Why do we interpret the accelerated expansion of the universe as the proof for the existence of dark energy?
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Why do we interpret the accelerated expansion of the universe as the proof for the existence of dark energy?
The accelerated expansion only tells us that the Einstein field equation must contain a cosmological constant, but I can put the constant on either side of the equation. Usually we put it on the right hand side and interpret it as an additional contribution to energy, namely dark energy. But if I put it in the left hand side instead, I would have a theory of gravity that explains both the "small scale" success of general relativity and the large scale expansion of the universe, without needing an element like dark energy.
So why do we keep saying that there is this dark energy and trying to identify it as the vacuum energy while we could more elegantly (in my opinion) use a theory of gravity with a cosmological constant and explain all observations?
general-relativity cosmology space-expansion dark-energy cosmological-constant
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add a comment |
$begingroup$
Why do we interpret the accelerated expansion of the universe as the proof for the existence of dark energy?
The accelerated expansion only tells us that the Einstein field equation must contain a cosmological constant, but I can put the constant on either side of the equation. Usually we put it on the right hand side and interpret it as an additional contribution to energy, namely dark energy. But if I put it in the left hand side instead, I would have a theory of gravity that explains both the "small scale" success of general relativity and the large scale expansion of the universe, without needing an element like dark energy.
So why do we keep saying that there is this dark energy and trying to identify it as the vacuum energy while we could more elegantly (in my opinion) use a theory of gravity with a cosmological constant and explain all observations?
general-relativity cosmology space-expansion dark-energy cosmological-constant
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Comments are not for extended discussion; this conversation has been moved to chat.
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– David Z♦
Feb 22 at 5:39
1
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I have spoken to numerous "inhomogeneous cosmologists" about this, and many of them indeed prefer to think of the cosmological constant $Lambda$ as a gravity effect (LHS of the Einstein field equations) rather than a matter/energy fluid (RHS of the equations). [Also a few of them hope to explain away dark energy altogether.]
$endgroup$
– Colin MacLaurin
Feb 27 at 1:44
add a comment |
$begingroup$
Why do we interpret the accelerated expansion of the universe as the proof for the existence of dark energy?
The accelerated expansion only tells us that the Einstein field equation must contain a cosmological constant, but I can put the constant on either side of the equation. Usually we put it on the right hand side and interpret it as an additional contribution to energy, namely dark energy. But if I put it in the left hand side instead, I would have a theory of gravity that explains both the "small scale" success of general relativity and the large scale expansion of the universe, without needing an element like dark energy.
So why do we keep saying that there is this dark energy and trying to identify it as the vacuum energy while we could more elegantly (in my opinion) use a theory of gravity with a cosmological constant and explain all observations?
general-relativity cosmology space-expansion dark-energy cosmological-constant
$endgroup$
Why do we interpret the accelerated expansion of the universe as the proof for the existence of dark energy?
The accelerated expansion only tells us that the Einstein field equation must contain a cosmological constant, but I can put the constant on either side of the equation. Usually we put it on the right hand side and interpret it as an additional contribution to energy, namely dark energy. But if I put it in the left hand side instead, I would have a theory of gravity that explains both the "small scale" success of general relativity and the large scale expansion of the universe, without needing an element like dark energy.
So why do we keep saying that there is this dark energy and trying to identify it as the vacuum energy while we could more elegantly (in my opinion) use a theory of gravity with a cosmological constant and explain all observations?
general-relativity cosmology space-expansion dark-energy cosmological-constant
general-relativity cosmology space-expansion dark-energy cosmological-constant
edited Mar 6 at 14:37
knzhou
45.1k11122219
45.1k11122219
asked Feb 21 at 15:11
Run like hellRun like hell
1,488727
1,488727
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Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– David Z♦
Feb 22 at 5:39
1
$begingroup$
I have spoken to numerous "inhomogeneous cosmologists" about this, and many of them indeed prefer to think of the cosmological constant $Lambda$ as a gravity effect (LHS of the Einstein field equations) rather than a matter/energy fluid (RHS of the equations). [Also a few of them hope to explain away dark energy altogether.]
