sed: replace part of text in previous line if match is found [duplicate]

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This question already has an answer here:

Replace a string before a certain line

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I want to replace create_test in the file with #create_test if the next line contains psfxxx_16_pi. How can I do it with sed for the whole file containing this?

Input file content:

create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

create_test -type hard -outer 0.0000 
 psfxxx_16_pi/psfop/deadline_south_re_1

Output file:

#create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

#create_test -type hard -outer 0.0000 
 psfxxx_16_pi/psfop/deadline_south_re_1

edited 2 days ago

Mr Shunz

2,99311822

asked 2 days ago

mandrake00

243

New contributor

marked as duplicate by don_crissti, Jeff Schaller, Isaac, RalfFriedl, Romeo Ninov yesterday

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

I can do it with perl, but I am looking for a compact one liner command using sed or awk. Thank you Mr. Shunz for the format.
– mandrake00
2 days ago

May be helpful? unix.stackexchange.com/questions/466798/…
– Sparhawk
2 days ago

I'm always curious when I see requests for one-liners; what's wrong with a perl solution?
– Jeff Schaller
2 days ago

add a comment |

up vote
0
down vote

favorite

This question already has an answer here:

Replace a string before a certain line

5 answers

I want to replace create_test in the file with #create_test if the next line contains psfxxx_16_pi. How can I do it with sed for the whole file containing this?

Input file content:

create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

create_test -type hard -outer 0.0000 
 psfxxx_16_pi/psfop/deadline_south_re_1

Output file:

#create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

#create_test -type hard -outer 0.0000 
 psfxxx_16_pi/psfop/deadline_south_re_1

edited 2 days ago

Mr Shunz

2,99311822

asked 2 days ago

mandrake00

243

New contributor

marked as duplicate by don_crissti, Jeff Schaller, Isaac, RalfFriedl, Romeo Ninov yesterday

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

I can do it with perl, but I am looking for a compact one liner command using sed or awk. Thank you Mr. Shunz for the format.
– mandrake00
2 days ago

May be helpful? unix.stackexchange.com/questions/466798/…
– Sparhawk
2 days ago

I'm always curious when I see requests for one-liners; what's wrong with a perl solution?
– Jeff Schaller
2 days ago

add a comment |

up vote
0
down vote

favorite

This question already has an answer here:

Replace a string before a certain line

5 answers

I want to replace create_test in the file with #create_test if the next line contains psfxxx_16_pi. How can I do it with sed for the whole file containing this?

Input file content:

create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

create_test -type hard -outer 0.0000 
 psfxxx_16_pi/psfop/deadline_south_re_1

Output file:

#create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

#create_test -type hard -outer 0.0000 
 psfxxx_16_pi/psfop/deadline_south_re_1

edited 2 days ago

Mr Shunz

2,99311822

asked 2 days ago

mandrake00

243

New contributor

This question already has an answer here:

Replace a string before a certain line

5 answers

I want to replace create_test in the file with #create_test if the next line contains psfxxx_16_pi. How can I do it with sed for the whole file containing this?

Input file content:

create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

create_test -type hard -outer 0.0000 
 psfxxx_16_pi/psfop/deadline_south_re_1

Output file:

#create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

#create_test -type hard -outer 0.0000 
 psfxxx_16_pi/psfop/deadline_south_re_1

This question already has an answer here:

Replace a string before a certain line

5 answers

sed

edited 2 days ago

Mr Shunz

2,99311822

asked 2 days ago

mandrake00

243

New contributor

edited 2 days ago

Mr Shunz

2,99311822

asked 2 days ago

mandrake00

243

New contributor

edited 2 days ago

Mr Shunz

2,99311822

edited 2 days ago

Mr Shunz

2,99311822

edited 2 days ago

Mr Shunz

2,99311822

asked 2 days ago

mandrake00

243

New contributor

asked 2 days ago

mandrake00

243

asked 2 days ago

mandrake00

243

New contributor

mandrake00 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

marked as duplicate by don_crissti, Jeff Schaller, Isaac, RalfFriedl, Romeo Ninov yesterday

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

marked as duplicate by don_crissti, Jeff Schaller, Isaac, RalfFriedl, Romeo Ninov yesterday

