1 not defined in the RE?
Clash Royale CLAN TAG#URR8PPP
My code goes like this:
cat file.ign | sed 's/^([^A-Za-z0-9]+ )/<ignore>1</ignore>/g'
Yet I receive an error saying :
sed: 1: "s/^([^A-Za-z0-9]+ )/<ig ...": 1 not defined in the RE
sed
add a comment |
My code goes like this:
cat file.ign | sed 's/^([^A-Za-z0-9]+ )/<ignore>1</ignore>/g'
Yet I receive an error saying :
sed: 1: "s/^([^A-Za-z0-9]+ )/<ig ...": 1 not defined in the RE
sed
add a comment |
My code goes like this:
cat file.ign | sed 's/^([^A-Za-z0-9]+ )/<ignore>1</ignore>/g'
Yet I receive an error saying :
sed: 1: "s/^([^A-Za-z0-9]+ )/<ig ...": 1 not defined in the RE
sed
My code goes like this:
cat file.ign | sed 's/^([^A-Za-z0-9]+ )/<ignore>1</ignore>/g'
Yet I receive an error saying :
sed: 1: "s/^([^A-Za-z0-9]+ )/<ig ...": 1 not defined in the RE
sed
sed
edited Feb 7 at 7:23
Rui F Ribeiro
40.7k1479137
40.7k1479137
asked Feb 6 at 23:34
Laura Laura
313
313
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Parentheses are literal in basic regular expression (BRE) syntax - to make them denote a capture group, they must be escaped, as (
and )
Additionally, as noted in a comment by @BenjaminW, +
is also literal in BRE. GNU sed supports +
as a quantifier in BRE:
sed 's/^([^A-Za-z0-9]+ )/<ignore>1</ignore>/g'
(but other implementations might not). Alternatively, turn on extended regular expression (ERE) mode using the -E
or -r
command line switch as appropriate (check your version's documentation):
sed -E 's/^([^A-Za-z0-9]+ )/<ignore>1</ignore>/g'
or use the POSIX-compliant quantifier 1,
sed 's/^([^A-Za-z0-9]1, )/<ignore>1</ignore>/g'
ASIDE the g
(global replacement) modifier won't have any effect here, since ^
anchors the expression to the start of the pattern (which can occur only once per line)
1
Furthermore,+
is only avalable in ERE; GNU sed supports it as an extension in BRE, but is has to be escaped.
– Benjamin W.
Feb 7 at 0:39
@BenjaminW. oops yes that's a good point - I missed that
– steeldriver
Feb 7 at 0:40
The-E
also is GNU or FreeBSD sed, not in POSIX. If you're going to recommend a non-POSIX solution, mentioning that might help the reader.
– Thomas Dickey
Feb 7 at 1:20
sed 's#^[^A-Za-z0-9][^A-Za-z0-9]* #<ignore>&</ignore>#'
will do the same in anysed
, and it's hardly uglier than(..1,..)/..</../
;-)
– pizdelect
Feb 7 at 5:47
1
@ThomasDickey But it looks like it has been accepted - not sure when it'll make it into the standard, though.
– Benjamin W.
Feb 7 at 14:10
|
show 1 more comment
Using GNU sed, you can invoke as sed -E
or else you can escape the parentheses in order to get the back-reference working, but if you're not using GNU sed, you can't rely on back references; POSIX sed doesn't (yet) support the -E
or -r
argument for Extended Regular Expressions (ERE) nor does it support GNU's Basic Regular Expression (BRE) backslash notation. (Here's more on POSIX ERE & BRE, though it doesn't speak in much depth about GNU's BRE implementation allowing escaping into ERE functionality.)
Fortunately, (in this case) you don't need ERE. This should work for you:
sed 's/^[^A-Za-z0-9][^A-Za-z0-9]* /<ignore>&</ignore>/' file.ign
BRE doesn't support the +
quantifier, so I needed to double the nonword character set so it would be "one or more" by requiring "one" and then "zero or more" of them. The ampersand (&
) denotes the entire match. There's no need to have parentheses around everything in this case. (The beginning-of-line anchor ^
is zero-width and doesn't matter here.)
