Where does the command lines are stored before they are implemented?

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0
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I have such a script in ~/draft

$ cat test.sh
#! /usr/local/bin/bash

for i in ./*;do
 echo $i
done

The chunk of code are stored in test.sh,

when I run it

$ bash test.sh
./first.html
./second.html
./test.sh
./third.html

So I run the script name test.sh and get the output.

Alternatively,I could run the command directly as:

$ for i in ./*; do echo $i; done
./first.html
./second.html
./test.sh
./third.html

The second chunk get the identical results.

Since the preceding codes resides in file test.sh, what's the filename where does command for i in ./*; do echo $i; done live?

asked 3 mins ago

rider dragon

22616

New contributor

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up vote
0
down vote

favorite

I have such a script in ~/draft

$ cat test.sh
#! /usr/local/bin/bash

for i in ./*;do
 echo $i
done

The chunk of code are stored in test.sh,

when I run it

$ bash test.sh
./first.html
./second.html
./test.sh
./third.html

So I run the script name test.sh and get the output.

Alternatively,I could run the command directly as:

$ for i in ./*; do echo $i; done
./first.html
./second.html
./test.sh
./third.html

The second chunk get the identical results.

Since the preceding codes resides in file test.sh, what's the filename where does command for i in ./*; do echo $i; done live?

asked 3 mins ago

rider dragon

22616

New contributor

add a commentÂ |Â

up vote
0
down vote

favorite

I have such a script in ~/draft

$ cat test.sh
#! /usr/local/bin/bash

for i in ./*;do
 echo $i
done

The chunk of code are stored in test.sh,

when I run it

$ bash test.sh
./first.html
./second.html
./test.sh
./third.html

So I run the script name test.sh and get the output.

Alternatively,I could run the command directly as:

$ for i in ./*; do echo $i; done
./first.html
./second.html
./test.sh
./third.html

The second chunk get the identical results.

Since the preceding codes resides in file test.sh, what's the filename where does command for i in ./*; do echo $i; done live?

asked 3 mins ago

rider dragon

22616

New contributor

I have such a script in ~/draft

$ cat test.sh
#! /usr/local/bin/bash

for i in ./*;do
 echo $i
done

The chunk of code are stored in test.sh,

when I run it

$ bash test.sh
./first.html
./second.html
./test.sh
./third.html

So I run the script name test.sh and get the output.

Alternatively,I could run the command directly as:

$ for i in ./*; do echo $i; done
./first.html
./second.html
./test.sh
./third.html

The second chunk get the identical results.

Since the preceding codes resides in file test.sh, what's the filename where does command for i in ./*; do echo $i; done live?

bash

asked 3 mins ago

rider dragon

22616

New contributor

asked 3 mins ago

rider dragon

22616

New contributor

asked 3 mins ago

rider dragon

22616

New contributor

asked 3 mins ago

rider dragon

22616

asked 3 mins ago

rider dragon

22616

New contributor

rider dragon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

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