replacing values in one with the values in another file

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I have a csv file named eche in following format:
INCON,--,INITIAL,CONDITIONS,FOR*****,ELEMENTS,AT,TIME ,0.315570E+13
VC76,0.10000000E+00,0.2837726135782E+08,0.6756896308414E+02
1K02,0.10000000E+00,0.2837950666778E+08,0.6757007619124E+02
P476,0.10000000E+00,0.2837975332748E+08,0.6756827783643E+02
KG76,0.10000000E+00,0.2838117264779E+08,0.6756840947964E+02
1K05,0.10000000E+00,0.2610647023303E+08,0.1841342000212E+03
1K06,0.10000000E+00,0.2611103965949E+08,0.1845191988294E+03
1K07,0.10000000E+00,0.2611275589639E+08,0.1845173169920E+03
1K08,0.10000000E+00,0.2611346615238E+08,0.1846393014710E+03
VC37,0.10000000E+00,0.2611374063470E+08,0.1849489276098E+03
1K10,0.10000000E+00,0.2610224473371E+08,0.1835417139884E+03
M037,0.10000000E+00,0.2611370504845E+08,0.1854150556422E+03
KG37,0.10000000E+00,0.2611331725657E+08,0.1859451266535E+03
I have another file named eche.txt which looks like the following :
VC76,207.64,0.40,2000.00,1154.00
S876,241.00,0.40,2000.00,1154.00
P476,241.06,0.40,2000.00,1154.00
M076,263.66,0.40,2000.00,1154.00
KG76,276.73,0.40,2000.00,1154.00
KG76,284.31,0.40,2000.00,1154.00
IW76,291.11,0.40,2000.00,1154.00
IW76,297.40,0.40,2000.00,1154.00
VC37,177.33,0.21,1998.00,1284.00
S837,240.20,0.21,1998.00,1284.00
P437,241.11,0.21,1998.00,1284.00
M037,263.58,0.21,1998.00,1284.00
KG37,276.42,0.21,1998.00,1284.00
KG37,283.85,0.21,1998.00,1284.00
I would like to replace the values in column 4 of eche with the values in column 2 of eche.txt if the value in the first columns of the two files are the same but when not same I retain the line in eche file. I tried the following two scripts which works but fail to replace the value in column 4 of eche with the value in column 2 of eche.txt:
file1="eche"
file2="eche.txt"
awk -F',' 'NR==FNRa[$2]=$3 NR>FNR$2=a[$4];print' OFS=' ' "$file2" "$file1" > test
perl -F',s*' -lane '$k$F[0]=$F[1]; next if $#F < 6; s/$F[1]/$k$F[3]/; print' "$file2" "$file1" > test
Here is the desired output:
P476,0.10000000E+00,0.2837975332748E+08,241.06
VC76,0.10000000E+00,0.2837726135782E+08,207.64
KG37,0.10000000E+00,0.2611331725657E+08,283.85
M037,0.10000000E+00,0.2611370504845E+08,263.58
VC37,0.10000000E+00,0.2611374063470E+08,177.33
1K08,0.10000000E+00,0.2611346615238E+08,0.1846393014710E+03
1K05,0.10000000E+00,0.2610647023303E+08,0.1841342000212E+03
1K06,0.10000000E+00,0.2611103965949E+08,0.1845191988294E+03
1K07,0.10000000E+00,0.2611275589639E+08,0.1845173169920E+03
KG76,0.10000000E+00,0.2838117264779E+08,284.31
1K02,0.10000000E+00,0.2837950666778E+08,0.6757007619124E+02
1K10,0.10000000E+00,0.2610224473371E+08,0.1835417139884E+03
text-processing command-line awk perl
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up vote
2
down vote
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I have a csv file named eche in following format:
