Addition of values in second columns if the first column entry is same in UNIX

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I am trying to aggregate a file containing the following data in UNIX.
I need to add the amounts if the key is same.



Key,amount,date,Time
abc-xyz-12234,45,15-08-91,23:00
pqr-vgh-5241,15,15-08-91,21:00
abc-xyz-12234,35,15-08-91,23:00
pqr-vgh-5241,24,15-08-91,21:00
abc-xyz-12234,655,15-08-91,23:00
lkj-erf-8542,281,15-08-91,10:00
pqr-vgh-5241,40,15-08-91,21:00


Output should be as following



abc-xyz-12234,735,15-08-91,23:00
pqr-vgh-5241,79,15-08-91,21:00
lkj-erf-8542,281,15-08-91,10:00


I tried by the following command ,but it just gives me uniq



cat file | grep "abc-xyz-12234" | uniq









share|improve this question



























    up vote
    2
    down vote

    favorite












    I am trying to aggregate a file containing the following data in UNIX.
    I need to add the amounts if the key is same.



    Key,amount,date,Time
    abc-xyz-12234,45,15-08-91,23:00
    pqr-vgh-5241,15,15-08-91,21:00
    abc-xyz-12234,35,15-08-91,23:00
    pqr-vgh-5241,24,15-08-91,21:00
    abc-xyz-12234,655,15-08-91,23:00
    lkj-erf-8542,281,15-08-91,10:00
    pqr-vgh-5241,40,15-08-91,21:00


    Output should be as following



    abc-xyz-12234,735,15-08-91,23:00
    pqr-vgh-5241,79,15-08-91,21:00
    lkj-erf-8542,281,15-08-91,10:00


    I tried by the following command ,but it just gives me uniq



    cat file | grep "abc-xyz-12234" | uniq









    share|improve this question

























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      I am trying to aggregate a file containing the following data in UNIX.
      I need to add the amounts if the key is same.



      Key,amount,date,Time
      abc-xyz-12234,45,15-08-91,23:00
      pqr-vgh-5241,15,15-08-91,21:00
      abc-xyz-12234,35,15-08-91,23:00
      pqr-vgh-5241,24,15-08-91,21:00
      abc-xyz-12234,655,15-08-91,23:00
      lkj-erf-8542,281,15-08-91,10:00
      pqr-vgh-5241,40,15-08-91,21:00


      Output should be as following



      abc-xyz-12234,735,15-08-91,23:00
      pqr-vgh-5241,79,15-08-91,21:00
      lkj-erf-8542,281,15-08-91,10:00


      I tried by the following command ,but it just gives me uniq



      cat file | grep "abc-xyz-12234" | uniq









      share|improve this question















      I am trying to aggregate a file containing the following data in UNIX.
      I need to add the amounts if the key is same.



      Key,amount,date,Time
      abc-xyz-12234,45,15-08-91,23:00
      pqr-vgh-5241,15,15-08-91,21:00
      abc-xyz-12234,35,15-08-91,23:00
      pqr-vgh-5241,24,15-08-91,21:00
      abc-xyz-12234,655,15-08-91,23:00
      lkj-erf-8542,281,15-08-91,10:00
      pqr-vgh-5241,40,15-08-91,21:00


      Output should be as following



      abc-xyz-12234,735,15-08-91,23:00
      pqr-vgh-5241,79,15-08-91,21:00
      lkj-erf-8542,281,15-08-91,10:00


      I tried by the following command ,but it just gives me uniq



      cat file | grep "abc-xyz-12234" | uniq






      csv






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 20 at 22:44









      Rui F Ribeiro

      38.2k1475125




      38.2k1475125










      asked Nov 6 '15 at 9:30









      Kshitij

      111




      111




















          3 Answers
          3






          active

          oldest

          votes

















          up vote
          3
          down vote













          Another possible solution with awk could be:



          awk 'BEGIN FS = OFS = "," 
          NR != 1 y[$1] += $2; $2 = y[$1]; x[$1] = $0;
          END for (i in x) print x[i]; ' file


          The flaw is it won't preserve your order. So result could be:



          pqr-vgh-5241,79,15-08-91,21:00
          abc-xyz-12234,735,15-08-91,23:00
          lkj-erf-8542,281,15-08-91,10:00





          share|improve this answer






















          • Order doesnt matters
            – Kshitij
            Nov 6 '15 at 10:19

















          up vote
          1
          down vote













          You can do this with awk:



