mjhjmtu

I am counting multiple log files with the range starting from 1 onward however it's starting from 0.

path=(/home/folder/text/*)

for 1 int $!path; do

 printf "$s: $sn" $i "$list[i]##*/";

done

Your shell code makes little sense as it uses the wrong syntax for the for loop and in the substitution to get the indexes, and also does not use printf format strings correctly.

I'm guessing that you'd want to do something like this:

i=0
for pathname in /home/folder/text/*; do
 i=$(( i + 1 ))
 printf '%s: %sn' "$i" "$( basename "$pathname" )"
done

This would enumerate the names found under /home/folder/text (excluding hidden names).

You can replace "$( basename "$pathname" )" in the above with "$pathname##*/" if you wish.

Using an array as you show in your own code:

pathnames=( /home/folder/text/* )

i=0
for pathname in "$pathnames[@]"; do
 i=$(( i + 1 ))
 printf '%s: %sn' "$i" "$( basename "$pathname" )"
done

Would you want to iterate over the indexes of the array:

pathnames=( /home/folder/text/* )

for index in "$!pathnames[@]"; do
 printf '%s: %sn' "$index" "$( basename "$pathnames[$index]" )"
done

Note that bash arrays start on index zero. Adding 1 to each index:

pathnames=( /home/folder/text/* )

for index in "$!pathnames[@]"; do
 printf '%s: %sn' "$(( index + 1 ))" "$( basename "$pathnames[$index]" )"
done