INCON,--,INITIAL,CONDITIONS,FOR*****,ELEMENTS,AT,TIME ,0.315570E+13
VC76,0.10000000E+00,0.2837726135782E+08,0.6756896308414E+02
1K02,0.10000000E+00,0.2837950666778E+08,0.6757007619124E+02
P476,0.10000000E+00,0.2837975332748E+08,0.6756827783643E+02
KG76,0.10000000E+00,0.2838117264779E+08,0.6756840947964E+02
1K05,0.10000000E+00,0.2610647023303E+08,0.1841342000212E+03
1K06,0.10000000E+00,0.2611103965949E+08,0.1845191988294E+03
1K07,0.10000000E+00,0.2611275589639E+08,0.1845173169920E+03
1K08,0.10000000E+00,0.2611346615238E+08,0.1846393014710E+03
VC37,0.10000000E+00,0.2611374063470E+08,0.1849489276098E+03
1K10,0.10000000E+00,0.2610224473371E+08,0.1835417139884E+03
M037,0.10000000E+00,0.2611370504845E+08,0.1854150556422E+03
KG37,0.10000000E+00,0.2611331725657E+08,0.1859451266535E+03
I have another file named eche.txt which looks like the following :
VC76,207.64,0.40,2000.00,1154.00
S876,241.00,0.40,2000.00,1154.00
P476,241.06,0.40,2000.00,1154.00
M076,263.66,0.40,2000.00,1154.00
KG76,276.73,0.40,2000.00,1154.00
KG76,284.31,0.40,2000.00,1154.00
IW76,291.11,0.40,2000.00,1154.00
IW76,297.40,0.40,2000.00,1154.00
VC37,177.33,0.21,1998.00,1284.00
S837,240.20,0.21,1998.00,1284.00
P437,241.11,0.21,1998.00,1284.00
M037,263.58,0.21,1998.00,1284.00
KG37,276.42,0.21,1998.00,1284.00
KG37,283.85,0.21,1998.00,1284.00
I would like to replace the values in column 4 of eche with the values in column 2 of eche.txt if the value in the first columns of the two files are the same but when not same I retain the line in eche file. I tried the following two scripts which works but fail to replace the value in column 4 of eche with the value in column 2 of eche.txt:
file1="eche"
file2="eche.txt"
awk -F',' 'NR==FNRa[$2]=$3 NR>FNR$2=a[$4];print' OFS=' ' "$file2" "$file1" > test
perl -F',s*' -lane '$k$F[0]=$F[1]; next if $#F < 6; s/$F[1]/$k$F[3]/; print' "$file2" "$file1" > test
Here is the desired output:
P476,0.10000000E+00,0.2837975332748E+08,241.06
VC76,0.10000000E+00,0.2837726135782E+08,207.64
KG37,0.10000000E+00,0.2611331725657E+08,283.85
M037,0.10000000E+00,0.2611370504845E+08,263.58
VC37,0.10000000E+00,0.2611374063470E+08,177.33
1K08,0.10000000E+00,0.2611346615238E+08,0.1846393014710E+03
1K05,0.10000000E+00,0.2610647023303E+08,0.1841342000212E+03
1K06,0.10000000E+00,0.2611103965949E+08,0.1845191988294E+03
1K07,0.10000000E+00,0.2611275589639E+08,0.1845173169920E+03
KG76,0.10000000E+00,0.2838117264779E+08,284.31
1K02,0.10000000E+00,0.2837950666778E+08,0.6757007619124E+02
1K10,0.10000000E+00,0.2610224473371E+08,0.1835417139884E+03
text-processing command-line awk perl
1
Could you add the desired output file for the given input files?
â igal
Nov 12 '17 at 16:30
It looks like the formatting on the first input file is incorrect - I don't think those line-breaks after the 3rd column are supposed to be there.
â igal
Nov 12 '17 at 16:30
Also, your header column for theetchfile looks pretty mangled. Are you sure that's what you want?
