grep using array values and make it faster
Clash Royale CLAN TAG#URR8PPP
up vote
1
down vote
favorite
array[1] is a string pulled from a 30k lines CSV:
example:
samsung black 2014
I need match those lines with one of the values contained within an array (arrayItems).
arrayItems contains 221 values like:
apple
sony
samsung
The actual script:
while IFS=$';' read -r -a array
do
mapfile -t arrayItems < $itemsFile
## now loop through the above array
for itemToFind in "$arrayItems[@]"
do
itemFound=""
itemFound="$(echo $array[1] | grep -o '^$itemToFind')"
if [ -n "$itemFound" ]
then
echo $itemFound
# so end to search in case the item is found
break
fi
done
# here I do something with $array[2], $array[4] line by line and so on,
# so I can't match the whole file $file_in at once but online line by line.
done < $file_in
The problem is that grep don't match.
but works If I try to hardcode $itemToFind like this:
itemFound="$(echo $array[1] | grep -o '^samsung')"
Another thing is... how to do it faster as $file_in is a 30k lines CSV?
bash shell-script grep array
add a comment |
up vote
1
down vote
favorite
array[1] is a string pulled from a 30k lines CSV:
example:
samsung black 2014
I need match those lines with one of the values contained within an array (arrayItems).
arrayItems contains 221 values like:
apple
sony
samsung
The actual script:
while IFS=$';' read -r -a array
do
mapfile -t arrayItems < $itemsFile
## now loop through the above array
for itemToFind in "$arrayItems[@]"
do
itemFound=""
itemFound="$(echo $array[1] | grep -o '^$itemToFind')"
if [ -n "$itemFound" ]
then
echo $itemFound
# so end to search in case the item is found
break
fi
done
# here I do something with $array[2], $array[4] line by line and so on,
# so I can't match the whole file $file_in at once but online line by line.
done < $file_in
The problem is that grep don't match.
but works If I try to hardcode $itemToFind like this:
itemFound="$(echo $array[1] | grep -o '^samsung')"
Another thing is... how to do it faster as $file_in is a 30k lines CSV?
bash shell-script grep array
If you want better answers, you need to provide a better example. You would also benefit from reading Raymond's smart question essay
– Thor
Nov 29 at 13:27
@Thor you're right. next time I will take a little more time and write a smarter question
– Kintaro
Nov 29 at 13:45
Can you provide an example of lines from the CSV file ?
– lauhub
Nov 29 at 15:20
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
array[1] is a string pulled from a 30k lines CSV:
example:
samsung black 2014
I need match those lines with one of the values contained within an array (arrayItems).
arrayItems contains 221 values like:
apple
sony
samsung
The actual script:
while IFS=$';' read -r -a array
do
mapfile -t arrayItems < $itemsFile
## now loop through the above array
for itemToFind in "$arrayItems[@]"
do
itemFound=""
itemFound="$(echo $array[1] | grep -o '^$itemToFind')"
if [ -n "$itemFound" ]
then
echo $itemFound
# so end to search in case the item is found
break
fi
done
# here I do something with $array[2], $array[4] line by line and so on,
# so I can't match the whole file $file_in at once but online line by line.
done < $file_in
The problem is that grep don't match.
but works If I try to hardcode $itemToFind like this:
itemFound="$(echo $array[1] | grep -o '^samsung')"
Another thing is... how to do it faster as $file_in is a 30k lines CSV?
bash shell-script grep array
array[1] is a string pulled from a 30k lines CSV:
example:
samsung black 2014
I need match those lines with one of the values contained within an array (arrayItems).
arrayItems contains 221 values like:
apple
sony
samsung
The actual script:
while IFS=$';' read -r -a array
do
mapfile -t arrayItems < $itemsFile
## now loop through the above array
for itemToFind in "$arrayItems[@]"
do
itemFound=""
itemFound="$(echo $array[1] | grep -o '^$itemToFind')"
if [ -n "$itemFound" ]
then
echo $itemFound
# so end to search in case the item is found
break
fi
done
# here I do something with $array[2], $array[4] line by line and so on,
# so I can't match the whole file $file_in at once but online line by line.
done < $file_in
The problem is that grep don't match.
