologin.
– KevinO
Jun 6 '17 at 15:16
userid 1506, username tax506, gid 5061, etc etc etc
– Jeff Schaller
Jun 6 '17 at 15:19
@Jeff/Kevin: I hope the edit is acceptable for you ...
– ChristophS
Jun 6 '17 at 15:33
|
show 2 more comments
If the id is not inside passwd (grep 506 /etc/passwd) there is no username to display.
In this case add an corresponding entry inside /etc/passwd.
EDIT
As mentioned by Jeff Schaller and KevinO:
This answer isn't quite complete! It's better to locate these lines from /etc/passwd, whose third field ($3, separated by colon -F:) contains exactly the value of 506. See first comment from Jeff. My simple example above would show lines containing username yx506, id 123506, and so on.
But anyway: if the userid is missing inside /etc/passwd, this answer could be a solution.
I'll try to be more concrete in future ...
edited Jun 6 '17 at 15:35
Jeff Schaller
41.4k1056131
answered Jun 6 '17 at 14:10
ChristophSChristophS
40329
orawk -F: '$3 == 506' /etc/passwdorgetent passwd | awk -F: '$3 == 506'
– Jeff Schaller
Jun 6 '17 at 15:08
Yes, my example could result in more than just one line. Wanted to keep it simple ... ;) Thanks anyway!
– ChristophS
Jun 6 '17 at 15:12
This answer isn't quite complete, as an entry may be in/etc/passwdbut still not display the textual user name. As an example, I have fromps -efa line of :68 1964 1 0 May17 ? 00:00:30 hald(so it is showing the numeric id; most other lines have "root" or "apache" showing), butgrep 68 /etc/passwdgiveshaldaemon:x:68:68:HAL daemon:/:/sbin/nologin.
– KevinO
Jun 6 '17 at 15:16
userid 1506, username tax506, gid 5061, etc etc etc
– Jeff Schaller
Jun 6 '17 at 15:19
@Jeff/Kevin: I hope the edit is acceptable for you ...
– ChristophS
Jun 6 '17 at 15:33
|
show 2 more comments
If the id is not inside passwd (grep 506 /etc/passwd) there is no username to display.
In this case add an corresponding entry inside /etc/passwd.
EDIT
As mentioned by Jeff Schaller and KevinO:
This answer isn't quite complete! It's better to locate these lines from /etc/passwd, whose third field ($3, separated by colon -F:) contains exactly the value of 506. See first comment from Jeff. My simple example above would show lines containing username yx506, id 123506, and so on.
But anyway: if the userid is missing inside /etc/passwd, this answer could be a solution.
I'll try to be more concrete in future ...
edited Jun 6 '17 at 15:35
Jeff Schaller
41.4k1056131
answered Jun 6 '17 at 14:10
ChristophSChristophS
40329
If the id is not inside passwd (grep 506 /etc/passwd) there is no username to display.
In this case add an corresponding entry inside /etc/passwd.
EDIT
As mentioned by Jeff Schaller and KevinO:
This answer isn't quite complete! It's better to locate these lines from /etc/passwd, whose third field ($3, separated by colon -F:) contains exactly the value of 506. See first comment from Jeff. My simple example above would show lines containing username yx506, id 123506, and so on.
But anyway: if the userid is missing inside /etc/passwd, this answer could be a solution.
I'll try to be more concrete in future ...
edited Jun 6 '17 at 15:35
Jeff Schaller
41.4k1056131
answered Jun 6 '17 at 14:10
ChristophSChristophS
40329
edited Jun 6 '17 at 15:35
Jeff Schaller
41.4k1056131
edited Jun 6 '17 at 15:35
Jeff Schaller
41.4k1056131
edited Jun 6 '17 at 15:35
Jeff Schaller
41.4k1056131
41.4k1056131
answered Jun 6 '17 at 14:10
ChristophSChristophS
40329
answered Jun 6 '17 at 14:10
ChristophSChristophS
40329
answered Jun 6 '17 at 14:10
ChristophSChristophS
40329
40329
orawk -F: '$3 == 506' /etc/passwdorgetent passwd | awk -F: '$3 == 506'
– Jeff Schaller
Jun 6 '17 at 15:08
Yes, my example could result in more than just one line. Wanted to keep it simple ... ;) Thanks anyway!
– ChristophS
Jun 6 '17 at 15:12
This answer isn't quite complete, as an entry may be in/etc/passwdbut still not display the textual user name. As an example, I have fromps -efa line of :68 1964 1 0 May17 ? 00:00:30 hald(so it is showing the numeric id; most other lines have "root" or "apache" showing), butgrep 68 /etc/passwdgiveshaldaemon:x:68:68:HAL daemon:/:/sbin/nologin.
