Why is 'logger' always executed as the same user?

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I'm using rsyslog 8.24 on debian. Each time I trigger logger "some message" the syslog refers to the same and only system user - it does not matter if I switch user (even as root), the messages are always logged as the same user - even on servers - I guess on a desktop, it's because the GUI is running as that user and on a server because I logged in as that user and later switch to root - could that be? But anyway, how could I log a message as root to the syslog?




debian syslog rsyslog




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  • What is the user that logger logs?
    – Kusalananda
    Aug 3 at 16:22










  • It's my default system user I use to login to X11 or SSH on servers.
    – chevallier
    Aug 3 at 16:26

















up vote
0
down vote

favorite












I'm using rsyslog 8.24 on debian. Each time I trigger logger "some message" the syslog refers to the same and only system user - it does not matter if I switch user (even as root), the messages are always logged as the same user - even on servers - I guess on a desktop, it's because the GUI is running as that user and on a server because I logged in as that user and later switch to root - could that be? But anyway, how could I log a message as root to the syslog?




debian syslog rsyslog




share|improve this question



















  • What is the user that logger logs?
    – Kusalananda
    Aug 3 at 16:22










  • It's my default system user I use to login to X11 or SSH on servers.
    – chevallier
    Aug 3 at 16:26













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I'm using rsyslog 8.24 on debian. Each time I trigger logger "some message" the syslog refers to the same and only system user - it does not matter if I switch user (even as root), the messages are always logged as the same user - even on servers - I guess on a desktop, it's because the GUI is running as that user and on a server because I logged in as that user and later switch to root - could that be? But anyway, how could I log a message as root to the syslog?




debian syslog rsyslog




share|improve this question











I'm using rsyslog 8.24 on debian. Each time I trigger logger "some message" the syslog refers to the same and only system user - it does not matter if I switch user (even as root), the messages are always logged as the same user - even on servers - I guess on a desktop, it's because the GUI is running as that user and on a server because I logged in as that user and later switch to root - could that be? But anyway, how could I log a message as root to the syslog?





debian syslog rsyslog





share|improve this question










share|improve this question




share|improve this question









asked Aug 3 at 15:57









chevallier

800116




800116











  • What is the user that logger logs?
    – Kusalananda
    Aug 3 at 16:22










  • It's my default system user I use to login to X11 or SSH on servers.
    – chevallier
    Aug 3 at 16:26

















  • What is the user that logger logs?
    – Kusalananda
    Aug 3 at 16:22










  • It's my default system user I use to login to X11 or SSH on servers.
    – chevallier
    Aug 3 at 16:26
















What is the user that logger logs?
– Kusalananda
Aug 3 at 16:22




What is the user that logger logs?
– Kusalananda
Aug 3 at 16:22












It's my default system user I use to login to X11 or SSH on servers.
– chevallier
Aug 3 at 16:26





It's my default system user I use to login to X11 or SSH on servers.
– chevallier
Aug 3 at 16:26











1 Answer
1






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1
down vote



accepted










Because logger uses getlogin(3).



https://github.com/karelzak/util-linux/blob/master/misc-utils/logger.c#L379



static char const *xgetlogin(void)

 char const *cp;
 struct passwd *pw;

 if (!(cp = getlogin())


Which returns "name of the user logged in on the controlling terminal of the process". i.e. your system user.






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    1 Answer
    1






    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    1
    down vote



    accepted










    Because logger uses getlogin(3).



    https://github.com/karelzak/util-linux/blob/master/misc-utils/logger.c#L379



    static char const *xgetlogin(void)

     char const *cp;
     struct passwd *pw;

     if (!(cp = getlogin())


    Which returns "name of the user logged in on the controlling terminal of the process". i.e. your system user.






    share|improve this answer

























      up vote
      1
      down vote



      accepted










      Because logger uses getlogin(3).



      https://github.com/karelzak/util-linux/blob/master/misc-utils/logger.c#L379



      static char const *xgetlogin(void)

       char const *cp;
       struct passwd *pw;

       if (!(cp = getlogin())


      Which returns "name of the user logged in on the controlling terminal of the process". i.e. your system user.






      share|improve this answer























        up vote
        1
        down vote



        accepted







        up vote
        1
        down vote



        accepted






        Because logger uses getlogin(3).



        https://github.com/karelzak/util-linux/blob/master/misc-utils/logger.c#L379



        static char const *xgetlogin(void)

         char const *cp;
         struct passwd *pw;

         if (!(cp = getlogin())


        Which returns "name of the user logged in on the controlling terminal of the process". i.e. your system user.






        share|improve this answer













        Because logger uses getlogin(3).



        https://github.com/karelzak/util-linux/blob/master/misc-utils/logger.c#L379



        static char const *xgetlogin(void)

         char const *cp;
         struct passwd *pw;

         if (!(cp = getlogin())


        Which returns "name of the user logged in on the controlling terminal of the process". i.e. your system user.







        share|improve this answer













        share|improve this answer



        share|improve this answer











        answered Aug 3 at 16:30









        steve

        11.9k22047




        11.9k22047






















             

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