grep multiple entries in openvpn.log
Clash Royale CLAN TAG#URR8PPP
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-1
down vote
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i need to determine which clients tried to connect to openvpn
$ grep -e 'client[1-20]' openvpn.log | sed 's/^.*client/client/'
gives me
client16
client16
client12_pool_defined = DISABLED
client12'/var/run/openvpn.pid'
client13
client15
client16
client16
any idea how to remove duplicate entries just leaving client12, client13 and so on?
bash sed grep openvpn
asked Apr 19 at 4:10
toxikas
6
add a comment |Â
up vote
-1
down vote
favorite
i need to determine which clients tried to connect to openvpn
$ grep -e 'client[1-20]' openvpn.log | sed 's/^.*client/client/'
gives me
client16
client16
client12_pool_defined = DISABLED
client12'/var/run/openvpn.pid'
client13
client15
client16
client16
any idea how to remove duplicate entries just leaving client12, client13 and so on?
bash sed grep openvpn
asked Apr 19 at 4:10
toxikas
6
Does adding| uniqgive you the expected output or is further sorting needed?
– Mikael Kjær
Apr 19 at 4:19
add a comment |Â
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
i need to determine which clients tried to connect to openvpn
$ grep -e 'client[1-20]' openvpn.log | sed 's/^.*client/client/'
gives me
client16
client16
client12_pool_defined = DISABLED
client12'/var/run/openvpn.pid'
client13
client15
client16
client16
any idea how to remove duplicate entries just leaving client12, client13 and so on?
bash sed grep openvpn
asked Apr 19 at 4:10
toxikas
6
i need to determine which clients tried to connect to openvpn
$ grep -e 'client[1-20]' openvpn.log | sed 's/^.*client/client/'
gives me
client16
client16
client12_pool_defined = DISABLED
client12'/var/run/openvpn.pid'
client13
client15
client16
client16
any idea how to remove duplicate entries just leaving client12, client13 and so on?
bash sed grep openvpn
asked Apr 19 at 4:10
toxikas
6
asked Apr 19 at 4:10
toxikas
6
asked Apr 19 at 4:10
toxikas
6
asked Apr 19 at 4:10
toxikas
6
6
Does adding| uniqgive you the expected output or is further sorting needed?
– Mikael Kjær
Apr 19 at 4:19
add a comment |Â
Does adding| uniqgive you the expected output or is further sorting needed?
– Mikael Kjær
Apr 19 at 4:19
Does adding
| uniq give you the expected output or is further sorting needed?– Mikael Kjær
Apr 19 at 4:19
Does adding
| uniq give you the expected output or is further sorting needed?– Mikael Kjær
Apr 19 at 4:19
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
1
down vote
First: grep 'client[1-20]' does not look for client followed by numbers between 1 and 20. It looks for client followed by any character out of 0, 1 and 2. Using grep for a range of numbers is cumbersome and dealt with multiple times in this site. See, for example, Grep for range of numbers, Looking to grep or egrep year ranges from 1965-1996, etc.
If you want just unique entries, use sort -u or sort | uniq.
Combined, something like (assuming zero-padded numbers):
grep -Eo 'client([01][1-9]|20)' | sort -u
answered Apr 19 at 4:30
Olorin
1,15711
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
First: grep 'client[1-20]' does not look for client followed by numbers between 1 and 20. It looks for client followed by any character out of 0, 1 and 2. Using grep for a range of numbers is cumbersome and dealt with multiple times in this site. See, for example, Grep for range of numbers, Looking to grep or egrep year ranges from 1965-1996, etc.
If you want just unique entries, use sort -u or sort | uniq.
Combined, something like (assuming zero-padded numbers):
grep -Eo 'client([01][1-9]|20)' | sort -u
answered Apr 19 at 4:30
Olorin
1,15711
add a comment |Â
up vote
1
down vote
First: grep 'client[1-20]' does not look for client followed by numbers between 1 and 20. It looks for client followed by any character out of 0, 1 and 2. Using grep for a range of numbers is cumbersome and dealt with multiple times in this site. See, for example, Grep for range of numbers, Looking to grep or egrep year ranges from 1965-1996, etc.
If you want just unique entries, use sort -u or sort | uniq.
Combined, something like (assuming zero-padded numbers):
grep -Eo 'client([01][1-9]|20)' | sort -u
answered Apr 19 at 4:30
Olorin
1,15711
add a comment |Â
up vote
1
down vote
up vote
1
down vote
First: grep 'client[1-20]' does not look for client followed by numbers between 1 and 20. It looks for client followed by any character out of 0, 1 and 2. Using grep for a range of numbers is cumbersome and dealt with multiple times in this site. See, for example, Grep for range of numbers, Looking to grep or egrep year ranges from 1965-1996, etc.
If you want just unique entries, use sort -u or sort | uniq.
Combined, something like (assuming zero-padded numbers):
grep -Eo 'client([01][1-9]|20)' | sort -u
answered Apr 19 at 4:30
Olorin
1,15711
First: grep 'client[1-20]' does not look for client followed by numbers between 1 and 20. It looks for client followed by any character out of 0, 1 and 2. Using grep for a range of numbers is cumbersome and dealt with multiple times in this site. See, for example, Grep for range of numbers, Looking to grep or egrep year ranges from 1965-1996, etc.
If you want just unique entries, use sort -u or sort | uniq.
Combined, something like (assuming zero-padded numbers):
grep -Eo 'client([01][1-9]|20)' | sort -u
answered Apr 19 at 4:30
Olorin
1,15711
answered Apr 19 at 4:30
Olorin
1,15711
answered Apr 19 at 4:30
Olorin
1,15711
answered Apr 19 at 4:30
Olorin
1,15711
1,15711
add a comment |Â
add a comment |Â
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Does adding
| uniqgive you the expected output or is further sorting needed?– Mikael Kjær
Apr 19 at 4:19