Bash - issue with grep conditional statement

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
0
down vote

favorite












Why does this code work correctly, while the other version of the same condition doesn't?



if grep -q string file; then
echo found
else
echo not found
fi


This doesn't work:



if [ ! `grep -q string file` ]; then
echo not found
else
echo found
fi






share|improve this question


















  • 1




    Why have you changed the syntax on the two examples?, just a ! to your original example
    – Raman Sailopal
    Oct 20 '17 at 9:04










  • Do you know what -q does, or are you just blindly using it because you've seen others use it?
    – chepner
    Oct 21 '17 at 1:27














up vote
0
down vote

favorite












Why does this code work correctly, while the other version of the same condition doesn't?



if grep -q string file; then
echo found
else
echo not found
fi


This doesn't work:



if [ ! `grep -q string file` ]; then
echo not found
else
echo found
fi






share|improve this question


















  • 1




    Why have you changed the syntax on the two examples?, just a ! to your original example
    – Raman Sailopal
    Oct 20 '17 at 9:04










  • Do you know what -q does, or are you just blindly using it because you've seen others use it?
    – chepner
    Oct 21 '17 at 1:27












up vote
0
down vote

favorite









up vote
0
down vote

favorite











Why does this code work correctly, while the other version of the same condition doesn't?



if grep -q string file; then
echo found
else
echo not found
fi


This doesn't work:



if [ ! `grep -q string file` ]; then
echo not found
else
echo found
fi






share|improve this question














Why does this code work correctly, while the other version of the same condition doesn't?



if grep -q string file; then
echo found
else
echo not found
fi


This doesn't work:



if [ ! `grep -q string file` ]; then
echo not found
else
echo found
fi








share|improve this question













share|improve this question




share|improve this question








edited Oct 20 '17 at 9:27









Jeff Schaller

32.1k849109




32.1k849109










asked Oct 20 '17 at 8:56









asd

33




33







  • 1




    Why have you changed the syntax on the two examples?, just a ! to your original example
    – Raman Sailopal
    Oct 20 '17 at 9:04










  • Do you know what -q does, or are you just blindly using it because you've seen others use it?
    – chepner
    Oct 21 '17 at 1:27












  • 1




    Why have you changed the syntax on the two examples?, just a ! to your original example
    – Raman Sailopal
    Oct 20 '17 at 9:04










  • Do you know what -q does, or are you just blindly using it because you've seen others use it?
    – chepner
    Oct 21 '17 at 1:27







1




1




Why have you changed the syntax on the two examples?, just a ! to your original example
– Raman Sailopal
Oct 20 '17 at 9:04




Why have you changed the syntax on the two examples?, just a ! to your original example
– Raman Sailopal
Oct 20 '17 at 9:04












Do you know what -q does, or are you just blindly using it because you've seen others use it?
– chepner
Oct 21 '17 at 1:27




Do you know what -q does, or are you just blindly using it because you've seen others use it?
– chepner
Oct 21 '17 at 1:27










1 Answer
1






active

oldest

votes

















up vote
5
down vote



accepted










`grep -q string file`, in backticks (or inside $(...), which is preferable), will be replaced by the output of grep. This will be an empty string since -q is used.



To negate a test, just insert ! before it:



if ! grep -q pattern file; then
echo not found
else
echo found
fi


If you truly want to search for a string (rather than a regular expression), then you should use -F with grep as well.






share|improve this answer






















    Your Answer







    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "106"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    convertImagesToLinks: false,
    noModals: false,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













     

    draft saved


    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f399303%2fbash-issue-with-grep-conditional-statement%23new-answer', 'question_page');

    );

    Post as a guest






























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    5
    down vote



    accepted










    `grep -q string file`, in backticks (or inside $(...), which is preferable), will be replaced by the output of grep. This will be an empty string since -q is used.



    To negate a test, just insert ! before it:



    if ! grep -q pattern file; then
    echo not found
    else
    echo found
    fi


    If you truly want to search for a string (rather than a regular expression), then you should use -F with grep as well.






    share|improve this answer


























      up vote
      5
      down vote



      accepted










      `grep -q string file`, in backticks (or inside $(...), which is preferable), will be replaced by the output of grep. This will be an empty string since -q is used.



      To negate a test, just insert ! before it:



      if ! grep -q pattern file; then
      echo not found
      else
      echo found
      fi


      If you truly want to search for a string (rather than a regular expression), then you should use -F with grep as well.






      share|improve this answer
























        up vote
        5
        down vote



        accepted







        up vote
        5
        down vote



        accepted






        `grep -q string file`, in backticks (or inside $(...), which is preferable), will be replaced by the output of grep. This will be an empty string since -q is used.



        To negate a test, just insert ! before it:



        if ! grep -q pattern file; then
        echo not found
        else
        echo found
        fi


        If you truly want to search for a string (rather than a regular expression), then you should use -F with grep as well.






        share|improve this answer














        `grep -q string file`, in backticks (or inside $(...), which is preferable), will be replaced by the output of grep. This will be an empty string since -q is used.



        To negate a test, just insert ! before it:



        if ! grep -q pattern file; then
        echo not found
        else
        echo found
        fi


        If you truly want to search for a string (rather than a regular expression), then you should use -F with grep as well.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Oct 20 '17 at 11:07

























        answered Oct 20 '17 at 9:19









        Kusalananda

        105k14209326




        105k14209326



























             

            draft saved


            draft discarded















































             


            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f399303%2fbash-issue-with-grep-conditional-statement%23new-answer', 'question_page');

            );

            Post as a guest













































































            Popular posts from this blog

            How to check contact read email or not when send email to Individual?

            Bahrain

            Postfix configuration issue with fips on centos 7; mailgun relay