Check that 2 arrays of file names are the same

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So I have the following:



cat file | grep -E regex 


which gives a list of lines

Now I also have a for loop the produces a list of files

So it is like I have 2 arrays.

But how do I check in bash if both arrays have the same content? My bash version does not support associative arrays (4.2).

Should I find another way other than bash or is it doable with bash easily too?



Update

I go over for i in foo/bar/* and record the paths so I essentially I have somewhere:



foo/bar/a/b 
foo/bar/c/d
foo/bar/e etc


So I essentially just want to re-run the for loop and check that I get exactly the same outcome.










share|improve this question



















  • 3




    Using grep or diffcould help. Add sample data to your post for more infos.
    – Michael D.
    Nov 29 at 12:15






  • 2




    filenames can span more than one line, unfortunately. Do you have any insight or control into what generates the contents of file? Or can you declare an assumption/restriction that your filenames will never have newlines in them?
    – Jeff Schaller
    Nov 29 at 13:39










  • @JeffSchaller: Yes no new lines in file names
    – Jim
    Nov 29 at 15:06










  • Some sample data / directory structure might help understand your request, as "a list of lines" does not necessarily equal "a list of files".
    – RudiC
    Nov 29 at 17:45






  • 1




    @JeffSchaller:I updated post
    – Jim
    Nov 29 at 18:22














up vote
0
down vote

favorite












So I have the following:



cat file | grep -E regex 


which gives a list of lines

Now I also have a for loop the produces a list of files

So it is like I have 2 arrays.

But how do I check in bash if both arrays have the same content? My bash version does not support associative arrays (4.2).

Should I find another way other than bash or is it doable with bash easily too?



Update

I go over for i in foo/bar/* and record the paths so I essentially I have somewhere:



foo/bar/a/b 
foo/bar/c/d
foo/bar/e etc


So I essentially just want to re-run the for loop and check that I get exactly the same outcome.










share|improve this question



















  • 3




    Using grep or diffcould help. Add sample data to your post for more infos.
    – Michael D.
    Nov 29 at 12:15






  • 2




    filenames can span more than one line, unfortunately. Do you have any insight or control into what generates the contents of file? Or can you declare an assumption/restriction that your filenames will never have newlines in them?
    – Jeff Schaller
    Nov 29 at 13:39










  • @JeffSchaller: Yes no new lines in file names
    – Jim
    Nov 29 at 15:06










  • Some sample data / directory structure might help understand your request, as "a list of lines" does not necessarily equal "a list of files".
    – RudiC
    Nov 29 at 17:45






  • 1




    @JeffSchaller:I updated post
    – Jim
    Nov 29 at 18:22












up vote
0
down vote

favorite









up vote
0
down vote

favorite











So I have the following:



cat file | grep -E regex 


which gives a list of lines

Now I also have a for loop the produces a list of files

So it is like I have 2 arrays.

But how do I check in bash if both arrays have the same content? My bash version does not support associative arrays (4.2).

Should I find another way other than bash or is it doable with bash easily too?



Update

I go over for i in foo/bar/* and record the paths so I essentially I have somewhere:



foo/bar/a/b 
foo/bar/c/d
foo/bar/e etc


So I essentially just want to re-run the for loop and check that I get exactly the same outcome.










share|improve this question















So I have the following:



cat file | grep -E regex 


which gives a list of lines

Now I also have a for loop the produces a list of files

So it is like I have 2 arrays.

But how do I check in bash if both arrays have the same content? My bash version does not support associative arrays (4.2).

Should I find another way other than bash or is it doable with bash easily too?



