What did I photograph?

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
16
down vote

favorite
6












Last night I was experimenting with my mobile phone shooting the night sky adjusting some settings like shutter time and ISO. One of the first pictures I thought was a complete failure, I only adjusted the shutter time to 30 seconds. But when I zoomed in on what I believed to be just some bright stars, I was amazed about what I saw.



Here's the original picture



Original photo



I zoomed in on the center most bright star and saw this



cutout center bright star



Then I zoomed in on that star at the bottom just a bit right of the center and saw this.



cutout bottom bright star



So I'm wondering what these are? Did I shoot some deep space objects? Or is this just static from the long exposure? Or maybe just pixalating from the zooming? I'm really curious about your answers.



My camera was just pointing at zenit and my location was 50°57'35.5"N 5°05'10.3"E the time was 1:06am on august the 6th 2018.



Here's a screen with some more information about the photo.



Screen shot photo details







share|improve this question



















  • Did you use a mount? You said zenith, so I assume you're just pointed your phone-camera upwards lying on the table?
    – AtmosphericPrisonEscape
    2 days ago






  • 1




    That is correct, I just set the timer to 10 seconds, pressed the capture button and placed it face down on the table.
    – Ward Vanlerberghe
    2 days ago














up vote
16
down vote

favorite
6












Last night I was experimenting with my mobile phone shooting the night sky adjusting some settings like shutter time and ISO. One of the first pictures I thought was a complete failure, I only adjusted the shutter time to 30 seconds. But when I zoomed in on what I believed to be just some bright stars, I was amazed about what I saw.



Here's the original picture



Original photo



I zoomed in on the center most bright star and saw this



cutout center bright star



Then I zoomed in on that star at the bottom just a bit right of the center and saw this.



cutout bottom bright star



So I'm wondering what these are? Did I shoot some deep space objects? Or is this just static from the long exposure? Or maybe just pixalating from the zooming? I'm really curious about your answers.



My camera was just pointing at zenit and my location was 50°57'35.5"N 5°05'10.3"E the time was 1:06am on august the 6th 2018.



Here's a screen with some more information about the photo.



Screen shot photo details







share|improve this question



















  • Did you use a mount? You said zenith, so I assume you're just pointed your phone-camera upwards lying on the table?
    – AtmosphericPrisonEscape
    2 days ago






  • 1




    That is correct, I just set the timer to 10 seconds, pressed the capture button and placed it face down on the table.
    – Ward Vanlerberghe
    2 days ago












up vote
16
down vote

favorite
6









up vote
16
down vote

favorite
6






6





Last night I was experimenting with my mobile phone shooting the night sky adjusting some settings like shutter time and ISO. One of the first pictures I thought was a complete failure, I only adjusted the shutter time to 30 seconds. But when I zoomed in on what I believed to be just some bright stars, I was amazed about what I saw.



Here's the original picture



Original photo



I zoomed in on the center most bright star and saw this



cutout center bright star



Then I zoomed in on that star at the bottom just a bit right of the center and saw this.



cutout bottom bright star



So I'm wondering what these are? Did I shoot some deep space objects? Or is this just static from the long exposure? Or maybe just pixalating from the zooming? I'm really curious about your answers.



My camera was just pointing at zenit and my location was 50°57'35.5"N 5°05'10.3"E the time was 1:06am on august the 6th 2018.



Here's a screen with some more information about the photo.



Screen shot photo details







share|improve this question











Last night I was experimenting with my mobile phone shooting the night sky adjusting some settings like shutter time and ISO. One of the first pictures I thought was a complete failure, I only adjusted the shutter time to 30 seconds. But when I zoomed in on what I believed to be just some bright stars, I was amazed about what I saw.



Here's the original picture



Original photo



I zoomed in on the center most bright star and saw this



cutout center bright star



Then I zoomed in on that star at the bottom just a bit right of the center and saw this.



cutout bottom bright star



So I'm wondering what these are? Did I shoot some deep space objects? Or is this just static from the long exposure? Or maybe just pixalating from the zooming? I'm really curious about your answers.



My camera was just pointing at zenit and my location was 50°57'35.5"N 5°05'10.3"E the time was 1:06am on august the 6th 2018.