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

I can do it with perl, but I am looking for a compact one liner command using sed or awk. Thank you Mr. Shunz for the format.
– mandrake00
2 days ago

May be helpful? unix.stackexchange.com/questions/466798/…
– Sparhawk
2 days ago

I'm always curious when I see requests for one-liners; what's wrong with a perl solution?
– Jeff Schaller
2 days ago

add a comment |

I can do it with perl, but I am looking for a compact one liner command using sed or awk. Thank you Mr. Shunz for the format.
– mandrake00
2 days ago

May be helpful? unix.stackexchange.com/questions/466798/…
– Sparhawk
2 days ago

I'm always curious when I see requests for one-liners; what's wrong with a perl solution?
– Jeff Schaller
2 days ago

I can do it with perl, but I am looking for a compact one liner command using sed or awk. Thank you Mr. Shunz for the format.
– mandrake00
2 days ago

May be helpful? unix.stackexchange.com/questions/466798/…
– Sparhawk
2 days ago

I'm always curious when I see requests for one-liners; what's wrong with a perl solution?
– Jeff Schaller
2 days ago

add a comment |

3 Answers
3

active

oldest

votes

up vote
2
down vote

Try

sed '/^create_test/ N; /psfxxx/ s/^/#/' file
#create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

#create_test -type hard -outer 0.0000 
 psfxxx_16_pi/psfop/deadline_south_re_1 

create_test -type hard -outer 1.0000 
 vsfxxx_16_pi/psfop/deadline_north_re_0 

create_test -type hard -outer 0.0000 
 vsfxxx_16_pi/psfop/deadline_south_re_1

When encountering "create_test" it appends the next line, and if that contains "psfxxx", it prefixes the "#".

answered 2 days ago

RudiC

3,0611211

Thank you RudiC. I tried. It replaces only the first occurance in the input text file. output: #create_test -type hard -outer 1.0000 psfxxx_16_pi/psfop/deadline_north_re_0 create_ test -type hard -outer 0.0000 psfxxx_16_pi/psfop/deadline_south_re_1
– mandrake00
2 days ago

Hi! RudiC. Your fix works. Great! my input file had an issue. It had create_ in one line and test... in the next. Fixed it and it's working fine now. You are a genius.
– mandrake00
2 days ago

You can see in my sample output that it replaces on matching records, and doesn't if no match. What's different in your input file? Hoppla - cross post.
– RudiC
2 days ago

Thank you RudiC. It works well.
– mandrake00
2 days ago

add a comment |

up vote
0
down vote

Another sed method:

$ sed -zE 's/create_test([^n]*n[^n]*psfxxx_16_pi)/#create_test1/g' file
#create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

#create_test -type hard -outer 0.0000 { 
 psfxxx_16_pi/psfop/deadline_south_re_1

answered 2 days ago

fpmurphy1

2,336915

add a comment |

up vote
0
down vote

If awk will do:

awk '/psfxxx_16_pi/prev = "#" prev print prev prev = $0 END print'

Here, I print the previous line (saved in prev) for each line, and save $0 for the next iteration in prev. If the line matches, I add # to prev. At the end, print the last line.

answered 2 days ago

JohnDoea

211

New contributor

add a comment |

3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

up vote
2
down vote

Try

sed '/^create_test/ N; /psfxxx/ s/^/#/' file
#create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

#create_test -type hard -outer 0.0000 
 psfxxx_16_pi/psfop/deadline_south_re_1 

create_test -type hard -outer 1.0000 
 vsfxxx_16_pi/psfop/deadline_north_re_0 

create_test -type hard -outer 0.0000 
 vsfxxx_16_pi/psfop/deadline_south_re_1

When encountering "create_test" it appends the next line, and if that contains "psfxxx", it prefixes the "#".

answered 2 days ago

RudiC

3,0611211

Thank you RudiC. I tried. It replaces only the first occurance in the input text file. output: #create_test -type hard -outer 1.0000 psfxxx_16_pi/psfop/deadline_north_re_0 create_ test -type hard -outer 0.0000 psfxxx_16_pi/psfop/deadline_south_re_1
– mandrake00
2 days ago