$endgroup$
– Colin MacLaurin
Feb 27 at 1:44
add a comment |
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– David Z♦
Feb 22 at 5:39
1
$begingroup$
I have spoken to numerous "inhomogeneous cosmologists" about this, and many of them indeed prefer to think of the cosmological constant $Lambda$ as a gravity effect (LHS of the Einstein field equations) rather than a matter/energy fluid (RHS of the equations). [Also a few of them hope to explain away dark energy altogether.]
$endgroup$
– Colin MacLaurin
Feb 27 at 1:44
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– David Z♦
Feb 22 at 5:39
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– David Z♦
Feb 22 at 5:39
1
1
$begingroup$
I have spoken to numerous "inhomogeneous cosmologists" about this, and many of them indeed prefer to think of the cosmological constant $Lambda$ as a gravity effect (LHS of the Einstein field equations) rather than a matter/energy fluid (RHS of the equations). [Also a few of them hope to explain away dark energy altogether.]
$endgroup$
– Colin MacLaurin
Feb 27 at 1:44
$begingroup$
I have spoken to numerous "inhomogeneous cosmologists" about this, and many of them indeed prefer to think of the cosmological constant $Lambda$ as a gravity effect (LHS of the Einstein field equations) rather than a matter/energy fluid (RHS of the equations). [Also a few of them hope to explain away dark energy altogether.]
$endgroup$
– Colin MacLaurin
Feb 27 at 1:44
add a comment |
1 Answer
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oldest
votes
$begingroup$
The accelerated expansion of the universe is not direct evidence for dark energy, i.e. a perfect fluid contribution to the stress-energy tensor with $w = -1$. Dark energy is just by far the simplest thing that fits the data well.
It's simple to cosmologists because they are used to dealing with matter in the form of perfect fluids, and dark energy is just another one. And it's simple to particle physicists because it can be sourced by a constant term in the Lagrangian, the simplest possible term.
At the classical level, the distinction you're making is not really important. A cosmological constant, which you call a "modification of gravity", amounts to adding a constant term to the Lagrangian. But the standard description of dark energy also amounts to adding a constant term to the Lagrangian. They're the exact same thing -- a constant is a constant, it doesn't come with a little tag saying if it's "from" gravity or something else. Neither is more elegant because functionally all the equations come out the same. It's a philosophical difference, not a real difference.
But the situation changes dramatically when you account for quantum effects. That's because we know that QFT generically produces vacuum energy, i.e. sources a constant term in the Lagrangian, whether or not we put that term in classically or not. So even if you do explain the accelerated expansion by some other mechanism, you have to explain why this one isn't in effect. This is a difficult argument to make, because the contribution from QFT is already too big even if you only trust it up to tiny energy scales like $1 text eV$!
Of course, there is room to work on alternative theories, such as quintessence and phantom energy; these are functionally different because they correspond to a perfect fluid with $w neq -1$. At present, observational constraints show that the acceleration can only be explained by one additional perfect fluid if that component has $w = -1$ to within about 20% accuracy. If you wish, you can think of these theories as a modification of gravity by just moving their contributions to the other side of the Einstein field equation.
My impression is that these theories simply ignore the QFT vacuum energy without explanation. That's the real elephant in the room, and probably the reason so few physicists work on explaining the accelerated expansion. We have an automatic mechanism to explain the expansion, and that mechanism appears to be $10^120$ times more powerful than it should be. It seems premature to start to consider additional mechanisms before understanding this one first, and there seems to be no possible understanding of it now except via the much-hated anthropic principle. The ultimate explanation of the expansion will be a job for physicists of another millenium.
$endgroup$
$begingroup$
Well done, I just wanted to point out that the quintessence is not the only theory put forward to explain the cosmological constant problem, I think that, maybe, the most promising one is Quantum Cosmology, as Weinberg pointed out in his 1989's paper: "The cosmological constant problem"
$endgroup$
– Kevin De Notariis
Feb 21 at 16:38
2
$begingroup$
Wait, did I read it correctly that vacuum energy is some ~$10^120$ times more powerful than dark energy? I'm not a physicist but I feel like I've never even seen a number that big in terms of energy scales in real-world physics.