â igal
Nov 12 '17 at 16:45
it would be better if you posted the expected result
â RomanPerekhrest
Nov 12 '17 at 16:51
add a comment |Â
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I have a csv file named eche in following format:
INCON,--,INITIAL,CONDITIONS,FOR*****,ELEMENTS,AT,TIME ,0.315570E+13
VC76,0.10000000E+00,0.2837726135782E+08,0.6756896308414E+02
1K02,0.10000000E+00,0.2837950666778E+08,0.6757007619124E+02
P476,0.10000000E+00,0.2837975332748E+08,0.6756827783643E+02
KG76,0.10000000E+00,0.2838117264779E+08,0.6756840947964E+02
1K05,0.10000000E+00,0.2610647023303E+08,0.1841342000212E+03
1K06,0.10000000E+00,0.2611103965949E+08,0.1845191988294E+03
1K07,0.10000000E+00,0.2611275589639E+08,0.1845173169920E+03
1K08,0.10000000E+00,0.2611346615238E+08,0.1846393014710E+03
VC37,0.10000000E+00,0.2611374063470E+08,0.1849489276098E+03
1K10,0.10000000E+00,0.2610224473371E+08,0.1835417139884E+03
M037,0.10000000E+00,0.2611370504845E+08,0.1854150556422E+03
KG37,0.10000000E+00,0.2611331725657E+08,0.1859451266535E+03
I have another file named eche.txt which looks like the following :
VC76,207.64,0.40,2000.00,1154.00
S876,241.00,0.40,2000.00,1154.00
P476,241.06,0.40,2000.00,1154.00
M076,263.66,0.40,2000.00,1154.00
KG76,276.73,0.40,2000.00,1154.00
KG76,284.31,0.40,2000.00,1154.00
IW76,291.11,0.40,2000.00,1154.00
IW76,297.40,0.40,2000.00,1154.00
VC37,177.33,0.21,1998.00,1284.00
S837,240.20,0.21,1998.00,1284.00
P437,241.11,0.21,1998.00,1284.00
M037,263.58,0.21,1998.00,1284.00
KG37,276.42,0.21,1998.00,1284.00
KG37,283.85,0.21,1998.00,1284.00
I would like to replace the values in column 4 of eche with the values in column 2 of eche.txt if the value in the first columns of the two files are the same but when not same I retain the line in eche file. I tried the following two scripts which works but fail to replace the value in column 4 of eche with the value in column 2 of eche.txt:
file1="eche"
file2="eche.txt"
awk -F',' 'NR==FNRa[$2]=$3 NR>FNR$2=a[$4];print' OFS=' ' "$file2" "$file1" > test
perl -F',s*' -lane '$k$F[0]=$F[1]; next if $#F < 6; s/$F[1]/$k$F[3]/; print' "$file2" "$file1" > test
Here is the desired output:
P476,0.10000000E+00,0.2837975332748E+08,241.06
VC76,0.10000000E+00,0.2837726135782E+08,207.64
KG37,0.10000000E+00,0.2611331725657E+08,283.85
M037,0.10000000E+00,0.2611370504845E+08,263.58
VC37,0.10000000E+00,0.2611374063470E+08,177.33
1K08,0.10000000E+00,0.2611346615238E+08,0.1846393014710E+03
1K05,0.10000000E+00,0.2610647023303E+08,0.1841342000212E+03
1K06,0.10000000E+00,0.2611103965949E+08,0.1845191988294E+03
1K07,0.10000000E+00,0.2611275589639E+08,0.1845173169920E+03
KG76,0.10000000E+00,0.2838117264779E+08,284.31
1K02,0.10000000E+00,0.2837950666778E+08,0.6757007619124E+02
1K10,0.10000000E+00,0.2610224473371E+08,0.1835417139884E+03
text-processing command-line awk perl
I have a csv file named eche in following format:
INCON,--,INITIAL,CONDITIONS,FOR*****,ELEMENTS,AT,TIME ,0.315570E+13
