Where is the command lines stored before it is executed?

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I have such a script in ~/draft



$ cat test.sh
#! /usr/local/bin/bash

for i in ./*;do
echo $i
done


The chunk of code are stored in test.sh,

when I run it



$ bash test.sh
./first.html
./second.html
./test.sh
./third.html


So I run the script name test.sh and get the output.



Alternatively, I could run the command directly as:



$ for i in ./*; do echo $i; done
./first.html
./second.html
./test.sh
./third.html


The second chunk get the identical results.



Since the preceding codes resides in file test.sh, what's the filename where the command for i in ./*; do echo $i; done live?










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    up vote
    -1
    down vote

    favorite












    I have such a script in ~/draft



    $ cat test.sh
    #! /usr/local/bin/bash

    for i in ./*;do
    echo $i
    done


    The chunk of code are stored in test.sh,

    when I run it



    $ bash test.sh
    ./first.html
    ./second.html
    ./test.sh
    ./third.html


    So I run the script name test.sh and get the output.



    Alternatively, I could run the command directly as:



    $ for i in ./*; do echo $i; done
    ./first.html
    ./second.html
    ./test.sh
    ./third.html


    The second chunk get the identical results.



    Since the preceding codes resides in file test.sh, what's the filename where the command for i in ./*; do echo $i; done live?










    share|improve this question









    New contributor




    rider dragon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





















      up vote
      -1
      down vote

      favorite









      up vote
      -1
      down vote

      favorite











      I have such a script in ~/draft



      $ cat test.sh
      #! /usr/local/bin/bash

      for i in ./*;do
      echo $i
      done


      The chunk of code are stored in test.sh,

      when I run it



      $ bash test.sh
      ./first.html
      ./second.html
      ./test.sh
      ./third.html


      So I run the script name test.sh and get the output.



      Alternatively, I could run the command directly as:



      $ for i in ./*; do echo $i; done
      ./first.html
      ./second.html
      ./test.sh
      ./third.html


      The second chunk get the identical results.



      Since the preceding codes resides in file test.sh, what's the filename where the command for i in ./*; do echo $i; done live?










      share|improve this question









      New contributor




      rider dragon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      I have such a script in ~/draft



      $ cat test.sh
      #! /usr/local/bin/bash

      for i in ./*;do
      echo $i
      done


      The chunk of code are stored in test.sh,

      when I run it



      $ bash test.sh
      ./first.html
      ./second.html
      ./test.sh
      ./third.html


      So I run the script name test.sh and get the output.



      Alternatively, I could run the command directly as:



      $ for i in ./*; do echo $i; done
      ./first.html
      ./second.html
      ./test.sh
      ./third.html


      The second chunk get the identical results.



      Since the preceding codes resides in file test.sh, what's the filename where the command for i in ./*; do echo $i; done live?







      bash






      share|improve this question









      New contributor




      rider dragon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      rider dragon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









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      edited 3 mins ago









      Kusalananda

      111k15216342




      111k15216342






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      asked 1 hour ago









      rider dragon

      22716




      22716




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      New contributor





      rider dragon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      rider dragon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




















          1 Answer
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          Commands don't have to be stored in a file to be executed - the interpreter (in this case bash) can simply read the command line into memory like it would read a script file (with some minor caveats related to buffering) and then execute it in exactly the same way.






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            up vote
            0
            down vote













            Commands don't have to be stored in a file to be executed - the interpreter (in this case bash) can simply read the command line into memory like it would read a script file (with some minor caveats related to buffering) and then execute it in exactly the same way.






            share|improve this answer
























              up vote
              0
              down vote













              Commands don't have to be stored in a file to be executed - the interpreter (in this case bash) can simply read the command line into memory like it would read a script file (with some minor caveats related to buffering) and then execute it in exactly the same way.






              share|improve this answer






















                up vote
                0
                down vote










                up vote
                0
                down vote









                Commands don't have to be stored in a file to be executed - the interpreter (in this case bash) can simply read the command line into memory like it would read a script file (with some minor caveats related to buffering) and then execute it in exactly the same way.






                share|improve this answer












                Commands don't have to be stored in a file to be executed - the interpreter (in this case bash) can simply read the command line into memory like it would read a script file (with some minor caveats related to buffering) and then execute it in exactly the same way.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 34 mins ago









                l0b0

                26.8k17107236




                26.8k17107236




















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