Hi! RudiC. Your fix works. Great! my input file had an issue. It had create_ in one line and test... in the next. Fixed it and it's working fine now. You are a genius.
– mandrake00
2 days ago

You can see in my sample output that it replaces on matching records, and doesn't if no match. What's different in your input file? Hoppla - cross post.
– RudiC
2 days ago

Thank you RudiC. It works well.
– mandrake00
2 days ago

add a comment |

up vote
2
down vote

Try

sed '/^create_test/ N; /psfxxx/ s/^/#/' file
#create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

#create_test -type hard -outer 0.0000 
 psfxxx_16_pi/psfop/deadline_south_re_1 

create_test -type hard -outer 1.0000 
 vsfxxx_16_pi/psfop/deadline_north_re_0 

create_test -type hard -outer 0.0000 
 vsfxxx_16_pi/psfop/deadline_south_re_1

When encountering "create_test" it appends the next line, and if that contains "psfxxx", it prefixes the "#".

answered 2 days ago

RudiC

3,0611211

Thank you RudiC. I tried. It replaces only the first occurance in the input text file. output: #create_test -type hard -outer 1.0000 psfxxx_16_pi/psfop/deadline_north_re_0 create_ test -type hard -outer 0.0000 psfxxx_16_pi/psfop/deadline_south_re_1
– mandrake00
2 days ago

Hi! RudiC. Your fix works. Great! my input file had an issue. It had create_ in one line and test... in the next. Fixed it and it's working fine now. You are a genius.
– mandrake00
2 days ago

You can see in my sample output that it replaces on matching records, and doesn't if no match. What's different in your input file? Hoppla - cross post.
– RudiC
2 days ago

Thank you RudiC. It works well.
– mandrake00
2 days ago

add a comment |

up vote
2
down vote

Try

sed '/^create_test/ N; /psfxxx/ s/^/#/' file
#create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

#create_test -type hard -outer 0.0000 
 psfxxx_16_pi/psfop/deadline_south_re_1 

create_test -type hard -outer 1.0000 
 vsfxxx_16_pi/psfop/deadline_north_re_0 

create_test -type hard -outer 0.0000 
 vsfxxx_16_pi/psfop/deadline_south_re_1

When encountering "create_test" it appends the next line, and if that contains "psfxxx", it prefixes the "#".

answered 2 days ago

RudiC

3,0611211

Try

sed '/^create_test/ N; /psfxxx/ s/^/#/' file
#create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

#create_test -type hard -outer 0.0000 
 psfxxx_16_pi/psfop/deadline_south_re_1 

create_test -type hard -outer 1.0000 
 vsfxxx_16_pi/psfop/deadline_north_re_0 

create_test -type hard -outer 0.0000 
 vsfxxx_16_pi/psfop/deadline_south_re_1

When encountering "create_test" it appends the next line, and if that contains "psfxxx", it prefixes the "#".

answered 2 days ago

RudiC

3,0611211

answered 2 days ago

RudiC

3,0611211

answered 2 days ago

RudiC

3,0611211

answered 2 days ago

RudiC

3,0611211

Thank you RudiC. I tried. It replaces only the first occurance in the input text file. output: #create_test -type hard -outer 1.0000 psfxxx_16_pi/psfop/deadline_north_re_0 create_ test -type hard -outer 0.0000 psfxxx_16_pi/psfop/deadline_south_re_1
– mandrake00
2 days ago

Hi! RudiC. Your fix works. Great! my input file had an issue. It had create_ in one line and test... in the next. Fixed it and it's working fine now. You are a genius.
– mandrake00
2 days ago

You can see in my sample output that it replaces on matching records, and doesn't if no match. What's different in your input file? Hoppla - cross post.
– RudiC
2 days ago

Thank you RudiC. It works well.
– mandrake00
2 days ago

add a comment |

Thank you RudiC. I tried. It replaces only the first occurance in the input text file. output: #create_test -type hard -outer 1.0000 psfxxx_16_pi/psfop/deadline_north_re_0 create_ test -type hard -outer 0.0000 psfxxx_16_pi/psfop/deadline_south_re_1
– mandrake00
2 days ago

Hi! RudiC. Your fix works. Great! my input file had an issue. It had create_ in one line and test... in the next. Fixed it and it's working fine now. You are a genius.
– mandrake00
2 days ago

