What is her real age? [closed]

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











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He : What is your age?



She : 35 years old, ignoring the intervening Saturdays and Sundays.




What is her real age?










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closed as off-topic by Quintec, JonMark Perry, El-Guest, Rubio♦ Aug 29 at 15:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is off-topic as it appears to be a mathematics problem, as opposed to a mathematical puzzle. For more info, see "Are math-textbook-style problems on topic?" on meta." – Quintec, JonMark Perry, El-Guest, Rubio
If this question can be reworded to fit the rules in the help center, please edit the question.












  • Today 35 years old, correct?
    – Doomenik
    Aug 29 at 9:31










  • @Doomenik Yes...
    – rsp
    Aug 29 at 9:32










  • @rsp But the year is 52 weeks (including Sat and Sun) plus a day or two. What does a year mean in the context of your question? 365 days? How about the leap years? Saturdays or Sunday on 29th February? Etc.
    – rhsquared
    Aug 29 at 9:40






  • 3




    How is this a puzzle and not merely an arithmetic story-problem?
    – Rubio♦
    Aug 29 at 13:32






  • 1




    @Rubio to me it seemed like a pretty decent trick question puzzle all the way up to the appearance of the tick..
    – Bass
    Aug 29 at 15:34














up vote
4
down vote

favorite
3













He : What is your age?



She : 35 years old, ignoring the intervening Saturdays and Sundays.




What is her real age?










share|improve this question















closed as off-topic by Quintec, JonMark Perry, El-Guest, Rubio♦ Aug 29 at 15:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is off-topic as it appears to be a mathematics problem, as opposed to a mathematical puzzle. For more info, see "Are math-textbook-style problems on topic?" on meta." – Quintec, JonMark Perry, El-Guest, Rubio
If this question can be reworded to fit the rules in the help center, please edit the question.












  • Today 35 years old, correct?
    – Doomenik
    Aug 29 at 9:31










  • @Doomenik Yes...
    – rsp
    Aug 29 at 9:32










  • @rsp But the year is 52 weeks (including Sat and Sun) plus a day or two. What does a year mean in the context of your question? 365 days? How about the leap years? Saturdays or Sunday on 29th February? Etc.
    – rhsquared
    Aug 29 at 9:40






  • 3




    How is this a puzzle and not merely an arithmetic story-problem?
    – Rubio♦
    Aug 29 at 13:32






  • 1




    @Rubio to me it seemed like a pretty decent trick question puzzle all the way up to the appearance of the tick..
    – Bass
    Aug 29 at 15:34












up vote
4
down vote

favorite
3









up vote
4
down vote

favorite
3






3






He : What is your age?



She : 35 years old, ignoring the intervening Saturdays and Sundays.




What is her real age?










share|improve this question
















He : What is your age?



She : 35 years old, ignoring the intervening Saturdays and Sundays.




What is her real age?







logical-deduction calculation-puzzle






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Aug 29 at 10:09









JonMark Perry

14.7k52972




14.7k52972










asked Aug 29 at 9:26









rsp

1,44531026




1,44531026




closed as off-topic by Quintec, JonMark Perry, El-Guest, Rubio♦ Aug 29 at 15:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is off-topic as it appears to be a mathematics problem, as opposed to a mathematical puzzle. For more info, see "Are math-textbook-style problems on topic?" on meta." – Quintec, JonMark Perry, El-Guest, Rubio
If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Quintec, JonMark Perry, El-Guest, Rubio♦ Aug 29 at 15:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is off-topic as it appears to be a mathematics problem, as opposed to a mathematical puzzle. For more info, see "Are math-textbook-style problems on topic?" on meta." – Quintec, JonMark Perry, El-Guest, Rubio
If this question can be reworded to fit the rules in the help center, please edit the question.











