mjhjmtu

I am trying to run bash script which run 8 for loops simulatenously.

one of the my for loop likes below

for i in 00 01 02 03 04 ; do cat $INDIR/sys*$1.$i*csv | awk -F 'xac' 'BEGINOFS=";"; ($4 == 10) $1=$1; print '> $OUTDIR/$1_$i.csv

So I have converted into following syntax to run with nohup

nohup bash -c 'for i in 00 01 02 03 04; do cat $INDIR/rti*$1.$i*csv|awk -F '\xac' 'BEGINOFS=";"; ($4==10) $1=$1; print '>$OUTDIR/$i.csv;done' &

But I am getting following error

test.sh: line 9: syntax error near unexpected token `('
test.sh: line 9: `nohup bash -c 'for i in 00 01 02 03 04; do cat $INDIR/rti*$1.$i*csv|awk -F '\xac' 'BEGINOFS=";"; ($4==10) $1=$1; print '>$OUTDIR/$i.csv;done' & '

I also tried with following code changes

nohup sh -c ''

nohup /bin/bash -c ''

'xac'

but no progress,

BTW my for loop works without nohup

Thanks for your help

It would be much easier (read: more read- and maintainable) if you divide your code into two scripts: One to execute the actual function(s), and one to start them. Sample code for the latter:

for i in 00 01 02 03 04; do
 nohup /path/to/workerScript.sh $i
done

If you want to keep the logic in a single script you can still use this approach:

if [ $# -eq 0 ]; then
 for i in 00 01 02 03 04; do
 nohup $0 $i
 done

 exit 0
fi

# Rest of the logic follows