VC76,0.10000000E+00,0.2837726135782E+08,0.6756896308414E+02
1K02,0.10000000E+00,0.2837950666778E+08,0.6757007619124E+02
P476,0.10000000E+00,0.2837975332748E+08,0.6756827783643E+02
KG76,0.10000000E+00,0.2838117264779E+08,0.6756840947964E+02
1K05,0.10000000E+00,0.2610647023303E+08,0.1841342000212E+03
1K06,0.10000000E+00,0.2611103965949E+08,0.1845191988294E+03
1K07,0.10000000E+00,0.2611275589639E+08,0.1845173169920E+03
1K08,0.10000000E+00,0.2611346615238E+08,0.1846393014710E+03
VC37,0.10000000E+00,0.2611374063470E+08,0.1849489276098E+03
1K10,0.10000000E+00,0.2610224473371E+08,0.1835417139884E+03
M037,0.10000000E+00,0.2611370504845E+08,0.1854150556422E+03
KG37,0.10000000E+00,0.2611331725657E+08,0.1859451266535E+03
I have another file named eche.txt which looks like the following :
VC76,207.64,0.40,2000.00,1154.00
S876,241.00,0.40,2000.00,1154.00
P476,241.06,0.40,2000.00,1154.00
M076,263.66,0.40,2000.00,1154.00
KG76,276.73,0.40,2000.00,1154.00
KG76,284.31,0.40,2000.00,1154.00
IW76,291.11,0.40,2000.00,1154.00
IW76,297.40,0.40,2000.00,1154.00
VC37,177.33,0.21,1998.00,1284.00
S837,240.20,0.21,1998.00,1284.00
P437,241.11,0.21,1998.00,1284.00
M037,263.58,0.21,1998.00,1284.00
KG37,276.42,0.21,1998.00,1284.00
KG37,283.85,0.21,1998.00,1284.00
I would like to replace the values in column 4 of eche with the values in column 2 of eche.txt if the value in the first columns of the two files are the same but when not same I retain the line in eche file. I tried the following two scripts which works but fail to replace the value in column 4 of eche with the value in column 2 of eche.txt:
file1="eche"
file2="eche.txt"
awk -F',' 'NR==FNRa[$2]=$3 NR>FNR$2=a[$4];print' OFS=' ' "$file2" "$file1" > test
perl -F',s*' -lane '$k$F[0]=$F[1]; next if $#F < 6; s/$F[1]/$k$F[3]/; print' "$file2" "$file1" > test
Here is the desired output:
P476,0.10000000E+00,0.2837975332748E+08,241.06
VC76,0.10000000E+00,0.2837726135782E+08,207.64
KG37,0.10000000E+00,0.2611331725657E+08,283.85
M037,0.10000000E+00,0.2611370504845E+08,263.58
VC37,0.10000000E+00,0.2611374063470E+08,177.33
1K08,0.10000000E+00,0.2611346615238E+08,0.1846393014710E+03
1K05,0.10000000E+00,0.2610647023303E+08,0.1841342000212E+03
1K06,0.10000000E+00,0.2611103965949E+08,0.1845191988294E+03
1K07,0.10000000E+00,0.2611275589639E+08,0.1845173169920E+03
KG76,0.10000000E+00,0.2838117264779E+08,284.31
1K02,0.10000000E+00,0.2837950666778E+08,0.6757007619124E+02
1K10,0.10000000E+00,0.2610224473371E+08,0.1835417139884E+03
text-processing command-line awk perl
edited Nov 16 '17 at 13:04
igal
4,830930
4,830930
asked Nov 12 '17 at 15:23
eric
113
113
1
Could you add the desired output file for the given input files?
â igal
Nov 12 '17 at 16:30
It looks like the formatting on the first input file is incorrect - I don't think those line-breaks after the 3rd column are supposed to be there.
â igal
Nov 12 '17 at 16:30
Also, your header column for theetchfile looks pretty mangled. Are you sure that's what you want?