Update

I go over for i in foo/bar/* and record the paths so I essentially I have somewhere:



foo/bar/a/b 
foo/bar/c/d
foo/bar/e etc


So I essentially just want to re-run the for loop and check that I get exactly the same outcome.







bash filenames array






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 29 at 18:22

























asked Nov 29 at 11:58









Jim

390213




390213







  • 3




    Using grep or diffcould help. Add sample data to your post for more infos.
    – Michael D.
    Nov 29 at 12:15






  • 2




    filenames can span more than one line, unfortunately. Do you have any insight or control into what generates the contents of file? Or can you declare an assumption/restriction that your filenames will never have newlines in them?
    – Jeff Schaller
    Nov 29 at 13:39










  • @JeffSchaller: Yes no new lines in file names
    – Jim
    Nov 29 at 15:06










  • Some sample data / directory structure might help understand your request, as "a list of lines" does not necessarily equal "a list of files".
    – RudiC
    Nov 29 at 17:45






  • 1




    @JeffSchaller:I updated post
    – Jim
    Nov 29 at 18:22












  • 3




    Using grep or diffcould help. Add sample data to your post for more infos.
    – Michael D.
    Nov 29 at 12:15






  • 2




    filenames can span more than one line, unfortunately. Do you have any insight or control into what generates the contents of file? Or can you declare an assumption/restriction that your filenames will never have newlines in them?
    – Jeff Schaller
    Nov 29 at 13:39










  • @JeffSchaller: Yes no new lines in file names
    – Jim
    Nov 29 at 15:06










  • Some sample data / directory structure might help understand your request, as "a list of lines" does not necessarily equal "a list of files".
    – RudiC
    Nov 29 at 17:45






  • 1




    @JeffSchaller:I updated post
    – Jim
    Nov 29 at 18:22







3




3




Using grep or diffcould help. Add sample data to your post for more infos.
– Michael D.
Nov 29 at 12:15




Using grep or diffcould help. Add sample data to your post for more infos.
– Michael D.
Nov 29 at 12:15




2




2




filenames can span more than one line, unfortunately. Do you have any insight or control into what generates the contents of file? Or can you declare an assumption/restriction that your filenames will never have newlines in them?
– Jeff Schaller
Nov 29 at 13:39




filenames can span more than one line, unfortunately. Do you have any insight or control into what generates the contents of file? Or can you declare an assumption/restriction that your filenames will never have newlines in them?
– Jeff Schaller
Nov 29 at 13:39












@JeffSchaller: Yes no new lines in file names
– Jim
Nov 29 at 15:06




@JeffSchaller: Yes no new lines in file names
– Jim
Nov 29 at 15:06












Some sample data / directory structure might help understand your request, as "a list of lines" does not necessarily equal "a list of files".
– RudiC
Nov 29 at 17:45




Some sample data / directory structure might help understand your request, as "a list of lines" does not necessarily equal "a list of files".
– RudiC
Nov 29 at 17:45




1




1




@JeffSchaller:I updated post
– Jim
Nov 29 at 18:22




@JeffSchaller:I updated post
– Jim
Nov 29 at 18:22










1 Answer
1






active

oldest

votes

















up vote
0
down vote













Assuming your arrays are named "array1" and "array2", bash code to check for equality:



equal=true
if [[ $#array1[@] -ne $#array2[@] ]]; then
equal=false
else
while IFS= read -r elem1 <&3; IFS= read -r elem2 <&4; do
if [[ "$elem1" != "$elem2" ]]; then
equal=false
break
fi
done 3< <(printf "%sn" "$array1[@]" | sort)
4< <(printf "%sn" "$array2[@]" | sort)
fi
if $equal; then
echo arrays have the same contents
else
echo arrays have different contents
fi


This will be (probably "much") slower than calling out to external tools.



diff <(grep -E regex file1) <(grep -E regex file2)





share|improve this answer




















  • How do I initialize the arrays? Also the 2 < in the diff snippet are they right?
    – Jim
    Nov 29 at 15:58











  • Also what is 3 and 4?
    – Jim
    Nov 29 at 16:46










  • "3" and "4" are file descriptors: I want to be able to read from 2 different files in the same loop, so I red them from different file descriptors. Note how 3< after the loop corresponds with the <&3 in one of the read commands.
    – glenn jackman
    Nov 30 at 0:17