          #!/bin/sh
          sort | awk -F, '
          function result()
          if ( key != "" )
          printf "%s,%d,%sn", key, value, datetime;


          BEGIN key = ""; value = 0; datetime = "";
          $2 ~ /^[0-9]+/
          if ( $1 == key )
          value += $2;
          else
          result();
          key = $1;
          value = $2;
          datetime = $3 "," $4;


          END result();
          '


          giving



          ./foo <input
          abc-xyz-12234,735,15-08-91,23:00
          lkj-erf-8542,281,15-08-91,10:00
          pqr-vgh-5241,79,15-08-91,21:00





          share|improve this answer



























            up vote
            0
            down vote













            Here's a way in Perl. Call it as such ./script file.ext:



            use warnings;
            use strict;

            my %data;
            my @order;

            while (<>)
            next if $. == 1;
            my @line = split /,/;
            if (defined $data$line[0])
            $data$line[0]->[1] += $line[1];

            else
            $data$line[0] = @line;
            push @order, $line[0];



            for (@order)
            print join(',', @$data$_);






            share|improve this answer




















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              3 Answers
              3






              active

              oldest

              votes








              3 Answers
              3






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes








              up vote
              3
              down vote













              Another possible solution with awk could be:



              awk 'BEGIN FS = OFS = "," 
              NR != 1 y[$1] += $2; $2 = y[$1]; x[$1] = $0;
              END for (i in x) print x[i]; ' file


              The flaw is it won't preserve your order. So result could be:



              pqr-vgh-5241,79,15-08-91,21:00
              abc-xyz-12234,735,15-08-91,23:00
              lkj-erf-8542,281,15-08-91,10:00





              share|improve this answer






















              • Order doesnt matters
                – Kshitij
                Nov 6 '15 at 10:19














              up vote
              3
              down vote













              Another possible solution with awk could be:



              awk 'BEGIN FS = OFS = "," 
              NR != 1 y[$1] += $2; $2 = y[$1]; x[$1] = $0;
              END for (i in x) print x[i]; ' file


              The flaw is it won't preserve your order. So result could be:



              pqr-vgh-5241,79,15-08-91,21:00
              abc-xyz-12234,735,15-08-91,23:00
              lkj-erf-8542,281,15-08-91,10:00





              share|improve this answer






















              • Order doesnt matters
                – Kshitij
                Nov 6 '15 at 10:19












              up vote
              3
              down vote










              up vote
              3
              down vote









              Another possible solution with awk could be:



              awk 'BEGIN FS = OFS = "," 
              NR != 1 y[$1] += $2; $2 = y[$1]; x[$1] = $0;
              END for (i in x) print x[i]; ' file


              The flaw is it won't preserve your order. So result could be:



              pqr-vgh-5241,79,15-08-91,21:00
              abc-xyz-12234,735,15-08-91,23:00
              lkj-erf-8542,281,15-08-91,10:00





              share|improve this answer














              Another possible solution with awk could be:



              awk 'BEGIN FS = OFS = "," 
              NR != 1 y[$1] += $2; $2 = y[$1]; x[$1] = $0;
              END for (i in x) print x[i]; ' file


              The flaw is it won't preserve your order. So result could be:



              pqr-vgh-5241,79,15-08-91,21:00
              abc-xyz-12234,735,15-08-91,23:00
              lkj-erf-8542,281,15-08-91,10:00






              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Nov 6 '15 at 10:38









              cas

              38.3k44898




              38.3k44898










              answered Nov 6 '15 at 9:48









              taliezin

              6,78011527




              6,78011527











              • Order doesnt matters
                – Kshitij
                Nov 6 '15 at 10:19
















              • Order doesnt matters
                – Kshitij
                Nov 6 '15 at 10:19















              Order doesnt matters
              – Kshitij
              Nov 6 '15 at 10:19




              Order doesnt matters
              – Kshitij
              Nov 6 '15 at 10:19












              up vote
              1
              down vote













              You can do this with awk:



              #!/bin/sh
              sort | awk -F, '
              function result()
              if ( key != "" )
              printf "%s,%d,%sn", key, value, datetime;


              BEGIN key = ""; value = 0; datetime = "";
              $2 ~ /^[0-9]+/
              if ( $1 == key )
              value += $2;
              else
              result();
              key = $1;
              value = $2;
              datetime = $3 "," $4;