– KevinO
Jun 6 '17 at 15:16
userid 1506, username tax506, gid 5061, etc etc etc
– Jeff Schaller
Jun 6 '17 at 15:19
@Jeff/Kevin: I hope the edit is acceptable for you ...
– ChristophS
Jun 6 '17 at 15:33
|
show 2 more comments
orawk -F: '$3 == 506' /etc/passwdorgetent passwd | awk -F: '$3 == 506'
– Jeff Schaller
Jun 6 '17 at 15:08
Yes, my example could result in more than just one line. Wanted to keep it simple ... ;) Thanks anyway!
– ChristophS
Jun 6 '17 at 15:12
This answer isn't quite complete, as an entry may be in/etc/passwdbut still not display the textual user name. As an example, I have fromps -efa line of :68 1964 1 0 May17 ? 00:00:30 hald(so it is showing the numeric id; most other lines have "root" or "apache" showing), butgrep 68 /etc/passwdgiveshaldaemon:x:68:68:HAL daemon:/:/sbin/nologin.
– KevinO
Jun 6 '17 at 15:16
userid 1506, username tax506, gid 5061, etc etc etc
– Jeff Schaller
Jun 6 '17 at 15:19
@Jeff/Kevin: I hope the edit is acceptable for you ...
– ChristophS
Jun 6 '17 at 15:33
or
awk -F: '$3 == 506' /etc/passwd or getent passwd | awk -F: '$3 == 506'– Jeff Schaller
Jun 6 '17 at 15:08
or
awk -F: '$3 == 506' /etc/passwd or getent passwd | awk -F: '$3 == 506'– Jeff Schaller
Jun 6 '17 at 15:08
Yes, my example could result in more than just one line. Wanted to keep it simple ... ;) Thanks anyway!
– ChristophS
Jun 6 '17 at 15:12
Yes, my example could result in more than just one line. Wanted to keep it simple ... ;) Thanks anyway!
– ChristophS
Jun 6 '17 at 15:12
This answer isn't quite complete, as an entry may be in
/etc/passwd but still not display the textual user name. As an example, I have from ps -ef a line of :68 1964 1 0 May17 ? 00:00:30 hald (so it is showing the numeric id; most other lines have "root" or "apache" showing), but grep 68 /etc/passwd gives haldaemon:x:68:68:HAL daemon:/:/sbin/nologin.– KevinO
Jun 6 '17 at 15:16
This answer isn't quite complete, as an entry may be in
/etc/passwd but still not display the textual user name. As an example, I have from ps -ef a line of :68 1964 1 0 May17 ? 00:00:30 hald (so it is showing the numeric id; most other lines have "root" or "apache" showing), but grep 68 /etc/passwd gives haldaemon:x:68:68:HAL daemon:/:/sbin/nologin.– KevinO
Jun 6 '17 at 15:16
userid 1506, username tax506, gid 5061, etc etc etc
– Jeff Schaller
Jun 6 '17 at 15:19
userid 1506, username tax506, gid 5061, etc etc etc
– Jeff Schaller
Jun 6 '17 at 15:19
@Jeff/Kevin: I hope the edit is acceptable for you ...
– ChristophS
Jun 6 '17 at 15:33
@Jeff/Kevin: I hope the edit is acceptable for you ...
– ChristophS
Jun 6 '17 at 15:33
|
show 2 more comments
Unfortunately the default ps does not display a username if the username is longer than 8 chars. If your system is running sssd with LDAP you can use "getent passwd userid" to find the user if they are in the LDAP database or the password file. My username "tvb" almost always shows up. However the username "flonglastname" would not in most cases. Other commands like "w" will show the first 8 chars "flonglas" and truncate the remaining. In the example by @KevinO above, "haldaemon" is 9 chars so that's why it doesn't appear in ps as a username, but a userid instead.
% getent passwd haldaemon
haldaemon:x:68:68:HAL daemon:/:/sbin/nologin
Also, the answer at blog.dbi-services.com helps with a way to specify the field length of the username field even in BSD format ps output. Simplifying their suggestion a little gives:
env PS_FORMAT='user:12,pid,%cpu,%mem,vsz,rss,tty,stat,start,time,command' ps ax | grep haldaemon
haldaemon 2032 0.0 0.0 53100 2020 ? Ssl Aug 12 00:01:10 hald
Which provides the desired output.
answered Jan 25 at 21:57
The Veritable BugeaterThe Veritable Bugeater
11
You know that you don’t need to useenvto run a command with a customized environment, right?
