mjhjmtu

I have a markdown file which contain code blocks as

In [310]: !cat data.md

**File Permission Related Commands**

These commands are used to change permissions of the files

```
72. chmod octal file-name : Changes the permissions of file to octal
 chmod 777 /data/test.c : Sets rwx permission for owner , group and others
```

**Network Related Commands**

These commands are used to view and edit network configurations related aspects of the system

```
75. ifconfig -a : Displays all network interface and set ip address
76. ifconfig eth0 : Displays eth0 ethernet port ip address and details
```

**Compression / Archive Related Commands**

These commands are used to compress and decompress files

```
89. tar cf home.tar home : Creates a tar named home.tar containing home/
 tar xf file.tar : Extracts the files from file.tar
 tar czf file.tar.gz files : Creates a tar with gzip compression

I'd like to replace the opening (triple cavet) withbash to mark the shell script which will be demonstrated in color by the editor.

I tried

In [311]: !sed "s/^(```)/(```bash)/g" 
/usr/local/bin/bash: command substitution: line 0: syntax error near unexpected token `)'
/usr/local/bin/bash: command substitution: line 0: `)/('
sed: -e expression #1, char 11: unterminated `s' command


In [316]: !sed -E "s/^```/```bash/g" 
/usr/local/bin/bash: /: Is a directory
sed: -e expression #1, char 9: unterminated `s' command

also other alternatives.

How could I accomplish such a task?