Filter out random username after string

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I have a full list of API status with lots of information like that.
I need to grep the name of the username so I can send it to another file or variable.

For example:

[ jq -r '.["username"]'

jq -r '.["username"]' file

But the string you provided is not proper json. It's missing the closing brackets (]) at the end and has a . instead.

jq should be available in most package managers, e.g. install it with:

sudo apt install jq

If you somehow need to use grep and have pgrep / grep -P available:

grep -Po '"username":"K[^"]*'

answered Nov 21 at 14:44

RoVo

2,224215

answered Nov 21 at 14:44

RoVo

2,224215

answered Nov 21 at 14:44

RoVo

2,224215

answered Nov 21 at 14:44

RoVo

2,224215

Actually that works, but shows me for only the first occurrence. Can it be done for every string that contains username? * UPDATE* IT Works with grep , thanks a lot
– Denis Hristov
Nov 21 at 14:50

did you see my update using instead of [0] ?
– RoVo
Nov 21 at 14:51

Yes, thanks a lot !! You saved me
– Denis Hristov
Nov 21 at 14:52

add a comment |

Actually that works, but shows me for only the first occurrence. Can it be done for every string that contains username? * UPDATE* IT Works with grep , thanks a lot
– Denis Hristov
Nov 21 at 14:50

did you see my update using instead of [0] ?
– RoVo
Nov 21 at 14:51

Yes, thanks a lot !! You saved me
– Denis Hristov
Nov 21 at 14:52

Actually that works, but shows me for only the first occurrence. Can it be done for every string that contains username? * UPDATE* IT Works with grep , thanks a lot
– Denis Hristov
Nov 21 at 14:50

did you see my update using instead of [0] ?
– RoVo
Nov 21 at 14:51

Yes, thanks a lot !! You saved me
– Denis Hristov
Nov 21 at 14:52

add a comment |

up vote
0
down vote

I have used the following command and it worked fine:

echo "[{"id":"1onyc4b1otgmtrmw37h83rjs9w","create_at":1542718790947,"update_at":1542728017634,"delete_at":0,"username":"ivan.ivanov","auth_data":""." |
 sed "s/,/n/g" |
 awk -F ":" '/username/print $NF'

output

ivan.ivanov

edited Nov 21 at 17:12

Bash bros

answered Nov 21 at 15:35

Praveen Kumar BS

1,114138

add a comment |

up vote
0
down vote

I have used the following command and it worked fine:

echo "[{"id":"1onyc4b1otgmtrmw37h83rjs9w","create_at":1542718790947,"update_at":1542728017634,"delete_at":0,"username":"ivan.ivanov","auth_data":""." |
 sed "s/,/n/g" |
 awk -F ":" '/username/print $NF'

output

ivan.ivanov

edited Nov 21 at 17:12

Bash bros

answered Nov 21 at 15:35

Praveen Kumar BS

1,114138

add a comment |

up vote
0
down vote

I have used the following command and it worked fine:

echo "[{"id":"1onyc4b1otgmtrmw37h83rjs9w","create_at":1542718790947,"update_at":1542728017634,"delete_at":0,"username":"ivan.ivanov","auth_data":""." |
 sed "s/,/n/g" |
 awk -F ":" '/username/print $NF'

output

ivan.ivanov

edited Nov 21 at 17:12

Bash bros

answered Nov 21 at 15:35

Praveen Kumar BS

1,114138

I have used the following command and it worked fine:

echo "[{"id":"1onyc4b1otgmtrmw37h83rjs9w","create_at":1542718790947,"update_at":1542728017634,"delete_at":0,"username":"ivan.ivanov","auth_data":""." |
 sed "s/,/n/g" |
 awk -F ":" '/username/print $NF'

output

ivan.ivanov

edited Nov 21 at 17:12

Bash bros

answered Nov 21 at 15:35

Praveen Kumar BS

1,114138

edited Nov 21 at 17:12

Bash bros

edited Nov 21 at 17:12

Bash bros

edited Nov 21 at 17:12

Bash bros

answered Nov 21 at 15:35

Praveen Kumar BS

1,114138

answered Nov 21 at 15:35

Praveen Kumar BS

1,114138

answered Nov 21 at 15:35

Praveen Kumar BS

1,114138

add a comment |

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