â igal
Nov 12 '17 at 16:45
it would be better if you posted the expected result
â RomanPerekhrest
Nov 12 '17 at 16:51
add a comment |Â
1
Could you add the desired output file for the given input files?
â igal
Nov 12 '17 at 16:30
It looks like the formatting on the first input file is incorrect - I don't think those line-breaks after the 3rd column are supposed to be there.
â igal
Nov 12 '17 at 16:30
Also, your header column for theetchfile looks pretty mangled. Are you sure that's what you want?
â igal
Nov 12 '17 at 16:45
it would be better if you posted the expected result
â RomanPerekhrest
Nov 12 '17 at 16:51
1
1
Could you add the desired output file for the given input files?
â igal
Nov 12 '17 at 16:30
Could you add the desired output file for the given input files?
â igal
Nov 12 '17 at 16:30
It looks like the formatting on the first input file is incorrect - I don't think those line-breaks after the 3rd column are supposed to be there.
â igal
Nov 12 '17 at 16:30
It looks like the formatting on the first input file is incorrect - I don't think those line-breaks after the 3rd column are supposed to be there.
â igal
Nov 12 '17 at 16:30
Also, your header column for the
etch file looks pretty mangled. Are you sure that's what you want?â igal
Nov 12 '17 at 16:45
Also, your header column for the
etch file looks pretty mangled. Are you sure that's what you want?â igal
Nov 12 '17 at 16:45
it would be better if you posted the expected result
â RomanPerekhrest
Nov 12 '17 at 16:51
it would be better if you posted the expected result
â RomanPerekhrest
Nov 12 '17 at 16:51
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
0
down vote
Here's a Python script that does what you want:
#!/usr/bin/env python2
# -*- coding: ascii -*-
"""eche.py"""
import csv
from collections import OrderedDict
# Open the first file
with open("eche", 'r') as csvfile1:
csvreader1 = csv.reader(csvfile1, delimiter=',')
# Skip the header row
next(csvreader1, None)
# Read the data into a dictionary,
# indexed by the value of the first column
rows1 = OrderedDict((row[0], row) for row in csvreader1)
# Open the second file
with open("eche.txt", 'r') as csvfile2:
# Read the data into a dictionary,
# indexed by the value of the first column
rows2 = row[0]: row for row in csv.reader(csvfile2, delimiter=',')
# Iterate through the rows of the first file
for key, row in rows1.iteritems():
# If the key from the first file matches a row in the second file,
# output the updated row
if key in rows2:
print(','.join(row[0:3] + [rows2[key][1]]))
# If the key from the first file does NOT match
# a row in the second file then output the row unchanged
else:
print(','.join(row))
Running this script with your example data produces the following output:
VC76,0.10000000E+00,0.2837726135782E+08,207.64
1K02,0.10000000E+00,0.2837950666778E+08,0.6757007619124E+02
P476,0.10000000E+00,0.2837975332748E+08,241.06
KG76,0.10000000E+00,0.2838117264779E+08,284.31
1K05,0.10000000E+00,0.2610647023303E+08,0.1841342000212E+03
1K06,0.10000000E+00,0.2611103965949E+08,0.1845191988294E+03
1K07,0.10000000E+00,0.2611275589639E+08,0.1845173169920E+03
1K08,0.10000000E+00,0.2611346615238E+08,0.1846393014710E+03
VC37,0.10000000E+00,0.2611374063470E+08,177.33
1K10,0.10000000E+00,0.2610224473371E+08,0.1835417139884E+03
M037,0.10000000E+00,0.2611370504845E+08,263.58
KG37,0.10000000E+00,0.2611331725657E+08,283.85
The script is okay but would like to retain the order of the values as original file
â eric
Nov 16 '17 at 8:19
@eric Updated. The order of the rows in the "eche" file is now preserved.