  • Today 35 years old, correct?
    – Doomenik
    Aug 29 at 9:31










  • @Doomenik Yes...
    – rsp
    Aug 29 at 9:32










  • @rsp But the year is 52 weeks (including Sat and Sun) plus a day or two. What does a year mean in the context of your question? 365 days? How about the leap years? Saturdays or Sunday on 29th February? Etc.
    – rhsquared
    Aug 29 at 9:40






  • 3




    How is this a puzzle and not merely an arithmetic story-problem?
    – Rubio♦
    Aug 29 at 13:32






  • 1




    @Rubio to me it seemed like a pretty decent trick question puzzle all the way up to the appearance of the tick..
    – Bass
    Aug 29 at 15:34
















  • Today 35 years old, correct?
    – Doomenik
    Aug 29 at 9:31










  • @Doomenik Yes...
    – rsp
    Aug 29 at 9:32










  • @rsp But the year is 52 weeks (including Sat and Sun) plus a day or two. What does a year mean in the context of your question? 365 days? How about the leap years? Saturdays or Sunday on 29th February? Etc.
    – rhsquared
    Aug 29 at 9:40






  • 3




    How is this a puzzle and not merely an arithmetic story-problem?
    – Rubio♦
    Aug 29 at 13:32






  • 1




    @Rubio to me it seemed like a pretty decent trick question puzzle all the way up to the appearance of the tick..
    – Bass
    Aug 29 at 15:34















Today 35 years old, correct?
– Doomenik
Aug 29 at 9:31




Today 35 years old, correct?
– Doomenik
Aug 29 at 9:31












@Doomenik Yes...
– rsp
Aug 29 at 9:32




@Doomenik Yes...
– rsp
Aug 29 at 9:32












@rsp But the year is 52 weeks (including Sat and Sun) plus a day or two. What does a year mean in the context of your question? 365 days? How about the leap years? Saturdays or Sunday on 29th February? Etc.
– rhsquared
Aug 29 at 9:40




@rsp But the year is 52 weeks (including Sat and Sun) plus a day or two. What does a year mean in the context of your question? 365 days? How about the leap years? Saturdays or Sunday on 29th February? Etc.
– rhsquared
Aug 29 at 9:40




3




3




How is this a puzzle and not merely an arithmetic story-problem?
– Rubio♦
Aug 29 at 13:32




How is this a puzzle and not merely an arithmetic story-problem?
– Rubio♦
Aug 29 at 13:32




1




1




@Rubio to me it seemed like a pretty decent trick question puzzle all the way up to the appearance of the tick..
– Bass
Aug 29 at 15:34




@Rubio to me it seemed like a pretty decent trick question puzzle all the way up to the appearance of the tick..
– Bass
Aug 29 at 15:34










5 Answers
5






active

oldest

votes

















up vote
15
down vote



accepted










Based on my initial intuition, I'm guessing it's




49




Since




It's as if she only lived for 5 days a week instead of 7, so she actually lived $frac75$ longer than her reported age.







share|improve this answer



























    up vote
    8
    down vote













    Her real age is




    35.




    If you ignore all the Saturdays and Sundays,




    the number of days lived is 5/7 of what it would normally be, but the number of days in a year is also 5/7 of the norm.







    share|improve this answer



























      up vote
      6
      down vote













      (fun answer)




      We do not know. Because women are known to lie about their ages all the time, even in riddles.







      share|improve this answer



























        up vote
        4
        down vote













        Ok, I've got a weird solution for this but here goes. If we go with the assumption that in this scenario your recorded age only increases on the date of your birthday each year and only then when that date falls on a weekday. If it was a weekend (Saturday or Sunday) in a particular year then you wouldn't increase your age.



        Taking that I ran some code to work out for each date from today's date to the start of the year how old you would be using these mechanics.




        The results came up that, depending on your birthday you could be anywhere between 47 (26 dates), 48 (110 dates) 49 (96 dates) and 50 (9 dates) years old in reality and still have the age of 35. The only outlier to this would be if you were born on February 29th (a Leap Year). For these lucky people if you could theoretically live that long they would have an age of 197.




