Drawing a Tank with Water in it
Clash Royale CLAN TAG#URR8PPP
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I am trying to draw a cylindrical tank that has water in it, using tikz. Here is what I have so far:
documentclass[a4paper, 12pt]article
usepackagepgfplots
pgfplotssetcompat=1.15
usepgfplotslibrarypolar
usepgflibraryshapes.geometric
usetikzlibrarycalc
begindocument
beginfigure[ht]
centering
begintikzpicture
node[draw, cylinder, rotate=90, shape aspect=4, minimum height=4cm, minimum
width=8cm, fill = blue, fill opacity = 0.2, blue] ;
node[draw, cylinder, rotate=90, shape aspect=4, minimum height=6cm, minimum
width=8cm, thick] (A) ;
draw[dashed, thick]
let p1 = ($ (A.after bottom) - (A.before bottom) $),
n1 = 0.5*veclen(x1,y1)-pgflinewidth,
p2 = ($ (A.bottom) - (A.after bottom)!.5!(A.before bottom) $),
n2 = veclen(x2,y2)-pgflinewidth
in
([xshift=-pgflinewidth] A.before bottom) arc [start angle=0, end
angle=180,
x radius=n1, y radius=n2];
endtikzpicture
captionThe tank.
labelfig:tank
endfigure
enddocument
This is the result:
I want the blue part to be shifted down so that it is at the same level as the bottom of the black one.
Any suggestions to this solution, or to making my code more efficient, would be great!
tikz-pgf draw shapes
add a comment |
up vote
7
down vote
favorite
I am trying to draw a cylindrical tank that has water in it, using tikz. Here is what I have so far:
documentclass[a4paper, 12pt]article
usepackagepgfplots
pgfplotssetcompat=1.15
usepgfplotslibrarypolar
usepgflibraryshapes.geometric
usetikzlibrarycalc
begindocument
beginfigure[ht]
centering
begintikzpicture
node[draw, cylinder, rotate=90, shape aspect=4, minimum height=4cm, minimum
width=8cm, fill = blue, fill opacity = 0.2, blue] ;
node[draw, cylinder, rotate=90, shape aspect=4, minimum height=6cm, minimum
width=8cm, thick] (A) ;
draw[dashed, thick]
let p1 = ($ (A.after bottom) - (A.before bottom) $),
n1 = 0.5*veclen(x1,y1)-pgflinewidth,
p2 = ($ (A.bottom) - (A.after bottom)!.5!(A.before bottom) $),
n2 = veclen(x2,y2)-pgflinewidth
in
([xshift=-pgflinewidth] A.before bottom) arc [start angle=0, end
angle=180,
x radius=n1, y radius=n2];
endtikzpicture
captionThe tank.
labelfig:tank
endfigure
enddocument
This is the result:
I want the blue part to be shifted down so that it is at the same level as the bottom of the black one.
Any suggestions to this solution, or to making my code more efficient, would be great!
tikz-pgf draw shapes
add a comment |
up vote
7
down vote
favorite
up vote
7
down vote
favorite
I am trying to draw a cylindrical tank that has water in it, using tikz. Here is what I have so far:
documentclass[a4paper, 12pt]article
usepackagepgfplots
pgfplotssetcompat=1.15
usepgfplotslibrarypolar
usepgflibraryshapes.geometric
usetikzlibrarycalc
begindocument
beginfigure[ht]
centering
begintikzpicture
node[draw, cylinder, rotate=90, shape aspect=4, minimum height=4cm, minimum
width=8cm, fill = blue, fill opacity = 0.2, blue] ;
node[draw, cylinder, rotate=90, shape aspect=4, minimum height=6cm, minimum
width=8cm, thick] (A) ;
draw[dashed, thick]
let p1 = ($ (A.after bottom) - (A.before bottom) $),
n1 = 0.5*veclen(x1,y1)-pgflinewidth,
p2 = ($ (A.bottom) - (A.after bottom)!.5!(A.before bottom) $),
n2 = veclen(x2,y2)-pgflinewidth
in
([xshift=-pgflinewidth] A.before bottom) arc [start angle=0, end
angle=180,
x radius=n1, y radius=n2];
endtikzpicture
captionThe tank.
labelfig:tank
endfigure
enddocument
This is the result:
I want the blue part to be shifted down so that it is at the same level as the bottom of the black one.