but works If I try to hardcode $itemToFind like this:
itemFound="$(echo $array[1] | grep -o '^samsung')"
Another thing is... how to do it faster as $file_in is a 30k lines CSV?
bash shell-script grep array
bash shell-script grep array
edited Nov 29 at 13:41
asked Nov 29 at 12:01
Kintaro
103
103
If you want better answers, you need to provide a better example. You would also benefit from reading Raymond's smart question essay
– Thor
Nov 29 at 13:27
@Thor you're right. next time I will take a little more time and write a smarter question
– Kintaro
Nov 29 at 13:45
Can you provide an example of lines from the CSV file ?
– lauhub
Nov 29 at 15:20
add a comment |
If you want better answers, you need to provide a better example. You would also benefit from reading Raymond's smart question essay
– Thor
Nov 29 at 13:27
@Thor you're right. next time I will take a little more time and write a smarter question
– Kintaro
Nov 29 at 13:45
Can you provide an example of lines from the CSV file ?
– lauhub
Nov 29 at 15:20
If you want better answers, you need to provide a better example. You would also benefit from reading Raymond's smart question essay
– Thor
Nov 29 at 13:27
If you want better answers, you need to provide a better example. You would also benefit from reading Raymond's smart question essay
– Thor
Nov 29 at 13:27
@Thor you're right. next time I will take a little more time and write a smarter question
– Kintaro
Nov 29 at 13:45
@Thor you're right. next time I will take a little more time and write a smarter question
– Kintaro
Nov 29 at 13:45
Can you provide an example of lines from the CSV file ?
– lauhub
Nov 29 at 15:20
Can you provide an example of lines from the CSV file ?
– lauhub
Nov 29 at 15:20
add a comment |
2 Answers
2
active
oldest
votes
up vote
2
down vote
accepted
You can use grep with file pattern option (-f)
Example:
$ echo -e "applensonynsamsung" > file_pattern
$ grep -f file_pattern your.csv
EDIT:
In response of your new contraints:
sed 's/^/^/g' $itemsFile > /tmp/pattern_file
while IFS=$';' read -r -a array
do
echo $array[1] | grep -q -f /tmp/pattern_file.txt
if [ $? -eq 0 ]; then
# here I do something with $array[2], $array[4] line by line and so on,
# so I can't match the whole file $file_in at once but online line by line.
fi
done < $file_in
I think you miss the-e
option for echo
– lauhub
Nov 29 at 12:22
I need to check it line by line. (question code updated)
– Kintaro
Nov 29 at 13:16
Yes, this is working very fast! I found it here too. Now the only thing I miss is the^
in the regex (I edited again, sorry)
– Kintaro
Nov 29 at 13:43
If you want check if line start with pattern, you need to add ^ at the start of each line of $itemsFile. You can usesed -i 's/^/^/g' $itemsFile
. Be careful, this command change your file.
– apapillon
Nov 29 at 13:59
add a comment |
up vote
1
down vote
There are two errors in your script:
grep tries to match the string
$itemToFind
because you put it between single quote'
. Use double-quote instead.you are using an array from index 1 while
help read
tells it is starting at zero.
This should give this:
while IFS=$';' read -r -a array
do
mapfile -t arrayItems < $itemsFile
## now loop through the above array
for itemToFind in "$arrayItems[@]"
do
itemFound=""
itemFound=$(echo $array[0] | grep -o "$itemToFind")
if [ -n "$itemFound" ]
then
echo $itemFound
# so end to search in case the item is found
break
fi
done
done < $file_in
EDIT:
If you want to make it faster, you can use extended regular expressions :
grep -E 'apple|sony|samsung' $file_in
And if you want to display only brands:
grep -E 'apple|sony|samsung' $file_in | awk 'print $1'
I use $array[1] because in the $array[1] doesn't contain the data I need from the CSV. $array[0] contain the first item of the column (which in this case is a reference code), I need the second item (which is the item name). Plus, the first while do other things during every loop (I'm going to add some code in the question)
– Kintaro
Nov 29 at 12:58
I suggest you to add the lineecho array0=$array[0] array1=$array[1]
in your loop and check what happens (to me,$array[0]
is the complete line, asread
separates entries with newline characters)
– lauhub
Nov 29 at 13:02
$file_in
is a CSV with;
as a separator (as you can see the 1st while have:IFS=$';'
),$array[0]
contains the first value of the line,$array[1]
the 2nd and so no. p.s. I just edited the question code.
