How can I use command expansion on `` in `find -exec`?

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0
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I would like to find some directories via

find /path/to/a/dir -type d -links 2

and then for each pathname found by find, assumed to be stored in variable pathname, I would like to

stow -d "$(dirname "$pathname")" -t /home/t/bin "$(basename "$pathname")"

How can I combine the above with find -exec, something similar to:

find /path/to/a/dir -type d -links 2 -exec stow -d "$(dirname )" -t /home/t/bin "$(basename )" ;

I think it doesn't work because the shell performs the command substitutions before running find, and no pathname is found yet to replace in the command substitutions.

Thanks.

asked Dec 2 at 3:53

Tim

25.3k72243447

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up vote
0
down vote

favorite

I would like to find some directories via

find /path/to/a/dir -type d -links 2

and then for each pathname found by find, assumed to be stored in variable pathname, I would like to

stow -d "$(dirname "$pathname")" -t /home/t/bin "$(basename "$pathname")"

How can I combine the above with find -exec, something similar to:

find /path/to/a/dir -type d -links 2 -exec stow -d "$(dirname )" -t /home/t/bin "$(basename )" ;

I think it doesn't work because the shell performs the command substitutions before running find, and no pathname is found yet to replace in the command substitutions.

Thanks.

asked Dec 2 at 3:53

Tim

25.3k72243447

add a comment |

up vote
0
down vote

favorite

I would like to find some directories via

find /path/to/a/dir -type d -links 2

and then for each pathname found by find, assumed to be stored in variable pathname, I would like to

stow -d "$(dirname "$pathname")" -t /home/t/bin "$(basename "$pathname")"

How can I combine the above with find -exec, something similar to:

find /path/to/a/dir -type d -links 2 -exec stow -d "$(dirname )" -t /home/t/bin "$(basename )" ;

I think it doesn't work because the shell performs the command substitutions before running find, and no pathname is found yet to replace in the command substitutions.

Thanks.

asked Dec 2 at 3:53

Tim

25.3k72243447

I would like to find some directories via

find /path/to/a/dir -type d -links 2

and then for each pathname found by find, assumed to be stored in variable pathname, I would like to

stow -d "$(dirname "$pathname")" -t /home/t/bin "$(basename "$pathname")"

How can I combine the above with find -exec, something similar to:

find /path/to/a/dir -type d -links 2 -exec stow -d "$(dirname )" -t /home/t/bin "$(basename )" ;

I think it doesn't work because the shell performs the command substitutions before running find, and no pathname is found yet to replace in the command substitutions.

Thanks.

bash find command-substitution

asked Dec 2 at 3:53

Tim

25.3k72243447

asked Dec 2 at 3:53

Tim

25.3k72243447

asked Dec 2 at 3:53

Tim

25.3k72243447

asked Dec 2 at 3:53

Tim

25.3k72243447

asked Dec 2 at 3:53

Tim

25.3k72243447

add a comment |

1 Answer
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2
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You wrap it in a sh -c command

find /path/to/dir -type d -links 2 -exec sh -c 'stow -d "$(dirname "$1")" -t /home/t/bin "$(basename "$1")"' sh ;

answered Dec 2 at 4:29

mosvy

5,1791323

Thanks. Why do you use sh instead of bash here?
– Tim
Dec 2 at 14:14

sh is guaranteed to exist on any Unix system. On linux, /bin/sh is either a symlink to /bin/bash itself (eg. rhel, centos) or to something smaller and faster (/bin/dash on ubuntu and debian).
– mosvy
Dec 2 at 14:28

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
2
down vote

accepted

You wrap it in a sh -c command

find /path/to/dir -type d -links 2 -exec sh -c 'stow -d "$(dirname "$1")" -t /home/t/bin "$(basename "$1")"' sh ;

answered Dec 2 at 4:29

mosvy

5,1791323

Thanks. Why do you use sh instead of bash here?
– Tim
Dec 2 at 14:14

sh is guaranteed to exist on any Unix system. On linux, /bin/sh is either a symlink to /bin/bash itself (eg. rhel, centos) or to something smaller and faster (/bin/dash on ubuntu and debian).
– mosvy
Dec 2 at 14:28

add a comment |

up vote
2
down vote

accepted

You wrap it in a sh -c command

find /path/to/dir -type d -links 2 -exec sh -c 'stow -d "$(dirname "$1")" -t /home/t/bin "$(basename "$1")"' sh ;

answered Dec 2 at 4:29

mosvy

5,1791323

Thanks. Why do you use sh instead of bash here?
– Tim
Dec 2 at 14:14

sh is guaranteed to exist on any Unix system. On linux, /bin/sh is either a symlink to /bin/bash itself (eg. rhel, centos) or to something smaller and faster (/bin/dash on ubuntu and debian).
– mosvy
Dec 2 at 14:28

add a comment |

up vote
2
down vote

accepted

You wrap it in a sh -c command

find /path/to/dir -type d -links 2 -exec sh -c 'stow -d "$(dirname "$1")" -t /home/t/bin "$(basename "$1")"' sh ;

answered Dec 2 at 4:29

mosvy

5,1791323

You wrap it in a sh -c command

find /path/to/dir -type d -links 2 -exec sh -c 'stow -d "$(dirname "$1")" -t /home/t/bin "$(basename "$1")"' sh ;

answered Dec 2 at 4:29

mosvy

5,1791323

answered Dec 2 at 4:29

mosvy

5,1791323

answered Dec 2 at 4:29

mosvy

5,1791323

answered Dec 2 at 4:29

mosvy

5,1791323

Thanks. Why do you use sh instead of bash here?
– Tim
Dec 2 at 14:14

sh is guaranteed to exist on any Unix system. On linux, /bin/sh is either a symlink to /bin/bash itself (eg. rhel, centos) or to something smaller and faster (/bin/dash on ubuntu and debian).
– mosvy
Dec 2 at 14:28

add a comment |

Thanks. Why do you use sh instead of bash here?
– Tim
Dec 2 at 14:14

sh is guaranteed to exist on any Unix system. On linux, /bin/sh is either a symlink to /bin/bash itself (eg. rhel, centos) or to something smaller and faster (/bin/dash on ubuntu and debian).
– mosvy
Dec 2 at 14:28

Thanks. Why do you use sh instead of bash here?
– Tim
Dec 2 at 14:14

sh is guaranteed to exist on any Unix system. On linux, /bin/sh is either a symlink to /bin/bash itself (eg. rhel, centos) or to something smaller and faster (/bin/dash on ubuntu and debian).
– mosvy
Dec 2 at 14:28

add a comment |

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