I removed the cat
because it's unnecessary. I also removed your /g
modifier because the ^
anchor means this can only match once per line, so you'll never get a second match and therefore a global replacement doesn't do anything.
add a comment |
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "106"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f499185%2f1-not-defined-in-the-re%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Parentheses are literal in basic regular expression (BRE) syntax - to make them denote a capture group, they must be escaped, as (
and )
Additionally, as noted in a comment by @BenjaminW, +
is also literal in BRE. GNU sed supports +
as a quantifier in BRE:
sed 's/^([^A-Za-z0-9]+ )/<ignore>1</ignore>/g'
(but other implementations might not). Alternatively, turn on extended regular expression (ERE) mode using the -E
or -r
command line switch as appropriate (check your version's documentation):
sed -E 's/^([^A-Za-z0-9]+ )/<ignore>1</ignore>/g'
or use the POSIX-compliant quantifier 1,
sed 's/^([^A-Za-z0-9]1, )/<ignore>1</ignore>/g'
ASIDE the g
(global replacement) modifier won't have any effect here, since ^
anchors the expression to the start of the pattern (which can occur only once per line)
1
Furthermore,+
is only avalable in ERE; GNU sed supports it as an extension in BRE, but is has to be escaped.
– Benjamin W.
Feb 7 at 0:39
@BenjaminW. oops yes that's a good point - I missed that
– steeldriver
Feb 7 at 0:40
The-E
also is GNU or FreeBSD sed, not in POSIX. If you're going to recommend a non-POSIX solution, mentioning that might help the reader.
– Thomas Dickey
Feb 7 at 1:20
sed 's#^[^A-Za-z0-9][^A-Za-z0-9]* #<ignore>&</ignore>#'
will do the same in anysed
, and it's hardly uglier than(..1,..)/..</../
;-)
– pizdelect
Feb 7 at 5:47
1
@ThomasDickey But it looks like it has been accepted - not sure when it'll make it into the standard, though.
– Benjamin W.
Feb 7 at 14:10
|
show 1 more comment
Parentheses are literal in basic regular expression (BRE) syntax - to make them denote a capture group, they must be escaped, as (
and )
Additionally, as noted in a comment by @BenjaminW, +
is also literal in BRE. GNU sed supports +
as a quantifier in BRE:
sed 's/^([^A-Za-z0-9]+ )/<ignore>1</ignore>/g'
(but other implementations might not). Alternatively, turn on extended regular expression (ERE) mode using the -E
or -r
command line switch as appropriate (check your version's documentation):
sed -E 's/^([^A-Za-z0-9]+ )/<ignore>1</ignore>/g'
or use the POSIX-compliant quantifier 1,
sed 's/^([^A-Za-z0-9]1, )/<ignore>1</ignore>/g'
ASIDE the g
(global replacement) modifier won't have any effect here, since ^
anchors the expression to the start of the pattern (which can occur only once per line)
1
Furthermore,+
is only avalable in ERE; GNU sed supports it as an extension in BRE, but is has to be escaped.
– Benjamin W.
Feb 7 at 0:39
@BenjaminW. oops yes that's a good point - I missed that
– steeldriver
Feb 7 at 0:40
The-E
also is GNU or FreeBSD sed, not in POSIX. If you're going to recommend a non-POSIX solution, mentioning that might help the reader.
– Thomas Dickey
Feb 7 at 1:20
sed 's#^[^A-Za-z0-9][^A-Za-z0-9]* #<ignore>&</ignore>#'
will do the same in anysed
, and it's hardly uglier than(..1,..)/..</../
;-)
– pizdelect
Feb 7 at 5:47
1
@ThomasDickey But it looks like it has been accepted - not sure when it'll make it into the standard, though.
– Benjamin W.
Feb 7 at 14:10
|
show 1 more comment
Parentheses are literal in basic regular expression (BRE) syntax - to make them denote a capture group, they must be escaped, as (
and )
Additionally, as noted in a comment by @BenjaminW, +
is also literal in BRE. GNU sed supports +
as a quantifier in BRE:
sed 's/^([^A-Za-z0-9]+ )/<ignore>1</ignore>/g'
(but other implementations might not). Alternatively, turn on extended regular expression (ERE) mode using the -E
or -r
command line switch as appropriate (check your version's documentation):
sed -E 's/^([^A-Za-z0-9]+ )/<ignore>1</ignore>/g'
or use the POSIX-compliant quantifier 1,
sed 's/^([^A-Za-z0-9]1, )/<ignore>1</ignore>/g'
ASIDE the g
(global replacement) modifier won't have any effect here, since ^
anchors the expression to the start of the pattern (which can occur only once per line)
Parentheses are literal in basic regular expression (BRE) syntax - to make them denote a capture group, they must be escaped, as (
and )
Additionally, as noted in a comment by @BenjaminW, +
is also literal in BRE. GNU sed supports +
as a quantifier in BRE:
sed 's/^([^A-Za-z0-9]+ )/<ignore>1</ignore>/g'
(but other implementations might not). Alternatively, turn on extended regular expression (ERE) mode using the -E
or -r
command line switch as appropriate (check your version's documentation):
sed -E 's/^([^A-Za-z0-9]+ )/<ignore>1</ignore>/g'
or use the POSIX-compliant quantifier 1,
sed 's/^([^A-Za-z0-9]1, )/<ignore>1</ignore>/g'
ASIDE the g
(global replacement) modifier won't have any effect here, since ^
anchors the expression to the start of the pattern (which can occur only once per line)
edited Feb 7 at 1:56
answered Feb 6 at 23:45
steeldriversteeldriver
36.4k35286
36.4k35286
1
Furthermore,+
is only avalable in ERE; GNU sed supports it as an extension in BRE, but is has to be escaped.