– Kintaro
Nov 29 at 13:10
@Kintaro Did changing the single-quote help ?
– lauhub
Nov 29 at 15:21
yes double quotes helped but then I switched to the -f option
– Kintaro
Nov 30 at 8:13
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
You can use grep with file pattern option (-f)
Example:
$ echo -e "applensonynsamsung" > file_pattern
$ grep -f file_pattern your.csv
EDIT:
In response of your new contraints:
sed 's/^/^/g' $itemsFile > /tmp/pattern_file
while IFS=$';' read -r -a array
do
echo $array[1] | grep -q -f /tmp/pattern_file.txt
if [ $? -eq 0 ]; then
# here I do something with $array[2], $array[4] line by line and so on,
# so I can't match the whole file $file_in at once but online line by line.
fi
done < $file_in
I think you miss the-e
option for echo
– lauhub
Nov 29 at 12:22
I need to check it line by line. (question code updated)
– Kintaro
Nov 29 at 13:16
Yes, this is working very fast! I found it here too. Now the only thing I miss is the^
in the regex (I edited again, sorry)
– Kintaro
Nov 29 at 13:43
If you want check if line start with pattern, you need to add ^ at the start of each line of $itemsFile. You can usesed -i 's/^/^/g' $itemsFile
. Be careful, this command change your file.
– apapillon
Nov 29 at 13:59
add a comment |
up vote
2
down vote
accepted
You can use grep with file pattern option (-f)
Example:
$ echo -e "applensonynsamsung" > file_pattern
$ grep -f file_pattern your.csv
EDIT:
In response of your new contraints:
sed 's/^/^/g' $itemsFile > /tmp/pattern_file
while IFS=$';' read -r -a array
do
echo $array[1] | grep -q -f /tmp/pattern_file.txt
if [ $? -eq 0 ]; then
# here I do something with $array[2], $array[4] line by line and so on,
# so I can't match the whole file $file_in at once but online line by line.
fi
done < $file_in
I think you miss the-e
option for echo
– lauhub
Nov 29 at 12:22
I need to check it line by line. (question code updated)
– Kintaro
Nov 29 at 13:16
Yes, this is working very fast! I found it here too. Now the only thing I miss is the^
in the regex (I edited again, sorry)
– Kintaro
Nov 29 at 13:43
If you want check if line start with pattern, you need to add ^ at the start of each line of $itemsFile. You can usesed -i 's/^/^/g' $itemsFile
. Be careful, this command change your file.
– apapillon
Nov 29 at 13:59
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
You can use grep with file pattern option (-f)
Example:
$ echo -e "applensonynsamsung" > file_pattern
$ grep -f file_pattern your.csv
EDIT:
In response of your new contraints:
sed 's/^/^/g' $itemsFile > /tmp/pattern_file
while IFS=$';' read -r -a array
do
echo $array[1] | grep -q -f /tmp/pattern_file.txt
if [ $? -eq 0 ]; then
# here I do something with $array[2], $array[4] line by line and so on,
# so I can't match the whole file $file_in at once but online line by line.
fi
done < $file_in
You can use grep with file pattern option (-f)
Example:
$ echo -e "applensonynsamsung" > file_pattern
$ grep -f file_pattern your.csv
EDIT:
In response of your new contraints:
