mjhjmtu

Using regular expression, I want to select only the words which:

• are alphanumeric


• do not contain only numbers


• do not contain only alphabets


• have unique numbers(1 or more)

I am not really good with the regex but so far, I have tried [^ds]*(d+)(?!.*1) which takes me nowhere close to the desired output :(

Here are the input strings:

I would like abc123 to match but not 123.
ab12s should also match
Only number-words like 1234 should not match
Words containing same numbers like ab22s should not match
234 should not match
hel1lo2haha3hoho4
hel1lo2haha3hoho3

Expected Matches:

abc123
ab12s
hel1lo2haha3hoho4

You can use

b(?=d*[a-z])(?=[a-z]*d)(?:[a-z]|(d)(?!w*1))+b

https://regex101.com/r/TimjdW/3

Anchor the start and end of the pattern at word boundaries with b, then:

• 
  (?=d*[a-z]) - Lookahead for an alphabetical character somewhere in the word


• 
  (?=[a-z]*d) - Lookahead for a digit somewhere in the word


• 
  (?:[a-z]|(d)(?!w*1))+ Repeatedly match either:
  
  
  • 
    [a-z] - Any alphabetical character, or
  
  
  • 
    (d)(?!w*1) - A digit which does not occur again in the same word
  
  

Here is a bit shorter & faster regex to make it happen since it doesn't assert negative lookahead for each character:

/b(?=[a-z]*d)(?=d*[a-z])(?!w*(d)w*1)[a-zd]+b/ig

RegEx Demo

RegEx Details:

• 
  b: Word boundary


• 
  (?=[a-z]*d): Make sure we have at least a digit


• 
  (?=d*[a-z]): Make sure we have at least a letter


• 
  (?!w*(d)w*1): Make sure digits are not repeated anywhere in the word


• 
  [a-zd]+: Match 1+ alphanumericals


• 
  b: Word boundary

You could assert all the conditions using one negative lookahead:

b(?![a-z]+b|d+b|w*(d)w*1)[a-zd]+b

See live demo here

The important parts are starting match from b and immediately looking for the conditions:

• [a-z]+b Only alphabetic




• d+b Only numeric




• w*(d)w*1 Has a repeating digit

You can use this

b(?!w*(d)w*1)(?=(?:[a-z]+d+)|(?:d+[a-z]+))[a-z0-9]+b

• 
  b - Word boundary.


• 
  (?!w*(d)w*1) - Condition to check unique digits.


• 
  (?=(?:[a-z]+d+)|(?:d+[a-z]+)) - Condition to check alphanumeric words.


• 
  [a-z0-9]+ - Matches a to z and 0 to 9
  

Demo