$endgroup$
– Mehrdad
Feb 21 at 21:34
$begingroup$
@Mehrdad That is the most naive estimate, if you estimate the vacuum energy density is $M_textpl^4$. But even if you just consider the electron's contribution, of the order $m_e^4$, it's still about $10^80$ times too big.
$endgroup$
– knzhou
Feb 21 at 21:36
$begingroup$
@Mehrdad Part of the largeness is that we are taking the fourth power to get an energy density, because that's how the parameter appears in the Lagrangian. Even phrased in terms of mass scales, for the electron the mass scale ratio is $10^20$, which is still outrageous.
$endgroup$
– knzhou
Feb 21 at 21:37
4
$begingroup$
@JeppeStigNielsen Possibly, or possibly not. If you think you've solved the problem, but you miss even a single particle, then the contribution of that particle alone will make the term, say, $10^100$ times too big. So at least naively, it appears you would have to know everything, including how quantum gravity works, before tackling this problem, because the vacuum energy depends on everything. In other words, this thing is at the very top of the tech tree of physics; it is the last thing to do. Still, there could definitely be a sneaky way out.
$endgroup$
– knzhou
Feb 21 at 22:54
|
show 2 more comments
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$begingroup$
The accelerated expansion of the universe is not direct evidence for dark energy, i.e. a perfect fluid contribution to the stress-energy tensor with $w = -1$. Dark energy is just by far the simplest thing that fits the data well.
It's simple to cosmologists because they are used to dealing with matter in the form of perfect fluids, and dark energy is just another one. And it's simple to particle physicists because it can be sourced by a constant term in the Lagrangian, the simplest possible term.
At the classical level, the distinction you're making is not really important. A cosmological constant, which you call a "modification of gravity", amounts to adding a constant term to the Lagrangian. But the standard description of dark energy also amounts to adding a constant term to the Lagrangian. They're the exact same thing -- a constant is a constant, it doesn't come with a little tag saying if it's "from" gravity or something else. Neither is more elegant because functionally all the equations come out the same. It's a philosophical difference, not a real difference.
But the situation changes dramatically when you account for quantum effects. That's because we know that QFT generically produces vacuum energy, i.e. sources a constant term in the Lagrangian, whether or not we put that term in classically or not. So even if you do explain the accelerated expansion by some other mechanism, you have to explain why this one isn't in effect. This is a difficult argument to make, because the contribution from QFT is already too big even if you only trust it up to tiny energy scales like $1 text eV$!
Of course, there is room to work on alternative theories, such as quintessence and phantom energy; these are functionally different because they correspond to a perfect fluid with $w neq -1$. At present, observational constraints show that the acceleration can only be explained by one additional perfect fluid if that component has $w = -1$ to within about 20% accuracy. If you wish, you can think of these theories as a modification of gravity by just moving their contributions to the other side of the Einstein field equation.
My impression is that these theories simply ignore the QFT vacuum energy without explanation. That's the real elephant in the room, and probably the reason so few physicists work on explaining the accelerated expansion. We have an automatic mechanism to explain the expansion, and that mechanism appears to be $10^120$ times more powerful than it should be. It seems premature to start to consider additional mechanisms before understanding this one first, and there seems to be no possible understanding of it now except via the much-hated anthropic principle. The ultimate explanation of the expansion will be a job for physicists of another millenium.
$endgroup$
$begingroup$
Well done, I just wanted to point out that the quintessence is not the only theory put forward to explain the cosmological constant problem, I think that, maybe, the most promising one is Quantum Cosmology, as Weinberg pointed out in his 1989's paper: "The cosmological constant problem"
$endgroup$
– Kevin De Notariis
Feb 21 at 16:38
2
$begingroup$
Wait, did I read it correctly that vacuum energy is some ~$10^120$ times more powerful than dark energy? I'm not a physicist but I feel like I've never even seen a number that big in terms of energy scales in real-world physics.
