bash + how to increment variables that contain letters a..z

up vote
0
down vote

favorite

how to increment variables - $var that contain the letters a..z

example:

 var=(b..z)
 for x in 1 2 3 4 5
 do
 echo $x,$var

 $var++ ( this is wrong but I need to do something like this )

 done

expected output:

 1,b
 2,c
 3,d
 4,e
 5,f
 .
 .
 .

asked Oct 2 '17 at 17:01

yael

2,0361145

add a commentÂ |Â

up vote
0
down vote

favorite

how to increment variables - $var that contain the letters a..z

example:

 var=(b..z)
 for x in 1 2 3 4 5
 do
 echo $x,$var

 $var++ ( this is wrong but I need to do something like this )

 done

expected output:

 1,b
 2,c
 3,d
 4,e
 5,f
 .
 .
 .

asked Oct 2 '17 at 17:01

yael

2,0361145

add a commentÂ |Â

up vote
0
down vote

favorite

how to increment variables - $var that contain the letters a..z

example:

 var=(b..z)
 for x in 1 2 3 4 5
 do
 echo $x,$var

 $var++ ( this is wrong but I need to do something like this )

 done

expected output:

 1,b
 2,c
 3,d
 4,e
 5,f
 .
 .
 .

asked Oct 2 '17 at 17:01

yael

2,0361145

how to increment variables - $var that contain the letters a..z

example:

 var=(b..z)
 for x in 1 2 3 4 5
 do
 echo $x,$var

 $var++ ( this is wrong but I need to do something like this )

 done

expected output:

 1,b
 2,c
 3,d
 4,e
 5,f
 .
 .
 .

linux bash shell-script rhel

asked Oct 2 '17 at 17:01

yael

2,0361145

asked Oct 2 '17 at 17:01

yael

2,0361145

asked Oct 2 '17 at 17:01

yael

2,0361145

asked Oct 2 '17 at 17:01

yael

2,0361145

asked Oct 2 '17 at 17:01

yael

2,0361145

add a commentÂ |Â

3 Answers
3

active

oldest

votes

up vote
5
down vote

accepted

The simple way:

echo "$x,$var"
var="$(echo $var | tr '[a-y]z' '[b-z]a')"

edited Oct 2 '17 at 20:48

answered Oct 2 '17 at 17:06

DopeGhoti

41k55080

why trailing a in [...]a ?
â€“Â RomanPerekhrest
Oct 2 '17 at 17:36

2

Absent direction for what an "incremented" z would become, I opted to have it "wrap around" to a.
â€“Â DopeGhoti
Oct 2 '17 at 18:19

1

In POSIX compliant tr implementations, that would convert z to ]. POSIXly: tr a-z b-za. To be compatible with both POSIX and SysV: tr '[a-y]z' '[b-z]a'
â€“Â StÃ©phane Chazelas
Oct 2 '17 at 19:43

add a commentÂ |Â

up vote
2
down vote

You have an array; just index it:

var=( b..z )
for ((x=0; x<5; x++)); do
 echo "$x, $var[x+1]"
done

answered Oct 3 '17 at 1:31

chepner

5,1801223

add a commentÂ |Â

up vote
1
down vote

paste -d, <( printf "%sn" 1..25 ) <( printf "%sn" b..z )

producing:

1,b
2,c
3,d
4,e
5,f
6,g
.
.

For a system like:

OS, ker|rel, machine: Linux, 3.16.0-4-amd64, x86_64
Distribution : Debian 8.9 (jessie) 
bash GNU bash 4.3.30
paste (GNU coreutils) 8.23

answered Oct 2 '17 at 21:50

drl

45225

add a commentÂ |Â

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

up vote
5
down vote

accepted

The simple way:

echo "$x,$var"
var="$(echo $var | tr '[a-y]z' '[b-z]a')"

edited Oct 2 '17 at 20:48

answered Oct 2 '17 at 17:06

DopeGhoti

41k55080

why trailing a in [...]a ?
â€“Â RomanPerekhrest
Oct 2 '17 at 17:36

2

Absent direction for what an "incremented" z would become, I opted to have it "wrap around" to a.
â€“Â DopeGhoti
Oct 2 '17 at 18:19

1

In POSIX compliant tr implementations, that would convert z to ]. POSIXly: tr a-z b-za. To be compatible with both POSIX and SysV: tr '[a-y]z' '[b-z]a'
â€“Â StÃ©phane Chazelas
Oct 2 '17 at 19:43

add a commentÂ |Â

up vote
5
down vote

accepted

The simple way:

echo "$x,$var"
var="$(echo $var | tr '[a-y]z' '[b-z]a')"

edited Oct 2 '17 at 20:48

answered Oct 2 '17 at 17:06

DopeGhoti

41k55080

why trailing a in [...]a ?
â€“Â RomanPerekhrest
Oct 2 '17 at 17:36

2

Absent direction for what an "incremented" z would become, I opted to have it "wrap around" to a.
â€“Â DopeGhoti
Oct 2 '17 at 18:19

