Capture exit code and output of a command

up vote
3
down vote

favorite

I'd like to do:

1.sh:

#!/usr/bin/env bash
set -eu
r=0
a=$(./2.sh || r=$?)
echo "$a"
echo "$r"

2.sh:

#!/usr/bin/env bash
echo output
exit 2

But it outputs:

$ ./1.sh
output
0 # I'd like to have `2` here

Since $(...) runs a separate shell. So, how do I capture both, exit code and output?

edited Aug 26 at 14:24

Peter Mortensen

79748

asked Mar 4 '16 at 11:28

x-yuri

1,11911641

a=$(./2.sh); r=$?; ## doesn't work?
â€“Â Jeff Schaller
Mar 4 '16 at 11:34

The reason 1.sh has an exit code of 0 not 2 is because echo "$r" is a command that exits 0.
â€“Â Mikkel
May 29 at 14:20

add a commentÂ |Â

up vote
3
down vote

favorite

I'd like to do:

1.sh:

#!/usr/bin/env bash
set -eu
r=0
a=$(./2.sh || r=$?)
echo "$a"
echo "$r"

2.sh:

#!/usr/bin/env bash
echo output
exit 2

But it outputs:

$ ./1.sh
output
0 # I'd like to have `2` here

Since $(...) runs a separate shell. So, how do I capture both, exit code and output?

edited Aug 26 at 14:24

Peter Mortensen

79748

asked Mar 4 '16 at 11:28

x-yuri

1,11911641

a=$(./2.sh); r=$?; ## doesn't work?
â€“Â Jeff Schaller
Mar 4 '16 at 11:34

The reason 1.sh has an exit code of 0 not 2 is because echo "$r" is a command that exits 0.
â€“Â Mikkel
May 29 at 14:20

add a commentÂ |Â

up vote
3
down vote

favorite

I'd like to do:

1.sh:

#!/usr/bin/env bash
set -eu
r=0
a=$(./2.sh || r=$?)
echo "$a"
echo "$r"

2.sh:

#!/usr/bin/env bash
echo output
exit 2

But it outputs:

$ ./1.sh
output
0 # I'd like to have `2` here

Since $(...) runs a separate shell. So, how do I capture both, exit code and output?

edited Aug 26 at 14:24

Peter Mortensen

79748

asked Mar 4 '16 at 11:28

x-yuri

1,11911641

I'd like to do:

1.sh:

#!/usr/bin/env bash
set -eu
r=0
a=$(./2.sh || r=$?)
echo "$a"
echo "$r"

2.sh:

#!/usr/bin/env bash
echo output
exit 2

But it outputs:

$ ./1.sh
output
0 # I'd like to have `2` here

Since $(...) runs a separate shell. So, how do I capture both, exit code and output?

shell command-substitution return-status

edited Aug 26 at 14:24

Peter Mortensen

79748

asked Mar 4 '16 at 11:28

x-yuri

1,11911641

edited Aug 26 at 14:24

Peter Mortensen

79748

asked Mar 4 '16 at 11:28

x-yuri

1,11911641

edited Aug 26 at 14:24

Peter Mortensen

79748

edited Aug 26 at 14:24

Peter Mortensen

79748

edited Aug 26 at 14:24

Peter Mortensen

79748

asked Mar 4 '16 at 11:28

x-yuri

1,11911641

asked Mar 4 '16 at 11:28

x-yuri

1,11911641

asked Mar 4 '16 at 11:28

x-yuri

1,11911641

a=$(./2.sh); r=$?; ## doesn't work?
â€“Â Jeff Schaller
Mar 4 '16 at 11:34

The reason 1.sh has an exit code of 0 not 2 is because echo "$r" is a command that exits 0.
â€“Â Mikkel
May 29 at 14:20

add a commentÂ |Â

a=$(./2.sh); r=$?; ## doesn't work?
â€“Â Jeff Schaller
Mar 4 '16 at 11:34

The reason 1.sh has an exit code of 0 not 2 is because echo "$r" is a command that exits 0.
â€“Â Mikkel
May 29 at 14:20

a=$(./2.sh); r=$?; ## doesn't work?
â€“Â Jeff Schaller
Mar 4 '16 at 11:34

The reason 1.sh has an exit code of 0 not 2 is because echo "$r" is a command that exits 0.
â€“Â Mikkel
May 29 at 14:20

add a commentÂ |Â

1 Answer
1

active

oldest

votes

up vote
8
down vote

accepted

The exit code of a process calling another process is the one of the called process.

$($($($($(exit 2)))))
echo $?
2

Here there are 5 levels of calling.

In your case:

r=0
a=$(./2.sh)
r=$?
echo "$a"
echo "$r"

edited Mar 4 '16 at 12:10

Jeff Schaller

32.7k849110

answered Mar 4 '16 at 11:36

Emmanuel

2,92911020

add a commentÂ |Â

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active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
8
down vote

accepted

The exit code of a process calling another process is the one of the called process.

$($($($($(exit 2)))))
echo $?
2

Here there are 5 levels of calling.

In your case:

r=0
a=$(./2.sh)
r=$?
echo "$a"
echo "$r"

edited Mar 4 '16 at 12:10

Jeff Schaller

32.7k849110

answered Mar 4 '16 at 11:36

Emmanuel

2,92911020

add a commentÂ |Â

up vote
8
down vote

accepted

The exit code of a process calling another process is the one of the called process.

$($($($($(exit 2)))))
echo $?
2

Here there are 5 levels of calling.

In your case:

r=0
a=$(./2.sh)
r=$?
echo "$a"
echo "$r"

edited Mar 4 '16 at 12:10

Jeff Schaller

32.7k849110

answered Mar 4 '16 at 11:36

Emmanuel

2,92911020

add a commentÂ |Â

up vote
8
down vote

accepted

The exit code of a process calling another process is the one of the called process.

$($($($($(exit 2)))))
echo $?
2

Here there are 5 levels of calling.

In your case:

r=0
a=$(./2.sh)
r=$?
echo "$a"
echo "$r"

edited Mar 4 '16 at 12:10

Jeff Schaller

32.7k849110

answered Mar 4 '16 at 11:36

Emmanuel

2,92911020

The exit code of a process calling another process is the one of the called process.

$($($($($(exit 2)))))
echo $?
2

Here there are 5 levels of calling.

In your case:

r=0
a=$(./2.sh)
r=$?
echo "$a"
echo "$r"

edited Mar 4 '16 at 12:10

Jeff Schaller

32.7k849110

answered Mar 4 '16 at 11:36

Emmanuel

2,92911020

edited Mar 4 '16 at 12:10

Jeff Schaller

32.7k849110

edited Mar 4 '16 at 12:10

Jeff Schaller

32.7k849110

edited Mar 4 '16 at 12:10

Jeff Schaller

32.7k849110

answered Mar 4 '16 at 11:36

Emmanuel

2,92911020

answered Mar 4 '16 at 11:36

Emmanuel

2,92911020

answered Mar 4 '16 at 11:36

Emmanuel

2,92911020

add a commentÂ |Â

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