mjhjmtu

var1="temp-pprod-deployment"

Need a shell script for the below use case;

if the above variable $var1 value contains "prod" string then execute a print message eg. echo "Found" else echo "Not found"

You can do something like this:

var1="temp-pprod-deployment"
if `echo "$var1" | grep -q "prod"` ;then
 echo "$var1 contains word 'prod'"
else 
 echo "Not found."
fi

Explanation: You are getting output of variable and piping it to grep for regex. The -q option, means to return 0 on success(true) and 1 on failure(false), which is test-ed with if.

Use bashes / operator to remove the test string from the variable contents, and see if that operation has changed it. If it has, you know the string is present:

$ var1="temp-pprod-deployment"
$ var2="temp-pdev-deployment"
$ [ "$var1/prod" == "$var1" ] && echo not found
$ [ "$var2/prod" == "$var2" ] && echo not found
not found
$ [ "$var1/dev" == "$var1" ] && echo not found
not found
$ [ "$var2/dev" == "$var2" ] && echo not found

In full compliance with the OP:

if [ "$var1/prod" != "$var1" ]
then
 echo "Found."
else
 echo "Not found."
fi