  • The 2 < are correct: this bit 3< is the redirection and this bit <(...) is a process substitution
    – glenn jackman
    Nov 30 at 0:18











  • I can't make that part work. I get an error as if diff us using the outputs of grep as files and says can't open them
    – Jim
    Nov 30 at 8:51










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1 Answer
1






active

oldest

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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes








up vote
0
down vote













Assuming your arrays are named "array1" and "array2", bash code to check for equality:



equal=true
if [[ $#array1[@] -ne $#array2[@] ]]; then
equal=false
else
while IFS= read -r elem1 <&3; IFS= read -r elem2 <&4; do
if [[ "$elem1" != "$elem2" ]]; then
equal=false
break
fi
done 3< <(printf "%sn" "$array1[@]" | sort)
4< <(printf "%sn" "$array2[@]" | sort)
fi
if $equal; then
echo arrays have the same contents
else
echo arrays have different contents
fi


This will be (probably "much") slower than calling out to external tools.



diff <(grep -E regex file1) <(grep -E regex file2)





share|improve this answer




















  • How do I initialize the arrays? Also the 2 < in the diff snippet are they right?
    – Jim
    Nov 29 at 15:58











  • Also what is 3 and 4?
    – Jim
    Nov 29 at 16:46










  • "3" and "4" are file descriptors: I want to be able to read from 2 different files in the same loop, so I red them from different file descriptors. Note how 3< after the loop corresponds with the <&3 in one of the read commands.
    – glenn jackman
    Nov 30 at 0:17











  • The 2 < are correct: this bit 3< is the redirection and this bit <(...) is a process substitution
    – glenn jackman
    Nov 30 at 0:18











  • I can't make that part work. I get an error as if diff us using the outputs of grep as files and says can't open them
    – Jim
    Nov 30 at 8:51














up vote
0
down vote













Assuming your arrays are named "array1" and "array2", bash code to check for equality:



equal=true
if [[ $#array1[@] -ne $#array2[@] ]]; then
equal=false
else
while IFS= read -r elem1 <&3; IFS= read -r elem2 <&4; do
if [[ "$elem1" != "$elem2" ]]; then
equal=false
break
fi
done 3< <(printf "%sn" "$array1[@]" | sort)
4< <(printf "%sn" "$array2[@]" | sort)
fi
if $equal; then
echo arrays have the same contents
else
echo arrays have different contents
fi


This will be (probably "much") slower than calling out to external tools.



diff <(grep -E regex file1) <(grep -E regex file2)





share|improve this answer




















  • How do I initialize the arrays? Also the 2 < in the diff snippet are they right?
    – Jim
    Nov 29 at 15:58











  • Also what is 3 and 4?
    – Jim
    Nov 29 at 16:46










  • "3" and "4" are file descriptors: I want to be able to read from 2 different files in the same loop, so I red them from different file descriptors. Note how 3< after the loop corresponds with the <&3 in one of the read commands.
    – glenn jackman
    Nov 30 at 0:17











  • The 2 < are correct: this bit 3< is the redirection and this bit <(...) is a process substitution
    – glenn jackman
    Nov 30 at 0:18











  • I can't make that part work. I get an error as if diff us using the outputs of grep as files and says can't open them
    – Jim
    Nov 30 at 8:51












up vote
0
down vote










up vote
0
down vote









Assuming your arrays are named "array1" and "array2", bash code to check for equality:



equal=true
if [[ $#array1[@] -ne $#array2[@] ]]; then
equal=false
else
while IFS= read -r elem1 <&3; IFS= read -r elem2 <&4; do
if [[ "$elem1" != "$elem2" ]]; then
equal=false
break
fi
done 3< <(printf "%sn" "$array1[@]" | sort)
4< <(printf "%sn" "$array2[@]" | sort)
fi
if $equal; then
echo arrays have the same contents
else
echo arrays have different contents
fi


