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I am working with a software (Oracle Siebel) that only supports Javascript expressions with operators multiply, divide, subtract, add, and XOR (*, /, -, +, ^). I don't have other operators such as ! or ?: available.

Using the above operators, is it possible to convert a number to 1 if it is non-zero and leave it 0 if it's already zero? The number may be positive, zero, or negative.

Example:

var c = 55;

var d; // d needs to set as 1

I tried c / c , but it evaluates to NaN when c is 0. d needs to be 0 when c is 0.

c is a currency value, it will have a maximum of two trailing digits and 12 leading digits.

I am trying to emulate an if condition by converting a number to a boolean 0 or 1, and then multiplying other parts of the expression.

c / (c + 5e-324) should work. If x is 0, that is exactly 0, and if x is nonzero (technically, if x is at least 4.45014771701440252e-308, which the smallest non-zero number allowed in the question, 0.01, is), JavaScript's floating-point math is too imprecise for the answer to be different than 1, so it will come out as exactly 1.

How about the expression n/n^0?

console.log([-1, 0, 1, 19575].map(n => n/n^0))

As you can see, all non-zero values get converted to 1, and 0 stays at 0. This leverages the fact that in Javascript, NaN^0 is 0.

Interesting problem. Here's a revised approach. First, let us create an OR function, which we can do with two XORs and an add.

function OR(x, y) 
 return (x + (x ^ y) ^ x);

Next let us use a modified bit-parity type algorithm, but with OR instead of XOR. The result of this process will be a number that has the least-significant bit set if and only if the original value is non-zero. We can then XOR with a value that is all 1's except the first bit (ie, -2).

function IS_TRUE(c) = c >> 2 */
 c = OR( c, c / 2 ); /* c