              END result();
              '


              giving



              ./foo <input
              abc-xyz-12234,735,15-08-91,23:00
              lkj-erf-8542,281,15-08-91,10:00
              pqr-vgh-5241,79,15-08-91,21:00





              share|improve this answer
























                up vote
                1
                down vote













                You can do this with awk:



                #!/bin/sh
                sort | awk -F, '
                function result()
                if ( key != "" )
                printf "%s,%d,%sn", key, value, datetime;


                BEGIN key = ""; value = 0; datetime = "";
                $2 ~ /^[0-9]+/
                if ( $1 == key )
                value += $2;
                else
                result();
                key = $1;
                value = $2;
                datetime = $3 "," $4;


                END result();
                '


                giving



                ./foo <input
                abc-xyz-12234,735,15-08-91,23:00
                lkj-erf-8542,281,15-08-91,10:00
                pqr-vgh-5241,79,15-08-91,21:00





                share|improve this answer






















                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  You can do this with awk:



                  #!/bin/sh
                  sort | awk -F, '
                  function result()
                  if ( key != "" )
                  printf "%s,%d,%sn", key, value, datetime;


                  BEGIN key = ""; value = 0; datetime = "";
                  $2 ~ /^[0-9]+/
                  if ( $1 == key )
                  value += $2;
                  else
                  result();
                  key = $1;
                  value = $2;
                  datetime = $3 "," $4;


                  END result();
                  '


                  giving



                  ./foo <input
                  abc-xyz-12234,735,15-08-91,23:00
                  lkj-erf-8542,281,15-08-91,10:00
                  pqr-vgh-5241,79,15-08-91,21:00





                  share|improve this answer












                  You can do this with awk:



                  #!/bin/sh
                  sort | awk -F, '
                  function result()
                  if ( key != "" )
                  printf "%s,%d,%sn", key, value, datetime;


                  BEGIN key = ""; value = 0; datetime = "";
                  $2 ~ /^[0-9]+/
                  if ( $1 == key )
                  value += $2;
                  else
                  result();
                  key = $1;
                  value = $2;
                  datetime = $3 "," $4;


                  END result();
                  '


                  giving



                  ./foo <input
                  abc-xyz-12234,735,15-08-91,23:00
                  lkj-erf-8542,281,15-08-91,10:00
                  pqr-vgh-5241,79,15-08-91,21:00






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 6 '15 at 9:46









                  Thomas Dickey

                  51.5k594164




                  51.5k594164




















                      up vote
                      0
                      down vote













                      Here's a way in Perl. Call it as such ./script file.ext:



                      use warnings;
                      use strict;

                      my %data;
                      my @order;

                      while (<>)
                      next if $. == 1;
                      my @line = split /,/;
                      if (defined $data$line[0])
                      $data$line[0]->[1] += $line[1];

                      else
                      $data$line[0] = @line;
                      push @order, $line[0];



                      for (@order)
                      print join(',', @$data$_);






                      share|improve this answer
























                        up vote
                        0
                        down vote













                        Here's a way in Perl. Call it as such ./script file.ext:



                        use warnings;
                        use strict;

                        my %data;
                        my @order;

                        while (<>)
                        next if $. == 1;
                        my @line = split /,/;
                        if (defined $data$line[0])
                        $data$line[0]->[1] += $line[1];

                        else
                        $data$line[0] = @line;
                        push @order, $line[0];



                        for (@order)
                        print join(',', @$data$_);






                        share|improve this answer






















                          up vote
                          0
                          down vote










                          up vote
                          0
                          down vote









                          Here's a way in Perl. Call it as such ./script file.ext:



                          use warnings;
                          use strict;

                          my %data;
                          my @order;

                          while (<>)
                          next if $. == 1;
                          my @line = split /,/;
                          if (defined $data$line[0])
                          $data$line[0]->[1] += $line[1];

                          else
                          $data$line[0] = @line;
                          push @order, $line[0];



                          for (@order)
                          print join(',', @$data$_);






                          share|improve this answer












                          Here's a way in Perl. Call it as such ./script file.ext:



                          use warnings;
                          use strict;

                          my %data;
                          my @order;

                          while (<>)
                          next if $. == 1;
                          my @line = split /,/;
                          if (defined $data$line[0])
                          $data$line[0]->[1] += $line[1];

                          else
                          $data$line[0] = @line;
                          push @order, $line[0];



                          for (@order)
                          print join(',', @$data$_);







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 6 '15 at 15:14









                          stevieb

                          81647




                          81647



























                               

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