Any suggestions to this solution, or to making my code more efficient, would be great!
tikz-pgf draw shapes
I am trying to draw a cylindrical tank that has water in it, using tikz. Here is what I have so far:
documentclass[a4paper, 12pt]article
usepackagepgfplots
pgfplotssetcompat=1.15
usepgfplotslibrarypolar
usepgflibraryshapes.geometric
usetikzlibrarycalc
begindocument
beginfigure[ht]
centering
begintikzpicture
node[draw, cylinder, rotate=90, shape aspect=4, minimum height=4cm, minimum
width=8cm, fill = blue, fill opacity = 0.2, blue] ;
node[draw, cylinder, rotate=90, shape aspect=4, minimum height=6cm, minimum
width=8cm, thick] (A) ;
draw[dashed, thick]
let p1 = ($ (A.after bottom) - (A.before bottom) $),
n1 = 0.5*veclen(x1,y1)-pgflinewidth,
p2 = ($ (A.bottom) - (A.after bottom)!.5!(A.before bottom) $),
n2 = veclen(x2,y2)-pgflinewidth
in
([xshift=-pgflinewidth] A.before bottom) arc [start angle=0, end
angle=180,
x radius=n1, y radius=n2];
endtikzpicture
captionThe tank.
labelfig:tank
endfigure
enddocument
This is the result:
I want the blue part to be shifted down so that it is at the same level as the bottom of the black one.
Any suggestions to this solution, or to making my code more efficient, would be great!
tikz-pgf draw shapes
tikz-pgf draw shapes
asked Dec 2 at 2:59
Aiden Kenny
1465
1465
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add a comment |
3 Answers
3
active
oldest
votes
up vote
7
down vote
you need to define anchors of your cylinders at their bottoms ...
documentclass[a4paper, 12pt]article
%usepackagepgfplots
%pgfplotssetcompat=1.15
%usepgfplotslibrarypolar
usepackagetikz
usetikzlibrarycalc,
positioning,
shapes.geometric
begindocument
beginfigure[ht]
centering
begintikzpicture[
node distance = 0pt,
valj/.style args = #1/#2draw, cylinder, shape aspect=4, shape border rotate=90,
fill=#2, fill opacity=0.2,
minimum height=#1, minimum width=8cm,
outer sep=0pt, anchor=bottom, % <--- added
node contents=
]
node (A) [valj=60mm/white];
node (B) [valj=40mm/blue,
above=of A.bottom]; % <--- positioning of cylinder
draw[dashed]
let p1 = ($ (A.after bottom) - (A.before bottom) $),
n1 = 0.5*veclen(x1,y1)-pgflinewidth,
p2 = ($ (A.bottom) - (A.after bottom)!.5!(A.before bottom) $),
n2 = veclen(x2,y2)
in (A.before bottom) arc [start angle=0, end angle=180,
x radius=n1, y radius=n2];
endtikzpicture
captionThe tank.
labelfig:tank
endfigure
enddocument
add a comment |
up vote
7
down vote
I would use tikz-3dplot
for it, in particular if you are considering adding more 3d-like elements. The following has 4 parameters, one view angle which is set to 100
, a radius R
, the height of the water HW
and the height of the cylinder HC
.
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usepgflibraryshapes.geometric
usetikzlibrarycalc
begindocument
tdplotsetmaincoords1000
begintikzpicture[tdplot_main_coords]
pgfmathsetmacroR4
pgfmathsetmacroHW4
pgfmathsetmacroHC6
% water
fill[blue!40] plot[variable=x,domain=0:180,smooth] (R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth] (R*cos(x),R*sin(x),HW)
-- cycle;
draw[blue] plot[variable=x,domain=0:360,smooth,samples=51]
(R*cos(x),R*sin(x),HW);
% "invisible" lined
draw[dashed] plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),0);
% visible cylinder lines
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),HC) -- cycle;
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),HC);
endtikzpicture
enddocument
The meaning of the view angle
is illustrated by this animation.
