Delete elements of list with certain length
Clash Royale CLAN TAG#URR8PPP
$begingroup$
I have a list containing some other lists having different lengths. I want to remove some of the lists with a certain length. For example, I have
a = 0, 5, 2, 15, 6, 9, 3, 1, 5, 5, 5, 4, 4, 5, 6, 5;
I want to remove some sub-lists of a
having length 1. I mean, I want the result to be as
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
How can I do that using Mathematica?
list-manipulation
$endgroup$
add a comment |
$begingroup$
I have a list containing some other lists having different lengths. I want to remove some of the lists with a certain length. For example, I have
a = 0, 5, 2, 15, 6, 9, 3, 1, 5, 5, 5, 4, 4, 5, 6, 5;
I want to remove some sub-lists of a
having length 1. I mean, I want the result to be as
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
How can I do that using Mathematica?
list-manipulation
$endgroup$
add a comment |
$begingroup$
I have a list containing some other lists having different lengths. I want to remove some of the lists with a certain length. For example, I have
a = 0, 5, 2, 15, 6, 9, 3, 1, 5, 5, 5, 4, 4, 5, 6, 5;
I want to remove some sub-lists of a
having length 1. I mean, I want the result to be as
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
How can I do that using Mathematica?
list-manipulation
$endgroup$
I have a list containing some other lists having different lengths. I want to remove some of the lists with a certain length. For example, I have
a = 0, 5, 2, 15, 6, 9, 3, 1, 5, 5, 5, 4, 4, 5, 6, 5;
I want to remove some sub-lists of a
having length 1. I mean, I want the result to be as
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
How can I do that using Mathematica?
list-manipulation
list-manipulation
asked Jan 3 at 6:38
Hadi SobhaniHadi Sobhani
37327
37327
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add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Select[a, Length@# != 1 &]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
Also
GeneralUtilities`Discard[a, Length[#] == 1 &]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
and
DeleteCases[a, _?(Length@# == 1 &)]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
$endgroup$
add a comment |
$begingroup$
This might be faster than klgr's solutions on large lists:
Pick[a, Unitize[Length /@ a - 1], 1]
Select
and DeleteCases
are known to be kind of slow.
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Select[a, Length@# != 1 &]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
Also
GeneralUtilities`Discard[a, Length[#] == 1 &]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
and
DeleteCases[a, _?(Length@# == 1 &)]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
$endgroup$
add a comment |
$begingroup$
Select[a, Length@# != 1 &]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
Also
GeneralUtilities`Discard[a, Length[#] == 1 &]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
and
DeleteCases[a, _?(Length@# == 1 &)]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
$endgroup$
add a comment |
$begingroup$
Select[a, Length@# != 1 &]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
Also
GeneralUtilities`Discard[a, Length[#] == 1 &]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
and
DeleteCases[a, _?(Length@# == 1 &)]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
$endgroup$
Select[a, Length@# != 1 &]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
Also
GeneralUtilities`Discard[a, Length[#] == 1 &]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
and
DeleteCases[a, _?(Length@# == 1 &)]
0, 5, 2, 15, 6, 9, 3, 5, 5, 5, 4, 4, 5, 6
edited Jan 3 at 9:03
answered Jan 3 at 6:44
kglrkglr
179k9198410
179k9198410
add a comment |
add a comment |
$begingroup$
This might be faster than klgr's solutions on large lists:
Pick[a, Unitize[Length /@ a - 1], 1]
Select
and DeleteCases
are known to be kind of slow.
$endgroup$
add a comment |
$begingroup$
This might be faster than klgr's solutions on large lists:
Pick[a, Unitize[Length /@ a - 1], 1]
Select
and DeleteCases
are known to be kind of slow.
$endgroup$
add a comment |
$begingroup$
This might be faster than klgr's solutions on large lists:
Pick[a, Unitize[Length /@ a - 1], 1]
Select
and DeleteCases
are known to be kind of slow.
$endgroup$
This might be faster than klgr's solutions on large lists:
Pick[a, Unitize[Length /@ a - 1], 1]
Select
and DeleteCases
are known to be kind of slow.
answered Jan 3 at 12:46
C. E.C. E.
50.2k397202
50.2k397202
add a comment |
add a comment |
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