        The code I used is below



        Sub CalcAge()

        Dim datBDay As Date
        Dim datTempDate As Date
        Dim iActAge As Integer
        Dim iCnt As Integer

        datBDay = Date

        While datBDay > #7/18/2018#
        iCnt = 1
        iActAge = 35

        While iCnt < iActAge
        datTempDate = DateAdd("yyyy", 0 - iCnt, datBDay)

        If Weekday(datTempDate, vbMonday) > 5 Then
        'falls on weekend therefore increases age
        iActAge = iActAge + 1
        End If

        iCnt = iCnt + 1
        Wend

        'Leap Year Calculations

        ' While iCnt < iActAge
        ' datTempDate = DateAdd("yyyy", 0 - iCnt, datBDay)
        ' If isLeapYear(Year(datTempDate)) Then
        ' If Weekday(datTempDate, vbMonday) > 5 Then
        ' 'falls on weekend therefore increases age
        ' iActAge = iActAge + 1
        ' End If
        ' Else
        ' iActAge = iActAge + 1
        ' End If
        '
        '
        ' iCnt = iCnt + 1
        ' Wend
        '
        Debug.Print "Actual Age if born on " & datBDay & " is :"; iActAge

        datBDay = datBDay - 1

        Wend

        End Sub


        Public Function isLeapYear(yr As Integer) As Boolean
        isLeapYear = (Month(DateSerial(yr, 2, 29)) = 2)
        End Function


        There might be some innacuracies as worked this up quickly but just wanted to look at this from a different angle.






        share|improve this answer





























          up vote
          1
          down vote













          I think




          $49$




          Calculation:




          Let $X =$ her actual age.

          There are $260.7$ week days in a year ( $365div 7 = 52.14$ and $52.14 times 5 = 260.7$)

          So...

          $35$ is to $X$ as $260.7$ is to $365$

          $35div X = 260.7div 365$

          Solving for X by cross multiplying

          $260.7X = 35 times 365$

          $260.7X = 12,775$







          $$X = 49.00$$







          share|improve this answer






















          • Always make sure to hide your answer(s) in spoiler quotes/tags >! as opposed to >, in order to not spoil the answer for users attempting to solve the puzzle. I have proposed such an edit :)
            – user477343
            Aug 29 at 11:38


















          5 Answers
          5






          active

          oldest

          votes








          5 Answers
          5






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          15
          down vote



          accepted










          Based on my initial intuition, I'm guessing it's




          49




          Since




          It's as if she only lived for 5 days a week instead of 7, so she actually lived $frac75$ longer than her reported age.







          share|improve this answer
























            up vote
            15
            down vote



            accepted










            Based on my initial intuition, I'm guessing it's




            49




            Since




            It's as if she only lived for 5 days a week instead of 7, so she actually lived $frac75$ longer than her reported age.







            share|improve this answer






















              up vote
              15
              down vote



              accepted







              up vote
              15
              down vote



              accepted






              Based on my initial intuition, I'm guessing it's




              49




              Since




              It's as if she only lived for 5 days a week instead of 7, so she actually lived $frac75$ longer than her reported age.







              share|improve this answer












              Based on my initial intuition, I'm guessing it's




              49




              Since




              It's as if she only lived for 5 days a week instead of 7, so she actually lived $frac75$ longer than her reported age.








              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Aug 29 at 9:41









              sedrick

              1,666514




              1,666514




















                  up vote
                  8
                  down vote













                  Her real age is




                  35.




                  If you ignore all the Saturdays and Sundays,




                  the number of days lived is 5/7 of what it would normally be, but the number of days in a year is also 5/7 of the norm.







                  share|improve this answer
























                    up vote
                    8
                    down vote













                    Her real age is




                    35.