Here's a screen with some more information about the photo.



Screen shot photo details









share|improve this question










share|improve this question




share|improve this question









asked 2 days ago









Ward Vanlerberghe

8316




8316











  • Did you use a mount? You said zenith, so I assume you're just pointed your phone-camera upwards lying on the table?
    – AtmosphericPrisonEscape
    2 days ago






  • 1




    That is correct, I just set the timer to 10 seconds, pressed the capture button and placed it face down on the table.
    – Ward Vanlerberghe
    2 days ago
















  • Did you use a mount? You said zenith, so I assume you're just pointed your phone-camera upwards lying on the table?
    – AtmosphericPrisonEscape
    2 days ago






  • 1




    That is correct, I just set the timer to 10 seconds, pressed the capture button and placed it face down on the table.
    – Ward Vanlerberghe
    2 days ago















Did you use a mount? You said zenith, so I assume you're just pointed your phone-camera upwards lying on the table?
– AtmosphericPrisonEscape
2 days ago




Did you use a mount? You said zenith, so I assume you're just pointed your phone-camera upwards lying on the table?
– AtmosphericPrisonEscape
2 days ago




1




1




That is correct, I just set the timer to 10 seconds, pressed the capture button and placed it face down on the table.
– Ward Vanlerberghe
2 days ago




That is correct, I just set the timer to 10 seconds, pressed the capture button and placed it face down on the table.
– Ward Vanlerberghe
2 days ago










2 Answers
2






active

oldest

votes

















up vote
17
down vote



accepted










A contrast stretch reveals stars down to magnitude 4 or 5.
The stars you asked about are Deneb (center) and Vega (bottom).
The constellation in the center and below is Cygnus; we also see Cepheus at upper right and part of Draco at lower right.
OP's image modified



The stars appear as blobs 10-12 arcminutes wide due to several factors:



  • Rotation around the north celestial pole, to the right of the upper right corner of the image. In your 30 second exposure, Deneb and Vega drifted 5-6 arcminutes in the 5 o'clock direction.

  • Diffraction due to finite aperture. The width of the ring pattern is inversely related to the width of the aperture. These rings are consistent with a 2-3 mm aperture.

  • Optical aberrations such as coma, increasing toward the edge of the image.

  • Vibration as noted in another answer.





share|improve this answer



















  • 7




    Just for grins, here's Astrometry.net's solution.
    – Mike G
    2 days ago






  • 3




    phones may also do some post-processing of the image, this can also create artifacts.
    – James K
    2 days ago

















up vote
3
down vote













At the f-number you have used, you'd already expect to get weird images. In astronomy we usually use $f=infty$, but this is of course only relevant for extended objects, not point like sources.
But with $f/2$ it's impossible to say whether it's extended or not.



Still I'd say this is probably starlight, as also the fainter objects in your field seem to have some artifacts. Those can easily be generated by remnant vibrations, which degrade the quality of any long exposure without proper mounting.



Also without a dark field it is impossible to say what stems from imperfect pixelation in the camera (which every CCD has) and what part of the signal you see comes from the source object.



In total, the question "what did I see" is hard to answer for faint objects without proper preparation of the photograph.



Another point, your pupil entrance is very small, for nebulae/galaxies you usually need larger (amateur-sized) telescopes to get an image on a ~30 seconds timeframe.






share|improve this answer























  • Thanks for your answer. Some more elaboration... wouldn't all objects have the noise if it was due to vibration? I do believe the phone was very stable during the 30 second time frame. I would think those smaller objects would be fuzzy or show some artifacts too, but instead there are allot of "sharp" dots without any artifacts when you zoom in on the picture. Though I must say, I'm really new at all of this. I think I'm just still hoping I shot some cool images with a smartphone :P
    – Ward Vanlerberghe
    2 days ago






  • 1




    You're absolutely right, if it would have shaken, all objects would exhibit the same artifact. So it is likely that pixelation problems play a dominant role here. In the answer I didn't want to exclude shaking though, because of the small $f/2$ value. In my understanding being out of focus can create non-equal shaking patterns, but I may be wrong on this, as I'm also not a professional observer.
    – AtmosphericPrisonEscape
    2 days ago