You can see in my sample output that it replaces on matching records, and doesn't if no match. What's different in your input file? Hoppla - cross post.
– RudiC
2 days ago

Thank you RudiC. It works well.
– mandrake00
2 days ago

Thank you RudiC. I tried. It replaces only the first occurance in the input text file. output: #create_test -type hard -outer 1.0000 psfxxx_16_pi/psfop/deadline_north_re_0 create_ test -type hard -outer 0.0000 psfxxx_16_pi/psfop/deadline_south_re_1
– mandrake00
2 days ago

Hi! RudiC. Your fix works. Great! my input file had an issue. It had create_ in one line and test... in the next. Fixed it and it's working fine now. You are a genius.
– mandrake00
2 days ago

You can see in my sample output that it replaces on matching records, and doesn't if no match. What's different in your input file? Hoppla - cross post.
– RudiC
2 days ago

Thank you RudiC. It works well.
– mandrake00
2 days ago

add a comment |

up vote
0
down vote

Another sed method:

$ sed -zE 's/create_test([^n]*n[^n]*psfxxx_16_pi)/#create_test1/g' file
#create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

#create_test -type hard -outer 0.0000 { 
 psfxxx_16_pi/psfop/deadline_south_re_1

answered 2 days ago

fpmurphy1

2,336915

add a comment |

up vote
0
down vote

Another sed method:

$ sed -zE 's/create_test([^n]*n[^n]*psfxxx_16_pi)/#create_test1/g' file
#create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

#create_test -type hard -outer 0.0000 { 
 psfxxx_16_pi/psfop/deadline_south_re_1

answered 2 days ago

fpmurphy1

2,336915

add a comment |

up vote
0
down vote

Another sed method:

$ sed -zE 's/create_test([^n]*n[^n]*psfxxx_16_pi)/#create_test1/g' file
#create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

#create_test -type hard -outer 0.0000 { 
 psfxxx_16_pi/psfop/deadline_south_re_1

answered 2 days ago

fpmurphy1

2,336915

Another sed method:

$ sed -zE 's/create_test([^n]*n[^n]*psfxxx_16_pi)/#create_test1/g' file
#create_test -type hard -outer 1.0000 
 psfxxx_16_pi/psfop/deadline_north_re_0 

#create_test -type hard -outer 0.0000 { 
 psfxxx_16_pi/psfop/deadline_south_re_1

answered 2 days ago

fpmurphy1

2,336915

answered 2 days ago

fpmurphy1

2,336915

answered 2 days ago

fpmurphy1

2,336915

answered 2 days ago

fpmurphy1

2,336915

add a comment |

up vote
0
down vote

If awk will do:

awk '/psfxxx_16_pi/prev = "#" prev print prev prev = $0 END print'

Here, I print the previous line (saved in prev) for each line, and save $0 for the next iteration in prev. If the line matches, I add # to prev. At the end, print the last line.

answered 2 days ago

JohnDoea

211

New contributor

add a comment |

up vote
0
down vote

If awk will do:

awk '/psfxxx_16_pi/prev = "#" prev print prev prev = $0 END print'

Here, I print the previous line (saved in prev) for each line, and save $0 for the next iteration in prev. If the line matches, I add # to prev. At the end, print the last line.

answered 2 days ago

JohnDoea

211

New contributor

add a comment |

up vote
0
down vote

If awk will do:

awk '/psfxxx_16_pi/prev = "#" prev print prev prev = $0 END print'

Here, I print the previous line (saved in prev) for each line, and save $0 for the next iteration in prev. If the line matches, I add # to prev. At the end, print the last line.

answered 2 days ago

JohnDoea

211

New contributor

If awk will do:

awk '/psfxxx_16_pi/prev = "#" prev print prev prev = $0 END print'

Here, I print the previous line (saved in prev) for each line, and save $0 for the next iteration in prev. If the line matches, I add # to prev. At the end, print the last line.

answered 2 days ago

JohnDoea

211

New contributor

answered 2 days ago

JohnDoea

211

New contributor

answered 2 days ago

JohnDoea

211

answered 2 days ago

JohnDoea

211

New contributor

JohnDoea is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment |

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