– Benjamin W.
Feb 7 at 0:39
@BenjaminW. oops yes that's a good point - I missed that
– steeldriver
Feb 7 at 0:40
The-E
also is GNU or FreeBSD sed, not in POSIX. If you're going to recommend a non-POSIX solution, mentioning that might help the reader.
– Thomas Dickey
Feb 7 at 1:20
sed 's#^[^A-Za-z0-9][^A-Za-z0-9]* #<ignore>&</ignore>#'
will do the same in anysed
, and it's hardly uglier than(..1,..)/..</../
;-)
– pizdelect
Feb 7 at 5:47
1
@ThomasDickey But it looks like it has been accepted - not sure when it'll make it into the standard, though.
– Benjamin W.
Feb 7 at 14:10
|
show 1 more comment
1
Furthermore,+
is only avalable in ERE; GNU sed supports it as an extension in BRE, but is has to be escaped.
– Benjamin W.
Feb 7 at 0:39
@BenjaminW. oops yes that's a good point - I missed that
– steeldriver
Feb 7 at 0:40
The-E
also is GNU or FreeBSD sed, not in POSIX. If you're going to recommend a non-POSIX solution, mentioning that might help the reader.
– Thomas Dickey
Feb 7 at 1:20
sed 's#^[^A-Za-z0-9][^A-Za-z0-9]* #<ignore>&</ignore>#'
will do the same in anysed
, and it's hardly uglier than(..1,..)/..</../
;-)
– pizdelect
Feb 7 at 5:47
1
@ThomasDickey But it looks like it has been accepted - not sure when it'll make it into the standard, though.
– Benjamin W.
Feb 7 at 14:10
1
1
Furthermore,
+
is only avalable in ERE; GNU sed supports it as an extension in BRE, but is has to be escaped.– Benjamin W.
Feb 7 at 0:39
Furthermore,
+
is only avalable in ERE; GNU sed supports it as an extension in BRE, but is has to be escaped.– Benjamin W.
Feb 7 at 0:39
@BenjaminW. oops yes that's a good point - I missed that
– steeldriver
Feb 7 at 0:40
@BenjaminW. oops yes that's a good point - I missed that
– steeldriver
Feb 7 at 0:40
The
-E
also is GNU or FreeBSD sed, not in POSIX. If you're going to recommend a non-POSIX solution, mentioning that might help the reader.– Thomas Dickey
Feb 7 at 1:20
The
-E
also is GNU or FreeBSD sed, not in POSIX. If you're going to recommend a non-POSIX solution, mentioning that might help the reader.– Thomas Dickey
Feb 7 at 1:20
sed 's#^[^A-Za-z0-9][^A-Za-z0-9]* #<ignore>&</ignore>#'
will do the same in any sed
, and it's hardly uglier than (..1,..)/..</../
;-)– pizdelect
Feb 7 at 5:47
sed 's#^[^A-Za-z0-9][^A-Za-z0-9]* #<ignore>&</ignore>#'
will do the same in any sed
, and it's hardly uglier than (..1,..)/..</../
;-)– pizdelect
Feb 7 at 5:47
1
1
@ThomasDickey But it looks like it has been accepted - not sure when it'll make it into the standard, though.
– Benjamin W.
Feb 7 at 14:10
@ThomasDickey But it looks like it has been accepted - not sure when it'll make it into the standard, though.
– Benjamin W.
Feb 7 at 14:10
|
show 1 more comment
Using GNU sed, you can invoke as sed -E
or else you can escape the parentheses in order to get the back-reference working, but if you're not using GNU sed, you can't rely on back references; POSIX sed doesn't (yet) support the -E
or -r
argument for Extended Regular Expressions (ERE) nor does it support GNU's Basic Regular Expression (BRE) backslash notation. (Here's more on POSIX ERE & BRE, though it doesn't speak in much depth about GNU's BRE implementation allowing escaping into ERE functionality.)