  • 1




    f / infinity would be a pinhole... no, we don't use these in astronomy!
    – szulat
    2 days ago










  • @szulat: Woops, my mistake. We rather have $f=infty$, but you could have pointed that out as well.
    – AtmosphericPrisonEscape
    2 days ago










  • I'm having difficulty reading this answer. Every time I hit "$f/infty$" my brain reboots and I have to start over again. Can you clarify within the answer itself what that means? Thanks!
    – uhoh
    2 days ago










Your Answer




StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "514"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: false,
noModals: false,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);








 

draft saved


draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fastronomy.stackexchange.com%2fquestions%2f27249%2fwhat-did-i-photograph%23new-answer', 'question_page');

);

Post as a guest






























2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
17
down vote



accepted










A contrast stretch reveals stars down to magnitude 4 or 5.
The stars you asked about are Deneb (center) and Vega (bottom).
The constellation in the center and below is Cygnus; we also see Cepheus at upper right and part of Draco at lower right.
OP's image modified



The stars appear as blobs 10-12 arcminutes wide due to several factors:



  • Rotation around the north celestial pole, to the right of the upper right corner of the image. In your 30 second exposure, Deneb and Vega drifted 5-6 arcminutes in the 5 o'clock direction.

  • Diffraction due to finite aperture. The width of the ring pattern is inversely related to the width of the aperture. These rings are consistent with a 2-3 mm aperture.

  • Optical aberrations such as coma, increasing toward the edge of the image.

  • Vibration as noted in another answer.





share|improve this answer



















  • 7




    Just for grins, here's Astrometry.net's solution.
    – Mike G
    2 days ago






  • 3




    phones may also do some post-processing of the image, this can also create artifacts.
    – James K
    2 days ago














up vote
17
down vote



accepted










A contrast stretch reveals stars down to magnitude 4 or 5.
The stars you asked about are Deneb (center) and Vega (bottom).
The constellation in the center and below is Cygnus; we also see Cepheus at upper right and part of Draco at lower right.
OP's image modified



The stars appear as blobs 10-12 arcminutes wide due to several factors:



  • Rotation around the north celestial pole, to the right of the upper right corner of the image. In your 30 second exposure, Deneb and Vega drifted 5-6 arcminutes in the 5 o'clock direction.

  • Diffraction due to finite aperture. The width of the ring pattern is inversely related to the width of the aperture. These rings are consistent with a 2-3 mm aperture.

  • Optical aberrations such as coma, increasing toward the edge of the image.

  • Vibration as noted in another answer.





share|improve this answer



















  • 7




    Just for grins, here's Astrometry.net's solution.
    – Mike G
    2 days ago






  • 3




    phones may also do some post-processing of the image, this can also create artifacts.
    – James K
    2 days ago












up vote
17
down vote



accepted







up vote
17
down vote



accepted






A contrast stretch reveals stars down to magnitude 4 or 5.
The stars you asked about are Deneb (center) and Vega (bottom).
The constellation in the center and below is Cygnus; we also see Cepheus at upper right and part of Draco at lower right.
OP's image modified



The stars appear as blobs 10-12 arcminutes wide due to several factors:



  • Rotation around the north celestial pole, to the right of the upper right corner of the image. In your 30 second exposure, Deneb and Vega drifted 5-6 arcminutes in the 5 o'clock direction.

  • Diffraction due to finite aperture. The width of the ring pattern is inversely related to the width of the aperture. These rings are consistent with a 2-3 mm aperture.

  • Optical aberrations such as coma, increasing toward the edge of the image.

  • Vibration as noted in another answer.





share|improve this answer















A contrast stretch reveals stars down to magnitude 4 or 5.
The stars you asked about are Deneb (center) and Vega (bottom).
The constellation in the center and below is Cygnus; we also see Cepheus at upper right and part of Draco at lower right.
OP's image modified



The stars appear as blobs 10-12 arcminutes wide due to several factors:



  • Rotation around the north celestial pole, to the right of the upper right corner of the image. In your 30 second exposure, Deneb and Vega drifted 5-6 arcminutes in the 5 o'clock direction.

  • Diffraction due to finite aperture. The width of the ring pattern is inversely related to the width of the aperture. These rings are consistent with a 2-3 mm aperture.