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usepgflibraryshapes.geometric
usetikzlibrarycalc
begindocument
foreach X in 0,10,...,350
tdplotsetmaincoords120+30*sin(X)0
begintikzpicture
pgfmathsetmacroR4
pgfmathsetmacroHW4
pgfmathsetmacroHC6
path[use as bounding box] (-1.1*R,-0.75*HC) rectangle (1.1*R,1.25*HC);
beginscope[tdplot_main_coords]
% water
fill[blue!40] plot[variable=x,domain=0:180,smooth] (R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth] (R*cos(x),R*sin(x),HW)
-- cycle;
draw[blue] plot[variable=x,domain=0:360,smooth,samples=51]
(R*cos(x),R*sin(x),HW);
% "invisible" lined
draw[dashed] plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),0);
% visible cylinder lines
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),HC) -- cycle;
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),HC);
endscope
endtikzpicture
enddocument
add a comment |
up vote
2
down vote
I have figured out a solution. In the square brackets containing the parameters for the first cylinder (the one drawing the water), we need only add xshift = -0.75cm
. Since the height of the outer cylinder is 6cm and the height of the inner is 4.5cm, so the difference in height is 1.5cm. Since both cylinders are centered at the same spot, the height of the gaps above and below the blue are 0.75cm each, so we just have to shift it down that distance. I was at first curious as to yshift
did not work, but then I realized that the cylinder is rotated in the beginning by 90 degrees, so that is probably the reason.
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
7
down vote
you need to define anchors of your cylinders at their bottoms ...
documentclass[a4paper, 12pt]article
%usepackagepgfplots
%pgfplotssetcompat=1.15
%usepgfplotslibrarypolar
usepackagetikz
usetikzlibrarycalc,
positioning,
shapes.geometric
begindocument
beginfigure[ht]
centering
begintikzpicture[
node distance = 0pt,
valj/.style args = #1/#2draw, cylinder, shape aspect=4, shape border rotate=90,
fill=#2, fill opacity=0.2,
minimum height=#1, minimum width=8cm,
outer sep=0pt, anchor=bottom, % <--- added
node contents=
]
node (A) [valj=60mm/white];
node (B) [valj=40mm/blue,
above=of A.bottom]; % <--- positioning of cylinder
draw[dashed]
let p1 = ($ (A.after bottom) - (A.before bottom) $),
n1 = 0.5*veclen(x1,y1)-pgflinewidth,
p2 = ($ (A.bottom) - (A.after bottom)!.5!(A.before bottom) $),
n2 = veclen(x2,y2)
in (A.before bottom) arc [start angle=0, end angle=180,
x radius=n1, y radius=n2];
endtikzpicture
captionThe tank.
labelfig:tank
endfigure
enddocument
add a comment |
up vote
7
down vote
you need to define anchors of your cylinders at their bottoms ...
documentclass[a4paper, 12pt]article
%usepackagepgfplots
%pgfplotssetcompat=1.15
%usepgfplotslibrarypolar
usepackagetikz
usetikzlibrarycalc,
positioning,
shapes.geometric
begindocument
beginfigure[ht]
centering
begintikzpicture[
node distance = 0pt,
valj/.style args = #1/#2draw, cylinder, shape aspect=4, shape border rotate=90,
fill=#2, fill opacity=0.2,
minimum height=#1, minimum width=8cm,
outer sep=0pt, anchor=bottom, % <--- added
node contents=
]
node (A) [valj=60mm/white];
node (B) [valj=40mm/blue,
above=of A.bottom]; % <--- positioning of cylinder
draw[dashed]
let p1 = ($ (A.after bottom) - (A.before bottom) $),
n1 = 0.5*veclen(x1,y1)-pgflinewidth,
p2 = ($ (A.bottom) - (A.after bottom)!.5!(A.before bottom) $),
n2 = veclen(x2,y2)
in (A.before bottom) arc [start angle=0, end angle=180,
x radius=n1, y radius=n2];
endtikzpicture
captionThe tank.
labelfig:tank
endfigure
enddocument
add a comment |
up vote
7
down vote
up vote
7
down vote
you need to define anchors of your cylinders at their bottoms ...