Fortunately, (in this case) you don't need ERE. This should work for you:
sed 's/^[^A-Za-z0-9][^A-Za-z0-9]* /<ignore>&</ignore>/' file.ign
BRE doesn't support the +
quantifier, so I needed to double the nonword character set so it would be "one or more" by requiring "one" and then "zero or more" of them. The ampersand (&
) denotes the entire match. There's no need to have parentheses around everything in this case. (The beginning-of-line anchor ^
is zero-width and doesn't matter here.)
I removed the cat
because it's unnecessary. I also removed your /g
modifier because the ^
anchor means this can only match once per line, so you'll never get a second match and therefore a global replacement doesn't do anything.
add a comment |
Using GNU sed, you can invoke as sed -E
or else you can escape the parentheses in order to get the back-reference working, but if you're not using GNU sed, you can't rely on back references; POSIX sed doesn't (yet) support the -E
or -r
argument for Extended Regular Expressions (ERE) nor does it support GNU's Basic Regular Expression (BRE) backslash notation. (Here's more on POSIX ERE & BRE, though it doesn't speak in much depth about GNU's BRE implementation allowing escaping into ERE functionality.)
Fortunately, (in this case) you don't need ERE. This should work for you:
sed 's/^[^A-Za-z0-9][^A-Za-z0-9]* /<ignore>&</ignore>/' file.ign
BRE doesn't support the +
quantifier, so I needed to double the nonword character set so it would be "one or more" by requiring "one" and then "zero or more" of them. The ampersand (&
) denotes the entire match. There's no need to have parentheses around everything in this case. (The beginning-of-line anchor ^
is zero-width and doesn't matter here.)
I removed the cat
because it's unnecessary. I also removed your /g
modifier because the ^
anchor means this can only match once per line, so you'll never get a second match and therefore a global replacement doesn't do anything.
add a comment |
Using GNU sed, you can invoke as sed -E
or else you can escape the parentheses in order to get the back-reference working, but if you're not using GNU sed, you can't rely on back references; POSIX sed doesn't (yet) support the -E
or -r
argument for Extended Regular Expressions (ERE) nor does it support GNU's Basic Regular Expression (BRE) backslash notation. (Here's more on POSIX ERE & BRE, though it doesn't speak in much depth about GNU's BRE implementation allowing escaping into ERE functionality.)
Fortunately, (in this case) you don't need ERE. This should work for you:
sed 's/^[^A-Za-z0-9][^A-Za-z0-9]* /<ignore>&</ignore>/' file.ign
BRE doesn't support the +
quantifier, so I needed to double the nonword character set so it would be "one or more" by requiring "one" and then "zero or more" of them. The ampersand (&
) denotes the entire match. There's no need to have parentheses around everything in this case. (The beginning-of-line anchor ^
is zero-width and doesn't matter here.)
I removed the cat
because it's unnecessary. I also removed your /g
modifier because the ^
anchor means this can only match once per line, so you'll never get a second match and therefore a global replacement doesn't do anything.
Using GNU sed, you can invoke as sed -E
or else you can escape the parentheses in order to get the back-reference working, but if you're not using GNU sed, you can't rely on back references; POSIX sed doesn't (yet) support the -E
or -r
argument for Extended Regular Expressions (ERE) nor does it support GNU's Basic Regular Expression (BRE) backslash notation. (Here's more on POSIX ERE & BRE, though it doesn't speak in much depth about GNU's BRE implementation allowing escaping into ERE functionality.)
Fortunately, (in this case) you don't need ERE. This should work for you:
sed 's/^[^A-Za-z0-9][^A-Za-z0-9]* /<ignore>&</ignore>/' file.ign
BRE doesn't support the +
quantifier, so I needed to double the nonword character set so it would be "one or more" by requiring "one" and then "zero or more" of them. The ampersand (&
) denotes the entire match. There's no need to have parentheses around everything in this case. (The beginning-of-line anchor ^
is zero-width and doesn't matter here.)
I removed the cat
because it's unnecessary. I also removed your /g
modifier because the ^
anchor means this can only match once per line, so you'll never get a second match and therefore a global replacement doesn't do anything.
edited Feb 8 at 15:27
answered Feb 7 at 16:31
Adam KatzAdam Katz
2,2501221
2,2501221
add a comment |
add a comment |
Thanks for contributing an answer to Unix & Linux Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f499185%2f1-not-defined-in-the-re%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown