What does this command with two filenames in it mean?
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./getProductAccess.sh access-2014-09-04.log
Normally there is only 1 file behind ./. Now there are two. It seems the second one is to provide input, but what should write in the first one to get the input? Because read doesn't work.
linux shell-script shell
edited Feb 1 at 9:35
Stéphane Chazelas
306k57581935
asked Feb 1 at 7:09
VictorVictor
6
add a comment |
./getProductAccess.sh access-2014-09-04.log
Normally there is only 1 file behind ./. Now there are two. It seems the second one is to provide input, but what should write in the first one to get the input? Because read doesn't work.
linux shell-script shell
edited Feb 1 at 9:35
Stéphane Chazelas
306k57581935
asked Feb 1 at 7:09
VictorVictor
6
add a comment |
./getProductAccess.sh access-2014-09-04.log
Normally there is only 1 file behind ./. Now there are two. It seems the second one is to provide input, but what should write in the first one to get the input? Because read doesn't work.
linux shell-script shell
edited Feb 1 at 9:35
Stéphane Chazelas
306k57581935
asked Feb 1 at 7:09
VictorVictor
6
./getProductAccess.sh access-2014-09-04.log
Normally there is only 1 file behind ./. Now there are two. It seems the second one is to provide input, but what should write in the first one to get the input? Because read doesn't work.
linux shell-script shell
linux shell-script shell
edited Feb 1 at 9:35
Stéphane Chazelas
306k57581935
asked Feb 1 at 7:09
VictorVictor
6
edited Feb 1 at 9:35
Stéphane Chazelas
306k57581935
asked Feb 1 at 7:09
VictorVictor
6
edited Feb 1 at 9:35
Stéphane Chazelas
306k57581935
edited Feb 1 at 9:35
Stéphane Chazelas
306k57581935
edited Feb 1 at 9:35
Stéphane Chazelas
306k57581935
306k57581935
asked Feb 1 at 7:09
VictorVictor
6
asked Feb 1 at 7:09
VictorVictor
6
asked Feb 1 at 7:09
VictorVictor
6
6
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
This really is beginners 101.
./getProductAccess.sh is the program to run (in the current directory) and access-2014-09-04.log is an argument supplied to that program.
If you're writing the program you could reference that first argument as "$1".
answered Feb 1 at 7:14
roaimaroaima
44.9k756122
add a comment |
There is no need to use read you can use $1.
So in your script if you will use echo "$1", then it will give output as access-2014-09-04.log.
$0 is the path(relative or absolute) of the file which you are executing. $1 is the first argument passed to file, $2 second and so on...
answered Feb 1 at 7:12
PRYPRY
2,55831026
add a comment |
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2 Answers
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active
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2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
This really is beginners 101.
./getProductAccess.sh is the program to run (in the current directory) and access-2014-09-04.log is an argument supplied to that program.
If you're writing the program you could reference that first argument as "$1".
answered Feb 1 at 7:14
roaimaroaima
44.9k756122
add a comment |
This really is beginners 101.
./getProductAccess.sh is the program to run (in the current directory) and access-2014-09-04.log is an argument supplied to that program.
If you're writing the program you could reference that first argument as "$1".
answered Feb 1 at 7:14
roaimaroaima
44.9k756122
add a comment |
This really is beginners 101.
./getProductAccess.sh is the program to run (in the current directory) and access-2014-09-04.log is an argument supplied to that program.
If you're writing the program you could reference that first argument as "$1".
answered Feb 1 at 7:14
roaimaroaima
44.9k756122
This really is beginners 101.
./getProductAccess.sh is the program to run (in the current directory) and access-2014-09-04.log is an argument supplied to that program.
If you're writing the program you could reference that first argument as "$1".
answered Feb 1 at 7:14
roaimaroaima
44.9k756122
answered Feb 1 at 7:14
roaimaroaima
44.9k756122
answered Feb 1 at 7:14
roaimaroaima
44.9k756122
answered Feb 1 at 7:14
roaimaroaima
44.9k756122
44.9k756122
add a comment |
add a comment |
There is no need to use read you can use $1.
So in your script if you will use echo "$1", then it will give output as access-2014-09-04.log.
$0 is the path(relative or absolute) of the file which you are executing. $1 is the first argument passed to file, $2 second and so on...
answered Feb 1 at 7:12
PRYPRY
2,55831026
add a comment |
There is no need to use read you can use $1.
So in your script if you will use echo "$1", then it will give output as access-2014-09-04.log.
$0 is the path(relative or absolute) of the file which you are executing. $1 is the first argument passed to file, $2 second and so on...
answered Feb 1 at 7:12
PRYPRY
2,55831026
add a comment |
There is no need to use read you can use $1.
So in your script if you will use echo "$1", then it will give output as access-2014-09-04.log.
$0 is the path(relative or absolute) of the file which you are executing. $1 is the first argument passed to file, $2 second and so on...
answered Feb 1 at 7:12
PRYPRY
2,55831026
There is no need to use read you can use $1.
So in your script if you will use echo "$1", then it will give output as access-2014-09-04.log.
$0 is the path(relative or absolute) of the file which you are executing. $1 is the first argument passed to file, $2 second and so on...
answered Feb 1 at 7:12
PRYPRY
2,55831026
edited Feb 1 at 7:19
answered Feb 1 at 7:12
PRYPRY
2,55831026
answered Feb 1 at 7:12
PRYPRY
2,55831026
answered Feb 1 at 7:12
PRYPRY
2,55831026
2,55831026
add a comment |
add a comment |
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