â igal
Nov 16 '17 at 12:03
supposing the one to be replaced is in column 3 it will print only up to column three and leave 4 blank. how do you you fix that?
â eric
Nov 16 '17 at 19:17
Any suggestions to fix it?
â eric
Nov 18 '17 at 8:15
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Here's a Python script that does what you want:
#!/usr/bin/env python2
# -*- coding: ascii -*-
"""eche.py"""
import csv
from collections import OrderedDict
# Open the first file
with open("eche", 'r') as csvfile1:
csvreader1 = csv.reader(csvfile1, delimiter=',')
# Skip the header row
next(csvreader1, None)
# Read the data into a dictionary,
# indexed by the value of the first column
rows1 = OrderedDict((row[0], row) for row in csvreader1)
# Open the second file
with open("eche.txt", 'r') as csvfile2:
# Read the data into a dictionary,
# indexed by the value of the first column
rows2 = row[0]: row for row in csv.reader(csvfile2, delimiter=',')
# Iterate through the rows of the first file
for key, row in rows1.iteritems():
# If the key from the first file matches a row in the second file,
# output the updated row
if key in rows2:
print(','.join(row[0:3] + [rows2[key][1]]))
# If the key from the first file does NOT match
# a row in the second file then output the row unchanged
else:
print(','.join(row))
Running this script with your example data produces the following output:
VC76,0.10000000E+00,0.2837726135782E+08,207.64
1K02,0.10000000E+00,0.2837950666778E+08,0.6757007619124E+02
P476,0.10000000E+00,0.2837975332748E+08,241.06
KG76,0.10000000E+00,0.2838117264779E+08,284.31
1K05,0.10000000E+00,0.2610647023303E+08,0.1841342000212E+03
1K06,0.10000000E+00,0.2611103965949E+08,0.1845191988294E+03
1K07,0.10000000E+00,0.2611275589639E+08,0.1845173169920E+03
1K08,0.10000000E+00,0.2611346615238E+08,0.1846393014710E+03
VC37,0.10000000E+00,0.2611374063470E+08,177.33
1K10,0.10000000E+00,0.2610224473371E+08,0.1835417139884E+03
M037,0.10000000E+00,0.2611370504845E+08,263.58
KG37,0.10000000E+00,0.2611331725657E+08,283.85
The script is okay but would like to retain the order of the values as original file
â eric
Nov 16 '17 at 8:19
@eric Updated. The order of the rows in the "eche" file is now preserved.
â igal
Nov 16 '17 at 12:03
supposing the one to be replaced is in column 3 it will print only up to column three and leave 4 blank. how do you you fix that?
â eric
Nov 16 '17 at 19:17
Any suggestions to fix it?
â eric
Nov 18 '17 at 8:15
add a comment |Â
up vote
0
down vote
Here's a Python script that does what you want:
#!/usr/bin/env python2
# -*- coding: ascii -*-
"""eche.py"""
import csv
from collections import OrderedDict
# Open the first file
with open("eche", 'r') as csvfile1:
csvreader1 = csv.reader(csvfile1, delimiter=',')
# Skip the header row
next(csvreader1, None)
# Read the data into a dictionary,
# indexed by the value of the first column
rows1 = OrderedDict((row[0], row) for row in csvreader1)
# Open the second file
with open("eche.txt", 'r') as csvfile2:
# Read the data into a dictionary,
# indexed by the value of the first column
rows2 = row[0]: row for row in csv.reader(csvfile2, delimiter=',')
# Iterate through the rows of the first file
for key, row in rows1.iteritems():
# If the key from the first file matches a row in the second file,
# output the updated row
if key in rows2:
print(','.join(row[0:3] + [rows2[key][1]]))
# If the key from the first file does NOT match
# a row in the second file then output the row unchanged
else:
print(','.join(row))
Running this script with your example data produces the following output:
VC76,0.10000000E+00,0.2837726135782E+08,207.64
1K02,0.10000000E+00,0.2837950666778E+08,0.6757007619124E+02
P476,0.10000000E+00,0.2837975332748E+08,241.06
KG76,0.10000000E+00,0.2838117264779E+08,284.31
1K05,0.10000000E+00,0.2610647023303E+08,0.1841342000212E+03
1K06,0.10000000E+00,0.2611103965949E+08,0.1845191988294E+03
1K07,0.10000000E+00,0.2611275589639E+08,0.1845173169920E+03
1K08,0.10000000E+00,0.2611346615238E+08,0.1846393014710E+03
VC37,0.10000000E+00,0.2611374063470E+08,177.33
1K10,0.10000000E+00,0.2610224473371E+08,0.1835417139884E+03
M037,0.10000000E+00,0.2611370504845E+08,263.58
KG37,0.10000000E+00,0.2611331725657E+08,283.85
The script is okay but would like to retain the order of the values as original file
â eric
Nov 16 '17 at 8:19
@eric Updated. The order of the rows in the "eche" file is now preserved.