                    If you ignore all the Saturdays and Sundays,




                    the number of days lived is 5/7 of what it would normally be, but the number of days in a year is also 5/7 of the norm.







                    share|improve this answer






















                      up vote
                      8
                      down vote










                      up vote
                      8
                      down vote









                      Her real age is




                      35.




                      If you ignore all the Saturdays and Sundays,




                      the number of days lived is 5/7 of what it would normally be, but the number of days in a year is also 5/7 of the norm.







                      share|improve this answer












                      Her real age is




                      35.




                      If you ignore all the Saturdays and Sundays,




                      the number of days lived is 5/7 of what it would normally be, but the number of days in a year is also 5/7 of the norm.








                      share|improve this answer












                      share|improve this answer



                      share|improve this answer










                      answered Aug 29 at 11:43









                      Bass

                      22.4k355145




                      22.4k355145




















                          up vote
                          6
                          down vote













                          (fun answer)




                          We do not know. Because women are known to lie about their ages all the time, even in riddles.







                          share|improve this answer
























                            up vote
                            6
                            down vote













                            (fun answer)




                            We do not know. Because women are known to lie about their ages all the time, even in riddles.







                            share|improve this answer






















                              up vote
                              6
                              down vote










                              up vote
                              6
                              down vote









                              (fun answer)




                              We do not know. Because women are known to lie about their ages all the time, even in riddles.







                              share|improve this answer












                              (fun answer)




                              We do not know. Because women are known to lie about their ages all the time, even in riddles.








                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered Aug 29 at 13:24









                              Cashbee

                              1,18015




                              1,18015




















                                  up vote
                                  4
                                  down vote













                                  Ok, I've got a weird solution for this but here goes. If we go with the assumption that in this scenario your recorded age only increases on the date of your birthday each year and only then when that date falls on a weekday. If it was a weekend (Saturday or Sunday) in a particular year then you wouldn't increase your age.



                                  Taking that I ran some code to work out for each date from today's date to the start of the year how old you would be using these mechanics.




                                  The results came up that, depending on your birthday you could be anywhere between 47 (26 dates), 48 (110 dates) 49 (96 dates) and 50 (9 dates) years old in reality and still have the age of 35. The only outlier to this would be if you were born on February 29th (a Leap Year). For these lucky people if you could theoretically live that long they would have an age of 197.




                                  The code I used is below



                                  Sub CalcAge()

                                  Dim datBDay As Date
                                  Dim datTempDate As Date
                                  Dim iActAge As Integer
                                  Dim iCnt As Integer

                                  datBDay = Date

                                  While datBDay > #7/18/2018#
                                  iCnt = 1
                                  iActAge = 35

                                  While iCnt < iActAge
                                  datTempDate = DateAdd("yyyy", 0 - iCnt, datBDay)

                                  If Weekday(datTempDate, vbMonday) > 5 Then
                                  'falls on weekend therefore increases age
                                  iActAge = iActAge + 1
                                  End If

                                  iCnt = iCnt + 1
                                  Wend

                                  'Leap Year Calculations

                                  ' While iCnt < iActAge
                                  ' datTempDate = DateAdd("yyyy", 0 - iCnt, datBDay)
                                  ' If isLeapYear(Year(datTempDate)) Then
                                  ' If Weekday(datTempDate, vbMonday) > 5 Then
                                  ' 'falls on weekend therefore increases age
                                  ' iActAge = iActAge + 1
                                  ' End If
                                  ' Else
                                  ' iActAge = iActAge + 1
                                  ' End If
                                  '
                                  '
                                  ' iCnt = iCnt + 1
                                  ' Wend
                                  '
                                  Debug.Print "Actual Age if born on " & datBDay & " is :"; iActAge

                                  datBDay = datBDay - 1

                                  Wend

                                  End Sub


                                  Public Function isLeapYear(yr As Integer) As Boolean
                                  isLeapYear = (Month(DateSerial(yr, 2, 29)) = 2)
                                  End Function


                                  There might be some innacuracies as worked this up quickly but just wanted to look at this from a different angle.