1

In POSIX compliant tr implementations, that would convert z to ]. POSIXly: tr a-z b-za. To be compatible with both POSIX and SysV: tr '[a-y]z' '[b-z]a'
â€“Â StÃ©phane Chazelas
Oct 2 '17 at 19:43

add a commentÂ |Â

up vote
5
down vote

accepted

The simple way:

echo "$x,$var"
var="$(echo $var | tr '[a-y]z' '[b-z]a')"

edited Oct 2 '17 at 20:48

answered Oct 2 '17 at 17:06

DopeGhoti

41k55080

The simple way:

echo "$x,$var"
var="$(echo $var | tr '[a-y]z' '[b-z]a')"

edited Oct 2 '17 at 20:48

answered Oct 2 '17 at 17:06

DopeGhoti

41k55080

edited Oct 2 '17 at 20:48

answered Oct 2 '17 at 17:06

DopeGhoti

41k55080

answered Oct 2 '17 at 17:06

DopeGhoti

41k55080

answered Oct 2 '17 at 17:06

DopeGhoti

41k55080

why trailing a in [...]a ?
â€“Â RomanPerekhrest
Oct 2 '17 at 17:36

2

Absent direction for what an "incremented" z would become, I opted to have it "wrap around" to a.
â€“Â DopeGhoti
Oct 2 '17 at 18:19

1

In POSIX compliant tr implementations, that would convert z to ]. POSIXly: tr a-z b-za. To be compatible with both POSIX and SysV: tr '[a-y]z' '[b-z]a'
â€“Â StÃ©phane Chazelas
Oct 2 '17 at 19:43

add a commentÂ |Â

why trailing a in [...]a ?
â€“Â RomanPerekhrest
Oct 2 '17 at 17:36

2

Absent direction for what an "incremented" z would become, I opted to have it "wrap around" to a.
â€“Â DopeGhoti
Oct 2 '17 at 18:19

1

In POSIX compliant tr implementations, that would convert z to ]. POSIXly: tr a-z b-za. To be compatible with both POSIX and SysV: tr '[a-y]z' '[b-z]a'
â€“Â StÃ©phane Chazelas
Oct 2 '17 at 19:43

why trailing a in [...]a ?
â€“Â RomanPerekhrest
Oct 2 '17 at 17:36

Absent direction for what an "incremented" z would become, I opted to have it "wrap around" to a.
â€“Â DopeGhoti
Oct 2 '17 at 18:19

In POSIX compliant tr implementations, that would convert z to ]. POSIXly: tr a-z b-za. To be compatible with both POSIX and SysV: tr '[a-y]z' '[b-z]a'
â€“Â StÃ©phane Chazelas
Oct 2 '17 at 19:43

add a commentÂ |Â

up vote
2
down vote

You have an array; just index it:

var=( b..z )
for ((x=0; x<5; x++)); do
 echo "$x, $var[x+1]"
done

answered Oct 3 '17 at 1:31

chepner

5,1801223

add a commentÂ |Â

up vote
2
down vote

You have an array; just index it:

var=( b..z )
for ((x=0; x<5; x++)); do
 echo "$x, $var[x+1]"
done

answered Oct 3 '17 at 1:31

chepner

5,1801223

add a commentÂ |Â

up vote
2
down vote

You have an array; just index it:

var=( b..z )
for ((x=0; x<5; x++)); do
 echo "$x, $var[x+1]"
done

answered Oct 3 '17 at 1:31

chepner

5,1801223

You have an array; just index it:

var=( b..z )
for ((x=0; x<5; x++)); do
 echo "$x, $var[x+1]"
done

answered Oct 3 '17 at 1:31

chepner

5,1801223

answered Oct 3 '17 at 1:31

chepner

5,1801223

answered Oct 3 '17 at 1:31

chepner

5,1801223

answered Oct 3 '17 at 1:31

chepner

5,1801223

add a commentÂ |Â

up vote
1
down vote

paste -d, <( printf "%sn" 1..25 ) <( printf "%sn" b..z )

producing:

1,b
2,c
3,d
4,e
5,f
6,g
.
.

For a system like:

OS, ker|rel, machine: Linux, 3.16.0-4-amd64, x86_64
Distribution : Debian 8.9 (jessie) 
bash GNU bash 4.3.30
paste (GNU coreutils) 8.23

answered Oct 2 '17 at 21:50

drl

45225

add a commentÂ |Â

up vote
1
down vote

paste -d, <( printf "%sn" 1..25 ) <( printf "%sn" b..z )

producing:

1,b
2,c
3,d
4,e
5,f
6,g
.
.

For a system like:

OS, ker|rel, machine: Linux, 3.16.0-4-amd64, x86_64
Distribution : Debian 8.9 (jessie) 
bash GNU bash 4.3.30
paste (GNU coreutils) 8.23

answered Oct 2 '17 at 21:50

drl

45225

add a commentÂ |Â

up vote
1
down vote

paste -d, <( printf "%sn" 1..25 ) <( printf "%sn" b..z )

producing:

1,b
2,c
3,d
4,e
5,f
6,g
.
.

For a system like:

OS, ker|rel, machine: Linux, 3.16.0-4-amd64, x86_64
Distribution : Debian 8.9 (jessie) 
bash GNU bash 4.3.30
paste (GNU coreutils) 8.23

answered Oct 2 '17 at 21:50

drl

45225

paste -d, <( printf "%sn" 1..25 ) <( printf "%sn" b..z )

producing:

1,b
2,c
3,d
4,e
5,f
6,g
.
.

For a system like:

OS, ker|rel, machine: Linux, 3.16.0-4-amd64, x86_64
Distribution : Debian 8.9 (jessie) 
bash GNU bash 4.3.30
paste (GNU coreutils) 8.23

answered Oct 2 '17 at 21:50

drl

45225

answered Oct 2 '17 at 21:50

drl

45225

answered Oct 2 '17 at 21:50

drl

45225

answered Oct 2 '17 at 21:50

drl

45225

add a commentÂ |Â

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