mjhjmtu

My code need compare "stop" with stop this is stand bash string.

pi@raspberrypi:~/Voice $ ./test.sh | more
"stop"
stop

My code:

#!/bin/bash
command=stop
while :
do
 QUESTION=$(cat stt.txt) #stt,txt has command "stop"
 echo $QUESTION
 echo $command
 if [ "$QUESTION" == "$command" ]; then
 echo "You said "stop"!"
 break
 fi
done

I had try different command="stop", the result is same.
I try to put command=$('stop'), it's okay only one time, then it complains:
./test.sh: line 2: stop: command not found.

I don't know why it is suddenly stop working to set stop as command, not "stop"

Thank everybody's help.
I try different one, this is working for me!

#!/bin/bash
command=""stop""
while :
do
 QUESTION=$(cat stt.txt) #stt,txt has command "stop"
 echo $QUESTION
 echo $command
 if [ "$QUESTION" = "$command" ]; then
 echo "You said $command"!
 break
 fi
done

#!/bin/bash
command="stop"
while :
do
 QUESTION=$(cat stt.txt) #stt,txt has command "stop"
 echo $QUESTION
 echo $command
 if [ "$QUESTION" == "$command" ]; then
 echo "You said $command"!
 break
 fi
done

I made a two changes to your script.

1. 
   

   All strings entered directly into scripts for use in variables should be quoted, otherwise bash will try to interpret them as commands. As such this is not a valid way to declare a variable 'command' with a string value 'stop'.

   
   
   

   command=stop
   

   
   
   

   This is a valid way.

   
   
   

   command="stop"
   

   
   


2. 
   

   Also bash will try to interpret your ! as you trying to recall an event, you would need to place that outside your quotes and escape it.

   
   
   

   echo "You said $command"!
   

   
   

grep -q '"stop"' < in > /dev/null && echo hooray