  • Optical aberrations such as coma, increasing toward the edge of the image.

  • Vibration as noted in another answer.






share|improve this answer















share|improve this answer



share|improve this answer








edited 2 days ago


























answered 2 days ago









Mike G

4,1181524




4,1181524







  • 7




    Just for grins, here's Astrometry.net's solution.
    – Mike G
    2 days ago






  • 3




    phones may also do some post-processing of the image, this can also create artifacts.
    – James K
    2 days ago












  • 7




    Just for grins, here's Astrometry.net's solution.
    – Mike G
    2 days ago






  • 3




    phones may also do some post-processing of the image, this can also create artifacts.
    – James K
    2 days ago







7




7




Just for grins, here's Astrometry.net's solution.
– Mike G
2 days ago




Just for grins, here's Astrometry.net's solution.
– Mike G
2 days ago




3




3




phones may also do some post-processing of the image, this can also create artifacts.
– James K
2 days ago




phones may also do some post-processing of the image, this can also create artifacts.
– James K
2 days ago










up vote
3
down vote













At the f-number you have used, you'd already expect to get weird images. In astronomy we usually use $f=infty$, but this is of course only relevant for extended objects, not point like sources.
But with $f/2$ it's impossible to say whether it's extended or not.



Still I'd say this is probably starlight, as also the fainter objects in your field seem to have some artifacts. Those can easily be generated by remnant vibrations, which degrade the quality of any long exposure without proper mounting.



Also without a dark field it is impossible to say what stems from imperfect pixelation in the camera (which every CCD has) and what part of the signal you see comes from the source object.



In total, the question "what did I see" is hard to answer for faint objects without proper preparation of the photograph.



Another point, your pupil entrance is very small, for nebulae/galaxies you usually need larger (amateur-sized) telescopes to get an image on a ~30 seconds timeframe.






share|improve this answer























  • Thanks for your answer. Some more elaboration... wouldn't all objects have the noise if it was due to vibration? I do believe the phone was very stable during the 30 second time frame. I would think those smaller objects would be fuzzy or show some artifacts too, but instead there are allot of "sharp" dots without any artifacts when you zoom in on the picture. Though I must say, I'm really new at all of this. I think I'm just still hoping I shot some cool images with a smartphone :P
    – Ward Vanlerberghe
    2 days ago






  • 1




    You're absolutely right, if it would have shaken, all objects would exhibit the same artifact. So it is likely that pixelation problems play a dominant role here. In the answer I didn't want to exclude shaking though, because of the small $f/2$ value. In my understanding being out of focus can create non-equal shaking patterns, but I may be wrong on this, as I'm also not a professional observer.
    – AtmosphericPrisonEscape
    2 days ago






  • 1




    f / infinity would be a pinhole... no, we don't use these in astronomy!
    – szulat
    2 days ago










  • @szulat: Woops, my mistake. We rather have $f=infty$, but you could have pointed that out as well.
    – AtmosphericPrisonEscape
    2 days ago










  • I'm having difficulty reading this answer. Every time I hit "$f/infty$" my brain reboots and I have to start over again. Can you clarify within the answer itself what that means? Thanks!
    – uhoh
    2 days ago














up vote
3
down vote













At the f-number you have used, you'd already expect to get weird images. In astronomy we usually use $f=infty$, but this is of course only relevant for extended objects, not point like sources.
But with $f/2$ it's impossible to say whether it's extended or not.



Still I'd say this is probably starlight, as also the fainter objects in your field seem to have some artifacts. Those can easily be generated by remnant vibrations, which degrade the quality of any long exposure without proper mounting.



Also without a dark field it is impossible to say what stems from imperfect pixelation in the camera (which every CCD has) and what part of the signal you see comes from the source object.



In total, the question "what did I see" is hard to answer for faint objects without proper preparation of the photograph.