$endgroup$
– Mehrdad
Feb 21 at 21:34
$begingroup$
@Mehrdad That is the most naive estimate, if you estimate the vacuum energy density is $M_textpl^4$. But even if you just consider the electron's contribution, of the order $m_e^4$, it's still about $10^80$ times too big.
$endgroup$
– knzhou
Feb 21 at 21:36
$begingroup$
@Mehrdad Part of the largeness is that we are taking the fourth power to get an energy density, because that's how the parameter appears in the Lagrangian. Even phrased in terms of mass scales, for the electron the mass scale ratio is $10^20$, which is still outrageous.
$endgroup$
– knzhou
Feb 21 at 21:37
4
$begingroup$
@JeppeStigNielsen Possibly, or possibly not. If you think you've solved the problem, but you miss even a single particle, then the contribution of that particle alone will make the term, say, $10^100$ times too big. So at least naively, it appears you would have to know everything, including how quantum gravity works, before tackling this problem, because the vacuum energy depends on everything. In other words, this thing is at the very top of the tech tree of physics; it is the last thing to do. Still, there could definitely be a sneaky way out.
$endgroup$
– knzhou
Feb 21 at 22:54
|
show 2 more comments
$begingroup$
The accelerated expansion of the universe is not direct evidence for dark energy, i.e. a perfect fluid contribution to the stress-energy tensor with $w = -1$. Dark energy is just by far the simplest thing that fits the data well.
It's simple to cosmologists because they are used to dealing with matter in the form of perfect fluids, and dark energy is just another one. And it's simple to particle physicists because it can be sourced by a constant term in the Lagrangian, the simplest possible term.
At the classical level, the distinction you're making is not really important. A cosmological constant, which you call a "modification of gravity", amounts to adding a constant term to the Lagrangian. But the standard description of dark energy also amounts to adding a constant term to the Lagrangian. They're the exact same thing -- a constant is a constant, it doesn't come with a little tag saying if it's "from" gravity or something else. Neither is more elegant because functionally all the equations come out the same. It's a philosophical difference, not a real difference.
But the situation changes dramatically when you account for quantum effects. That's because we know that QFT generically produces vacuum energy, i.e. sources a constant term in the Lagrangian, whether or not we put that term in classically or not. So even if you do explain the accelerated expansion by some other mechanism, you have to explain why this one isn't in effect. This is a difficult argument to make, because the contribution from QFT is already too big even if you only trust it up to tiny energy scales like $1 text eV$!
Of course, there is room to work on alternative theories, such as quintessence and phantom energy; these are functionally different because they correspond to a perfect fluid with $w neq -1$. At present, observational constraints show that the acceleration can only be explained by one additional perfect fluid if that component has $w = -1$ to within about 20% accuracy. If you wish, you can think of these theories as a modification of gravity by just moving their contributions to the other side of the Einstein field equation.
My impression is that these theories simply ignore the QFT vacuum energy without explanation. That's the real elephant in the room, and probably the reason so few physicists work on explaining the accelerated expansion. We have an automatic mechanism to explain the expansion, and that mechanism appears to be $10^120$ times more powerful than it should be. It seems premature to start to consider additional mechanisms before understanding this one first, and there seems to be no possible understanding of it now except via the much-hated anthropic principle. The ultimate explanation of the expansion will be a job for physicists of another millenium.
$endgroup$
$begingroup$
Well done, I just wanted to point out that the quintessence is not the only theory put forward to explain the cosmological constant problem, I think that, maybe, the most promising one is Quantum Cosmology, as Weinberg pointed out in his 1989's paper: "The cosmological constant problem"
$endgroup$
– Kevin De Notariis
Feb 21 at 16:38
2
$begingroup$
Wait, did I read it correctly that vacuum energy is some ~$10^120$ times more powerful than dark energy? I'm not a physicist but I feel like I've never even seen a number that big in terms of energy scales in real-world physics.
$endgroup$
– Mehrdad
Feb 21 at 21:34
$begingroup$
@Mehrdad That is the most naive estimate, if you estimate the vacuum energy density is $M_textpl^4$. But even if you just consider the electron's contribution, of the order $m_e^4$, it's still about $10^80$ times too big.