documentclass[a4paper, 12pt]article
%usepackagepgfplots
%pgfplotssetcompat=1.15
%usepgfplotslibrarypolar
usepackagetikz
usetikzlibrarycalc,
positioning,
shapes.geometric
begindocument
beginfigure[ht]
centering
begintikzpicture[
node distance = 0pt,
valj/.style args = #1/#2draw, cylinder, shape aspect=4, shape border rotate=90,
fill=#2, fill opacity=0.2,
minimum height=#1, minimum width=8cm,
outer sep=0pt, anchor=bottom, % <--- added
node contents=
]
node (A) [valj=60mm/white];
node (B) [valj=40mm/blue,
above=of A.bottom]; % <--- positioning of cylinder
draw[dashed]
let p1 = ($ (A.after bottom) - (A.before bottom) $),
n1 = 0.5*veclen(x1,y1)-pgflinewidth,
p2 = ($ (A.bottom) - (A.after bottom)!.5!(A.before bottom) $),
n2 = veclen(x2,y2)
in (A.before bottom) arc [start angle=0, end angle=180,
x radius=n1, y radius=n2];
endtikzpicture
captionThe tank.
labelfig:tank
endfigure
enddocument
you need to define anchors of your cylinders at their bottoms ...
documentclass[a4paper, 12pt]article
%usepackagepgfplots
%pgfplotssetcompat=1.15
%usepgfplotslibrarypolar
usepackagetikz
usetikzlibrarycalc,
positioning,
shapes.geometric
begindocument
beginfigure[ht]
centering
begintikzpicture[
node distance = 0pt,
valj/.style args = #1/#2draw, cylinder, shape aspect=4, shape border rotate=90,
fill=#2, fill opacity=0.2,
minimum height=#1, minimum width=8cm,
outer sep=0pt, anchor=bottom, % <--- added
node contents=
]
node (A) [valj=60mm/white];
node (B) [valj=40mm/blue,
above=of A.bottom]; % <--- positioning of cylinder
draw[dashed]
let p1 = ($ (A.after bottom) - (A.before bottom) $),
n1 = 0.5*veclen(x1,y1)-pgflinewidth,
p2 = ($ (A.bottom) - (A.after bottom)!.5!(A.before bottom) $),
n2 = veclen(x2,y2)
in (A.before bottom) arc [start angle=0, end angle=180,
x radius=n1, y radius=n2];
endtikzpicture
captionThe tank.
labelfig:tank
endfigure
enddocument
answered Dec 2 at 4:06
Zarko
118k865155
118k865155
add a comment |
add a comment |
up vote
7
down vote
I would use tikz-3dplot
for it, in particular if you are considering adding more 3d-like elements. The following has 4 parameters, one view angle which is set to 100
, a radius R
, the height of the water HW
and the height of the cylinder HC
.
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usepgflibraryshapes.geometric
usetikzlibrarycalc
begindocument
tdplotsetmaincoords1000
begintikzpicture[tdplot_main_coords]
pgfmathsetmacroR4
pgfmathsetmacroHW4
pgfmathsetmacroHC6
% water
fill[blue!40] plot[variable=x,domain=0:180,smooth] (R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth] (R*cos(x),R*sin(x),HW)
-- cycle;
draw[blue] plot[variable=x,domain=0:360,smooth,samples=51]
(R*cos(x),R*sin(x),HW);
% "invisible" lined
draw[dashed] plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),0);
% visible cylinder lines
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),HC) -- cycle;
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),HC);
endtikzpicture
enddocument
The meaning of the view angle
is illustrated by this animation.
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usepgflibraryshapes.geometric
usetikzlibrarycalc
begindocument
foreach X in 0,10,...,350
tdplotsetmaincoords120+30*sin(X)0
begintikzpicture
pgfmathsetmacroR4
pgfmathsetmacroHW4
pgfmathsetmacroHC6
path[use as bounding box] (-1.1*R,-0.75*HC) rectangle (1.1*R,1.25*HC);
beginscope[tdplot_main_coords]
% water
fill[blue!40] plot[variable=x,domain=0:180,smooth] (R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth] (R*cos(x),R*sin(x),HW)
-- cycle;
draw[blue] plot[variable=x,domain=0:360,smooth,samples=51]
(R*cos(x),R*sin(x),HW);
% "invisible" lined
draw[dashed] plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),0);
% visible cylinder lines
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),HC) -- cycle;
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),HC);
endscope
endtikzpicture
enddocument
add a comment |
up vote
7
down vote
I would use tikz-3dplot
for it, in particular if you are considering adding more 3d-like elements. The following has 4 parameters, one view angle which is set to 100
, a radius R
, the height of the water HW
and the height of the cylinder HC
.