sed 's/^/^/g' $itemsFile > /tmp/pattern_file
while IFS=$';' read -r -a array
do
echo $array[1] | grep -q -f /tmp/pattern_file.txt
if [ $? -eq 0 ]; then
# here I do something with $array[2], $array[4] line by line and so on,
# so I can't match the whole file $file_in at once but online line by line.
fi
done < $file_in
edited Nov 29 at 13:56
answered Nov 29 at 12:19
apapillon
615
615
I think you miss the-e
option for echo
– lauhub
Nov 29 at 12:22
I need to check it line by line. (question code updated)
– Kintaro
Nov 29 at 13:16
Yes, this is working very fast! I found it here too. Now the only thing I miss is the^
in the regex (I edited again, sorry)
– Kintaro
Nov 29 at 13:43
If you want check if line start with pattern, you need to add ^ at the start of each line of $itemsFile. You can usesed -i 's/^/^/g' $itemsFile
. Be careful, this command change your file.
– apapillon
Nov 29 at 13:59
add a comment |
I think you miss the-e
option for echo
– lauhub
Nov 29 at 12:22
I need to check it line by line. (question code updated)
– Kintaro
Nov 29 at 13:16
Yes, this is working very fast! I found it here too. Now the only thing I miss is the^
in the regex (I edited again, sorry)
– Kintaro
Nov 29 at 13:43
If you want check if line start with pattern, you need to add ^ at the start of each line of $itemsFile. You can usesed -i 's/^/^/g' $itemsFile
. Be careful, this command change your file.
– apapillon
Nov 29 at 13:59
I think you miss the
-e
option for echo– lauhub
Nov 29 at 12:22
I think you miss the
-e
option for echo– lauhub
Nov 29 at 12:22
I need to check it line by line. (question code updated)
– Kintaro
Nov 29 at 13:16
I need to check it line by line. (question code updated)
– Kintaro
Nov 29 at 13:16
Yes, this is working very fast! I found it here too. Now the only thing I miss is the
^
in the regex (I edited again, sorry)– Kintaro
Nov 29 at 13:43
Yes, this is working very fast! I found it here too. Now the only thing I miss is the
^
in the regex (I edited again, sorry)– Kintaro
Nov 29 at 13:43
If you want check if line start with pattern, you need to add ^ at the start of each line of $itemsFile. You can use
sed -i 's/^/^/g' $itemsFile
. Be careful, this command change your file.– apapillon
Nov 29 at 13:59
If you want check if line start with pattern, you need to add ^ at the start of each line of $itemsFile. You can use
sed -i 's/^/^/g' $itemsFile
. Be careful, this command change your file.– apapillon
Nov 29 at 13:59
add a comment |
up vote
1
down vote
There are two errors in your script:
grep tries to match the string
$itemToFind
because you put it between single quote'
. Use double-quote instead.you are using an array from index 1 while
help read
tells it is starting at zero.
This should give this:
while IFS=$';' read -r -a array
do
mapfile -t arrayItems < $itemsFile
## now loop through the above array
for itemToFind in "$arrayItems[@]"
do
itemFound=""
itemFound=$(echo $array[0] | grep -o "$itemToFind")
if [ -n "$itemFound" ]
then
echo $itemFound
# so end to search in case the item is found
break
fi
done
done < $file_in
EDIT:
If you want to make it faster, you can use extended regular expressions :
grep -E 'apple|sony|samsung' $file_in
And if you want to display only brands:
grep -E 'apple|sony|samsung' $file_in | awk 'print $1'
I use $array[1] because in the $array[1] doesn't contain the data I need from the CSV. $array[0] contain the first item of the column (which in this case is a reference code), I need the second item (which is the item name). Plus, the first while do other things during every loop (I'm going to add some code in the question)
– Kintaro
Nov 29 at 12:58
I suggest you to add the lineecho array0=$array[0] array1=$array[1]
in your loop and check what happens (to me,$array[0]
is the complete line, asread
separates entries with newline characters)
– lauhub
Nov 29 at 13:02
$file_in
is a CSV with;
as a separator (as you can see the 1st while have:IFS=$';'
),$array[0]
contains the first value of the line,$array[1]
the 2nd and so no. p.s. I just edited the question code.