â igal
Nov 16 '17 at 12:03
supposing the one to be replaced is in column 3 it will print only up to column three and leave 4 blank. how do you you fix that?
â eric
Nov 16 '17 at 19:17
Any suggestions to fix it?
â eric
Nov 18 '17 at 8:15
add a comment |Â
up vote
0
down vote
up vote
0
down vote
Here's a Python script that does what you want:
#!/usr/bin/env python2
# -*- coding: ascii -*-
"""eche.py"""
import csv
from collections import OrderedDict
# Open the first file
with open("eche", 'r') as csvfile1:
csvreader1 = csv.reader(csvfile1, delimiter=',')
# Skip the header row
next(csvreader1, None)
# Read the data into a dictionary,
# indexed by the value of the first column
rows1 = OrderedDict((row[0], row) for row in csvreader1)
# Open the second file
with open("eche.txt", 'r') as csvfile2:
# Read the data into a dictionary,
# indexed by the value of the first column
rows2 = row[0]: row for row in csv.reader(csvfile2, delimiter=',')
# Iterate through the rows of the first file
for key, row in rows1.iteritems():
# If the key from the first file matches a row in the second file,
# output the updated row
if key in rows2:
print(','.join(row[0:3] + [rows2[key][1]]))
# If the key from the first file does NOT match
# a row in the second file then output the row unchanged
else:
print(','.join(row))
Running this script with your example data produces the following output:
VC76,0.10000000E+00,0.2837726135782E+08,207.64
1K02,0.10000000E+00,0.2837950666778E+08,0.6757007619124E+02
P476,0.10000000E+00,0.2837975332748E+08,241.06
KG76,0.10000000E+00,0.2838117264779E+08,284.31
1K05,0.10000000E+00,0.2610647023303E+08,0.1841342000212E+03
1K06,0.10000000E+00,0.2611103965949E+08,0.1845191988294E+03
1K07,0.10000000E+00,0.2611275589639E+08,0.1845173169920E+03
1K08,0.10000000E+00,0.2611346615238E+08,0.1846393014710E+03
VC37,0.10000000E+00,0.2611374063470E+08,177.33
1K10,0.10000000E+00,0.2610224473371E+08,0.1835417139884E+03
M037,0.10000000E+00,0.2611370504845E+08,263.58
KG37,0.10000000E+00,0.2611331725657E+08,283.85
Here's a Python script that does what you want:
#!/usr/bin/env python2
# -*- coding: ascii -*-
"""eche.py"""
import csv
from collections import OrderedDict
# Open the first file
with open("eche", 'r') as csvfile1:
csvreader1 = csv.reader(csvfile1, delimiter=',')
# Skip the header row
next(csvreader1, None)
# Read the data into a dictionary,
# indexed by the value of the first column
rows1 = OrderedDict((row[0], row) for row in csvreader1)
# Open the second file
with open("eche.txt", 'r') as csvfile2:
# Read the data into a dictionary,
# indexed by the value of the first column
rows2 = row[0]: row for row in csv.reader(csvfile2, delimiter=',')
# Iterate through the rows of the first file
for key, row in rows1.iteritems():
# If the key from the first file matches a row in the second file,
# output the updated row
if key in rows2:
print(','.join(row[0:3] + [rows2[key][1]]))
# If the key from the first file does NOT match
# a row in the second file then output the row unchanged
else:
print(','.join(row))