$endgroup$
– knzhou
Feb 21 at 21:36
$begingroup$
@Mehrdad Part of the largeness is that we are taking the fourth power to get an energy density, because that's how the parameter appears in the Lagrangian. Even phrased in terms of mass scales, for the electron the mass scale ratio is $10^20$, which is still outrageous.
$endgroup$
– knzhou
Feb 21 at 21:37
4
$begingroup$
@JeppeStigNielsen Possibly, or possibly not. If you think you've solved the problem, but you miss even a single particle, then the contribution of that particle alone will make the term, say, $10^100$ times too big. So at least naively, it appears you would have to know everything, including how quantum gravity works, before tackling this problem, because the vacuum energy depends on everything. In other words, this thing is at the very top of the tech tree of physics; it is the last thing to do. Still, there could definitely be a sneaky way out.
$endgroup$
– knzhou
Feb 21 at 22:54
|
show 2 more comments
$begingroup$
The accelerated expansion of the universe is not direct evidence for dark energy, i.e. a perfect fluid contribution to the stress-energy tensor with $w = -1$. Dark energy is just by far the simplest thing that fits the data well.
It's simple to cosmologists because they are used to dealing with matter in the form of perfect fluids, and dark energy is just another one. And it's simple to particle physicists because it can be sourced by a constant term in the Lagrangian, the simplest possible term.
At the classical level, the distinction you're making is not really important. A cosmological constant, which you call a "modification of gravity", amounts to adding a constant term to the Lagrangian. But the standard description of dark energy also amounts to adding a constant term to the Lagrangian. They're the exact same thing -- a constant is a constant, it doesn't come with a little tag saying if it's "from" gravity or something else. Neither is more elegant because functionally all the equations come out the same. It's a philosophical difference, not a real difference.
But the situation changes dramatically when you account for quantum effects. That's because we know that QFT generically produces vacuum energy, i.e. sources a constant term in the Lagrangian, whether or not we put that term in classically or not. So even if you do explain the accelerated expansion by some other mechanism, you have to explain why this one isn't in effect. This is a difficult argument to make, because the contribution from QFT is already too big even if you only trust it up to tiny energy scales like $1 text eV$!
Of course, there is room to work on alternative theories, such as quintessence and phantom energy; these are functionally different because they correspond to a perfect fluid with $w neq -1$. At present, observational constraints show that the acceleration can only be explained by one additional perfect fluid if that component has $w = -1$ to within about 20% accuracy. If you wish, you can think of these theories as a modification of gravity by just moving their contributions to the other side of the Einstein field equation.
My impression is that these theories simply ignore the QFT vacuum energy without explanation. That's the real elephant in the room, and probably the reason so few physicists work on explaining the accelerated expansion. We have an automatic mechanism to explain the expansion, and that mechanism appears to be $10^120$ times more powerful than it should be. It seems premature to start to consider additional mechanisms before understanding this one first, and there seems to be no possible understanding of it now except via the much-hated anthropic principle. The ultimate explanation of the expansion will be a job for physicists of another millenium.
$endgroup$
The accelerated expansion of the universe is not direct evidence for dark energy, i.e. a perfect fluid contribution to the stress-energy tensor with $w = -1$. Dark energy is just by far the simplest thing that fits the data well.
It's simple to cosmologists because they are used to dealing with matter in the form of perfect fluids, and dark energy is just another one. And it's simple to particle physicists because it can be sourced by a constant term in the Lagrangian, the simplest possible term.
At the classical level, the distinction you're making is not really important. A cosmological constant, which you call a "modification of gravity", amounts to adding a constant term to the Lagrangian. But the standard description of dark energy also amounts to adding a constant term to the Lagrangian. They're the exact same thing -- a constant is a constant, it doesn't come with a little tag saying if it's "from" gravity or something else. Neither is more elegant because functionally all the equations come out the same. It's a philosophical difference, not a real difference.
But the situation changes dramatically when you account for quantum effects. That's because we know that QFT generically produces vacuum energy, i.e. sources a constant term in the Lagrangian, whether or not we put that term in classically or not. So even if you do explain the accelerated expansion by some other mechanism, you have to explain why this one isn't in effect. This is a difficult argument to make, because the contribution from QFT is already too big even if you only trust it up to tiny energy scales like $1 text eV$!
