Get container directory more easily

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I have a bash script here:



$GOPATH/
src/
build.sh


and in build.sh I have:



export GOPATH="$(cd $(dirname "$BASH_SOURCE") && pwd)"


is there a shorter way to get the containing dir of build.sh?









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    up vote
    0
    down vote

    favorite












    I have a bash script here:



    $GOPATH/
    src/
    build.sh


    and in build.sh I have:



    export GOPATH="$(cd $(dirname "$BASH_SOURCE") && pwd)"


    is there a shorter way to get the containing dir of build.sh?









    share























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have a bash script here:



      $GOPATH/
      src/
      build.sh


      and in build.sh I have:



      export GOPATH="$(cd $(dirname "$BASH_SOURCE") && pwd)"


      is there a shorter way to get the containing dir of build.sh?









      share













      I have a bash script here:



      $GOPATH/
      src/
      build.sh


      and in build.sh I have:



      export GOPATH="$(cd $(dirname "$BASH_SOURCE") && pwd)"


      is there a shorter way to get the containing dir of build.sh?







      bash shell pwd basename dirname





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      asked 3 mins ago









      Alexander Mills

      2,0671133




      2,0671133

























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