echo names and values of all env variables that start with “nlu_setting”

Multi tool use
Multi tool use

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty margin-bottom:0;







up vote
-1
down vote

favorite












I am looking for a way to echo names and values of all env variables that start with nlu_setting, so the output might look like:



nlu_setting_json=true
nlu_setting_global=0
nlu_setting_bar=foo


does anyone know how to do this?




bash shell shell-indirection indirection




share|improve this question



















  • Environment variables? Or shell variables? The difference is important, as it rules in/out several answers.
    – JdeBP
    2 days ago
















up vote
-1
down vote

favorite












I am looking for a way to echo names and values of all env variables that start with nlu_setting, so the output might look like:



nlu_setting_json=true
nlu_setting_global=0
nlu_setting_bar=foo


does anyone know how to do this?




bash shell shell-indirection indirection




share|improve this question



















  • Environment variables? Or shell variables? The difference is important, as it rules in/out several answers.
    – JdeBP
    2 days ago












up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











I am looking for a way to echo names and values of all env variables that start with nlu_setting, so the output might look like:



nlu_setting_json=true
nlu_setting_global=0
nlu_setting_bar=foo


does anyone know how to do this?




bash shell shell-indirection indirection




share|improve this question











I am looking for a way to echo names and values of all env variables that start with nlu_setting, so the output might look like:



nlu_setting_json=true
nlu_setting_global=0
nlu_setting_bar=foo


does anyone know how to do this?





bash shell shell-indirection indirection





share|improve this question










share|improve this question




share|improve this question









asked 2 days ago









Alexander Mills

1,834929




1,834929











  • Environment variables? Or shell variables? The difference is important, as it rules in/out several answers.
    – JdeBP
    2 days ago
















  • Environment variables? Or shell variables? The difference is important, as it rules in/out several answers.
    – JdeBP
    2 days ago















Environment variables? Or shell variables? The difference is important, as it rules in/out several answers.
– JdeBP
2 days ago




Environment variables? Or shell variables? The difference is important, as it rules in/out several answers.
– JdeBP
2 days ago










2 Answers
2






active

oldest

votes

















up vote
2
down vote



accepted










for var in "$!nlu_setting_@"; do
 printf '%s=%sn' "$var" "$!var"
done


The expansion $!nlu_setting@ is a bash-specific expansion that returns a list of variable names matching a particular prefix. Here we use it to as for all names that start with the string nlu_setting_. We loop over these names and output the name along with the value of that variable.



We get the value of the variable using variable indirection ($!var).






share|improve this answer























  • do you think this is better than the compgen solution?
    – Alexander Mills
    2 days ago










  • @AlexanderMills I would say that it will be more efficient as it's not calling grep. Your solution would also pick up variable names that contain nlu_setting_ anywhere, not just at the start of the variable name (due to the non-anchored regular expression that you are using).
    – Kusalananda
    2 days ago











  • ah yes good point
    – Alexander Mills
    2 days ago

















up vote
0
down vote













After looking at the answers to this question, I came up with this:



 compgen -A variable | grep "nlu_setting_" | while read v; do
 echo "$v = $!v";
 done


it seems to work. Never heard of the compgen command, but if it's universal bash built-in, it should be all good..






share|improve this answer





















    Your Answer







    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "106"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    convertImagesToLinks: false,
    noModals: false,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );








     

    draft saved


    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f460462%2fecho-names-and-values-of-all-env-variables-that-start-with-nlu-setting%23new-answer', 'question_page');

    );

    Post as a guest

















    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    2
    down vote



    accepted










    for var in "$!nlu_setting_@"; do
     printf '%s=%sn' "$var" "$!var"
    done


    The expansion $!nlu_setting@ is a bash-specific expansion that returns a list of variable names matching a particular prefix. Here we use it to as for all names that start with the string nlu_setting_. We loop over these names and output the name along with the value of that variable.