– Kintaro
Nov 29 at 13:10
@Kintaro Did changing the single-quote help ?
– lauhub
Nov 29 at 15:21
yes double quotes helped but then I switched to the -f option
– Kintaro
Nov 30 at 8:13
add a comment |
up vote
1
down vote
There are two errors in your script:
grep tries to match the string
$itemToFind
because you put it between single quote'
. Use double-quote instead.you are using an array from index 1 while
help read
tells it is starting at zero.
This should give this:
while IFS=$';' read -r -a array
do
mapfile -t arrayItems < $itemsFile
## now loop through the above array
for itemToFind in "$arrayItems[@]"
do
itemFound=""
itemFound=$(echo $array[0] | grep -o "$itemToFind")
if [ -n "$itemFound" ]
then
echo $itemFound
# so end to search in case the item is found
break
fi
done
done < $file_in
EDIT:
If you want to make it faster, you can use extended regular expressions :
grep -E 'apple|sony|samsung' $file_in
And if you want to display only brands:
grep -E 'apple|sony|samsung' $file_in | awk 'print $1'
I use $array[1] because in the $array[1] doesn't contain the data I need from the CSV. $array[0] contain the first item of the column (which in this case is a reference code), I need the second item (which is the item name). Plus, the first while do other things during every loop (I'm going to add some code in the question)
– Kintaro
Nov 29 at 12:58
I suggest you to add the lineecho array0=$array[0] array1=$array[1]
in your loop and check what happens (to me,$array[0]
is the complete line, asread
separates entries with newline characters)
– lauhub
Nov 29 at 13:02
$file_in
is a CSV with;
as a separator (as you can see the 1st while have:IFS=$';'
),$array[0]
contains the first value of the line,$array[1]
the 2nd and so no. p.s. I just edited the question code.
– Kintaro
Nov 29 at 13:10
@Kintaro Did changing the single-quote help ?
– lauhub
Nov 29 at 15:21
yes double quotes helped but then I switched to the -f option
– Kintaro
Nov 30 at 8:13
add a comment |
up vote
1
down vote
up vote
1
down vote
There are two errors in your script:
grep tries to match the string
$itemToFind
because you put it between single quote'
. Use double-quote instead.you are using an array from index 1 while
help read
tells it is starting at zero.
This should give this:
while IFS=$';' read -r -a array
do
mapfile -t arrayItems < $itemsFile
## now loop through the above array
for itemToFind in "$arrayItems[@]"
do
itemFound=""
itemFound=$(echo $array[0] | grep -o "$itemToFind")
if [ -n "$itemFound" ]
then
echo $itemFound
# so end to search in case the item is found
break
fi
done
done < $file_in
EDIT:
If you want to make it faster, you can use extended regular expressions :
grep -E 'apple|sony|samsung' $file_in
And if you want to display only brands:
grep -E 'apple|sony|samsung' $file_in | awk 'print $1'
There are two errors in your script:
grep tries to match the string
$itemToFind
because you put it between single quote'
. Use double-quote instead.you are using an array from index 1 while
help read
tells it is starting at zero.
This should give this:
while IFS=$';' read -r -a array
do
mapfile -t arrayItems < $itemsFile
## now loop through the above array
for itemToFind in "$arrayItems[@]"
do
itemFound=""
itemFound=$(echo $array[0] | grep -o "$itemToFind")
if [ -n "$itemFound" ]
then
echo $itemFound
# so end to search in case the item is found
break
fi
done
done < $file_in
EDIT:
If you want to make it faster, you can use extended regular expressions :
grep -E 'apple|sony|samsung' $file_in
And if you want to display only brands:
grep -E 'apple|sony|samsung' $file_in | awk 'print $1'
edited Nov 29 at 12:27
answered Nov 29 at 12:18
lauhub
430616
430616
I use $array[1] because in the $array[1] doesn't contain the data I need from the CSV. $array[0] contain the first item of the column (which in this case is a reference code), I need the second item (which is the item name). Plus, the first while do other things during every loop (I'm going to add some code in the question)
– Kintaro
Nov 29 at 12:58
I suggest you to add the lineecho array0=$array[0] array1=$array[1]
in your loop and check what happens (to me,$array[0]
is the complete line, asread
separates entries with newline characters)
– lauhub
Nov 29 at 13:02
$file_in
is a CSV with;
as a separator (as you can see the 1st while have:IFS=$';'
),$array[0]
contains the first value of the line,$array[1]
the 2nd and so no. p.s. I just edited the question code.
