How to record PID and its command every 15s?

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For troubleshooting purpose, I'd like to record PID and its command every 15s and write them to a text file.



The desired output:
TimeStamp, PID, Command










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    up vote
    -1
    down vote

    favorite












    For troubleshooting purpose, I'd like to record PID and its command every 15s and write them to a text file.



    The desired output:
    TimeStamp, PID, Command










    share|improve this question























      up vote
      -1
      down vote

      favorite









      up vote
      -1
      down vote

      favorite











      For troubleshooting purpose, I'd like to record PID and its command every 15s and write them to a text file.



      The desired output:
      TimeStamp, PID, Command










      share|improve this question













      For troubleshooting purpose, I'd like to record PID and its command every 15s and write them to a text file.



      The desired output:
      TimeStamp, PID, Command







      linux process ps top htop






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      asked 1 hour ago









      John Hass

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          This will get you you the three columns you want:



          $ ps -hopid,comm | perl -anle'print time, ", $F[0], $F[1]"'
          1541626566, 6496, gedit
          1541626566, 7513, bash


          You can limit or extend the scope of ps, ie. what processes it lists. Then you put this in a loop with redirection.



          while true; do echo x; sleep 15; done > out


          Replace echo x with the command proper and out with the file name you choose.



          As for the command producing the information, here's a run-down.




          • ps -hopid,comm - ps is obvious, -h turns off the header line and -o stands for the output (PID and command).

          • This goes to the Perl command, namely perl -anle'print time, ", $F[0], $F[1]"'. Here perl is Perl. The -anle flags reprent correspondingly: a - load input into an array, n - take care of new lines, l - process each single line, and finally e - execute the code that follows.

          • And now the code follows: 'print time, ", $F[0], $F[1]"'. First print the time stamp, then the first column of the array that holds the input material, and then the second.





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            1 Answer
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            up vote
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            down vote













            This will get you you the three columns you want:



            $ ps -hopid,comm | perl -anle'print time, ", $F[0], $F[1]"'
            1541626566, 6496, gedit
            1541626566, 7513, bash


            You can limit or extend the scope of ps, ie. what processes it lists. Then you put this in a loop with redirection.



            while true; do echo x; sleep 15; done > out


            Replace echo x with the command proper and out with the file name you choose.



            As for the command producing the information, here's a run-down.




            • ps -hopid,comm - ps is obvious, -h turns off the header line and -o stands for the output (PID and command).

            • This goes to the Perl command, namely perl -anle'print time, ", $F[0], $F[1]"'. Here perl is Perl. The -anle flags reprent correspondingly: a - load input into an array, n - take care of new lines, l - process each single line, and finally e - execute the code that follows.

            • And now the code follows: 'print time, ", $F[0], $F[1]"'. First print the time stamp, then the first column of the array that holds the input material, and then the second.





            share|improve this answer


























              up vote
              0
              down vote













              This will get you you the three columns you want:



              $ ps -hopid,comm | perl -anle'print time, ", $F[0], $F[1]"'
              1541626566, 6496, gedit
              1541626566, 7513, bash


              You can limit or extend the scope of ps, ie. what processes it lists. Then you put this in a loop with redirection.



              while true; do echo x; sleep 15; done > out


              Replace echo x with the command proper and out with the file name you choose.



              As for the command producing the information, here's a run-down.




              • ps -hopid,comm - ps is obvious, -h turns off the header line and -o stands for the output (PID and command).

              • This goes to the Perl command, namely perl -anle'print time, ", $F[0], $F[1]"'. Here perl is Perl. The -anle flags reprent correspondingly: a - load input into an array, n - take care of new lines, l - process each single line, and finally e - execute the code that follows.

              • And now the code follows: 'print time, ", $F[0], $F[1]"'. First print the time stamp, then the first column of the array that holds the input material, and then the second.





              share|improve this answer
























                up vote
                0
                down vote










                up vote
                0
                down vote









                This will get you you the three columns you want:



                $ ps -hopid,comm | perl -anle'print time, ", $F[0], $F[1]"'
                1541626566, 6496, gedit
                1541626566, 7513, bash


                You can limit or extend the scope of ps, ie. what processes it lists. Then you put this in a loop with redirection.



                while true; do echo x; sleep 15; done > out


                Replace echo x with the command proper and out with the file name you choose.



                As for the command producing the information, here's a run-down.




                • ps -hopid,comm - ps is obvious, -h turns off the header line and -o stands for the output (PID and command).

                • This goes to the Perl command, namely perl -anle'print time, ", $F[0], $F[1]"'. Here perl is Perl. The -anle flags reprent correspondingly: a - load input into an array, n - take care of new lines, l - process each single line, and finally e - execute the code that follows.

                • And now the code follows: 'print time, ", $F[0], $F[1]"'. First print the time stamp, then the first column of the array that holds the input material, and then the second.





                share|improve this answer














                This will get you you the three columns you want:



                $ ps -hopid,comm | perl -anle'print time, ", $F[0], $F[1]"'
                1541626566, 6496, gedit
                1541626566, 7513, bash


                You can limit or extend the scope of ps, ie. what processes it lists. Then you put this in a loop with redirection.



                while true; do echo x; sleep 15; done > out


                Replace echo x with the command proper and out with the file name you choose.



                As for the command producing the information, here's a run-down.




                • ps -hopid,comm - ps is obvious, -h turns off the header line and -o stands for the output (PID and command).

                • This goes to the Perl command, namely perl -anle'print time, ", $F[0], $F[1]"'. Here perl is Perl. The -anle flags reprent correspondingly: a - load input into an array, n - take care of new lines, l - process each single line, and finally e - execute the code that follows.

                • And now the code follows: 'print time, ", $F[0], $F[1]"'. First print the time stamp, then the first column of the array that holds the input material, and then the second.






                share|improve this answer














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                edited 43 mins ago

























                answered 52 mins ago









                Tomasz

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                8,62052761



























                     

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