Of course, there is room to work on alternative theories, such as quintessence and phantom energy; these are functionally different because they correspond to a perfect fluid with $w neq -1$. At present, observational constraints show that the acceleration can only be explained by one additional perfect fluid if that component has $w = -1$ to within about 20% accuracy. If you wish, you can think of these theories as a modification of gravity by just moving their contributions to the other side of the Einstein field equation.
My impression is that these theories simply ignore the QFT vacuum energy without explanation. That's the real elephant in the room, and probably the reason so few physicists work on explaining the accelerated expansion. We have an automatic mechanism to explain the expansion, and that mechanism appears to be $10^120$ times more powerful than it should be. It seems premature to start to consider additional mechanisms before understanding this one first, and there seems to be no possible understanding of it now except via the much-hated anthropic principle. The ultimate explanation of the expansion will be a job for physicists of another millenium.
answered Feb 21 at 16:02
knzhouknzhou
45.1k11122219
45.1k11122219
$begingroup$
Well done, I just wanted to point out that the quintessence is not the only theory put forward to explain the cosmological constant problem, I think that, maybe, the most promising one is Quantum Cosmology, as Weinberg pointed out in his 1989's paper: "The cosmological constant problem"
$endgroup$
– Kevin De Notariis
Feb 21 at 16:38
2
$begingroup$
Wait, did I read it correctly that vacuum energy is some ~$10^120$ times more powerful than dark energy? I'm not a physicist but I feel like I've never even seen a number that big in terms of energy scales in real-world physics.
$endgroup$
– Mehrdad
Feb 21 at 21:34
$begingroup$
@Mehrdad That is the most naive estimate, if you estimate the vacuum energy density is $M_textpl^4$. But even if you just consider the electron's contribution, of the order $m_e^4$, it's still about $10^80$ times too big.
$endgroup$
– knzhou
Feb 21 at 21:36
$begingroup$
@Mehrdad Part of the largeness is that we are taking the fourth power to get an energy density, because that's how the parameter appears in the Lagrangian. Even phrased in terms of mass scales, for the electron the mass scale ratio is $10^20$, which is still outrageous.
$endgroup$
– knzhou
Feb 21 at 21:37
4
$begingroup$
@JeppeStigNielsen Possibly, or possibly not. If you think you've solved the problem, but you miss even a single particle, then the contribution of that particle alone will make the term, say, $10^100$ times too big. So at least naively, it appears you would have to know everything, including how quantum gravity works, before tackling this problem, because the vacuum energy depends on everything. In other words, this thing is at the very top of the tech tree of physics; it is the last thing to do. Still, there could definitely be a sneaky way out.
$endgroup$
– knzhou
Feb 21 at 22:54
|
show 2 more comments
$begingroup$
Well done, I just wanted to point out that the quintessence is not the only theory put forward to explain the cosmological constant problem, I think that, maybe, the most promising one is Quantum Cosmology, as Weinberg pointed out in his 1989's paper: "The cosmological constant problem"
$endgroup$
– Kevin De Notariis
Feb 21 at 16:38
2
$begingroup$
Wait, did I read it correctly that vacuum energy is some ~$10^120$ times more powerful than dark energy? I'm not a physicist but I feel like I've never even seen a number that big in terms of energy scales in real-world physics.
$endgroup$
– Mehrdad
Feb 21 at 21:34
$begingroup$
@Mehrdad That is the most naive estimate, if you estimate the vacuum energy density is $M_textpl^4$. But even if you just consider the electron's contribution, of the order $m_e^4$, it's still about $10^80$ times too big.
$endgroup$
– knzhou
Feb 21 at 21:36
$begingroup$
@Mehrdad Part of the largeness is that we are taking the fourth power to get an energy density, because that's how the parameter appears in the Lagrangian. Even phrased in terms of mass scales, for the electron the mass scale ratio is $10^20$, which is still outrageous.