– Kintaro
Nov 29 at 13:10
@Kintaro Did changing the single-quote help ?
– lauhub
Nov 29 at 15:21
yes double quotes helped but then I switched to the -f option
– Kintaro
Nov 30 at 8:13
add a comment |
I use $array[1] because in the $array[1] doesn't contain the data I need from the CSV. $array[0] contain the first item of the column (which in this case is a reference code), I need the second item (which is the item name). Plus, the first while do other things during every loop (I'm going to add some code in the question)
– Kintaro
Nov 29 at 12:58
I suggest you to add the lineecho array0=$array[0] array1=$array[1]
in your loop and check what happens (to me,$array[0]
is the complete line, asread
separates entries with newline characters)
– lauhub
Nov 29 at 13:02
$file_in
is a CSV with;
as a separator (as you can see the 1st while have:IFS=$';'
),$array[0]
contains the first value of the line,$array[1]
the 2nd and so no. p.s. I just edited the question code.
– Kintaro
Nov 29 at 13:10
@Kintaro Did changing the single-quote help ?
– lauhub
Nov 29 at 15:21
yes double quotes helped but then I switched to the -f option
– Kintaro
Nov 30 at 8:13
I use $array[1] because in the $array[1] doesn't contain the data I need from the CSV. $array[0] contain the first item of the column (which in this case is a reference code), I need the second item (which is the item name). Plus, the first while do other things during every loop (I'm going to add some code in the question)
– Kintaro
Nov 29 at 12:58
I use $array[1] because in the $array[1] doesn't contain the data I need from the CSV. $array[0] contain the first item of the column (which in this case is a reference code), I need the second item (which is the item name). Plus, the first while do other things during every loop (I'm going to add some code in the question)
– Kintaro
Nov 29 at 12:58
I suggest you to add the line
echo array0=$array[0] array1=$array[1]
in your loop and check what happens (to me, $array[0]
is the complete line, as read
separates entries with newline characters)– lauhub
Nov 29 at 13:02
I suggest you to add the line
echo array0=$array[0] array1=$array[1]
in your loop and check what happens (to me, $array[0]
is the complete line, as read
separates entries with newline characters)– lauhub
Nov 29 at 13:02
$file_in
is a CSV with ;
as a separator (as you can see the 1st while have: IFS=$';'
), $array[0]
contains the first value of the line, $array[1]
the 2nd and so no. p.s. I just edited the question code.– Kintaro
Nov 29 at 13:10
$file_in
is a CSV with ;
as a separator (as you can see the 1st while have: IFS=$';'
), $array[0]
contains the first value of the line, $array[1]
the 2nd and so no. p.s. I just edited the question code.– Kintaro
Nov 29 at 13:10
@Kintaro Did changing the single-quote help ?
– lauhub
Nov 29 at 15:21
@Kintaro Did changing the single-quote help ?
– lauhub
Nov 29 at 15:21
yes double quotes helped but then I switched to the -f option
– Kintaro
Nov 30 at 8:13
yes double quotes helped but then I switched to the -f option
– Kintaro
Nov 30 at 8:13
add a comment |
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If you want better answers, you need to provide a better example. You would also benefit from reading Raymond's smart question essay
– Thor
Nov 29 at 13:27
@Thor you're right. next time I will take a little more time and write a smarter question
– Kintaro
Nov 29 at 13:45
Can you provide an example of lines from the CSV file ?
– lauhub
Nov 29 at 15:20