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usepgflibraryshapes.geometric
usetikzlibrarycalc
begindocument
tdplotsetmaincoords1000
begintikzpicture[tdplot_main_coords]
pgfmathsetmacroR4
pgfmathsetmacroHW4
pgfmathsetmacroHC6
% water
fill[blue!40] plot[variable=x,domain=0:180,smooth] (R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth] (R*cos(x),R*sin(x),HW)
-- cycle;
draw[blue] plot[variable=x,domain=0:360,smooth,samples=51]
(R*cos(x),R*sin(x),HW);
% "invisible" lined
draw[dashed] plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),0);
% visible cylinder lines
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),HC) -- cycle;
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),HC);
endtikzpicture
enddocument
The meaning of the view angle
is illustrated by this animation.
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usepgflibraryshapes.geometric
usetikzlibrarycalc
begindocument
foreach X in 0,10,...,350
tdplotsetmaincoords120+30*sin(X)0
begintikzpicture
pgfmathsetmacroR4
pgfmathsetmacroHW4
pgfmathsetmacroHC6
path[use as bounding box] (-1.1*R,-0.75*HC) rectangle (1.1*R,1.25*HC);
beginscope[tdplot_main_coords]
% water
fill[blue!40] plot[variable=x,domain=0:180,smooth] (R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth] (R*cos(x),R*sin(x),HW)
-- cycle;
draw[blue] plot[variable=x,domain=0:360,smooth,samples=51]
(R*cos(x),R*sin(x),HW);
% "invisible" lined
draw[dashed] plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),0);
% visible cylinder lines
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),HC) -- cycle;
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),HC);
endscope
endtikzpicture
enddocument
add a comment |
up vote
7
down vote
up vote
7
down vote
I would use tikz-3dplot
for it, in particular if you are considering adding more 3d-like elements. The following has 4 parameters, one view angle which is set to 100
, a radius R
, the height of the water HW
and the height of the cylinder HC
.
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usepgflibraryshapes.geometric
usetikzlibrarycalc
begindocument
tdplotsetmaincoords1000
begintikzpicture[tdplot_main_coords]
pgfmathsetmacroR4
pgfmathsetmacroHW4
pgfmathsetmacroHC6
% water
fill[blue!40] plot[variable=x,domain=0:180,smooth] (R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth] (R*cos(x),R*sin(x),HW)
-- cycle;
draw[blue] plot[variable=x,domain=0:360,smooth,samples=51]
(R*cos(x),R*sin(x),HW);
% "invisible" lined
draw[dashed] plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),0);
% visible cylinder lines
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),HC) -- cycle;
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),HC);
endtikzpicture
enddocument
The meaning of the view angle
is illustrated by this animation.
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usepgflibraryshapes.geometric
usetikzlibrarycalc
begindocument
foreach X in 0,10,...,350
tdplotsetmaincoords120+30*sin(X)0
begintikzpicture
pgfmathsetmacroR4
pgfmathsetmacroHW4
pgfmathsetmacroHC6
path[use as bounding box] (-1.1*R,-0.75*HC) rectangle (1.1*R,1.25*HC);
beginscope[tdplot_main_coords]
% water
fill[blue!40] plot[variable=x,domain=0:180,smooth] (R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth] (R*cos(x),R*sin(x),HW)
-- cycle;
draw[blue] plot[variable=x,domain=0:360,smooth,samples=51]
(R*cos(x),R*sin(x),HW);
% "invisible" lined
draw[dashed] plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),0);
% visible cylinder lines
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),HC) -- cycle;
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),HC);
endscope
endtikzpicture
enddocument
I would use tikz-3dplot
for it, in particular if you are considering adding more 3d-like elements. The following has 4 parameters, one view angle which is set to 100
, a radius R
, the height of the water HW
and the height of the cylinder HC
.