                                  share|improve this answer


























                                    up vote
                                    4
                                    down vote













                                    Ok, I've got a weird solution for this but here goes. If we go with the assumption that in this scenario your recorded age only increases on the date of your birthday each year and only then when that date falls on a weekday. If it was a weekend (Saturday or Sunday) in a particular year then you wouldn't increase your age.



                                    Taking that I ran some code to work out for each date from today's date to the start of the year how old you would be using these mechanics.




                                    The results came up that, depending on your birthday you could be anywhere between 47 (26 dates), 48 (110 dates) 49 (96 dates) and 50 (9 dates) years old in reality and still have the age of 35. The only outlier to this would be if you were born on February 29th (a Leap Year). For these lucky people if you could theoretically live that long they would have an age of 197.




                                    The code I used is below



                                    Sub CalcAge()

                                    Dim datBDay As Date
                                    Dim datTempDate As Date
                                    Dim iActAge As Integer
                                    Dim iCnt As Integer

                                    datBDay = Date

                                    While datBDay > #7/18/2018#
                                    iCnt = 1
                                    iActAge = 35

                                    While iCnt < iActAge
                                    datTempDate = DateAdd("yyyy", 0 - iCnt, datBDay)

                                    If Weekday(datTempDate, vbMonday) > 5 Then
                                    'falls on weekend therefore increases age
                                    iActAge = iActAge + 1
                                    End If

                                    iCnt = iCnt + 1
                                    Wend

                                    'Leap Year Calculations

                                    ' While iCnt < iActAge
                                    ' datTempDate = DateAdd("yyyy", 0 - iCnt, datBDay)
                                    ' If isLeapYear(Year(datTempDate)) Then
                                    ' If Weekday(datTempDate, vbMonday) > 5 Then
                                    ' 'falls on weekend therefore increases age
                                    ' iActAge = iActAge + 1
                                    ' End If
                                    ' Else
                                    ' iActAge = iActAge + 1
                                    ' End If
                                    '
                                    '
                                    ' iCnt = iCnt + 1
                                    ' Wend
                                    '
                                    Debug.Print "Actual Age if born on " & datBDay & " is :"; iActAge

                                    datBDay = datBDay - 1

                                    Wend

                                    End Sub


                                    Public Function isLeapYear(yr As Integer) As Boolean
                                    isLeapYear = (Month(DateSerial(yr, 2, 29)) = 2)
                                    End Function


                                    There might be some innacuracies as worked this up quickly but just wanted to look at this from a different angle.






                                    share|improve this answer
























                                      up vote
                                      4
                                      down vote










                                      up vote
                                      4
                                      down vote









                                      Ok, I've got a weird solution for this but here goes. If we go with the assumption that in this scenario your recorded age only increases on the date of your birthday each year and only then when that date falls on a weekday. If it was a weekend (Saturday or Sunday) in a particular year then you wouldn't increase your age.



                                      Taking that I ran some code to work out for each date from today's date to the start of the year how old you would be using these mechanics.




                                      The results came up that, depending on your birthday you could be anywhere between 47 (26 dates), 48 (110 dates) 49 (96 dates) and 50 (9 dates) years old in reality and still have the age of 35. The only outlier to this would be if you were born on February 29th (a Leap Year). For these lucky people if you could theoretically live that long they would have an age of 197.




                                      The code I used is below



                                      Sub CalcAge()

                                      Dim datBDay As Date
                                      Dim datTempDate As Date
                                      Dim iActAge As Integer
                                      Dim iCnt As Integer

                                      datBDay = Date

                                      While datBDay > #7/18/2018#
                                      iCnt = 1
                                      iActAge = 35

                                      While iCnt < iActAge
                                      datTempDate = DateAdd("yyyy", 0 - iCnt, datBDay)

                                      If Weekday(datTempDate, vbMonday) > 5 Then
                                      'falls on weekend therefore increases age
                                      iActAge = iActAge + 1
                                      End If

