mjhjmtu

You really should not parse the output of ls. If this is a homework assignment and you are required to, your professor does not know what they're talking about. Why don't you do something like this:

The good...

find ./ -printf "%fn"

or

for n in *; do printf '%sn' "$n"; done

...the bad...

If you really really want to use ls, you can make it a little bit more robust by doing something like this:

ls -lA | awk -F':[0-9]* ' '/:/print $2'

...and the ugly

If you insist on doing it the wrong, dangerous way and just have to use a while loop, do this:

ls -Al | while IFS= read -r string; do echo "$string" | 
 awk -F':[0-9]* ' '/:/print $2'; done

Seriously though, just don't.

Is there some reason that ls -A1* won't work?

E.g.:

$ touch file1 file2 file with spaces
$ ls -Al
total 0
-rw-r--r-- 1 bahamat bahamat 0 Mar 30 22:31 file1
-rw-r--r-- 1 bahamat bahamat 0 Mar 30 22:31 file2
-rw-r--r-- 1 bahamat bahamat 0 Mar 30 22:31 file with spaces
$ ls -A1
file1
file2
file with spaces
$

* Note: that's a capital letter A and the number one.

I wonder why no one mentioned this simple command:

ls -a | sort

You cannot parse the output of ls, let alone ls -l because newline, just like space is as valid a character as any in a filename. Also, you'll need to consider symlinks that have an output like ... foo -> bar.

Why would you use -l anyway if you only want the file name?

Just do:

for file in *; do
 ...
done

If you want to include dot files (except . and ..), depending on the shell:

zsh:

for file in *(ND); do
 ...
done

bash:

shopt -s nullglob dotglob
for file in *; do
 ...
done

ksh93:

FIGNORE='@(.|..)'
for file in ~(N)*; do
 ...
done

POSIXly:

for file in .[!.]* ..?* *; do
 [ -e "$file" ] || [ -L "$file" ] || continue
 ...
done

How about:

for file in * .[!.]*
do
 printf "%sn" "$file"
done

ls -Al | tr -s ' ' | cut -f9- -d' '

compress multiple spaces into single spaces with tr then you can use cut to split on the fields

Try (bash, zsh, ksh93 syntax):

find . -type f -print0 | while IFS= read -r -d '' filename; do
 ...
done

This goes recursive and lists only on normal files (i.e. no dirs or symlinks/fifos/devices...).

See also:

• List only regular files (but not directories) in current directory


• 
  Why you shouldn't parse the output of ls(1) at wooledge wiki


• 
  Why not parse ls? at unix SE

try ls -1

Thats Integer 1

From man page.

 ls -1 list one file per line. Avoid 'n' with -q or -b

ls --file *|grep ^ 

it displays what files under what directory.