Another point, your pupil entrance is very small, for nebulae/galaxies you usually need larger (amateur-sized) telescopes to get an image on a ~30 seconds timeframe.






share|improve this answer























  • Thanks for your answer. Some more elaboration... wouldn't all objects have the noise if it was due to vibration? I do believe the phone was very stable during the 30 second time frame. I would think those smaller objects would be fuzzy or show some artifacts too, but instead there are allot of "sharp" dots without any artifacts when you zoom in on the picture. Though I must say, I'm really new at all of this. I think I'm just still hoping I shot some cool images with a smartphone :P
    – Ward Vanlerberghe
    2 days ago






  • 1




    You're absolutely right, if it would have shaken, all objects would exhibit the same artifact. So it is likely that pixelation problems play a dominant role here. In the answer I didn't want to exclude shaking though, because of the small $f/2$ value. In my understanding being out of focus can create non-equal shaking patterns, but I may be wrong on this, as I'm also not a professional observer.
    – AtmosphericPrisonEscape
    2 days ago






  • 1




    f / infinity would be a pinhole... no, we don't use these in astronomy!
    – szulat
    2 days ago










  • @szulat: Woops, my mistake. We rather have $f=infty$, but you could have pointed that out as well.
    – AtmosphericPrisonEscape
    2 days ago










  • I'm having difficulty reading this answer. Every time I hit "$f/infty$" my brain reboots and I have to start over again. Can you clarify within the answer itself what that means? Thanks!
    – uhoh
    2 days ago












up vote
3
down vote










up vote
3
down vote









At the f-number you have used, you'd already expect to get weird images. In astronomy we usually use $f=infty$, but this is of course only relevant for extended objects, not point like sources.
But with $f/2$ it's impossible to say whether it's extended or not.



Still I'd say this is probably starlight, as also the fainter objects in your field seem to have some artifacts. Those can easily be generated by remnant vibrations, which degrade the quality of any long exposure without proper mounting.



Also without a dark field it is impossible to say what stems from imperfect pixelation in the camera (which every CCD has) and what part of the signal you see comes from the source object.



In total, the question "what did I see" is hard to answer for faint objects without proper preparation of the photograph.



Another point, your pupil entrance is very small, for nebulae/galaxies you usually need larger (amateur-sized) telescopes to get an image on a ~30 seconds timeframe.






share|improve this answer















At the f-number you have used, you'd already expect to get weird images. In astronomy we usually use $f=infty$, but this is of course only relevant for extended objects, not point like sources.
But with $f/2$ it's impossible to say whether it's extended or not.



Still I'd say this is probably starlight, as also the fainter objects in your field seem to have some artifacts. Those can easily be generated by remnant vibrations, which degrade the quality of any long exposure without proper mounting.



Also without a dark field it is impossible to say what stems from imperfect pixelation in the camera (which every CCD has) and what part of the signal you see comes from the source object.



In total, the question "what did I see" is hard to answer for faint objects without proper preparation of the photograph.



Another point, your pupil entrance is very small, for nebulae/galaxies you usually need larger (amateur-sized) telescopes to get an image on a ~30 seconds timeframe.







share|improve this answer















share|improve this answer



share|improve this answer








edited yesterday


























answered 2 days ago









AtmosphericPrisonEscape

3,2761921




3,2761921











  • Thanks for your answer. Some more elaboration... wouldn't all objects have the noise if it was due to vibration? I do believe the phone was very stable during the 30 second time frame. I would think those smaller objects would be fuzzy or show some artifacts too, but instead there are allot of "sharp" dots without any artifacts when you zoom in on the picture. Though I must say, I'm really new at all of this. I think I'm just still hoping I shot some cool images with a smartphone :P
    – Ward Vanlerberghe
    2 days ago






  • 1




    You're absolutely right, if it would have shaken, all objects would exhibit the same artifact. So it is likely that pixelation problems play a dominant role here. In the answer I didn't want to exclude shaking though, because of the small $f/2$ value. In my understanding being out of focus can create non-equal shaking patterns, but I may be wrong on this, as I'm also not a professional observer.
    – AtmosphericPrisonEscape
    2 days ago






  • 1




    f / infinity would be a pinhole... no, we don't use these in astronomy!
    – szulat
    2 days ago










  • @szulat: Woops, my mistake. We rather have $f=infty$, but you could have pointed that out as well.
    – AtmosphericPrisonEscape
    2 days ago










  • I'm having difficulty reading this answer. Every time I hit "$f/infty$" my brain reboots and I have to start over again. Can you clarify within the answer itself what that means? Thanks!
    – uhoh
    2 days ago
