                                      iCnt = iCnt + 1
                                      Wend

                                      'Leap Year Calculations

                                      ' While iCnt < iActAge
                                      ' datTempDate = DateAdd("yyyy", 0 - iCnt, datBDay)
                                      ' If isLeapYear(Year(datTempDate)) Then
                                      ' If Weekday(datTempDate, vbMonday) > 5 Then
                                      ' 'falls on weekend therefore increases age
                                      ' iActAge = iActAge + 1
                                      ' End If
                                      ' Else
                                      ' iActAge = iActAge + 1
                                      ' End If
                                      '
                                      '
                                      ' iCnt = iCnt + 1
                                      ' Wend
                                      '
                                      Debug.Print "Actual Age if born on " & datBDay & " is :"; iActAge

                                      datBDay = datBDay - 1

                                      Wend

                                      End Sub


                                      Public Function isLeapYear(yr As Integer) As Boolean
                                      isLeapYear = (Month(DateSerial(yr, 2, 29)) = 2)
                                      End Function


                                      There might be some innacuracies as worked this up quickly but just wanted to look at this from a different angle.






                                      share|improve this answer














                                      Ok, I've got a weird solution for this but here goes. If we go with the assumption that in this scenario your recorded age only increases on the date of your birthday each year and only then when that date falls on a weekday. If it was a weekend (Saturday or Sunday) in a particular year then you wouldn't increase your age.



                                      Taking that I ran some code to work out for each date from today's date to the start of the year how old you would be using these mechanics.




                                      The results came up that, depending on your birthday you could be anywhere between 47 (26 dates), 48 (110 dates) 49 (96 dates) and 50 (9 dates) years old in reality and still have the age of 35. The only outlier to this would be if you were born on February 29th (a Leap Year). For these lucky people if you could theoretically live that long they would have an age of 197.




                                      The code I used is below



                                      Sub CalcAge()

                                      Dim datBDay As Date
                                      Dim datTempDate As Date
                                      Dim iActAge As Integer
                                      Dim iCnt As Integer

                                      datBDay = Date

                                      While datBDay > #7/18/2018#
                                      iCnt = 1
                                      iActAge = 35

                                      While iCnt < iActAge
                                      datTempDate = DateAdd("yyyy", 0 - iCnt, datBDay)

                                      If Weekday(datTempDate, vbMonday) > 5 Then
                                      'falls on weekend therefore increases age
                                      iActAge = iActAge + 1
                                      End If

                                      iCnt = iCnt + 1
                                      Wend

                                      'Leap Year Calculations

                                      ' While iCnt < iActAge
                                      ' datTempDate = DateAdd("yyyy", 0 - iCnt, datBDay)
                                      ' If isLeapYear(Year(datTempDate)) Then
                                      ' If Weekday(datTempDate, vbMonday) > 5 Then
                                      ' 'falls on weekend therefore increases age
                                      ' iActAge = iActAge + 1
                                      ' End If
                                      ' Else
                                      ' iActAge = iActAge + 1
                                      ' End If
                                      '
                                      '
                                      ' iCnt = iCnt + 1
                                      ' Wend
                                      '
                                      Debug.Print "Actual Age if born on " & datBDay & " is :"; iActAge

                                      datBDay = datBDay - 1

                                      Wend

                                      End Sub


                                      Public Function isLeapYear(yr As Integer) As Boolean
                                      isLeapYear = (Month(DateSerial(yr, 2, 29)) = 2)
                                      End Function


                                      There might be some innacuracies as worked this up quickly but just wanted to look at this from a different angle.







                                      share|improve this answer














                                      share|improve this answer



                                      share|improve this answer








                                      edited Aug 29 at 15:18

























                                      answered Aug 29 at 14:57









                                      FrazzleUK

                                      1413




                                      1413




















                                          up vote
                                          1
                                          down vote













                                          I think




                                          $49$




                                          Calculation:




                                          Let $X =$ her actual age.