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usepgflibraryshapes.geometric
usetikzlibrarycalc
begindocument
tdplotsetmaincoords1000
begintikzpicture[tdplot_main_coords]
pgfmathsetmacroR4
pgfmathsetmacroHW4
pgfmathsetmacroHC6
% water
fill[blue!40] plot[variable=x,domain=0:180,smooth] (R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth] (R*cos(x),R*sin(x),HW)
-- cycle;
draw[blue] plot[variable=x,domain=0:360,smooth,samples=51]
(R*cos(x),R*sin(x),HW);
% "invisible" lined
draw[dashed] plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),0);
% visible cylinder lines
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),HC) -- cycle;
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),HC);
endtikzpicture
enddocument
The meaning of the view angle
is illustrated by this animation.
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usepgflibraryshapes.geometric
usetikzlibrarycalc
begindocument
foreach X in 0,10,...,350
tdplotsetmaincoords120+30*sin(X)0
begintikzpicture
pgfmathsetmacroR4
pgfmathsetmacroHW4
pgfmathsetmacroHC6
path[use as bounding box] (-1.1*R,-0.75*HC) rectangle (1.1*R,1.25*HC);
beginscope[tdplot_main_coords]
% water
fill[blue!40] plot[variable=x,domain=0:180,smooth] (R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth] (R*cos(x),R*sin(x),HW)
-- cycle;
draw[blue] plot[variable=x,domain=0:360,smooth,samples=51]
(R*cos(x),R*sin(x),HW);
% "invisible" lined
draw[dashed] plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),0);
% visible cylinder lines
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),0)
--
plot[variable=x,domain=180:360,smooth]
(R*cos(x),R*sin(x),HC) -- cycle;
draw plot[variable=x,domain=0:180,smooth]
(R*cos(x),R*sin(x),HC);
endscope
endtikzpicture
enddocument
edited Dec 2 at 4:30
answered Dec 2 at 3:43
marmot
82k492175
82k492175
add a comment |
add a comment |
up vote
2
down vote
I have figured out a solution. In the square brackets containing the parameters for the first cylinder (the one drawing the water), we need only add xshift = -0.75cm
. Since the height of the outer cylinder is 6cm and the height of the inner is 4.5cm, so the difference in height is 1.5cm. Since both cylinders are centered at the same spot, the height of the gaps above and below the blue are 0.75cm each, so we just have to shift it down that distance. I was at first curious as to yshift
did not work, but then I realized that the cylinder is rotated in the beginning by 90 degrees, so that is probably the reason.
add a comment |
up vote
2
down vote
I have figured out a solution. In the square brackets containing the parameters for the first cylinder (the one drawing the water), we need only add xshift = -0.75cm
. Since the height of the outer cylinder is 6cm and the height of the inner is 4.5cm, so the difference in height is 1.5cm. Since both cylinders are centered at the same spot, the height of the gaps above and below the blue are 0.75cm each, so we just have to shift it down that distance. I was at first curious as to yshift
did not work, but then I realized that the cylinder is rotated in the beginning by 90 degrees, so that is probably the reason.
add a comment |
up vote
2
down vote
up vote
2
down vote
I have figured out a solution. In the square brackets containing the parameters for the first cylinder (the one drawing the water), we need only add xshift = -0.75cm
. Since the height of the outer cylinder is 6cm and the height of the inner is 4.5cm, so the difference in height is 1.5cm. Since both cylinders are centered at the same spot, the height of the gaps above and below the blue are 0.75cm each, so we just have to shift it down that distance. I was at first curious as to yshift
did not work, but then I realized that the cylinder is rotated in the beginning by 90 degrees, so that is probably the reason.
I have figured out a solution. In the square brackets containing the parameters for the first cylinder (the one drawing the water), we need only add xshift = -0.75cm
. Since the height of the outer cylinder is 6cm and the height of the inner is 4.5cm, so the difference in height is 1.5cm. Since both cylinders are centered at the same spot, the height of the gaps above and below the blue are 0.75cm each, so we just have to shift it down that distance. I was at first curious as to yshift
did not work, but then I realized that the cylinder is rotated in the beginning by 90 degrees, so that is probably the reason.
answered Dec 2 at 3:36
Aiden Kenny
1465
1465
add a comment |
add a comment |
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