This will be (probably "much") slower than calling out to external tools.



diff <(grep -E regex file1) <(grep -E regex file2)





share|improve this answer












Assuming your arrays are named "array1" and "array2", bash code to check for equality:



equal=true
if [[ $#array1[@] -ne $#array2[@] ]]; then
equal=false
else
while IFS= read -r elem1 <&3; IFS= read -r elem2 <&4; do
if [[ "$elem1" != "$elem2" ]]; then
equal=false
break
fi
done 3< <(printf "%sn" "$array1[@]" | sort)
4< <(printf "%sn" "$array2[@]" | sort)
fi
if $equal; then
echo arrays have the same contents
else
echo arrays have different contents
fi


This will be (probably "much") slower than calling out to external tools.



diff <(grep -E regex file1) <(grep -E regex file2)






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 29 at 15:30









glenn jackman

49.7k569106




49.7k569106











  • How do I initialize the arrays? Also the 2 < in the diff snippet are they right?
    – Jim
    Nov 29 at 15:58











  • Also what is 3 and 4?
    – Jim
    Nov 29 at 16:46










  • "3" and "4" are file descriptors: I want to be able to read from 2 different files in the same loop, so I red them from different file descriptors. Note how 3< after the loop corresponds with the <&3 in one of the read commands.
    – glenn jackman
    Nov 30 at 0:17











  • The 2 < are correct: this bit 3< is the redirection and this bit <(...) is a process substitution
    – glenn jackman
    Nov 30 at 0:18











  • I can't make that part work. I get an error as if diff us using the outputs of grep as files and says can't open them
    – Jim
    Nov 30 at 8:51
















  • How do I initialize the arrays? Also the 2 < in the diff snippet are they right?
    – Jim
    Nov 29 at 15:58











  • Also what is 3 and 4?
    – Jim
    Nov 29 at 16:46










  • "3" and "4" are file descriptors: I want to be able to read from 2 different files in the same loop, so I red them from different file descriptors. Note how 3< after the loop corresponds with the <&3 in one of the read commands.
    – glenn jackman
    Nov 30 at 0:17











  • The 2 < are correct: this bit 3< is the redirection and this bit <(...) is a process substitution
    – glenn jackman
    Nov 30 at 0:18











  • I can't make that part work. I get an error as if diff us using the outputs of grep as files and says can't open them
    – Jim
    Nov 30 at 8:51















How do I initialize the arrays? Also the 2 < in the diff snippet are they right?
– Jim
Nov 29 at 15:58





How do I initialize the arrays? Also the 2 < in the diff snippet are they right?
– Jim
Nov 29 at 15:58













Also what is 3 and 4?
– Jim
Nov 29 at 16:46




Also what is 3 and 4?
– Jim
Nov 29 at 16:46












"3" and "4" are file descriptors: I want to be able to read from 2 different files in the same loop, so I red them from different file descriptors. Note how 3< after the loop corresponds with the <&3 in one of the read commands.
– glenn jackman
Nov 30 at 0:17





"3" and "4" are file descriptors: I want to be able to read from 2 different files in the same loop, so I red them from different file descriptors. Note how 3< after the loop corresponds with the <&3 in one of the read commands.
– glenn jackman
Nov 30 at 0:17













The 2 < are correct: this bit 3< is the redirection and this bit <(...) is a process substitution
– glenn jackman
Nov 30 at 0:18





The 2 < are correct: this bit 3< is the redirection and this bit <(...) is a process substitution
– glenn jackman
Nov 30 at 0:18













I can't make that part work. I get an error as if diff us using the outputs of grep as files and says can't open them
– Jim
Nov 30 at 8:51




I can't make that part work. I get an error as if diff us using the outputs of grep as files and says can't open them
– Jim
Nov 30 at 8:51

















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