                                          There are $260.7$ week days in a year ( $365div 7 = 52.14$ and $52.14 times 5 = 260.7$)

                                          So...

                                          $35$ is to $X$ as $260.7$ is to $365$

                                          $35div X = 260.7div 365$

                                          Solving for X by cross multiplying

                                          $260.7X = 35 times 365$

                                          $260.7X = 12,775$







                                          $$X = 49.00$$







                                          share|improve this answer






















                                          • Always make sure to hide your answer(s) in spoiler quotes/tags >! as opposed to >, in order to not spoil the answer for users attempting to solve the puzzle. I have proposed such an edit :)
                                            – user477343
                                            Aug 29 at 11:38















                                          up vote
                                          1
                                          down vote













                                          I think




                                          $49$




                                          Calculation:




                                          Let $X =$ her actual age.

                                          There are $260.7$ week days in a year ( $365div 7 = 52.14$ and $52.14 times 5 = 260.7$)

                                          So...

                                          $35$ is to $X$ as $260.7$ is to $365$

                                          $35div X = 260.7div 365$

                                          Solving for X by cross multiplying

                                          $260.7X = 35 times 365$

                                          $260.7X = 12,775$







                                          $$X = 49.00$$







                                          share|improve this answer






















                                          • Always make sure to hide your answer(s) in spoiler quotes/tags >! as opposed to >, in order to not spoil the answer for users attempting to solve the puzzle. I have proposed such an edit :)
                                            – user477343
                                            Aug 29 at 11:38













                                          up vote
                                          1
                                          down vote










                                          up vote
                                          1
                                          down vote









                                          I think




                                          $49$




                                          Calculation:




                                          Let $X =$ her actual age.

                                          There are $260.7$ week days in a year ( $365div 7 = 52.14$ and $52.14 times 5 = 260.7$)

                                          So...

                                          $35$ is to $X$ as $260.7$ is to $365$

                                          $35div X = 260.7div 365$

                                          Solving for X by cross multiplying

                                          $260.7X = 35 times 365$

                                          $260.7X = 12,775$







                                          $$X = 49.00$$







                                          share|improve this answer














                                          I think




                                          $49$




                                          Calculation:




                                          Let $X =$ her actual age.

                                          There are $260.7$ week days in a year ( $365div 7 = 52.14$ and $52.14 times 5 = 260.7$)

                                          So...

                                          $35$ is to $X$ as $260.7$ is to $365$

                                          $35div X = 260.7div 365$

                                          Solving for X by cross multiplying

                                          $260.7X = 35 times 365$

                                          $260.7X = 12,775$







                                          $$X = 49.00$$








                                          share|improve this answer














                                          share|improve this answer



                                          share|improve this answer








                                          edited Aug 29 at 11:41









                                          user477343

                                          3,3981745




                                          3,3981745










                                          answered Aug 29 at 10:08









                                          James

                                          24127




                                          24127











                                          • Always make sure to hide your answer(s) in spoiler quotes/tags >! as opposed to >, in order to not spoil the answer for users attempting to solve the puzzle. I have proposed such an edit :)
                                            – user477343
                                            Aug 29 at 11:38

















                                          • Always make sure to hide your answer(s) in spoiler quotes/tags >! as opposed to >, in order to not spoil the answer for users attempting to solve the puzzle. I have proposed such an edit :)
                                            – user477343
                                            Aug 29 at 11:38
















                                          Always make sure to hide your answer(s) in spoiler quotes/tags >! as opposed to >, in order to not spoil the answer for users attempting to solve the puzzle. I have proposed such an edit :)
                                          – user477343
                                          Aug 29 at 11:38





                                          Always make sure to hide your answer(s) in spoiler quotes/tags >! as opposed to >, in order to not spoil the answer for users attempting to solve the puzzle. I have proposed such an edit :)
                                          – user477343
                                          Aug 29 at 11:38



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