– G-Man
Jan 25 at 22:51
add a comment |
Unfortunately the default ps does not display a username if the username is longer than 8 chars. If your system is running sssd with LDAP you can use "getent passwd userid" to find the user if they are in the LDAP database or the password file. My username "tvb" almost always shows up. However the username "flonglastname" would not in most cases. Other commands like "w" will show the first 8 chars "flonglas" and truncate the remaining. In the example by @KevinO above, "haldaemon" is 9 chars so that's why it doesn't appear in ps as a username, but a userid instead.
% getent passwd haldaemon
haldaemon:x:68:68:HAL daemon:/:/sbin/nologin
Also, the answer at blog.dbi-services.com helps with a way to specify the field length of the username field even in BSD format ps output. Simplifying their suggestion a little gives:
env PS_FORMAT='user:12,pid,%cpu,%mem,vsz,rss,tty,stat,start,time,command' ps ax | grep haldaemon
haldaemon 2032 0.0 0.0 53100 2020 ? Ssl Aug 12 00:01:10 hald
Which provides the desired output.
answered Jan 25 at 21:57
The Veritable BugeaterThe Veritable Bugeater
11
You know that you don’t need to useenvto run a command with a customized environment, right?
– G-Man
Jan 25 at 22:51
add a comment |
Unfortunately the default ps does not display a username if the username is longer than 8 chars. If your system is running sssd with LDAP you can use "getent passwd userid" to find the user if they are in the LDAP database or the password file. My username "tvb" almost always shows up. However the username "flonglastname" would not in most cases. Other commands like "w" will show the first 8 chars "flonglas" and truncate the remaining. In the example by @KevinO above, "haldaemon" is 9 chars so that's why it doesn't appear in ps as a username, but a userid instead.
% getent passwd haldaemon
haldaemon:x:68:68:HAL daemon:/:/sbin/nologin
Also, the answer at blog.dbi-services.com helps with a way to specify the field length of the username field even in BSD format ps output. Simplifying their suggestion a little gives:
env PS_FORMAT='user:12,pid,%cpu,%mem,vsz,rss,tty,stat,start,time,command' ps ax | grep haldaemon
haldaemon 2032 0.0 0.0 53100 2020 ? Ssl Aug 12 00:01:10 hald
Which provides the desired output.
answered Jan 25 at 21:57
The Veritable BugeaterThe Veritable Bugeater
11
Unfortunately the default ps does not display a username if the username is longer than 8 chars. If your system is running sssd with LDAP you can use "getent passwd userid" to find the user if they are in the LDAP database or the password file. My username "tvb" almost always shows up. However the username "flonglastname" would not in most cases. Other commands like "w" will show the first 8 chars "flonglas" and truncate the remaining. In the example by @KevinO above, "haldaemon" is 9 chars so that's why it doesn't appear in ps as a username, but a userid instead.
% getent passwd haldaemon
haldaemon:x:68:68:HAL daemon:/:/sbin/nologin
Also, the answer at blog.dbi-services.com helps with a way to specify the field length of the username field even in BSD format ps output. Simplifying their suggestion a little gives:
env PS_FORMAT='user:12,pid,%cpu,%mem,vsz,rss,tty,stat,start,time,command' ps ax | grep haldaemon
haldaemon 2032 0.0 0.0 53100 2020 ? Ssl Aug 12 00:01:10 hald
Which provides the desired output.
answered Jan 25 at 21:57
The Veritable BugeaterThe Veritable Bugeater
11
edited Jan 25 at 22:36
answered Jan 25 at 21:57
The Veritable BugeaterThe Veritable Bugeater
11
answered Jan 25 at 21:57
The Veritable BugeaterThe Veritable Bugeater
11
answered Jan 25 at 21:57
The Veritable BugeaterThe Veritable Bugeater
11
11
You know that you don’t need to useenvto run a command with a customized environment, right?
– G-Man
Jan 25 at 22:51
add a comment |
You know that you don’t need to useenvto run a command with a customized environment, right?
– G-Man
Jan 25 at 22:51
You know that you don’t need to use
env to run a command with a customized environment, right?– G-Man
Jan 25 at 22:51
You know that you don’t need to use
env to run a command with a customized environment, right?– G-Man
Jan 25 at 22:51
add a comment |
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2
Is answerd hier why unix.stackexchange.com/questions/363910/…
– user192526
Jun 6 '17 at 14:01
1
Does it show the numeric UID for processes of all users, or just some? Do
getent passwd 506andgetent passwd $usernamework? (I thinkgetentshould lookup by number on CentOS)– ilkkachu
Jun 6 '17 at 14:19
It shows for some users. As pointed by Bahamut, it seems that the user name length is important!
– mahmood
Jun 6 '17 at 14:21
or maybe you have a numeric username: unix.stackexchange.com/questions/287077/…
– Jeff Schaller
Jun 6 '17 at 15:09