mjhjmtu

I have following script to check disk usage

 #!/bin/bash

# set alert level 90% is default
ALERT=10

OIFS=$IFS
IFS=','

storage=$(df -H | grep -vE '^Filesystem|tmpfs|cdrom' | awk ' print $5 " " $1 ')



for output in $storage ;

do
 echo "---------------@@@@@@@@@ output started @@@@@@@@@@@@@@@@-----------"
 echo $output
 echo "---------------@@@@@@@@@ output end @@@@@@@@@@@@@@@@-----------"

 usep=$(echo $output | awk ' print $1' | cut -d'%' -f1 )
 echo "---------------###### useo started ######-----------"
 echo $usep
 echo "---------------###### usep end ######-----------"

 if [ $usep -ge $ALERT ]; then

 echo "Running out of space "$partition ($usep%)" on $(hostname) as on $(date)" 
 fi
done

But when i am running this code i am getting the integer expression expected error at if conditional statement, Here is the output of this script

 97% /dev/sda1
1% udev
0% none
2% none
---------------@@@@@@@@@ output end @@@@@@@@@@@@@@@@-----------
---------------###### useo started ######-----------
97
1
0
2
---------------###### usep end ######-----------
./fordiskfor.sh: line 24: [: 97
1
0
2: integer expression expected

The problem is there:

if [ $usep -ge $ALERT ]; then
 ...
fi

$usep contains multiple lines of digits. To cycle trough all of them use somthing like this instead of that part:

for $space in $usep;
do
 if [ $space -ge $ALERT ]; then
 echo "Running out of space..."
 fi
done

The value stored in the variable $storage comprises of multiple lines. As a result, $output will also contain multiple lines, and so will $usep.

You can extract and compare all values stored in $usep, one by one, using another for loop as mentioned in this answer. Or you can use while statement as follows:

echo $storage | while read output
do 
 ...
 ...

 if [ $usep -ge $ALERT ]; then 
 echo "Running out of space "$partition ($usep%)" on $(hostname) as on $(date)"
 fi
done