$endgroup$
– knzhou
Feb 21 at 21:37
4
$begingroup$
@JeppeStigNielsen Possibly, or possibly not. If you think you've solved the problem, but you miss even a single particle, then the contribution of that particle alone will make the term, say, $10^100$ times too big. So at least naively, it appears you would have to know everything, including how quantum gravity works, before tackling this problem, because the vacuum energy depends on everything. In other words, this thing is at the very top of the tech tree of physics; it is the last thing to do. Still, there could definitely be a sneaky way out.
$endgroup$
– knzhou
Feb 21 at 22:54
$begingroup$
Well done, I just wanted to point out that the quintessence is not the only theory put forward to explain the cosmological constant problem, I think that, maybe, the most promising one is Quantum Cosmology, as Weinberg pointed out in his 1989's paper: "The cosmological constant problem"
$endgroup$
– Kevin De Notariis
Feb 21 at 16:38
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Well done, I just wanted to point out that the quintessence is not the only theory put forward to explain the cosmological constant problem, I think that, maybe, the most promising one is Quantum Cosmology, as Weinberg pointed out in his 1989's paper: "The cosmological constant problem"
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– Kevin De Notariis
Feb 21 at 16:38
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Wait, did I read it correctly that vacuum energy is some ~$10^120$ times more powerful than dark energy? I'm not a physicist but I feel like I've never even seen a number that big in terms of energy scales in real-world physics.
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– Mehrdad
Feb 21 at 21:34
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Wait, did I read it correctly that vacuum energy is some ~$10^120$ times more powerful than dark energy? I'm not a physicist but I feel like I've never even seen a number that big in terms of energy scales in real-world physics.
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– Mehrdad
Feb 21 at 21:34
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@Mehrdad That is the most naive estimate, if you estimate the vacuum energy density is $M_textpl^4$. But even if you just consider the electron's contribution, of the order $m_e^4$, it's still about $10^80$ times too big.
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– knzhou
Feb 21 at 21:36
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@Mehrdad That is the most naive estimate, if you estimate the vacuum energy density is $M_textpl^4$. But even if you just consider the electron's contribution, of the order $m_e^4$, it's still about $10^80$ times too big.
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– knzhou
Feb 21 at 21:36
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@Mehrdad Part of the largeness is that we are taking the fourth power to get an energy density, because that's how the parameter appears in the Lagrangian. Even phrased in terms of mass scales, for the electron the mass scale ratio is $10^20$, which is still outrageous.
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– knzhou
Feb 21 at 21:37
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@Mehrdad Part of the largeness is that we are taking the fourth power to get an energy density, because that's how the parameter appears in the Lagrangian. Even phrased in terms of mass scales, for the electron the mass scale ratio is $10^20$, which is still outrageous.
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– knzhou
Feb 21 at 21:37
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@JeppeStigNielsen Possibly, or possibly not. If you think you've solved the problem, but you miss even a single particle, then the contribution of that particle alone will make the term, say, $10^100$ times too big. So at least naively, it appears you would have to know everything, including how quantum gravity works, before tackling this problem, because the vacuum energy depends on everything. In other words, this thing is at the very top of the tech tree of physics; it is the last thing to do. Still, there could definitely be a sneaky way out.
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– knzhou
Feb 21 at 22:54
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@JeppeStigNielsen Possibly, or possibly not. If you think you've solved the problem, but you miss even a single particle, then the contribution of that particle alone will make the term, say, $10^100$ times too big. So at least naively, it appears you would have to know everything, including how quantum gravity works, before tackling this problem, because the vacuum energy depends on everything. In other words, this thing is at the very top of the tech tree of physics; it is the last thing to do. Still, there could definitely be a sneaky way out.
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– knzhou
Feb 21 at 22:54
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– David Z♦
Feb 22 at 5:39
1
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I have spoken to numerous "inhomogeneous cosmologists" about this, and many of them indeed prefer to think of the cosmological constant $Lambda$ as a gravity effect (LHS of the Einstein field equations) rather than a matter/energy fluid (RHS of the equations). [Also a few of them hope to explain away dark energy altogether.]
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– Colin MacLaurin
Feb 27 at 1:44