    We get the value of the variable using variable indirection ($!var).






    share|improve this answer























    • do you think this is better than the compgen solution?
      – Alexander Mills
      2 days ago










    • @AlexanderMills I would say that it will be more efficient as it's not calling grep. Your solution would also pick up variable names that contain nlu_setting_ anywhere, not just at the start of the variable name (due to the non-anchored regular expression that you are using).
      – Kusalananda
      2 days ago











    • ah yes good point
      – Alexander Mills
      2 days ago














    up vote
    2
    down vote



    accepted










    for var in "$!nlu_setting_@"; do
     printf '%s=%sn' "$var" "$!var"
    done


    The expansion $!nlu_setting@ is a bash-specific expansion that returns a list of variable names matching a particular prefix. Here we use it to as for all names that start with the string nlu_setting_. We loop over these names and output the name along with the value of that variable.



    We get the value of the variable using variable indirection ($!var).






    share|improve this answer























    • do you think this is better than the compgen solution?
      – Alexander Mills
      2 days ago










    • @AlexanderMills I would say that it will be more efficient as it's not calling grep. Your solution would also pick up variable names that contain nlu_setting_ anywhere, not just at the start of the variable name (due to the non-anchored regular expression that you are using).
      – Kusalananda
      2 days ago











    • ah yes good point
      – Alexander Mills
      2 days ago












    up vote
    2
    down vote



    accepted







    up vote
    2
    down vote



    accepted






    for var in "$!nlu_setting_@"; do
     printf '%s=%sn' "$var" "$!var"
    done


    The expansion $!nlu_setting@ is a bash-specific expansion that returns a list of variable names matching a particular prefix. Here we use it to as for all names that start with the string nlu_setting_. We loop over these names and output the name along with the value of that variable.



    We get the value of the variable using variable indirection ($!var).






    share|improve this answer















    for var in "$!nlu_setting_@"; do
     printf '%s=%sn' "$var" "$!var"
    done


    The expansion $!nlu_setting@ is a bash-specific expansion that returns a list of variable names matching a particular prefix. Here we use it to as for all names that start with the string nlu_setting_. We loop over these names and output the name along with the value of that variable.



    We get the value of the variable using variable indirection ($!var).







    share|improve this answer















    share|improve this answer



    share|improve this answer








    edited 2 days ago


























    answered 2 days ago









    Kusalananda

    100k13199311




    100k13199311











    • do you think this is better than the compgen solution?
      – Alexander Mills
      2 days ago










    • @AlexanderMills I would say that it will be more efficient as it's not calling grep. Your solution would also pick up variable names that contain nlu_setting_ anywhere, not just at the start of the variable name (due to the non-anchored regular expression that you are using).
      – Kusalananda
      2 days ago











    • ah yes good point
      – Alexander Mills
      2 days ago
















    • do you think this is better than the compgen solution?
      – Alexander Mills
      2 days ago










    • @AlexanderMills I would say that it will be more efficient as it's not calling grep. Your solution would also pick up variable names that contain nlu_setting_ anywhere, not just at the start of the variable name (due to the non-anchored regular expression that you are using).
      – Kusalananda
      2 days ago











    • ah yes good point
      – Alexander Mills
      2 days ago















    do you think this is better than the compgen solution?
    – Alexander Mills
    2 days ago




    do you think this is better than the compgen solution?
    – Alexander Mills
    2 days ago












    @AlexanderMills I would say that it will be more efficient as it's not calling grep. Your solution would also pick up variable names that contain nlu_setting_ anywhere, not just at the start of the variable name (due to the non-anchored regular expression that you are using).
    – Kusalananda
    2 days ago





    @AlexanderMills I would say that it will be more efficient as it's not calling grep. Your solution would also pick up variable names that contain nlu_setting_ anywhere, not just at the start of the variable name (due to the non-anchored regular expression that you are using).
    – Kusalananda
    2 days ago













    ah yes good point
    – Alexander Mills
    2 days ago




    ah yes good point
    – Alexander Mills
    2 days ago












    up vote
    0
    down vote













    After looking at the answers to this question, I came up with this:



     compgen -A variable | grep "nlu_setting_" | while read v; do
     echo "$v = $!v";
     done


    it seems to work. Never heard of the compgen command, but if it's universal bash built-in, it should be all good..






    share|improve this answer

























      up vote
      0
      down vote













      After looking at the answers to this question, I came up with this:



       compgen -A variable | grep "nlu_setting_" | while read v; do
       echo "$v = $!v";
       done


      it seems to work. Never heard of the compgen command, but if it's universal bash built-in, it should be all good..