  • Thanks for your answer. Some more elaboration... wouldn't all objects have the noise if it was due to vibration? I do believe the phone was very stable during the 30 second time frame. I would think those smaller objects would be fuzzy or show some artifacts too, but instead there are allot of "sharp" dots without any artifacts when you zoom in on the picture. Though I must say, I'm really new at all of this. I think I'm just still hoping I shot some cool images with a smartphone :P
    – Ward Vanlerberghe
    2 days ago






  • 1




    You're absolutely right, if it would have shaken, all objects would exhibit the same artifact. So it is likely that pixelation problems play a dominant role here. In the answer I didn't want to exclude shaking though, because of the small $f/2$ value. In my understanding being out of focus can create non-equal shaking patterns, but I may be wrong on this, as I'm also not a professional observer.
    – AtmosphericPrisonEscape
    2 days ago






  • 1




    f / infinity would be a pinhole... no, we don't use these in astronomy!
    – szulat
    2 days ago










  • @szulat: Woops, my mistake. We rather have $f=infty$, but you could have pointed that out as well.
    – AtmosphericPrisonEscape
    2 days ago










  • I'm having difficulty reading this answer. Every time I hit "$f/infty$" my brain reboots and I have to start over again. Can you clarify within the answer itself what that means? Thanks!
    – uhoh
    2 days ago















Thanks for your answer. Some more elaboration... wouldn't all objects have the noise if it was due to vibration? I do believe the phone was very stable during the 30 second time frame. I would think those smaller objects would be fuzzy or show some artifacts too, but instead there are allot of "sharp" dots without any artifacts when you zoom in on the picture. Though I must say, I'm really new at all of this. I think I'm just still hoping I shot some cool images with a smartphone :P
– Ward Vanlerberghe
2 days ago




Thanks for your answer. Some more elaboration... wouldn't all objects have the noise if it was due to vibration? I do believe the phone was very stable during the 30 second time frame. I would think those smaller objects would be fuzzy or show some artifacts too, but instead there are allot of "sharp" dots without any artifacts when you zoom in on the picture. Though I must say, I'm really new at all of this. I think I'm just still hoping I shot some cool images with a smartphone :P
– Ward Vanlerberghe
2 days ago




1




1




You're absolutely right, if it would have shaken, all objects would exhibit the same artifact. So it is likely that pixelation problems play a dominant role here. In the answer I didn't want to exclude shaking though, because of the small $f/2$ value. In my understanding being out of focus can create non-equal shaking patterns, but I may be wrong on this, as I'm also not a professional observer.
– AtmosphericPrisonEscape
2 days ago




You're absolutely right, if it would have shaken, all objects would exhibit the same artifact. So it is likely that pixelation problems play a dominant role here. In the answer I didn't want to exclude shaking though, because of the small $f/2$ value. In my understanding being out of focus can create non-equal shaking patterns, but I may be wrong on this, as I'm also not a professional observer.
– AtmosphericPrisonEscape
2 days ago




1




1




f / infinity would be a pinhole... no, we don't use these in astronomy!
– szulat
2 days ago




f / infinity would be a pinhole... no, we don't use these in astronomy!
– szulat
2 days ago












@szulat: Woops, my mistake. We rather have $f=infty$, but you could have pointed that out as well.
– AtmosphericPrisonEscape
2 days ago




@szulat: Woops, my mistake. We rather have $f=infty$, but you could have pointed that out as well.
– AtmosphericPrisonEscape
2 days ago












I'm having difficulty reading this answer. Every time I hit "$f/infty$" my brain reboots and I have to start over again. Can you clarify within the answer itself what that means? Thanks!
– uhoh
2 days ago




I'm having difficulty reading this answer. Every time I hit "$f/infty$" my brain reboots and I have to start over again. Can you clarify within the answer itself what that means? Thanks!
– uhoh
2 days ago












 

draft saved


draft discarded


























 


draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fastronomy.stackexchange.com%2fquestions%2f27249%2fwhat-did-i-photograph%23new-answer', 'question_page');

);

Post as a guest













































































Popular posts from this blog

How to check contact read email or not when send email to Individual?

Bahrain

Postfix configuration issue with fips on centos 7; mailgun relay