Running this script with your example data produces the following output:
VC76,0.10000000E+00,0.2837726135782E+08,207.64
1K02,0.10000000E+00,0.2837950666778E+08,0.6757007619124E+02
P476,0.10000000E+00,0.2837975332748E+08,241.06
KG76,0.10000000E+00,0.2838117264779E+08,284.31
1K05,0.10000000E+00,0.2610647023303E+08,0.1841342000212E+03
1K06,0.10000000E+00,0.2611103965949E+08,0.1845191988294E+03
1K07,0.10000000E+00,0.2611275589639E+08,0.1845173169920E+03
1K08,0.10000000E+00,0.2611346615238E+08,0.1846393014710E+03
VC37,0.10000000E+00,0.2611374063470E+08,177.33
1K10,0.10000000E+00,0.2610224473371E+08,0.1835417139884E+03
M037,0.10000000E+00,0.2611370504845E+08,263.58
KG37,0.10000000E+00,0.2611331725657E+08,283.85
edited Nov 16 '17 at 12:02
answered Nov 12 '17 at 16:28
igal
4,830930
4,830930
The script is okay but would like to retain the order of the values as original file
â eric
Nov 16 '17 at 8:19
@eric Updated. The order of the rows in the "eche" file is now preserved.
â igal
Nov 16 '17 at 12:03
supposing the one to be replaced is in column 3 it will print only up to column three and leave 4 blank. how do you you fix that?
â eric
Nov 16 '17 at 19:17
Any suggestions to fix it?
â eric
Nov 18 '17 at 8:15
add a comment |Â
The script is okay but would like to retain the order of the values as original file
â eric
Nov 16 '17 at 8:19
@eric Updated. The order of the rows in the "eche" file is now preserved.
â igal
Nov 16 '17 at 12:03
supposing the one to be replaced is in column 3 it will print only up to column three and leave 4 blank. how do you you fix that?
â eric
Nov 16 '17 at 19:17
Any suggestions to fix it?
â eric
Nov 18 '17 at 8:15
The script is okay but would like to retain the order of the values as original file
â eric
Nov 16 '17 at 8:19
The script is okay but would like to retain the order of the values as original file
â eric
Nov 16 '17 at 8:19
@eric Updated. The order of the rows in the "eche" file is now preserved.
â igal
Nov 16 '17 at 12:03
@eric Updated. The order of the rows in the "eche" file is now preserved.
â igal
Nov 16 '17 at 12:03
supposing the one to be replaced is in column 3 it will print only up to column three and leave 4 blank. how do you you fix that?
â eric
Nov 16 '17 at 19:17
supposing the one to be replaced is in column 3 it will print only up to column three and leave 4 blank. how do you you fix that?
â eric
Nov 16 '17 at 19:17
Any suggestions to fix it?
â eric
Nov 18 '17 at 8:15
Any suggestions to fix it?
â eric
Nov 18 '17 at 8:15
add a comment |Â
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1
Could you add the desired output file for the given input files?
â igal
Nov 12 '17 at 16:30
It looks like the formatting on the first input file is incorrect - I don't think those line-breaks after the 3rd column are supposed to be there.
â igal
Nov 12 '17 at 16:30
Also, your header column for the
etchfile looks pretty mangled. Are you sure that's what you want?â igal
Nov 12 '17 at 16:45
it would be better if you posted the expected result
â RomanPerekhrest
Nov 12 '17 at 16:51