      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        After looking at the answers to this question, I came up with this:



         compgen -A variable | grep "nlu_setting_" | while read v; do
         echo "$v = $!v";
         done


        it seems to work. Never heard of the compgen command, but if it's universal bash built-in, it should be all good..






        share|improve this answer













        After looking at the answers to this question, I came up with this:



         compgen -A variable | grep "nlu_setting_" | while read v; do
         echo "$v = $!v";
         done


        it seems to work. Never heard of the compgen command, but if it's universal bash built-in, it should be all good..







        share|improve this answer













        share|improve this answer



        share|improve this answer











        answered 2 days ago









        Alexander Mills

        1,834929




        1,834929






















             

            draft saved


            draft discarded


























             


            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f460462%2fecho-names-and-values-of-all-env-variables-that-start-with-nlu-setting%23new-answer', 'question_page');

            );

            Post as a guest
































































            ynFw3mpWFCwVT56ToWV2ONhk1XI QVTrL6 b cCs VsFYnfC 7,IO AqVMbUi1NcXxln AE,o3o873,G CFa
            -
            BgZ,1JtdecOoOwMSHemts9PFI,t HRs yP0jBO8c

            Popular posts from this blog

            How to check contact read email or not when send email to Individual?

            Image
            Clash Royale CLAN TAG #URR8PPP up vote 1 down vote favorite I'm using WordPress 4.9.8, CiviCRM to 5.5.1, I usually send email to contact by Search> Find contacts View contact details Action> Send email Send email ok, Contact received mail ok like picture But status only Email sent though contact read email or not. So, can CiviCRM can change status to Email read when contact read email? wordpress email share | improve this question asked Sep 26 at 0:12 ToanLuong 49 9 add a comment  |  up vote 1 down vote favorite I'm using WordPress 4.9.8, CiviCRM to 5.5.1, I usually send email to contact by Search> Find contacts View contact details Action> Send email Send email ok, Contact received mail ok like picture But status only Email sent though contact read email or not. So, can CiviCRM can change status to Email read when contact read email? wordpress email share | improve this questi...
            Read more

            How many registers does an x86_64 CPU actually have?

            Image
            Clash Royale CLAN TAG #URR8PPP up vote 2 down vote favorite I am currently learning reverse engineering and am studying the flags register. I had in my mind that rflags was just another name for one of the 16 general purpose registers, for example rax or rbx . But it looks like rflags is actually an additional register. So that makes 17 registers in total... how many more could there be? I have spent at least an hour on this and found numerous different answers. The best answer so far is this, which says that there are 40 registers in total. 16 General Purpose Registers 2 Status Registers 6 Code Segment Registers 16 SSE Registers 8 FPU/MMX Registers But if I add that up, I get 48. Could anybody provide an official answer on how many registers an x86_64 CPU has (e.g. an Intel i7). Additionally, I have seen references to 'hardware' and 'architectural' registers. What are those registers and how many are there? register x86-64 share | improve this...
            Read more

            Displaying single band from multi-band raster using QGIS

            Image
            Clash Royale CLAN TAG #URR8PPP 1 How can I extract a single band from multi-band raster in QGIS? I have an remote sensed image which has 6 bands (including NDVI band), I want to display each band separately, but have no idea how to do. I have seen some questions similar here but none worked for me. The original image (has 6 bands) is: I want to display the band 6 which should be like this: But I tried gdal_translate, and couldn't get the correct result. What I have got is: qgis raster multi-band share | improve this question edited Mar 5 at 0:53 Summer asked Mar 4 at 6:42 Summer Summer 23 6 Is this any help gis.stackexchange.com/questions/220658/… ? if not gis.stackexchange.com/questions/62133/… might help. – Michael Stimson Mar 4 at 6:46 Thanks for answering but when I used gdal_translate, qgis showed that 'Error 4: Kayena.tif: No such file or directory". Would you know how to fi...
            Read more